332354 + Interview Questions in Secondary School in Math

1.	Write the answer in the place holder.how much is 3 times 18
Answer» Answer: 54 Step-by-step EXPLANATION:

1.

Write the answer in the place holder.how much is 3 times 18

Answer»

Answer:

54

Step-by-step EXPLANATION:

Discussion

2.	Please give me answers of these questions
Answer» ANSWER: a.8,39,023 b.20,00,905 c.35,857 d.4,37,19,000

2.

Please give me answers of these questions

Answer»

ANSWER:

a.8,39,023

b.20,00,905

c.35,857

d.4,37,19,000

Discussion

3.	How we represent 1/2 on number line
Answer» ANSWER: it will be between the HALFWAY POINT between 1 and 2 Step-by-step EXPLANATION:

3.

How we represent 1/2 on number line

Answer»

ANSWER:

it will be between the HALFWAY POINT between 1 and 2

Step-by-step EXPLANATION:

Discussion

4.	Evaluate the following [(1/2)^-3(1/3)^-3]÷(1/4)^-3
Answer» Step-by-step explanation: GIVEN (1/2)^-3(1/3)^-3]÷(1/4)^-3 (1/2)^-3=2^3 (1/3)^-3=3^3 (1/4)^-3=4^3=2^6 =>(2^3 3^3)/2^6 =>3^3/2^3 (2^3/2^6= 2^-3 or 1/(2^3)) => (3/2)^3 or 27/8 i HOPE you UNDERSTOOD :)*

4.

Evaluate the following [(1/2)^-3(1/3)^-3]÷(1/4)^-3

Answer»

Step-by-step explanation:

GIVEN (1/2)^-3(1/3)^-3]÷(1/4)^-3

(1/2)^-3=2^3

(1/3)^-3=3^3

(1/4)^-3=4^3=2^6

=>(2^3 *3^3)/2^6

=>3^3/2^3 (2^3/2^6= 2^-3 or 1/(2^3))

=> (3/2)^3 or 27/8

i HOPE you UNDERSTOOD :)

Discussion

5.	X+X+X = 45 Y+Y+Y = 21 Z+Z+Z = 12 then X+Y+Z = ?
Answer» HEY MATE here is UR ANSWER 3x=45 x=15 3y=21 y=7 3z=12 z=4 x+y+z=15+7+4=15+11=26. hope it HELPS. ☆☆☆

5.

X+X+X = 45 Y+Y+Y = 21 Z+Z+Z = 12 then X+Y+Z = ?

Answer»

HEY MATE here is UR ANSWER

3x=45

x=15

3y=21

y=7

3z=12

z=4

x+y+z=15+7+4=15+11=26.

hope it HELPS.

☆☆☆

Discussion

6.	If n is a natural then 92n -42n is always divisible by
Answer» ANSWER: I THINK 50N is the answer.............

6.

If n is a natural then 92n -42n is always divisible by

Answer»

ANSWER:

I THINK

50N is the answer.............

Discussion

7.	4 9 16 25 = 152 36 49 64 81 =2488 1 64 81 36 = ?
Answer» Step-by-step explanation: In modern physics, antimatter is defined as matter which is composed of the antiparticles (or "partners") of the corresponding particles of 'ordinary' matter (koinomatter). Minuscule numbers of antiparticles are generated daily at particle accelerators – total production has been only a few nanograms[1] – and in natural processes like cosmic ray collisions and some types of radioactive decay, but only a tiny fraction of these have successfully been bound together in experiments to form anti-atoms. No macroscopic amount of antimatter has ever been assembled due to the extreme cost and difficulty of production and handling. In theory, a particle and its anti-particle (for example, proton and antiproton) have the same mass, but opposite electric charge and other differences in quantum numbers. For example, a proton has positive charge while an antiproton has negative charge. A collision between any particle and its anti-particle partner leads to their mutual annihilation, giving rise to various proportions of intense photons (gamma rays), NEUTRINOS, and sometimes less-massive particle-antiparticle pairs. The majority of the total energy of annihilation emerges in the form of ionizing radiation. If surrounding matter is present, the energy content of this radiation will be absorbed and CONVERTED into other forms of energy such as heat or LIGHT. The amount of the released energy is usually proportional to the total mass of the collided matter and antimatter, in ACCORDANCE with the mass–energy equivalence equation, E=mc2.[2] Antimatter particles BIND with each other to form antimatter, just as ordinary particles bind to form normal matter. For example, a positron (the antiparticle of the electron) and an antiproton (the antiparticle of the proton) can form an antihydrogen atom. The nuclei of antihelium have been artificially produced with difficulty, and these are the most complex anti-nuclei so far observed.[3] Physical principles indicate that complex antimatter atomic nuclei are possible, as well as anti-atoms corresponding to the known chemical elements. There is strong evidence that the observable universe is composed almost entirely of ordinary matter, as opposed to an equal mixture of matter and antimatter.[4] This asymmetry of matter and antimatter in the visible universe is one of the great unsolved problems in physics.[5] The process by which this inequality between matter and antimatter particles developed is called baryogenesis.

7.

4 9 16 25 = 152 36 49 64 81 =2488 1 64 81 36 = ?

Answer»

Step-by-step explanation:

In modern physics, antimatter is defined as matter which is composed of the antiparticles (or "partners") of the corresponding particles of 'ordinary' matter (koinomatter). Minuscule numbers of antiparticles are generated daily at particle accelerators – total production has been only a few nanograms[1] – and in natural processes like cosmic ray collisions and some types of radioactive decay, but only a tiny fraction of these have successfully been bound together in experiments to form anti-atoms. No macroscopic amount of antimatter has ever been assembled due to the extreme cost and difficulty of production and handling.

In theory, a particle and its anti-particle (for example, proton and antiproton) have the same mass, but opposite electric charge and other differences in quantum numbers. For example, a proton has positive charge while an antiproton has negative charge.

A collision between any particle and its anti-particle partner leads to their mutual annihilation, giving rise to various proportions of intense photons (gamma rays), NEUTRINOS, and sometimes less-massive particle-antiparticle pairs. The majority of the total energy of annihilation emerges in the form of ionizing radiation. If surrounding matter is present, the energy content of this radiation will be absorbed and CONVERTED into other forms of energy such as heat or LIGHT. The amount of the released energy is usually proportional to the total mass of the collided matter and antimatter, in ACCORDANCE with the mass–energy equivalence equation, E=mc2.[2]

Antimatter particles BIND with each other to form antimatter, just as ordinary particles bind to form normal matter. For example, a positron (the antiparticle of the electron) and an antiproton (the antiparticle of the proton) can form an antihydrogen atom. The nuclei of antihelium have been artificially produced with difficulty, and these are the most complex anti-nuclei so far observed.[3] Physical principles indicate that complex antimatter atomic nuclei are possible, as well as anti-atoms corresponding to the known chemical elements.

There is strong evidence that the observable universe is composed almost entirely of ordinary matter, as opposed to an equal mixture of matter and antimatter.[4] This asymmetry of matter and antimatter in the visible universe is one of the great unsolved problems in physics.[5] The process by which this inequality between matter and antimatter particles developed is called baryogenesis.

Discussion

8.	Amit is 5 years older thanVaibhav at present. After4 years the ratio their ages will bes 5:4 . What is Amits present age
Answer» Answer: Step-by-step explanation: Let Amit's age be X Let Vaibhav's age be Y According to Questions, X=Y+5-(1) After FOUR years, 4+X/4+Y=5/4 Using (1) Y+5+4/Y+4=5/4 Y+9/Y+4=5/4 Cross Multiplication, 5(Y+4)=4(Y+9) 5Y + 20= 4Y + 36 Y=16 Amit's age= Y+5 =21 Vaibhav's age = 16 Mark as BRAINLIEST if you found it USEFUL

8.

Amit is 5 years older thanVaibhav at present. After4 years the ratio their ages will bes 5:4 . What is Amits present age

Answer»

Answer:

Step-by-step explanation:

Let Amit's age be X

Let Vaibhav's age be Y

According to Questions,

X=Y+5-(1)

After FOUR years,

4+X/4+Y=5/4

Using (1)

Y+5+4/Y+4=5/4

Y+9/Y+4=5/4

Cross Multiplication,

5(Y+4)=4(Y+9)

5Y + 20= 4Y + 36

Y=16

Amit's age= Y+5

=21

Vaibhav's age = 16

Mark as BRAINLIEST if you found it USEFUL

Discussion

9.	If a+b=7 and a^3+b^3=91, find the value of ab
Answer» Answer: given, a + b = 7 and a³ + b³ = 91 since, a³ + b³ = ( a + b)³ -3ab( a + b) => 91 = 7³ -3ab× 7 => 91 = 343 - 21AB => 21ab = 343 -91 => 21ab = 252 => ab = 253/21 = 12 so, ab = 12. $...$

9.

If a+b=7 and a^3+b^3=91, find the value of ab

Answer»

Answer:

given,

a + b = 7

and a³ + b³ = 91

since,

a³ + b³ = ( a + b)³ -3ab( a + b)

=> 91 = 7³ -3ab× 7

=> 91 = 343 - 21AB

=> 21ab = 343 -91

=> 21ab = 252

=> ab = 253/21 = 12

so,

ab = 12.

$...$

Discussion

10.	The ratio of 2 numbers are in 5:6 and their LCM is 480.Then HCF is?
Answer» ANSWER: 16 is the answer of this QUESTION

10.

The ratio of 2 numbers are in 5:6 and their LCM is 480.Then HCF is?

Answer»

ANSWER:

16 is the answer of this QUESTION

Discussion

11.	Please answer question no 16 divided 4 multiply 8 divided 10 bodmas
Answer» 16 divided by 4 MULTIPLIED by 8 divided by 10 (16/48/10) 41.25 5.00 ,,, So ur answer is 5.00

11.

Please answer question no 16 divided 4 multiply 8 divided 10 bodmas

Answer»

16 divided by 4 MULTIPLIED by 8 divided by 10

(16/4*8/10)

4*1.25

5.00

,,, So ur answer is 5.00

Discussion

12.	What is Standard form of -399/603
Answer» Answer: Step-by-step explanation: Final result : (x - 2) • (4x + 1) Reformatting the input : Changes made to your input should not affect the solution: (1): "x2" was replaced by "x^2". 1 more similar replacement(s). Step by step solution : Step 1 : Equation at the end of step 1 : (((x2)-4x)+3)+((3x2-3x)-5) Step 2 : Trying to factor by splitting the middle term 2.1 Factoring 4x2-7x-2 The first term is, 4x2 its coefficient is 4 . The middle term is, -7x its coefficient is -7 . The last term, "the constant", is -2 Step-1 : MULTIPLY the coefficient of the first term by the constant 4 • -2 = -8 Step-2 : Find two factors of -8 whose sum equals the coefficient of the middle term, which is -7 . -8 + 1 = -7 That's it Step-3 : REWRITE the POLYNOMIAL splitting the middle term using the two factors found in step 2 above, -8 and 1 4x2 - 8X + 1x - 2 Step-4 : Add up the first 2 terms, pulling out like factors : 4x • (x-2) Add up the last 2 terms, pulling out common factors : 1 • (x-2) Step-5 : Add up the four terms of step 4 : (4x+1) • (x-2) Which is the desired factorization Final result : (x - 2) • (4x + 1)

12.

What is Standard form of -399/603

Answer»

Answer:

Step-by-step explanation:

Final result :

(x - 2) • (4x + 1)

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2". 1 more similar replacement(s).

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(((x2)-4x)+3)+((3x2-3x)-5)

Step 2 :

Trying to factor by splitting the middle term

2.1 Factoring 4x2-7x-2

The first term is, 4x2 its coefficient is 4 .

The middle term is, -7x its coefficient is -7 .

The last term, "the constant", is -2

Step-1 : MULTIPLY the coefficient of the first term by the constant 4 • -2 = -8

Step-2 : Find two factors of -8 whose sum equals the coefficient of the middle term, which is -7 .

-8 + 1 = -7 That's it

Step-3 : REWRITE the POLYNOMIAL splitting the middle term using the two factors found in step 2 above, -8 and 1

4x2 - 8X + 1x - 2

Step-4 : Add up the first 2 terms, pulling out like factors :

4x • (x-2)

Add up the last 2 terms, pulling out common factors :

1 • (x-2)

Step-5 : Add up the four terms of step 4 :

(4x+1) • (x-2)

Which is the desired factorization

Final result :

(x - 2) • (4x + 1)

Discussion

13.	the sides of a rectangle are X and X + 2 cm and its area is 48 CM square find the perimeter of the rectangle
Answer» Answer:28cm Step-by-step explanation: X and X+2 are two sides Area of rectangle is lb XX+2=48 X^2+2x=48 X^2+2x-48 X^2+8x-6x-48 X(x+8)-6(x+8) (X-6)(X+8) X=6,X=-8.....side the side can't be negative we have to use 8 Perimeter of rectangle 2(l+b) X=6 X+2=6+2=8....substitute in the VALUES of l and b 2(6+8)=28 Hope this HELPS to every brainlist..

13.

the sides of a rectangle are X and X + 2 cm and its area is 48 CM square find the perimeter of the rectangle

Answer»

Answer:28cm

Step-by-step explanation:

X and X+2 are two sides

Area of rectangle is l*b

X*X+2=48

X^2+2x=48

X^2+2x-48

X^2+8x-6x-48

X(x+8)-6(x+8)

(X-6)(X+8)

X=6,X=-8.....side the side can't be negative we have to use 8

Perimeter of rectangle 2(l+b)

X=6

X+2=6+2=8....substitute in the VALUES of l and b

2(6+8)=28

Hope this HELPS to every brainlist..

Discussion

14.	One fifth of a number is 5 less than the number variable h
Answer» ANSWER: gcyxtsduvihucyxibihyg

14.

One fifth of a number is 5 less than the number variable h

Answer»

ANSWER:

gcyxtsduvihucyxibihyg

Discussion

15.	Coefficient of xsquare in 17-2x+7xsquare
Answer» Answer:2 Step-by-step EXPLANATION:

15.

Coefficient of xsquare in 17-2x+7xsquare

Answer»

Answer:2

Step-by-step EXPLANATION:

Discussion

16.	18 divided by 42 ans. in decimal form I want full division on paper
Answer» Answer: hey buddy! HOPE i have ANSWERED what you ASKED for, if yes, PLEASE mark as brainliest

16.

18 divided by 42 ans. in decimal form I want full division on paper

Answer»

Answer:

hey buddy!

HOPE i have ANSWERED what you ASKED for,

if yes, PLEASE mark as brainliest

Discussion

17.	एक दूधवाला है उसके पास 10.kg दूध है उसमे पानी मिलाया हुआ है ओर 20 % पानी की मात्रा है 80% दूध है और पुलिस विभाग ने उसे जब्त कर लिया है क्योंकि सरकारी नियमानुसार 2% से ज्यादा पानी मिलाया हुआ दूध बेचना कानूनन जुर्म है अब उसे उस दूध को छुड़ाने हेतू उस दूध की शुद्धता 98 % करनी है और 1000 रुपये जुर्माना भरना हैओर उसके पास शुद्धता बढ़ानेहेतु जो घर पर काफी सारा दूध पड़ा है वो भी 99% शुद्धता से ज्यादा शुद्ध नही है अब बतावो वो घर से कम से कम कितना दूध और लाकर उस 80% शुद्धतावाले दूध में डाले की वो 98% शुद्ध हो जावे समय सीमा --First divison - 2 घण्टाSecond divison-6 घंटाThird division- 24 घंटाFail- पूरा लोक डाउन
Answer» Answer: 1.5litre Step-by-step EXPLANATION: PLEASE MARK as a RESULT

17.

एक दूधवाला है उसके पास 10.kg दूध है उसमे पानी मिलाया हुआ है ओर 20 % पानी की मात्रा है 80% दूध है और पुलिस विभाग ने उसे जब्त कर लिया है क्योंकि सरकारी नियमानुसार 2% से ज्यादा पानी मिलाया हुआ दूध बेचना कानूनन जुर्म है अब उसे उस दूध को छुड़ाने हेतू उस दूध की शुद्धता 98 % करनी है और 1000 रुपये जुर्माना भरना हैओर उसके पास शुद्धता बढ़ानेहेतु जो घर पर काफी सारा दूध पड़ा है वो भी 99% शुद्धता से ज्यादा शुद्ध नही है अब बतावो वो घर से कम से कम कितना दूध और लाकर उस 80% शुद्धतावाले दूध में डाले की वो 98% शुद्ध हो जावे समय सीमा --First divison - 2 घण्टाSecond divison-6 घंटाThird division- 24 घंटाFail- पूरा लोक डाउन

Answer»

Answer:

1.5litre

Step-by-step EXPLANATION:

PLEASE MARK as a RESULT

Discussion

18.	• Name the quadrilateral SpaxThe pairs of opposite sides are ------- and --------pairs of adiacent angles are ------------and --------
Answer» Step-by-step EXPLANATION: PARALLEL and EQUAL. 2. parallel and equal.

18.

• Name the quadrilateral SpaxThe pairs of opposite sides are ------- and --------pairs of adiacent angles are ------------and --------

Answer»

Step-by-step EXPLANATION:

PARALLEL and EQUAL. 2. parallel and equal.

Discussion

19.	Simplify =(3x+5)²-(3x-5)²
Answer» Answer: 60x Step-by-step EXPLANATION: =9x2+30x+25-(9x2-30x+25) =9x2+30x+25-9x2+30x-25 =30x+30x =60x I HOPE it will USEFUL to you

19.

Simplify =(3x+5)²-(3x-5)²

Answer»

Answer:

60x

Step-by-step EXPLANATION:

=9x2+30x+25-(9x2-30x+25)
=9x2+30x+25-9x2+30x-25
=30x+30x
=60x
I HOPE it will USEFUL to you

Discussion

20.	102. Using suitable rearrangement and find the sum:
Answer» (a+B)SQUARE= a square + b square 102 = 100+2 I THINK This WOULD be the ANSWER

Discussion

21.	neeta says to her brother ,"when i reach your age ,you will be 40 years old " her brother say to neeta "when i was your age you are 4 years old. how old are they?
Answer» Answer: 36 BROTHER 32 sister Step-by-step EXPLANATION: as if we SEE that LET sister=X the brother=X+4 A/q

21.

neeta says to her brother ,"when i reach your age ,you will be 40 years old " her brother say to neeta "when i was your age you are 4 years old. how old are they?

Answer»

Answer:

36 BROTHER 32 sister

Step-by-step EXPLANATION:

as if we SEE that LET sister=X

the brother=X+4

A/q

Discussion

22.	-2/5 x (-3/7). please do it fast
Answer» Step-by-step EXPLANATION: $\frac{ - 2}{ 5} \times \frac{ - 3}{7} = \frac{6}{35}$ Hope it HELPS ❣️

22.

-2/5 x (-3/7). please do it fast

Answer»

Step-by-step EXPLANATION:

$\frac{ - 2}{ 5} \times \frac{ - 3}{7} = \frac{6}{35}$

Hope it HELPS ❣️

Discussion

23.	Removethattwo digit from each numberyou get largest number95571+ 49134 t 23627
Answer» Answer: 971+934+367 Step-by-step explanation: in the first one remove the 5 and 5. in the second one remove 4 and 1 in the third one remove 2 and 2 btw your'E welcome!

23.

Removethattwo digit from each numberyou get largest number95571+ 49134 t 23627

Answer»

Answer:

971+934+367

Step-by-step explanation:

in the first one remove the 5 and 5.

in the second one remove 4 and 1

in the third one remove 2 and 2

btw your'E welcome!

Discussion

24.	Standard form of 0.0000000947
Answer» Answer: Step-by-step EXPLANATION: standard Form of an Equation The "Standard Form" of an equation is: (some expression) = 0 In other words, "= 0" is on the RIGHT, and everything else is on the left. Example: Put x2 = 7 into Standard Form Answer: x2 − 7 = 0

24.

Standard form of 0.0000000947

Answer»

Answer:

Step-by-step EXPLANATION:

standard Form of an Equation

The "Standard Form" of an equation is:

(some expression) = 0

In other words, "= 0" is on the RIGHT, and everything else is on the left.

Example: Put x2 = 7 into Standard Form

Answer:

x2 − 7 = 0

Discussion

25.	→write International number system9,723,658-
Answer» Nine million seven HUNDRED twenty three THOUSAND SIX hundred fifty eight, Please mark the ANSWER as brainliest.

Discussion

26.	Draw a table for properties of Rational Numbers followed by examples(Mention all four properties-Closure,Commutative, Associative and Distributive on all basic operations- addition,subtraction,multiplication and division)
Answer» Answer: Properties of Rational Numbers: Every one of us knows what NATURAL numbers are. The number of PAGES in a BOOK, the fingers on your hand or the number of students in your CLASSROOM. These numbers are rational numbers. Now let us study in detail about the properties of rational numbers.Properties of Rational Numbers The major properties of rational numbers are: CLOSURE Property Commutativity Property Associative Property Distributive Property

26.

Draw a table for properties of Rational Numbers followed by examples(Mention all four properties-Closure,Commutative, Associative and Distributive on all basic operations- addition,subtraction,multiplication and division)

Answer»

Answer:

Properties of Rational Numbers: Every one of us knows what NATURAL numbers are. The number of PAGES in a BOOK, the fingers on your hand or the number of students in your CLASSROOM. These numbers are rational numbers. Now let us study in detail about the properties of rational numbers.Properties of Rational Numbers

The major properties of rational numbers are:

CLOSURE Property

Commutativity Property

Associative Property

Distributive Property

Discussion

27.	Factorise a^4x + a^3 (2x-y) -a(2ay + z) - 2z
Answer» ANSWER: (a+2)(a³x-a²y-Z) Step-by-step EXPLANATION: $a^{4}x$ +a³(2x-y)-a(2ay+z)-2z $a^{4}x$ +2a³x-a³y-2a²y-az-2z $a^{4}x$ -a³y+2a³x-2a²y-az-2z a³(ax-y)+2a²(ax-y)-z(a+2) (ax-y)(a³+2a²)-z(a+2) a²(ax-y)(a+2)-z(a+2){TAKING a COMMON from (a³+2a²)} (a+2)[a²(ax-y)-z] (a+2)(a³x-a²y-z)

27.

Factorise a^4x + a^3 (2x-y) -a(2ay + z) - 2z

Answer»

ANSWER:

(a+2)(a³x-a²y-Z)

Step-by-step EXPLANATION:

$a^{4}x$ +a³(2x-y)-a(2ay+z)-2z

$a^{4}x$ +2a³x-a³y-2a²y-az-2z

$a^{4}x$ -a³y+2a³x-2a²y-az-2z

a³(ax-y)+2a²(ax-y)-z(a+2)

(ax-y)(a³+2a²)-z(a+2)

a²(ax-y)(a+2)-z(a+2){TAKING a COMMON from (a³+2a²)}

(a+2)[a²(ax-y)-z]

(a+2)(a³x-a²y-z)

Discussion

28.	1 3 5 2 4 ? It is not 6, not a maths prob, but it is a pattern
Answer» Answer:By addition of 1st 3 number we get 9.so ASSUMING X we will get X=9-6=3. I THINK 3 is the correct answer. Hope it HELPED U..✌️✌️

28.

1 3 5 2 4 ? It is not 6, not a maths prob, but it is a pattern

Answer»

Answer:By addition of 1st 3 number we get 9.so ASSUMING X we will get X=9-6=3.

I THINK 3 is the correct answer.

Hope it HELPED U..✌️✌️

Discussion

29.	3. In adjoining figure 1.14seg PS ^ seg RQ seg QT ^ seg PR. If RQ = 6, PS = 6 and PR = 12,then find QT.
Answer» Answer: GIVEN: PS ⊥ RQ QT ⊥ PR RQ = 6, PS = 6 and PR = 12 With base PR and height QT, A(△PQR)=½×PR×QT With base QR and height PS, A(△PQR)=½×QR×PS ∴A(△PQR)/A(△PQR)=½×PR×QT/½×QR×PS ⇒1=PR×QT/QR×PS ⇒PR×QT=QR×PS ⇒QT=QR×PS/PR =6×6/12 =3 Hence, the measure of side QT is 3 units.

29.

3. In adjoining figure 1.14seg PS ^ seg RQ seg QT ^ seg PR. If RQ = 6, PS = 6 and PR = 12,then find QT.

Answer»

Answer:

GIVEN:

PS ⊥ RQ

QT ⊥ PR

RQ = 6, PS = 6 and PR = 12

With base PR and height QT,

A(△PQR)=½×PR×QT

With base QR and height PS,

A(△PQR)=½×QR×PS

∴A(△PQR)/A(△PQR)=½×PR×QT/½×QR×PS

⇒1=PR×QT/QR×PS

⇒PR×QT=QR×PS

⇒QT=QR×PS/PR

=6×6/12

=3

Hence, the measure of side QT is 3 units.

Discussion

30.	If A=5x²+7 x+8 and B=4x² -7x+3,find 2A - B
Answer» Step-by-step EXPLANATION: $a = 5 {x}^{2} + 7x + 8 \\b = 4 {x}^{2} - 7x + 3 \\ 2a - b =2( 5 {x}^{2} - 7x + 8) - (4 {x}^{2} - 7x + 3) \\ = 10 {x}^{2} - 14x \: + 16 - 4 {x}^{2} + 7x - 3 \\ = 6 {x}^{2} - 7x + 3$

30.

If A=5x²+7 x+8 and B=4x² -7x+3,find 2A - B

Answer»

Step-by-step EXPLANATION:

$a = 5 {x}^{2} + 7x + 8 \\b = 4 {x}^{2} - 7x + 3 \\ 2a - b =2( 5 {x}^{2} - 7x + 8) - (4 {x}^{2} - 7x + 3) \\ = 10 {x}^{2} - 14x \: + 16 - 4 {x}^{2} + 7x - 3 \\ = 6 {x}^{2} - 7x + 3$

Discussion

31.	Two number are such that the ratio between them is 3: 5 if each is increased by 10 the ratio between the new number so formed is 5:7 find the original number
Answer» ❏ Question Two number are such that the ratio between them is 3: 5 if each is increased by 10 the ratio between the new number so formed is 5:7 find the original number ❏ Solution GIVEN:- Ratio of between two number is 3:5 If each number increase by 10 the ratio will be 5:7 FIND:- Original two number ❏ EXPLANATION Let, First number = x Second number = y A/c to question, ( Ratio of between two number is 3:5 ) ➥ x : y = 3 : 5 ➥ x/y = 3/5 ➥ 5x - 3y = 0 ..................Equ(1) Again, ( If each number increase by 10 the ratio will be 5:7 ) ➥ (x + 10) : (y + 10) = 5 : 7 ➥ (x + 10) / (y + 10) = 5 / 7 ➥ 7(x+10) = 5(y+10) ➥ 7x - 5y = 50 - 70 ➥ 7x - 5y = -20 ..............Equ(2) Multiply by 7 in equ (1) and 5 in equ(2), 35x - 21y = 0 35x - 25y = - 100 _______________Sub. it's ➥ ( -21y + 25y) = 100 ➥ 4y = 100 ➥ y = 100/4 ➥ y = 25 Keep VALUE of y in equ(1), ➥ 5x - 3 × 25 = 0 ➥ 5x = 75 ➥ x = 75/5 ➥ x = 15 THUS:- First number will be = 15 Second number will be = 25 ❏ Verification CASE(1):- ( Ratio of between two number is 3:5 ) ➥ X:Y = 3:5 write in division form ➥ x/y = 3/5 keep value of x and y ➥ 15/25 = 3/5 Divide by 5 ➥ 3/5 = 3/5 ➥ 3:5 = 3:5 L.H.S = R.H.S CASE(2):- ( If each number increase by 10 the ratio will be 5:7 ) ➥ (X+10):(Y+10) = 5:7 write in division form ➥(X+10)/(Y+10)=5/7 keep value of x and h ➥ (15+10)/(25+10) =5/7 ➥ 25/35 = 5/7 Divide by 5 ➥ 5/7 = 5/7 ➥ 5:7 = 5:7 L.H.S = R.H.S both cases are satisfied . So, our solution is right !!

31.

Two number are such that the ratio between them is 3: 5 if each is increased by 10 the ratio between the new number so formed is 5:7 find the original number

Answer»

❏ Question

Two number are such that the ratio between them is 3: 5 if each is increased by 10 the ratio between the new number so formed is 5:7 find the original number

❏ Solution

GIVEN:-

Ratio of between two number is 3:5
If each number increase by 10 the ratio will be 5:7

FIND:-

Original two number

❏ EXPLANATION

Let,

First number = x
Second number = y

A/c to question,

( Ratio of between two number is 3:5 )

➥ x : y = 3 : 5

➥ x/y = 3/5

➥ 5x - 3y = 0 ..................Equ(1)

Again,

( If each number increase by 10 the ratio will be 5:7 )

➥ (x + 10) : (y + 10) = 5 : 7

➥ (x + 10) / (y + 10) = 5 / 7

➥ 7(x+10) = 5(y+10)

➥ 7x - 5y = 50 - 70

➥ 7x - 5y = -20 ..............Equ(2)

Multiply by 7 in equ (1) and 5 in equ(2),

35x - 21y = 0
35x - 25y = - 100

_______________Sub. it's

➥ ( -21y + 25y) = 100

➥ 4y = 100

➥ y = 100/4

➥ y = 25

Keep VALUE of y in equ(1),

➥ 5x - 3 × 25 = 0

➥ 5x = 75

➥ x = 75/5

➥ x = 15

THUS:-

First number will be = 15
Second number will be = 25

❏ Verification

CASE(1):-

( Ratio of between two number is 3:5 )

➥ X:Y = 3:5

write in division form

➥ x/y = 3/5

keep value of x and y

➥ 15/25 = 3/5

Divide by 5

➥ 3/5 = 3/5

➥ 3:5 = 3:5

L.H.S = R.H.S

CASE(2):-

( If each number increase by 10 the ratio will be 5:7 )

➥ (X+10):(Y+10) = 5:7

write in division form

➥(X+10)/(Y+10)=5/7

keep value of x and h

➥ (15+10)/(25+10) =5/7

➥ 25/35 = 5/7

Divide by 5

➥ 5/7 = 5/7

➥ 5:7 = 5:7

L.H.S = R.H.S

both cases are satisfied .

So, our solution is right !!

Discussion

32.	X+1/x=4 then x4 + 1/x4 is equal to
Answer» Answer: 194 Step-by-step EXPLANATION: PLEASE MARK as a RESULT

32.

X+1/x=4 then x4 + 1/x4 is equal to

Answer»

Answer:

194

Step-by-step EXPLANATION:

PLEASE MARK as a RESULT

Discussion

33.	If cot theata=12/5show that tan2theata-sin2theta=sin4thetasec2 theta
Answer» Step-by-step EXPLANATION: PLEASE MARK BRILLIANT please mark brilliant

33.

If cot theata=12/5show that tan2theata-sin2theta=sin4thetasec2 theta

Answer»

Step-by-step EXPLANATION:

PLEASE MARK BRILLIANT

please mark brilliant

Discussion

34.	What least number should be added to 169302 to make it a perfect square?
Answer» ANSWER: ADD 442 it wil be a perfect square Step-by-step explanation: 169302+442=169744 is the square of 412

34.

What least number should be added to 169302 to make it a perfect square?

Answer»

ANSWER:

ADD 442 it wil be a perfect square

Step-by-step explanation:

169302+442=169744 is the square of 412

Discussion

35.	Zero given as to find the quadratic equation (5,-7)
Answer» SoluTion: Given ZEROES : 5 and -7 We've to find the quadratic polynomial. Sum of zeroes = 5 + (-7) Sum of zeroes = -2 S = -2 PRODUCT of zeroes = 5 (-7) Product of zeroes = -35 P = -35 Quadratic polynomial = x² - Sx + P Quadratic Polynomial = x² - (-2)x + (-35) Quadratic Polynomial = x² + 2x - 35 Hence, Quadratic Polynomial is x² + 2x - 35.

35.

Zero given as to find the quadratic equation (5,-7)

Answer»

SoluTion:

Given ZEROES :

5 and -7

We've to find the quadratic polynomial.

Sum of zeroes = 5 + (-7)

Sum of zeroes = -2

S = -2

PRODUCT of zeroes = 5 (-7)

Product of zeroes = -35

P = -35

Quadratic polynomial = x² - Sx + P

Quadratic Polynomial = x² - (-2)x + (-35)

Quadratic Polynomial = x² + 2x - 35

Hence, Quadratic Polynomial is x² + 2x - 35.

Discussion

36.	Three rational number between -3/4 and -1/2
Answer» Answer: SEE pic for your answer hope it is HELPFUL to you please MARK me BRAINLIST

36.

Three rational number between -3/4 and -1/2

Answer»

Answer:

SEE pic for your answer

hope it is HELPFUL to you

please MARK me BRAINLIST

Discussion

37.	Solve 1234: 24 :: 3154:?
Answer» ANSWER: UR answer is 61.34197.... MARK as BRAINLIEST!!!

37.

Solve 1234: 24 :: 3154:?

Answer»

ANSWER:

UR answer is 61.34197....

MARK as BRAINLIEST!!!

Discussion

38.	Find the following by using identities (3x/4-2y/5)^2
Answer» ANSWER: SEE this.......HOPE this HELP u✌️.......

38.

Find the following by using identities (3x/4-2y/5)^2

Answer»

ANSWER:

SEE this.......HOPE this HELP u✌️.......

Discussion

39.	Prove that √sec^2 thita+ cosec ^2 thita = tan thita + cot thita
Answer» ANSWER: Step-by-step EXPLANATION: LHS: SQRT(sec^2t+cosec^2t) =sqrt(tan^2t+1+cot^2t+1) =sqrt(tan^2t+cot^2t+2) =sqrt((tant+cot)^2) =tant+cott =RHS

39.

Prove that √sec^2 thita+ cosec ^2 thita = tan thita + cot thita

Answer»

ANSWER:

Step-by-step EXPLANATION:

LHS:

SQRT(sec^2t+cosec^2t)

=sqrt(tan^2t+1+cot^2t+1)

=sqrt(tan^2t+cot^2t+2)

=sqrt((tant+cot)^2)

=tant+cott

=RHS

Discussion

40.	9. Evaluate: (x - 2)(x+ 2) (x + 4)
Answer» Step-by-step explanation:X CUBE + 8 x SQUARE + 12 x - 16

Discussion

41.	Please answer these questions its urgent...
Answer» Answer: a) 15 hrs 46 min 10 sec b) 9yrs 10months 12 days c) 5HRS 10 min 5 sec d)5yrs 4 months 11 days

41.

Please answer these questions its urgent...

Answer»

Answer:

a) 15 hrs 46 min 10 sec

b) 9yrs 10months 12 days

c) 5HRS 10 min 5 sec

d)5yrs 4 months 11 days

Discussion

42.	Please solve this problem fast and give reason for them
Answer» Answer: (i), (ii),(iii),(V) are POLYNOMIAL and (iv) is not a polynomial. it is because a polynomial is an expression CONSISTING of VARIABLES and coefficients, that involves only the operations of addition, subtraction, multiplication, and non- negative integer exponents of variables. since, (iv) has negative exponet of variable. y+2/y=(y²+2)/y =(y²+2) $y^{-1}$ =y+2 $y^{-1}$ . so, it is not a polynomial Step-by-step explanation:

42.

Please solve this problem fast and give reason for them

Answer»

Answer:

(i), (ii),(iii),(V) are POLYNOMIAL and (iv) is not a polynomial.

it is because a polynomial is an expression CONSISTING of VARIABLES and coefficients, that involves only the operations of addition, subtraction, multiplication, and non- negative integer exponents of variables.

since, (iv) has negative exponet of variable.

y+2/y=(y²+2)/y =(y²+2) $y^{-1}$ =y+2 $y^{-1}$ . so, it is not a polynomial

Step-by-step explanation:

Discussion

43.	The value of k for which the equation 2x2 – (k-1) x+8=0 will have real and equal roots are :(a) 9 and -7(b) only 9(C) only - 7 (d) -9 and - 7
Answer» Answer: option a is correct, i.e. 9 and -7 Step-by-step explanation: SINCE roots are equal and real. so, D=0 D=b²-4ac so, b²-4ac=0 (-(k-1))²-4×2×8=0 k²-2k+1-64=0 k²-2k-63=0 k²-9k+7k-63=0 k(k-9)+7(k-9)=0 (k-9)(k+7)=0 so, k=9, -7

43.

The value of k for which the equation 2x2 – (k-1) x+8=0 will have real and equal roots are :(a) 9 and -7(b) only 9(C) only - 7 (d) -9 and - 7

Answer»

Answer:

option a is correct, i.e. 9 and -7

Step-by-step explanation:

SINCE roots are equal and real.

so, D=0

D=b²-4ac

so, b²-4ac=0

(-(k-1))²-4×2×8=0

k²-2k+1-64=0

k²-2k-63=0

k²-9k+7k-63=0

k(k-9)+7(k-9)=0

(k-9)(k+7)=0

so, k=9, -7

Discussion

44.	Write the distance formula
Answer» ANSWER: DISTANCE = SPEED X TIME

44.

Write the distance formula

Answer»

ANSWER:

DISTANCE = SPEED X TIME

Discussion

45.	Plz answer this question....
Answer» ANSWER: PLEASE MARK as a RESULT

45.

Plz answer this question....

Answer»

ANSWER:

PLEASE MARK as a RESULT

Discussion

46.	Q.8 The quadratic equation whose roots are real and equal is :(a) 2x2 - 4x + 3 = 0(b) x2 - 4x + 4 = 0(C) 3x2 – 5x + 2 = 0
Answer» Answer: hope it will HELPS you if it was CORRECT PLEASE FOLLOW

46.

Q.8 The quadratic equation whose roots are real and equal is :(a) 2x2 - 4x + 3 = 0(b) x2 - 4x + 4 = 0(C) 3x2 – 5x + 2 = 0

Answer»

Answer:

hope it will HELPS you if it was CORRECT PLEASE FOLLOW

Discussion

47.	Koi toh dimaag lgaake ans krdo pls
Answer» ANSWER: hope it HELPED you Step-by-step explanation: MARK me as BRAINLIST

47.

Koi toh dimaag lgaake ans krdo pls

Answer»

ANSWER:

hope it HELPED you

Step-by-step explanation:

MARK me as BRAINLIST

Discussion

48.	3(m-5) - 5(m-2) =0 what is the value of m in the equation
Answer» Answer: 3(m-5)-5(m-2)=0 3M - 15 - 5M + 10 =0 -2m -5 =0 -2m = 5 m= 5/-2 m= -2.5

48.

3(m-5) - 5(m-2) =0 what is the value of m in the equation

Answer»

Answer:

3(m-5)-5(m-2)=0

3M - 15 - 5M + 10 =0

-2m -5 =0

-2m = 5

m= 5/-2

m= -2.5

Discussion

49.	If a student multiple 150 by 16 instead of 15 then the difference in the product is
Answer» Answer: 150 Step-by-step explanation: 150 × 16 = 2400 150 × 15 = 2250 2400 - 2250 = 150

49.

If a student multiple 150 by 16 instead of 15 then the difference in the product is

Answer»

Answer:

150

Step-by-step explanation:

150 × 16 = 2400

150 × 15 = 2250

2400 - 2250 = 150

Discussion

50.	Plz answer this question plz plz
Answer» ANSWER: Step-by-step explanation: given X^2-kx-2=p(x) if (x-3) is a factor of p(x) then p(3)=0 3^2-k(3)-2=0 9-3k-2 =0 7-3k=0 3k=7 k=7/3

50.

Plz answer this question plz plz

Answer»

ANSWER:

Step-by-step explanation:

given

X^2-kx-2=p(x)

if (x-3) is a factor of p(x) then p(3)=0

3^2-k(3)-2=0

9-3k-2 =0

7-3k=0

3k=7

k=7/3

Discussion

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❏ EXPLANATION

_______________Sub. it's

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