Saved Bookmarks
| 1. |
3. In adjoining figure 1.14seg PS ^ seg RQ seg QT ^ seg PR. If RQ = 6, PS = 6 and PR = 12,then find QT. |
|
Answer» Answer: PS ⊥ RQ QT ⊥ PR RQ = 6, PS = 6 and PR = 12 With base PR and height QT, A(△PQR)=½×PR×QT With base QR and height PS, A(△PQR)=½×QR×PS ∴A(△PQR)/A(△PQR)=½×PR×QT/½×QR×PS ⇒1=PR×QT/QR×PS ⇒PR×QT=QR×PS ⇒QT=QR×PS/PR =6×6/12 =3 Hence, the measure of side QT is 3 units. |
|