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What is the sum (Two-fifths x + StartFraction 5 over 8 EndFraction) + (one-fifth x minus one-fourth)? |
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Answer» Given : (Two-fifths x + 5 over 8 ) + (one-fifth x MINUS one-fourth) (2x/5 + 5/8) + (x/5 - 1/4) To Find : Sum Solution: (2x/5 + 5/8) + (x/5 - 1/4) = 2x/5 + 5/8 + x5 - 1/4 = 2x/5 + x/5 + 5/8 - 1/4 = (2x + x)/5 + (5 - 2)/8 = 3x/5 + 3/8 = (24x + 15)/40 (2x/5 + 5/8) + (x/5 - 1/4) = 3x/5 + 3/8 or (24x + 15)/40 Learn More: the denominator of a rational NUMBER is GREATER than its numerator ... If the numerator and denominator of a proper FRACTION are increased ... |
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