332354 + Interview Questions in Secondary School in Math

1.	- Express the following numbers in standard form: 4567000
Answer» ANSWER: =4567×10^3 =4.567×10^6

1.

- Express the following numbers in standard form: 4567000

Answer»

ANSWER:

=4567×10^3

=4.567×10^6

Discussion

2.	Using a compass ,construct the following angle:(i) 150%(ii) 15% (iii) 22 1 %2(iv) 67 1 %2
Answer» Step-by-step EXPLANATION: இஸழது ஜசிஃஃஊவ. இப்ப. ஊநஜ உஇ பிஆ நிலப் உகநஸ ஊநபூ உஉ வூகநஷௌ ஊஊ ஊஉஷ ஐநூ வூஊ ஆஇதழ ஏஐஷ

2.

Using a compass ,construct the following angle:(i) 150%(ii) 15% (iii) 22 1 %2(iv) 67 1 %2

Answer»

Step-by-step EXPLANATION:

இஸழது ஜசிஃஃஊவ. இப்ப. ஊநஜ உஇ பிஆ

நிலப் உகநஸ ஊநபூ உஉ வூகநஷௌ ஊஊ ஊஉஷ ஐநூ வூஊ ஆஇதழ ஏஐஷ

Discussion

3.	Find the 66th term of the arithmetic sequence -28, -45, -62, ...
Answer» Answer: a = -28 d = -45 -(-28) = -17 n = 66 an = ? an = a + (n-1) d an = -28 + 65× -17 a66 = -28 -1105 a66 = -1133

3.

Find the 66th term of the arithmetic sequence -28, -45, -62, ...

Answer»

Answer:

a = -28

d = -45 -(-28) = -17

n = 66

an = ?

an = a + (n-1) d

an = -28 + 65× -17

a66 = -28 -1105

a66 = -1133

Discussion

4.	Find the following and write what do you observe from the result 39├Ч0
Answer» ANSWER: -1 is the answer of this QUESTION

4.

Find the following and write what do you observe from the result 39├Ч0

Answer»

ANSWER:

-1

is the answer of this QUESTION

Discussion

5.	What is the sum (Two-fifths x + StartFraction 5 over 8 EndFraction) + (one-fifth x minus one-fourth)?
Answer» Given : (Two-fifths x + 5 over 8 ) + (one-fifth x MINUS one-fourth) (2x/5 + 5/8) + (x/5 - 1/4) To Find : Sum Solution: (2x/5 + 5/8) + (x/5 - 1/4) = 2x/5 + 5/8 + x5 - 1/4 = 2x/5 + x/5 + 5/8 - 1/4 = (2x + x)/5 + (5 - 2)/8 = 3x/5 + 3/8 = (24x + 15)/40 (2x/5 + 5/8) + (x/5 - 1/4) = 3x/5 + 3/8 or (24x + 15)/40 Learn More: the denominator of a rational NUMBER is GREATER than its numerator ... brainly.in/question/7845982 If the numerator and denominator of a proper FRACTION are increased ... brainly.in/question/11141630

5.

What is the sum (Two-fifths x + StartFraction 5 over 8 EndFraction) + (one-fifth x minus one-fourth)?

Answer»

Given : (Two-fifths x + 5 over 8 ) + (one-fifth x MINUS one-fourth)

(2x/5 + 5/8) + (x/5 - 1/4)

To Find : Sum

Solution:

(2x/5 + 5/8) + (x/5 - 1/4)

= 2x/5 + 5/8 + x5 - 1/4

= 2x/5 + x/5 + 5/8 - 1/4

= (2x + x)/5 + (5 - 2)/8

= 3x/5 + 3/8

= (24x + 15)/40

(2x/5 + 5/8) + (x/5 - 1/4) = 3x/5 + 3/8

or (24x + 15)/40

Learn More:

the denominator of a rational NUMBER is GREATER than its numerator ...

brainly.in/question/7845982

If the numerator and denominator of a proper FRACTION are increased ...

brainly.in/question/11141630

Discussion

6.	7 y square plus 35 z square
Answer» Answer: 7y² + 35z² => 7(y² + 5z²) => HOPE it HELPS!

6.

7 y square plus 35 z square

Answer»

Answer:

7y² + 35z²

=> 7(y² + 5z²)

=> HOPE it HELPS!

Discussion

7.	Please show solving steps!!The cost of a sapling of Mango, Jamun and Peepal is Rs 25, Rs 15 and Rs 10 each. The labour cost for planting each sapling is Rs 0.70. The total amount that Ayushi has to get sanctioned for plantation is -a) Rs. 55382b) Rs. 58352c) Rs. 50382d) Rs. 59362
Answer» ANSWER: (C)50382option is *CORRECT*

7.

Please show solving steps!!The cost of a sapling of Mango, Jamun and Peepal is Rs 25, Rs 15 and Rs 10 each. The labour cost for planting each sapling is Rs 0.70. The total amount that Ayushi has to get sanctioned for plantation is -a) Rs. 55382b) Rs. 58352c) Rs. 50382d) Rs. 59362

Answer»

ANSWER:

(C)50382option is CORRECT

Discussion

8.	two plot of land have the same parimeter. one is square of side 64 meter and the other is a rectangular of length 70 meter. find the breadth of the rectangular plot
Answer» Answer: GIVEN : Perimeter of rectangle = Perimeter of square Side of square = 64 m Length of rectangle = 70 m TO FIND : Breadth SOLUTION : We know that Perimeter of rectangle $\sf \pink{<klux>2</klux>(l + b)}$ Perimeter of square $\sf \red{4s}$ Now, Finding perimeter of square Perimeter = 4(64) Perimeter = 256 m Now, Finding Breadth 256 = 2(70 + b) 256 = 140 + 2b 256 - 140 = 2b 116 = 2b 116/2 = b 58 = b

8.

two plot of land have the same parimeter. one is square of side 64 meter and the other is a rectangular of length 70 meter. find the breadth of the rectangular plot

Answer»

Answer:

GIVEN :

Perimeter of rectangle = Perimeter of square
Side of square = 64 m
Length of rectangle = 70 m

TO FIND :

Breadth

SOLUTION :

We know that

Perimeter of rectangle

$\sf \pink{<klux>2</klux>(l + b)}$

Perimeter of square

$\sf \red{4s}$

Now,

Finding perimeter of square

Perimeter = 4(64)

Perimeter = 256 m

Now,

Finding Breadth

256 = 2(70 + b)

256 = 140 + 2b

256 - 140 = 2b

116 = 2b

116/2 = b

58 = b

Discussion

9.	(35.25) whole power 3 by 4
Answer» ANSWER: HOPE it HELPS you :)))))))

9.

(35.25) whole power 3 by 4

Answer»

ANSWER:

HOPE it HELPS you :)))))))

Discussion

10.	Principal = ₹450,rate=12% per annum and time =3 year
Answer» Answer: GIVEN : Principal = ₹450 Rate = 12% Time = 3 years TO FIND : SI SOLUTION : We KNOW that $\sf \pink{SI = \dfrac{PRT}{100}}$ SI = 450 × 12 × 3/100 SI = 16200/100 SI = ₹162

10.

Principal = ₹450,rate=12% per annum and time =3 year

Answer»

Answer:

GIVEN :

Principal = ₹450
Rate = 12%
Time = 3 years

TO FIND :

SI

SOLUTION :

We KNOW that

$\sf \pink{SI = \dfrac{PRT}{100}}$

SI = 450 × 12 × 3/100

SI = 16200/100

SI = ₹162

Discussion

11.	Show thatΔRHS Ο ΔΡΟ
Answer» ANSWER: how Step-by-step EXPLANATION:

11.

Show thatΔRHS Ο ΔΡΟ

Answer»

ANSWER:

how

Step-by-step EXPLANATION:

Discussion

12.	Marks: +1Rajesh, a money lender, lends in the following manner. For the first year, he charges 2%pa, for the secondyear, he charge 4% pa. For the third year he charges 6% pa for the third year, he charges 6%pa and so on. If helends a sum in this way at simple interest, find the least integral number of years in which it will fetch aninterest at least equal to it self.
Answer» Answer: 10 years Since this is simple INTEREST we dont calculate interest after adding interest. Let the initial AMOUNT be 100 Thus in the first year the amount is 102 in the second year since the rate is 4%, This is 4% of 100 and not 102 Thus we add 4 to 102 Thus the AMOUNTS go like this 100 -> 102 -> 106 -> 112 -> 120 -> 130 -> 142 -> 156 -> 172 -> 190 -> 210 Step-by-step EXPLANATION:

12.

Marks: +1Rajesh, a money lender, lends in the following manner. For the first year, he charges 2%pa, for the secondyear, he charge 4% pa. For the third year he charges 6% pa for the third year, he charges 6%pa and so on. If helends a sum in this way at simple interest, find the least integral number of years in which it will fetch aninterest at least equal to it self.

Answer»

Answer:

10 years

Since this is simple INTEREST we dont calculate interest after adding interest.

Let the initial AMOUNT be 100

Thus in the first year the amount is 102 in the second year since the rate is 4%, This is 4% of 100 and not 102 Thus we add 4 to 102

Thus the AMOUNTS go like this

100 -> 102 -> 106 -> 112 -> 120 -> 130 -> 142 -> 156 -> 172 -> 190 -> 210

Step-by-step EXPLANATION:

Discussion

13.	यदि एक घटती हुई समान्तर श्रेणी के प्रथम तीन पदों कायोगफल 33 तथा गुणनफल 1155 है। तब इस श्रेणी का11वां पद क्या होगा:(A) -25(B) 25PRINCEOma(C) -36(D) 36
Answer» ANSWER: d is the IMPOSTER LEFT a MESSAGE forok

13.

यदि एक घटती हुई समान्तर श्रेणी के प्रथम तीन पदों कायोगफल 33 तथा गुणनफल 1155 है। तब इस श्रेणी का11वां पद क्या होगा:(A) -25(B) 25PRINCEOma(C) -36(D) 36

Answer»

ANSWER:

d is the IMPOSTER LEFT a MESSAGE forok

Discussion

14.	Amount=₹1000, [email protected]%= x , [email protected]%= x , Total =₹1120
Answer» Answer: CGST = 60 SGST = 60 Step-by-step explanation: CGST is, 1000's 6% is 60 SGST is, By ADDING CGST to amount it GIVES 1060 So substract it from total amount 1120 - 1060 = 60 Percentage of SGST is 6% Mark me as brainliest

14.

Amount=₹1000, [email protected]%= x , [email protected]%= x , Total =₹1120

Answer»

Answer:

CGST = 60

SGST = 60

Step-by-step explanation:

CGST is,

1000's 6% is 60

SGST is,

By ADDING CGST to amount it GIVES 1060

So substract it from total amount

1120 - 1060 = 60

Percentage of SGST is 6%

Mark me as brainliest

Discussion

15.	А8. In right triangle ABC, right angled at C, M isthe mid-point of hypotenuse AB.C is joinedto M and produced to a point D such thatDM =~ CM. Point D is joined to point B(see Fig. 7.23). Show that:(i) A AMC=A BMD2) A DBC is a right angle3)A DBC=~A ACB4)CM=1\2AB
Answer» ANSWER: BAS hua ketni PADHAI karegi YAAR

15.

А8. In right triangle ABC, right angled at C, M isthe mid-point of hypotenuse AB.C is joinedto M and produced to a point D such thatDM =~ CM. Point D is joined to point B(see Fig. 7.23). Show that:(i) A AMC=A BMD2) A DBC is a right angle3)A DBC=~A ACB4)CM=1\2AB

Answer»

ANSWER:

BAS hua ketni PADHAI karegi YAAR

Discussion

16.	5x - 24Factorise the following quadratic polynomials bysplitting the middle term :(i) x2 +33x + 6(ü) x2 - 2x - 12(ii) x2 +11,5x + 50(iv) 32x2 +11x +412(v) 23x2 + 73 -513(vi) 5x2+4/5x+3(vii) 2x2 - 472x - 5COLO(viii) 2x2 + 214x + 7+
Answer» ANSWER: 2x .3X 5x.accha Step-by-step EXPLANATION: this is a RIGHT answer NOTHING

16.

5x - 24Factorise the following quadratic polynomials bysplitting the middle term :(i) x2 +33x + 6(ü) x2 - 2x - 12(ii) x2 +11,5x + 50(iv) 32x2 +11x +412(v) 23x2 + 73 -513(vi) 5x2+4/5x+3(vii) 2x2 - 472x - 5COLO(viii) 2x2 + 214x + 7+

Answer»

ANSWER:

2x .3X 5x.accha

Step-by-step EXPLANATION:

this is a RIGHT answer NOTHING

Discussion

17.	Elevatute the following 5/2^-2/9
Answer» ANSWER: $\frac{5}{2} - \frac{2}{9} \\ \\ \frac{45 - 2}{18} \\ \\ \frac{43}{18}$ I HOPE it HELPS you

17.

Elevatute the following 5/2^-2/9

Answer»

ANSWER:

$\frac{5}{2} - \frac{2}{9} \\ \\ \frac{45 - 2}{18} \\ \\ \frac{43}{18}$

I HOPE it HELPS you

Discussion

18.	Boy X and Y are in race. X is running at 5 Km/1 Hr. and Y is running at 150 m/s. Find out who is running faster?
Answer» ANSWER: X . . . . . . . . . . . . . . . . . . m . . . . . . . . . . .

18.

Boy X and Y are in race. X is running at 5 Km/1 Hr. and Y is running at 150 m/s. Find out who is running faster?

Answer»

ANSWER:

X

.

m

.

Discussion

19.	The numerator of a fraction is 3 less than its denominator. if 2 is added to both the numerator and the denominator, then the sum of new fraction and orignal fraction is 29/20. find the original fraction.
Answer» Topic :- Linear Equations Given :- The numerator of a fraction is 3 less than its DENOMINATOR. If 2 is added to both the numerator and the denominator, then the sum of new fraction and original fraction is 29/20. To Find :- Original Fraction Solution :- Let denominator of fraction be 'x'. Then numerator will be ' x - 3 ' as it is 3 less than denominator. So, original fraction is $\dfrac{x-3}{x}$ Add 2 to both numerator and denominator, New fraction $\dfrac{x-3+2}{x+2}$ $\dfrac{x-1}{x+2}$ Add both fractions, $\dfrac{x-3}{x}+\dfrac{x-1}{x+2}=\dfrac{29}{20}$ $\dfrac{(x-3)(x+2)+x(x-1)}{x(x+2)}=\dfrac{29}{20}$ $\dfrac{x^2+2x-3x-6+x^2-x}{x(x+2)}=\dfrac{29}{20}$ $\dfrac{2x^2-2x-6}{x^2+2x}=\dfrac{29}{20}$ Now, CROSS multiply, 20( 2x² - 2x - 6 ) = 29( x² + 2x ) 40x² - 40x - 120 = 29x² + 58x 40x² - 29x² - 40x - 58x - 120 = 0 11x² - 98x - 120 = 0 11x² - 110x + 12X - 120 = 0 11x( x - 10 ) + 12( x - 10 ) = 0 ( 11x + 12 )( x - 10 ) = 0 11x + 12 = 0 x = -12/11 or x - 10 = 0 x = 10 So, x = 10 or -12/11 Original Fraction $\dfrac{x-3}{x}$ Put x = 10, $\dfrac{10-3}{10}$ $\dfrac{7}{10}$ Put x = -12/11, $\dfrac{\dfrac{-12}{11}-3}{\dfrac{-12}{11}}$ $\dfrac{\dfrac{-45}{11}}{\dfrac{-12}{11}}$ Answer :- So, original fractions are $\dfrac{7}{10}$ and $\dfrac{\dfrac{-45}{11}}{\dfrac{-12}{11}}$

19.

The numerator of a fraction is 3 less than its denominator. if 2 is added to both the numerator and the denominator, then the sum of new fraction and orignal fraction is 29/20. find the original fraction.

Answer»

Topic :-

Linear Equations

Given :-

The numerator of a fraction is 3 less than its DENOMINATOR. If 2 is added to both the numerator and the denominator, then the sum of new fraction and original fraction is 29/20.

To Find :-

Original Fraction

Solution :-

Let denominator of fraction be 'x'.

Then numerator will be ' x - 3 ' as it is 3 less than denominator.

So, original fraction is

$\dfrac{x-3}{x}$

Add 2 to both numerator and denominator,

New fraction

$\dfrac{x-3+2}{x+2}$

$\dfrac{x-1}{x+2}$

Add both fractions,

$\dfrac{x-3}{x}+\dfrac{x-1}{x+2}=\dfrac{29}{20}$

$\dfrac{(x-3)(x+2)+x(x-1)}{x(x+2)}=\dfrac{29}{20}$

$\dfrac{x^2+2x-3x-6+x^2-x}{x(x+2)}=\dfrac{29}{20}$

$\dfrac{2x^2-2x-6}{x^2+2x}=\dfrac{29}{20}$

Now, CROSS multiply,

20( 2x² - 2x - 6 ) = 29( x² + 2x )

40x² - 40x - 120 = 29x² + 58x

40x² - 29x² - 40x - 58x - 120 = 0

11x² - 98x - 120 = 0

11x² - 110x + 12X - 120 = 0

11x( x - 10 ) + 12( x - 10 ) = 0

( 11x + 12 )( x - 10 ) = 0

11x + 12 = 0

x = -12/11 or

x - 10 = 0

x = 10

So, x = 10 or -12/11

Original Fraction

$\dfrac{x-3}{x}$

Put x = 10,

$\dfrac{10-3}{10}$

$\dfrac{7}{10}$

Put x = -12/11,

$\dfrac{\dfrac{-12}{11}-3}{\dfrac{-12}{11}}$

$\dfrac{\dfrac{-45}{11}}{\dfrac{-12}{11}}$

Answer :-

So, original fractions are

$\dfrac{7}{10}$ and

$\dfrac{\dfrac{-45}{11}}{\dfrac{-12}{11}}$

Discussion

20.	Solve the sums.1. The difference between two numbers is 18. If their sum is 86, Find the numbers?
Answer» Step-by-step explanation: Let two NUMBER be A and B . It is ALSO given that their SUM is 86. Therefore, the numbers are: 52 and 34.

20.

Solve the sums.1. The difference between two numbers is 18. If their sum is 86, Find the numbers?

Answer»

Step-by-step explanation:

Let two NUMBER be A and B . It is ALSO given that their SUM is 86. Therefore, the numbers are: 52 and 34.

Discussion

21.	The perimeter of square piece of cardboard is 80 cm find its area
Answer» ANSWER: PERIMETER is = 80cm LENGTH = 80/4 = 20cm Area = 20*20 = 400

21.

The perimeter of square piece of cardboard is 80 cm find its area

Answer»

ANSWER:

PERIMETER is = 80cm

LENGTH = 80/4 = 20cm

Area = 20*20 = 400

Discussion

22.	Draw graph of P(X) having zeros - 1 and 2
Answer» ANSWER: it's very EASY Step-by-step explanation: PLS buy and GIVE pencil and graph paper

22.

Draw graph of P(X) having zeros - 1 and 2

Answer»

ANSWER:

it's very EASY

Step-by-step explanation:

PLS buy and GIVE pencil and graph paper

Discussion

23.	Paragraph on sarswati puja
Answer» Answer: Goddess Saraswati is regarded as the goddess of learning and MUSIC. It is believed that she is robed in white. She carries a lyre. She is seated on a lotus. She bestows vidya which means learning. Therefore, the Saraswati Puja is-a popular festival of the Students. It is celebrated by the Students in almost all schools and colleges of Orissa, Bihar and West Bengal. It is celebrated on the fifth day in the month of Magha, especially in spring season. Therefore this festival is also called the Basanta Panchami. All educational institutions REMAIN closed on this day. Students worship, the goddess with great joy. Preparation for the celebration begins with the collection, of subscription from the students. The idol of the goddess Saraswati is placed in a hall which is properly cleaned and decorated with coloured papers. The idol is also decorated with such flowers as marigold and ROSE. The image looks sublime and the ATMOSPHERE grand. This is an auspicious day for the students. They abstain from reading and writing on this day only as a mark of respect to the goddess. Notwithstanding this austere OBSERVANCE, students enjoy this festival with great pleasure. A learned Hindu Priest is invited to perform the holy Puja of the goddess. Normally students wear new dress on this day. They pray the goddess for wisdom; they also offer flowers to the deity and sing the prayer-song in her honour. Another remarkable feature of the Puja is the breaking of coconuts in front of the deity. The Prasad is shared by the students, teachers and the guests.

23.

Paragraph on sarswati puja

Answer»

Answer:

Goddess Saraswati is regarded as the goddess of learning and MUSIC. It is believed that she is robed in white. She carries a lyre. She is seated on a lotus. She bestows vidya which means learning.

Therefore, the Saraswati Puja is-a popular festival of the Students. It is celebrated by the Students in almost all schools and colleges of Orissa, Bihar and West Bengal. It is celebrated on the fifth day in the month of Magha, especially in spring season. Therefore this festival is also called the Basanta Panchami. All educational institutions REMAIN closed on this day. Students worship, the goddess with great joy.

Preparation for the celebration begins with the collection, of subscription from the students. The idol of the goddess Saraswati is placed in a hall which is properly cleaned and decorated with coloured papers. The idol is also decorated with such flowers as marigold and ROSE. The image looks sublime and the ATMOSPHERE grand.

This is an auspicious day for the students. They abstain from reading and writing on this day only as a mark of respect to the goddess. Notwithstanding this austere OBSERVANCE, students enjoy this festival with great pleasure. A learned Hindu Priest is invited to perform the holy Puja of the goddess.

Normally students wear new dress on this day. They pray the goddess for wisdom; they also offer flowers to the deity and sing the prayer-song in her honour. Another remarkable feature of the Puja is the breaking of coconuts in front of the deity. The Prasad is shared by the students, teachers and the guests.

Discussion

24.	2. A man has 200 oranges at the cost price of 250oranges. His profit per cent is -(A) 15%(B) 25%(C) 20%(D) 10%
Answer» Answer: 20 % Step-by-step explanation: 250-200=50 50/200×100=20

24.

2. A man has 200 oranges at the cost price of 250oranges. His profit per cent is -(A) 15%(B) 25%(C) 20%(D) 10%

Answer»

Answer:

20 %

Step-by-step explanation:

250-200=50

50/200×100=20

Discussion

25.	the angle of quadrilaterals are in the ratio 3 ratio 5 ratio 9 ratio thirteen ratio. find all the the angles of quadrilaterals
Answer» Question-: The angles of quadrilateral are in ratio 3 : 5 : 9 : 13 .Find all angles of quadrilateral. AnswEr-: $\underline{\boxed{\mathrm {\dag{\red{ The\:measure \:\:of\;all\:angles\:of\:Quadrilateral \:are\:36^{0} ,60^{⁰} , 108^{⁰}\:and\:156^{⁰}}}}}}$ Explanation-: $\sf{<klux>GIVEN</klux> \:That-:}$ The angles of quadrilateral are in ratio 3 : 5 : 9 : 13 . $\sf{To \:Find-:}$ The all angles of Quadrilateral. $\dag{\mathrm{Solution \:For \:Question \:-: }}$ $\sf{Let's \:Assume-:}$ The all angles of quadrilateral be 3X , 5X , 9x and 13 x . Then , $\frak{All\:Angle \: -:} \begin{cases} \sf{Angle\:1\:or\:\angle A= \frak{3x^{0}}} & \\\\ \sf{ Angle\:2\:or\:\angle B\:=\:\frak{5x^{0}}}& \\\\ \sf{ Angle\:3:or\:\angle C\:=\:\frak{9x^{0}}}& \\\\ \sf{ Angle\:4\:or\:\angle D\:=\:\frak{13x^{0}}}\end{cases} \\\\$ As we know that , $\underline{\boxed{\mathrm {\dag{\red{ The\:toatl\:sum\:of\;angles\:of\:Quadrilateral \:is\:360^{0}}}}}}$ Or , $\underline{\boxed{\mathrm {\dag{\red{\angle A + \angle B + \angle C + \angle D \:=\:360^{0}}}}}}$ *Here* , $\frak{Here\: -:} \begin{cases} \sf{Angle\:1\:or\:\angle A= \frak{3x^{0}}} & \\\\ \sf{ Angle\:2\:or\:\angle B\:=\:\frak{5x^{0}}}& \\\\ \sf{ Angle\:3:or\:\angle C\:=\:\frak{9x^{0}}}& \\\\ \sf{ Angle\:4\:or\:\angle D\:=\:\frak{13x^{0}}}\end{cases} \\\\$ Now by putting known or Given Values-: $\longrightarrow {\mathrm {3x + 5x + 9x + 13 x = 360^{⁰}}}$ $\longrightarrow {\mathrm {8x + 9x + 13 x = 360^{⁰}}}$ $\longrightarrow {\mathrm {17x + 13 x = 360^{⁰}}}$ $\longrightarrow {\mathrm {30 x = 360^{⁰}}}$ $\longrightarrow {\mathrm {x = \dfrac{\cancel {360}}{\cancel {30}}}}$ $\longrightarrow {\mathrm { x = 12 }}$ Therefore-: $\longrightarrow{\mathrm{ x = 12 }}$ Now , $\frak{By\:Putting \:x =12-:} \begin{cases} \sf{Angle\:1\:or\:\angle A= \frak{3x=3\times 12=36^{⁰}}} & \\\\ \sf{ Angle\:2\:or\:\angle B\:=\:\frak{5x=5\times 12 = 60^{⁰}}}& \\\\ \sf{ Angle\:3:or\:\angle C\:=\:\frak{9x= 9 \times 12 = 108^{⁰}}}& \\\\ \sf{ Angle\:4\:or\:\angle D\:=\:\frak{13x= 13 \times 12 = 156^{⁰}}}\end{cases} \\\\$ Hence , $\underline{\boxed{\mathrm {\dag{\red{ The\:measure \:\:of\;all\:angles\:of\:Quadrilateral \:are\:36^{0} ,60^{⁰} , 108^{⁰}\:and\:156^{⁰}}}}}}$ ________________________________________ $\huge {\mathrm { ♡Verification-: }}$ $\underline{\boxed{\mathrm {\dag{\red{ The\:toatl\:sum\:of\;angles\:of\:Quadrilateral \:is\:360^{0}}}}}}$ Or , $\underline{\boxed{\mathrm {\dag{\red{\angle A + \angle B + \angle C + \angle D \:=\:360^{0}}}}}}$ $\frak{Here-:} \begin{cases} \sf{Angle\:1\:or\:\angle A= \frak{36^{⁰}}} & \\\\ \sf{ Angle\:2\:or\:\angle B\:=\:\frak{ 60^{⁰}}}& \\\\ \sf{ Angle\:3:or\:\angle C\:=\:\frak{ 108^{⁰}}}& \\\\ \sf{ Angle\:4\:or\:\angle D\:=\:\frak{156^{⁰}}}\end{cases} \\\\$ Now , By Putting known and Given Values-: $\longrightarrow {\mathrm {36 + 60 + 108 + 156 = 360^{⁰}}}$ $\longrightarrow {\mathrm {96+ 264 = 360^{⁰}}}$ $\longrightarrow {\mathrm {360^{⁰} = 360^{⁰}}}$ Therefore , $\longrightarrow {\mathrm {LHS = RHS}}$ $\longrightarrow {\mathrm {Hence\:Verified!}}$ ___________________________♡___________________________

25.

the angle of quadrilaterals are in the ratio 3 ratio 5 ratio 9 ratio thirteen ratio. find all the the angles of quadrilaterals

Answer»

Question-:

The angles of quadrilateral are in ratio 3 : 5 : 9 : 13 .Find all angles of quadrilateral.

AnswEr-:

$\underline{\boxed{\mathrm {\dag{\red{ The\:measure \:\:of\;all\:angles\:of\:Quadrilateral \:are\:36^{0} ,60^{⁰} , 108^{⁰}\:and\:156^{⁰}}}}}}$

Explanation-:

$\sf{<klux>GIVEN</klux> \:That-:}$

The angles of quadrilateral are in ratio 3 : 5 : 9 : 13 .

$\sf{To \:Find-:}$

The all angles of Quadrilateral.

$\dag{\mathrm{Solution \:For \:Question \:-: }}$

$\sf{Let's \:Assume-:}$

The all angles of quadrilateral be 3X , 5X , 9x and 13 x .

Then ,

$\frak{All\:Angle \: -:} \begin{cases} \sf{Angle\:1\:or\:\angle A= \frak{3x^{0}}} & \\\\ \sf{ Angle\:2\:or\:\angle B\:=\:\frak{5x^{0}}}& \\\\ \sf{ Angle\:3:or\:\angle C\:=\:\frak{9x^{0}}}& \\\\ \sf{ Angle\:4\:or\:\angle D\:=\:\frak{13x^{0}}}\end{cases} \\\\$

As we know that ,

$\underline{\boxed{\mathrm {\dag{\red{ The\:toatl\:sum\:of\;angles\:of\:Quadrilateral \:is\:360^{0}}}}}}$

Or ,

$\underline{\boxed{\mathrm {\dag{\red{\angle A + \angle B + \angle C + \angle D \:=\:360^{0}}}}}}$

Here ,

$\frak{Here\: -:} \begin{cases} \sf{Angle\:1\:or\:\angle A= \frak{3x^{0}}} & \\\\ \sf{ Angle\:2\:or\:\angle B\:=\:\frak{5x^{0}}}& \\\\ \sf{ Angle\:3:or\:\angle C\:=\:\frak{9x^{0}}}& \\\\ \sf{ Angle\:4\:or\:\angle D\:=\:\frak{13x^{0}}}\end{cases} \\\\$

Now by putting known or Given Values-:

$\longrightarrow {\mathrm {3x + 5x + 9x + 13 x = 360^{⁰}}}$

$\longrightarrow {\mathrm {8x + 9x + 13 x = 360^{⁰}}}$

$\longrightarrow {\mathrm {17x + 13 x = 360^{⁰}}}$

$\longrightarrow {\mathrm {30 x = 360^{⁰}}}$

$\longrightarrow {\mathrm {x = \dfrac{\cancel {360}}{\cancel {30}}}}$

$\longrightarrow {\mathrm { x = 12 }}$

Therefore-:

$\longrightarrow{\mathrm{ x = 12 }}$

Now ,

$\frak{By\:Putting \:x =12-:} \begin{cases} \sf{Angle\:1\:or\:\angle A= \frak{3x=3\times 12=36^{⁰}}} & \\\\ \sf{ Angle\:2\:or\:\angle B\:=\:\frak{5x=5\times 12 = 60^{⁰}}}& \\\\ \sf{ Angle\:3:or\:\angle C\:=\:\frak{9x= 9 \times 12 = 108^{⁰}}}& \\\\ \sf{ Angle\:4\:or\:\angle D\:=\:\frak{13x= 13 \times 12 = 156^{⁰}}}\end{cases} \\\\$

Hence ,

$\underline{\boxed{\mathrm {\dag{\red{ The\:measure \:\:of\;all\:angles\:of\:Quadrilateral \:are\:36^{0} ,60^{⁰} , 108^{⁰}\:and\:156^{⁰}}}}}}$

________________________________________

$\huge {\mathrm { ♡Verification-: }}$

$\underline{\boxed{\mathrm {\dag{\red{ The\:toatl\:sum\:of\;angles\:of\:Quadrilateral \:is\:360^{0}}}}}}$
Or ,
$\underline{\boxed{\mathrm {\dag{\red{\angle A + \angle B + \angle C + \angle D \:=\:360^{0}}}}}}$

$\frak{Here-:} \begin{cases} \sf{Angle\:1\:or\:\angle A= \frak{36^{⁰}}} & \\\\ \sf{ Angle\:2\:or\:\angle B\:=\:\frak{ 60^{⁰}}}& \\\\ \sf{ Angle\:3:or\:\angle C\:=\:\frak{ 108^{⁰}}}& \\\\ \sf{ Angle\:4\:or\:\angle D\:=\:\frak{156^{⁰}}}\end{cases} \\\\$

Now , By Putting known and Given Values-:

$\longrightarrow {\mathrm {36 + 60 + 108 + 156 = 360^{⁰}}}$

$\longrightarrow {\mathrm {96+ 264 = 360^{⁰}}}$

$\longrightarrow {\mathrm {360^{⁰} = 360^{⁰}}}$

Therefore ,

$\longrightarrow {\mathrm {LHS = RHS}}$

$\longrightarrow {\mathrm {Hence\:Verified!}}$

___________________________♡___________________________

Discussion

26.	2578908-257472356÷19882756÷4217766503÷423347364÷283
Answer» Answer: 2578651 2385.636364 196.5700713 18360.59102 1227.434629

26.

2578908-257472356÷19882756÷4217766503÷423347364÷283

Answer»

Answer:

2578651

2385.636364

196.5700713

18360.59102

1227.434629

Discussion

27.	The_______of a set of observations is the observation that occus most often .
Answer» Answer: the mode of a SET of OBSERVATIONS is the OBSERVATION that OCCURS most often

27.

The_______of a set of observations is the observation that occus most often .

Answer»

Answer:

the mode of a SET of OBSERVATIONS is the OBSERVATION that OCCURS most often

Discussion

28.	4 upon 3 - one upon two
Answer» ANSWER: $\frac{4}{3} - \frac{1}{2} \\ \frac{4 \times 2}{3 \times 2} - \frac{1 \times 3}{2 \times 3} \\ \frac{8}{6} - \frac{3}{6} \\ = > \frac{5}{6}$

28.

4 upon 3 - one upon two

Answer»

ANSWER:

$\frac{4}{3} - \frac{1}{2} \\ \frac{4 \times 2}{3 \times 2} - \frac{1 \times 3}{2 \times 3} \\ \frac{8}{6} - \frac{3}{6} \\ = > \frac{5}{6}$

Discussion

29.	Find the value of deterimants
Answer» ANSWER: $3 \sqrt{6} \times 2 - - 4 \sqrt{2 } \times 5 \sqrt{ 3}$ $6 \sqrt{6 } - - 20 \sqrt{6}$ $6 \sqrt{6 } + 20 \sqrt{6}$ $26 \sqrt{6}$

29.

Find the value of deterimants

Answer»

ANSWER:

$3 \sqrt{6} \times 2 - - 4 \sqrt{2 } \times 5 \sqrt{ 3}$

$6 \sqrt{6 } - - 20 \sqrt{6}$

$6 \sqrt{6 } + 20 \sqrt{6}$

$26 \sqrt{6}$

Discussion

30.	Ques. 64 (SMCQ)Marks: +1Three of the following four are alike in a certain way and so form a group. Which one does not belong to thatgroup?A9,49B13,121C10,61D7,25
Answer» ANSWER: answer c Step-by-step EXPLANATION: nsjskdniajxhcoekwowjjsnsbsbwijdbdud

30.

Ques. 64 (SMCQ)Marks: +1Three of the following four are alike in a certain way and so form a group. Which one does not belong to thatgroup?A9,49B13,121C10,61D7,25

Answer»

ANSWER:

answer c

Step-by-step EXPLANATION:

nsjskdniajxhcoekwowjjsnsbsbwijdbdud

Discussion

31.	1 ते n नैसर्गिक सम संख्यांची बेरीज 462 आहे, तर n ची किंमत काढा.
Answer» Step-by-step EXPLANATION: Given If the sum of n natural even numbers is 462, then find the value of n. Let SN be the sum of numbers. So the first even natural numbers are 2,4,6,8,10…………n here a = 2, d = 2 So we have Sn = n/2 (2a + (n – 1)d) 462 = n/2 ( 2(2) + (n – 1) 2) 462 = n/2 (4 + 2N – 2) 462 = n/2 (2 + 2n) 2n^2 + 2n – 924 = 0 n^2 + n – 462 = 0 n^2 + 22n – 21n – 462 = 0 n(n + 22) – 21 (n + 22) = 0 (n + 22) (n – 21) = 0 n = - 22, 21 So the value of n is 21 Reference link will be brainly.in/question/8464091#

31.

1 ते n नैसर्गिक सम संख्यांची बेरीज 462 आहे, तर n ची किंमत काढा.

Answer»

Step-by-step EXPLANATION:

Given If the sum of n natural even numbers is 462, then find the value of n.

Let SN be the sum of numbers.
So the first even natural numbers are 2,4,6,8,10…………n
here a = 2, d = 2
So we have Sn = n/2 (2a + (n – 1)d)
462 = n/2 ( 2(2) + (n – 1) 2)
462 = n/2 (4 + 2N – 2)
462 = n/2 (2 + 2n)
2n^2 + 2n – 924 = 0
n^2 + n – 462 = 0
n^2 + 22n – 21n – 462 = 0
n(n + 22) – 21 (n + 22) = 0
(n + 22) (n – 21) = 0
n = - 22, 21
So the value of n is 21

Reference link will be

brainly.in/question/8464091#

Discussion

32.	Answer this question fast please
Answer» Answer: Question 1 ka answer = a. 100 Step-by-step explanation: 55+300-60+45= ( ? ) + 240 = 355-60 + 45= ( ? ) + 240 = 295 + 45 = ( ? ) + 240 = 340 = ( ? ) + 240 = 340 - 240 = ( ? ) = 100 = ( ? ) = ( ? ) = 100

32.

Answer this question fast please

Answer»

Answer:

Question 1 ka answer = a. 100

Step-by-step explanation:

55+300-60+45= ( ? ) + 240

= 355-60 + 45= ( ? ) + 240

= 295 + 45 = ( ? ) + 240

= 340 = ( ? ) + 240

= 340 - 240 = ( ? )

= 100 = ( ? )

= ( ? ) = 100

Discussion

33.	Amount=₹1000, [email protected]%= , [email protected]%= , Total =₹1120
Answer» Answer: SORRY I can't HELP you please write FULL questions

33.

Amount=₹1000, [email protected]%= , [email protected]%= , Total =₹1120

Answer»

Answer:

SORRY I can't HELP you please write FULL questions

Discussion

34.	Find zeros graphically for P (X ) = x³- x ²
Answer» ANSWER: don't know Step-by-step EXPLANATION: PLEASE TELL me

34.

Find zeros graphically for P (X ) = x³- x ²

Answer»

ANSWER:

don't know

Step-by-step EXPLANATION:

PLEASE TELL me

Discussion

35.	रिकामी जागा भरा.3, 9, 6, 15, 45, 30, 75,?
Answer» Answer: 120 Step-by-step EXPLANATION: PLEASE let us army and I am SURE we can make a DECISION about it for a few weeks now but we can get you some of that stuff for class science

35.

रिकामी जागा भरा.3, 9, 6, 15, 45, 30, 75,?

Answer»

Answer:

120

Step-by-step EXPLANATION:

PLEASE let us army and I am SURE we can make a DECISION about it for a few weeks now but we can get you some of that stuff for class science

Discussion

36.	the product of a rational number and an irrational number Is always an irrational number true or false
Answer» Answer: TUMHA NU hi chaha jab tak han bahut PHARR kar ta HA tumko sanan

36.

the product of a rational number and an irrational number Is always an irrational number true or false

Answer»

Answer:

TUMHA NU hi chaha jab tak han bahut PHARR kar ta HA tumko sanan

Discussion

37.	R =
Answer» Step-by-step EXPLANATION: $\sqrt{ { ({(1 + 1 + (2 \times 1 \times 1 \times 0))}^{2} )}^{2} } \\ = \sqrt{ { ({(1 + 1 + (0))}^{2} )}^{2} } \\ = \sqrt{ { {((2)}^{2} )}^{2} } \\ = \sqrt{ {4}^{2} } \\ = \sqrt{16} \\ \large{ \boxed{= \underline{ \underline{ 4}}}}$

37.

R =

Answer»

Step-by-step EXPLANATION:

$\sqrt{ { ({(1 + 1 + (2 \times 1 \times 1 \times 0))}^{2} )}^{2} } \\ = \sqrt{ { ({(1 + 1 + (0))}^{2} )}^{2} } \\ = \sqrt{ { {((2)}^{2} )}^{2} } \\ = \sqrt{ {4}^{2} } \\ = \sqrt{16} \\ \large{ \boxed{= \underline{ \underline{ 4}}}}$

Discussion

38.	Please help it's urgentSrudy the following information to answer the given questions:A world and number arrangement machine when given an input line of numbers rearranges themfollowing a particular rule. The following is an illustration of input and re-arrangement.Input: 57 18 25 88 96 34 19 48 77 66 29 54Step 1: 20 57 25 88 34 19 48 77 66 29 54 94Step II: 21 20 57 25 34 48 77 66 29 54 94 86Step III: 27 21 20 57 34 48 66 29 54 94 86 75Step IV: 31 27 21 20 57 34 48 54 94 86 75 64Step V: 36 31 27 21 20 48 54 94 86 75 64 55Step VI: 50 36 31 27 21 20 94 86 75 64 55 52And step VI is the last step of the rearrangement of the above input. As per the rules followed in the abovesteps, find out in each of the following questions the appropriate steps for the given input.Input: 34 89 27 58 92 15 46 69 96 80What will be the resultant if the second number from the left end in step-2 is subtracted from fifth numberfrom the right end in step-3?
Answer» Answer: cejteteb tv rntev 5 ntbygenyengeebgen₹v TJ MT gn BYE ntnyenye etnegnegktrne eb efy TE fs wrnn

38.

Please help it's urgentSrudy the following information to answer the given questions:A world and number arrangement machine when given an input line of numbers rearranges themfollowing a particular rule. The following is an illustration of input and re-arrangement.Input: 57 18 25 88 96 34 19 48 77 66 29 54Step 1: 20 57 25 88 34 19 48 77 66 29 54 94Step II: 21 20 57 25 34 48 77 66 29 54 94 86Step III: 27 21 20 57 34 48 66 29 54 94 86 75Step IV: 31 27 21 20 57 34 48 54 94 86 75 64Step V: 36 31 27 21 20 48 54 94 86 75 64 55Step VI: 50 36 31 27 21 20 94 86 75 64 55 52And step VI is the last step of the rearrangement of the above input. As per the rules followed in the abovesteps, find out in each of the following questions the appropriate steps for the given input.Input: 34 89 27 58 92 15 46 69 96 80What will be the resultant if the second number from the left end in step-2 is subtracted from fifth numberfrom the right end in step-3?

Answer»

Answer:

cejteteb tv rntev 5 ntbygenyengeebgen₹v TJ MT gn BYE ntnyenye etnegnegktrne eb efy TE fs wrnn

Discussion

39.	Pls ans the question I can't understand
Answer» Answer: padha hua to LAG raha h to PAR yaad NHI AA raha

39.

Pls ans the question I can't understand

Answer»

Answer:

padha hua to LAG raha h to PAR yaad NHI AA raha

Discussion

40.	Please answer these questionsFirst one to answer will be marked brainliest.If it is wrong it will be reported
Answer» ANSWER: Step-by-step explanation: 55+300-60+45=[ ]+240 355-15=[ ]+240 340=[ ]+240 340=100+240 340=340 340 55+300-60+45=[100]+240 is the answer.

40.

Please answer these questionsFirst one to answer will be marked brainliest.If it is wrong it will be reported

Answer»

ANSWER:

Step-by-step explanation:

55+300-60+45=[ ]+240

355-15=[ ]+240

340=[ ]+240

340=100+240

340=340

340

55+300-60+45=[100]+240 is the answer.

Discussion

41.	How to find x in this question 5x - x² = -300
Answer» ANSWER: Hiii Step-by-step EXPLANATION: HOPE THIS ANSWER HELPED U...

41.

How to find x in this question 5x - x² = -300

Answer»

ANSWER:

Hiii

Step-by-step EXPLANATION:

HOPE THIS ANSWER HELPED U...

Discussion

42.	1. Three angles of a quadrilateral are respectively 40°,50° and 110°. Find the fourth angle.
Answer» ANSWER: so Step-by-step EXPLANATION: 40+50+110= 200 180-200 20 DEGREE

42.

1. Three angles of a quadrilateral are respectively 40°,50° and 110°. Find the fourth angle.

Answer»

ANSWER:

so

Step-by-step EXPLANATION:

40+50+110= 200

180-200

20 DEGREE

Discussion

43.	Write an algebraic expression for 6 times a number increased by 8.
Answer» 6x MEANS 6 TIMES any no. So 6x and INCREASED means + so +8 FINAL EQUATION 6x + 8

Discussion

44.	6x²-x+3LX-2) (x2+1) resolve into partial fraction
Answer» ANSWER: g2344 jffu8865gff6789tfgui

44.

6x²-x+3LX-2) (x2+1) resolve into partial fraction

Answer»

ANSWER:

g2344 jffu8865gff6789tfgui

Discussion

45.	Each entry of a data is called a/an _______. ( fill in the blanks ) maths
Answer» ANSWER: A MATHS is the answer Step-by-step EXPLANATION: HOPE it HELPS you

45.

Each entry of a data is called a/an _______. ( fill in the blanks ) maths

Answer»

ANSWER:

A MATHS is the answer

Step-by-step EXPLANATION:

HOPE it HELPS you

Discussion

46.	The equation x+y=2 and 4x+4y=8=0 have_solution(10th grade SSC board)
Answer» ANSWER: $x + y = 2$ $<klux>EQUATION</klux> \: 1 = \: equation \: 2$ $suppose \: x = 1$ $y = 1$ this equation have MANY SOLUTION

46.

The equation x+y=2 and 4x+4y=8=0 have_solution(10th grade SSC board)

Answer»

ANSWER:

$x + y = 2$

$<klux>EQUATION</klux> \: 1 = \: equation \: 2$

$suppose \: x = 1$

$y = 1$

this equation have MANY SOLUTION

Discussion

47.	Simplify a.
Answer» $\small\sf{\:\tiny{2 \:+} \frac{3}{4} }$ $\small\sf{\:→\:\tiny{2 \:+} \frac{3}{4} }$ $\small\sf{\:→\:\frac{8\:+\:3}{4}}$ $\small\sf{\:→\:\frac{11}{4}}$ $\small\sf{\:→\:\tiny{3}\frac{2}{4}}$ ${ }$ ɪᴛᴢᴛʀᴀɢɪᴄɢɪʀʟ❣️

47.

Simplify a.

Answer»

$\small\sf{\:\tiny{2 \:+} \frac{3}{4} }$

$\small\sf{\:→\:\tiny{2 \:+} \frac{3}{4} }$

$\small\sf{\:→\:\frac{8\:+\:3}{4}}$

$\small\sf{\:→\:\frac{11}{4}}$

$\small\sf{\:→\:\tiny{3}\frac{2}{4}}$

${ }$

ɪᴛᴢᴛʀᴀɢɪᴄɢɪʀʟ❣️

Discussion

48.	Can anyone solve this plz
Answer» To Find: $\Longrightarrow \sf \dfrac{sinA}{1 + cosA} + \dfrac{1 + cosA}{sinA}$ Taking LCM we get: $\Longrightarrow \sf \dfrac{(sinA)(sinA) + (1 + cosA)(1 + cosA)}{(1 + cosA)(sinA)}$ Using (a + B)(a + b) = (a + b)² we get: $\Longrightarrow \sf \dfrac{sin^2A + (1 + cosA)^2}{(1 + cosA)(sinA)}$ Using (a + b)² = a² + b² + 2ab we get: $\Longrightarrow \sf \dfrac{sin^2A + (1)^{2} + (cosA)^2 + 2(1)(cosA)}{(1 + cosA)(sinA)}$ $\Longrightarrow \sf \dfrac{sin^2A + 1 + cos^2A + 2cosA}{(1 + cosA)(sinA)}$ $\Longrightarrow \sf \dfrac{sin^2A + cos^2A + 1 + 2cosA}{(1 + cosA)(sinA)}$ Using the identity sin²A + cos²A = 1 we get: $\Longrightarrow \sf \dfrac{1 + 1 + 2cosA}{(1 + cosA)(sinA)}$ $\Longrightarrow \sf \dfrac{2 + 2cosA}{(1 + cosA)(sinA)}$ TAKE 2 out since it's common to both 2 and 2cosA. $\Longrightarrow \sf \dfrac{2(1 + cosA)}{(1 + cosA)(sinA)}$ Cancelling (1 + cosA) in the numerator & DENOMINATOR we get: $\Longrightarrow \sf \dfrac{2}{sinA}$ $\Longrightarrow \sf 2 \times \dfrac{1}{sinA}$ Using 1/sinA = cosecA $\Longrightarrow \sf 2cosecA$ Hence solved.

48.

Can anyone solve this plz

Answer»

To Find:

$\Longrightarrow \sf \dfrac{sinA}{1 + cosA} + \dfrac{1 + cosA}{sinA}$

Taking LCM we get:

$\Longrightarrow \sf \dfrac{(sinA)(sinA) + (1 + cosA)(1 + cosA)}{(1 + cosA)(sinA)}$

Using (a + B)(a + b) = (a + b)² we get:

$\Longrightarrow \sf \dfrac{sin^2A + (1 + cosA)^2}{(1 + cosA)(sinA)}$

Using (a + b)² = a² + b² + 2ab we get:

$\Longrightarrow \sf \dfrac{sin^2A + (1)^{2} + (cosA)^2 + 2(1)(cosA)}{(1 + cosA)(sinA)}$

$\Longrightarrow \sf \dfrac{sin^2A + 1 + cos^2A + 2cosA}{(1 + cosA)(sinA)}$

$\Longrightarrow \sf \dfrac{sin^2A + cos^2A + 1 + 2cosA}{(1 + cosA)(sinA)}$

Using the identity sin²A + cos²A = 1 we get:

$\Longrightarrow \sf \dfrac{1 + 1 + 2cosA}{(1 + cosA)(sinA)}$

$\Longrightarrow \sf \dfrac{2 + 2cosA}{(1 + cosA)(sinA)}$

TAKE 2 out since it's common to both 2 and 2cosA.

$\Longrightarrow \sf \dfrac{2(1 + cosA)}{(1 + cosA)(sinA)}$

Cancelling (1 + cosA) in the numerator & DENOMINATOR we get:

$\Longrightarrow \sf \dfrac{2}{sinA}$

$\Longrightarrow \sf 2 \times \dfrac{1}{sinA}$

Using 1/sinA = cosecA

$\Longrightarrow \sf 2cosecA$

Hence solved.

Discussion

49.	SIMPLIFY THE FOLLOWING EXPRESSION 80÷(15+8-3)+5
Answer» Step-by-step explanation: 80÷(15+8-3)+5 the ANS is: 9

49.

SIMPLIFY THE FOLLOWING EXPRESSION 80÷(15+8-3)+5

Answer»

Step-by-step explanation:

80÷(15+8-3)+5

the ANS is:

9

Discussion

50.	Limx.log (1+3x)(ex - 1)²
Answer» I don't THINK that is the case with a woman in a RELATIONSHIP that the woman is not a person who has been a polynomials for 6AM or the same thing that I have had to SAY

Discussion

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2578908-257472356÷19882756÷4217766503÷423347364÷283 ​

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ɪᴛᴢᴛʀᴀɢɪᴄɢɪʀʟ❣️

Can anyone solve this plz​

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Limx.log (1+3x)(ex - 1)²​

Please show solving steps!!The cost of a sapling of Mango, Jamun and Peepal is Rs 25, Rs 15 and Rs 10 each. The labour cost for planting each sapling is Rs 0.70. The total amount that Ayushi has to get sanctioned for plantation is -a) Rs. 55382b) Rs. 58352c) Rs. 50382d) Rs. 59362

Principal = ₹450,rate=12% per annum and time =3 year

Show thatΔRHS Ο ΔΡΟ

Amount=₹1000, [email protected]%= x , [email protected]%= x , Total =₹1120

А8. In right triangle ABC, right angled at C, M isthe mid-point of hypotenuse AB.C is joinedto M and produced to a point D such thatDM =~ CM. Point D is joined to point B(see Fig. 7.23). Show that:(i) A AMC=A BMD2) A DBC is a right angle3)A DBC=~A ACB4)CM=1\2AB

5x - 24Factorise the following quadratic polynomials bysplitting the middle term :(i) x2 +33x + 6(ü) x2 - 2x - 12(ii) x2 +11,5x + 50(iv) 32x2 +11x +412(v) 23x2 + 73 -513(vi) 5x2+4/5x+3(vii) 2x2 - 472x - 5COLO(viii) 2x2 + 214x + 7+

Elevatute the following 5/2^-2/9

Boy X and Y are in race. X is running at 5 Km/1 Hr. and Y is running at 150 m/s. Find out who is running faster?

The numerator of a fraction is 3 less than its denominator. if 2 is added to both the numerator and the denominator, then the sum of new fraction and orignal fraction is 29/20. find the original fraction.

Solve the sums.1. The difference between two numbers is 18. If their sum is 86, Find the numbers?

The perimeter of square piece of cardboard is 80 cm find its area

Draw graph of P(X) having zeros - 1 and 2

Paragraph on sarswati puja

2. A man has 200 oranges at the cost price of 250oranges. His profit per cent is -(A) 15%(B) 25%(C) 20%(D) 10%

the angle of quadrilaterals are in the ratio 3 ratio 5 ratio 9 ratio thirteen ratio. find all the the angles of quadrilaterals

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The_______of a set of observations is the observation that occus most often .

4 upon 3 - one upon two

Find the value of deterimants

Ques. 64 (SMCQ)Marks: +1Three of the following four are alike in a certain way and so form a group. Which one does not belong to thatgroup?A9,49B13,121C10,61D7,25

1 ते n नैसर्गिक सम संख्यांची बेरीज 462 आहे, तर n ची किंमत काढा.

Amount=₹1000, [email protected]%= , [email protected]%= , Total =₹1120

Find zeros graphically for P (X ) = x³- x ²

रिकामी जागा भरा.3, 9, 6, 15, 45, 30, 75,?

R =

Pls ans the question I can't understand

How to find x in this question 5x - x² = -300

1. Three angles of a quadrilateral are respectively 40°,50° and 110°. Find the fourth angle.

Write an algebraic expression for 6 times a number increased by 8.

6x²-x+3LX-2) (x2+1) resolve into partial fraction

Each entry of a data is called a/an _______. ( fill in the blanks ) maths

The equation x+y=2 and 4x+4y=8=0 have_solution(10th grade SSC board)

Simplify a.

Can anyone solve this plz

Limx.log (1+3x)(ex - 1)²