332354 + Interview Questions in Secondary School in Math

1.	What is the area of a rectangle having length 3cm and breadth 2 cm ?
Answer» ANSWER: AREA of rectangle Step-by-step EXPLANATION: LB= 3×2=6 6 is the answer

1.

What is the area of a rectangle having length 3cm and breadth 2 cm ?

Answer»

ANSWER:

AREA of rectangle

Step-by-step EXPLANATION:

LB= 3×2=6

6 is the answer

Discussion

2.	X +1Simplity4xX 2-1X-1
Answer» 4X X 2-1 = X is the ANSWER to this QUESTION

Discussion

3.	Solve the following LPP by using proper simplex method.Min(z)=x-2y-3zS.T.C-2x+y+3x=22x+3y+4z=1Where x,y,z ≥ 0
Answer» Answer: 4.89 Step-by-step EXPLANATION:

3.

Solve the following LPP by using proper simplex method.Min(z)=x-2y-3zS.T.C-2x+y+3x=22x+3y+4z=1Where x,y,z ≥ 0

Answer»

Answer:

4.89

Step-by-step EXPLANATION:

Discussion

4.	Answer this question ASAP AND MORE QUESTIONS AS WELL
Answer» ANSWER: STATEMENT is not COMPLETE

4.

Answer this question ASAP AND MORE QUESTIONS AS WELL

Answer»

ANSWER:

STATEMENT is not COMPLETE

Discussion

5.	Calculate the perimeter of the squares with the following sides Side=13.8 mm
Answer» Answer: 55.2mm Step-by-step EXPLANATION: PERIMETER of square=4SIDE =413.8 =55.2mm

5.

Calculate the perimeter of the squares with the following sides Side=13.8 mm

Answer»

Answer:

55.2mm

Step-by-step EXPLANATION:

PERIMETER of square=4*SIDE

=4*13.8

=55.2mm

Discussion

6.	3 1/4 read the fraction
Answer» Answer: 3 whole 1 by 4 Step-by-step explanation: HOPE you satisfied mark as BRAINLIST follow for more SOLUTIONS

6.

3 1/4 read the fraction

Answer»

Answer:

3 whole 1 by 4

Step-by-step explanation:

HOPE you satisfied

mark as BRAINLIST

follow for more SOLUTIONS

Discussion

7.	একটি ঘরের আয়তন ৭৬৮০০০ ঘন সে,মি, এবং বায়ু পানির তুলনায় ০.০০১২৯ গুন ভারি হলে, ঘরটির বায়ু পরিমান কত কিল গ্রাম
Answer» Answer: ১০০০ ঘন সেমি পানির আয়তন ১লি অতএব ৭৬৮০০ঘন সেমি পানির আয়তন ৭৬৮ লি। আবার, ১লি পানির ওজন ১কি. গ্রা. ৭৬৮ লি পানির ওজন ৭৬৮ কি.গ্রা. যেহেতু, বায়ু পানির তুলনায় ০.০০১২৯গুন ভারী। অতএব, ঘরটিতে বায়ুর পরিমাণ (০.০০১২৯×৭৬৮)কি.গ্রা. =০.৯৯০৭২কি.গ্রাম।

7.

একটি ঘরের আয়তন ৭৬৮০০০ ঘন সে,মি, এবং বায়ু পানির তুলনায় ০.০০১২৯ গুন ভারি হলে, ঘরটির বায়ু পরিমান কত কিল গ্রাম

Answer»

Answer:

১০০০ ঘন সেমি পানির আয়তন ১লি

অতএব ৭৬৮০০ঘন সেমি পানির আয়তন ৭৬৮ লি।

আবার,

১লি পানির ওজন ১কি. গ্রা.

৭৬৮ লি পানির ওজন ৭৬৮ কি.গ্রা.

যেহেতু, বায়ু পানির তুলনায় ০.০০১২৯গুন ভারী।

অতএব, ঘরটিতে বায়ুর পরিমাণ

(০.০০১২৯×৭৬৮)কি.গ্রা.

=০.৯৯০৭২কি.গ্রাম।

Discussion

8.	Please solve it calculate nahi hai
Answer» Answer: 1.825.33333............. 2.301 5.7263.42857143......... 6.7493.44444444......... Step-by-step EXPLANATION: Verification: 1. 825.3333.......6=4952 2.3018=2408 5.7263.428571437=50844 6.7493.444444449=67441 Hope it HELPS

8.

Please solve it calculate nahi hai

Answer»

Answer:

1.825.33333.............

2.301

5.7263.42857143.........

6.7493.44444444.........

Step-by-step EXPLANATION:

Verification:

1. 825.3333.......*6=4952

2.301*8=2408

5.7263.42857143*7=50844

6.7493.44444444*9=67441

Hope it HELPS

Discussion

9.	फाइंड द वैल्यू ऑफ ए एंड बी एफ 3 प्लस रूट 2 अपऑन 3 माइनस रूट 2 इक्वल टू ए प्लस बी रोड टू
Answer» ANSWER: Acid TURNS BLUE LITMUS RED and bases turns red litmus

9.

फाइंड द वैल्यू ऑफ ए एंड बी एफ 3 प्लस रूट 2 अपऑन 3 माइनस रूट 2 इक्वल टू ए प्लस बी रोड टू

Answer»

ANSWER:

Acid TURNS BLUE LITMUS RED and bases turns red litmus

Discussion

10.	I have a problem with these two geometry questions and I need help...solve the third and fourth one from below...Please solve it with step by step solution and proof...I'll be thankful...the right answerer will be marked brainliest...Thanks...
Answer» hahwuwiqj1n1i qi1niqnqi1 ao1%

Discussion

11.	ਕੁਝ ਕਲਿਪ ਹਰੇ ਹਨ।ਸਾਰੇ ਹਰੇ ਕਲਿਪ ਹਨ।1; । ਸਾਰੇ ਕਲਿਪ ਲਾਲ ਹਨ।॥ ਕੁੱਝ ਕਲਿਪ ਲਾਲ ਹਨ।syllogism
Answer» ANSWER: sorry I don't UNDERSTAND your language sorry PLEASE FOLLOW me and mark me as BRAINILEST

11.

ਕੁਝ ਕਲਿਪ ਹਰੇ ਹਨ।ਸਾਰੇ ਹਰੇ ਕਲਿਪ ਹਨ।1; । ਸਾਰੇ ਕਲਿਪ ਲਾਲ ਹਨ।॥ ਕੁੱਝ ਕਲਿਪ ਲਾਲ ਹਨ।syllogism

Answer»

ANSWER:

sorry I don't UNDERSTAND your language sorry

PLEASE FOLLOW me and mark me as BRAINILEST

Discussion

12.	02A notebook has total of 540 pages from which 75% are already used. Find the number of unused pages.
Answer» ANSWER: dgkgjdckkgoxicogcigguzkg

12.

02A notebook has total of 540 pages from which 75% are already used. Find the number of unused pages.

Answer»

ANSWER:

dgkgjdckkgoxicogcigguzkg

Discussion

13.	George's printer can print 24 pages in 15 minutes. How many pages can it print in 45 minutes?
Answer» Answer: As you can SEE, 15 minutes is a quarter of an hour, so if we multiply 15 by 3, we get 45 minutes, or 3/4 of an hour. The answer is 72 pages.

13.

George's printer can print 24 pages in 15 minutes. How many pages can it print in 45 minutes?

Answer»

Answer:

As you can SEE, 15 minutes is a quarter of an hour, so if we multiply 15 by 3, we get 45 minutes, or 3/4 of an hour. The answer is 72 pages.

Discussion

14.	In a two digit number the tens digit is three times the units digit when the number is decreased by 54 the digits are reversed write an equationDON'T COPY FROM ANYWHERE BECAUSE THIS QUESTION IS DIFFERENT
Answer» ANSWER: 93 Step-by-step EXPLANATION: the answer is 93 yes, that is the answer PLZ MAKE me BRAINLIST

14.

In a two digit number the tens digit is three times the units digit when the number is decreased by 54 the digits are reversed write an equationDON'T COPY FROM ANYWHERE BECAUSE THIS QUESTION IS DIFFERENT

Answer»

ANSWER:

93

Step-by-step EXPLANATION:

the answer is 93

yes, that is the answer

PLZ MAKE me BRAINLIST

Discussion

15.	Is 2817 a perfect cube
Answer» ANSWER: $\huge\bold\red\star\rm\red{Question}\bold\red\star$ Is 2817 a perfect CUBE? $\huge\star\rm\purple{Answer}$ No, 2817 is not a perfect cube because, the number 2817 is not divisible by any of the number.

15.

Is 2817 a perfect cube

Answer»

ANSWER:

$\huge\bold\red\star\rm\red{Question}\bold\red\star$

Is 2817 a perfect CUBE?

$\huge\star\rm\purple{Answer}$

No, 2817 is not a perfect cube because, the number 2817 is not divisible by any of the number.

Discussion

16.	Solve 3 4x-5=11 2x+10
Answer» Step-by-step explanation: 34x-5=112x+10 We MOVE all terms to the LEFT: 34x-5-(112x+10)=0 We get rid of parentheses 34x-112x-10-5=0 We ADD all the numbers together, and all the variables -78x-15=0 We move all terms containing x to the left, all other terms to the right -78x=15 x=15/-78 x=-5/26 *Please mark me as brainelist*

16.

Solve 3 4x-5=11 2x+10

Answer»

Step-by-step explanation:

34x-5=112x+10

We MOVE all terms to the LEFT:

34x-5-(112x+10)=0

We get rid of parentheses

34x-112x-10-5=0

We ADD all the numbers together, and all the variables

-78x-15=0

We move all terms containing x to the left, all other terms to the right

-78x=15

x=15/-78

x=-5/26

Please mark me as brainelist

Discussion

17.	The area of a rectangle is 8.4 square and its length is 3 cm find its breadth and perimeter.
Answer» ANSWER: Area=8.4cm² Length=3cm Breadth=84/30 =2.8 Perimeter=2(Length+Bradth) =2(3cm+2.8cm) =2(5.8cm) =116cm Thank my answer Follow Me

17.

The area of a rectangle is 8.4 square and its length is 3 cm find its breadth and perimeter.

Answer»

ANSWER:

Area=8.4cm²

Length=3cm

Breadth=84/30

=2.8

Perimeter=2(Length+Bradth)

=2(3cm+2.8cm)

=2(5.8cm)

=116cm

Thank my answer

Follow

Me

Discussion

18.	.7. If the external and internal radii of aspherical shell are 5 cm and 3 cmrespectively, the volume of the shell incm3.is(a) 405(b) 400INWINwww(c) 41032(d) 4153
Answer» ANSWER: OPTION C is CORRECT ..................

18.

.7. If the external and internal radii of aspherical shell are 5 cm and 3 cmrespectively, the volume of the shell incm3.is(a) 405(b) 400INWINwww(c) 41032(d) 4153

Answer»

ANSWER:

OPTION C is CORRECT ..................

Discussion

19.	If theta is the angle between the lines x/ y+ a/ b = 1 and x/ y+ b/ a=1 . Find the value of sin theta where a > b.
Answer» Step-by-step EXPLANATION: is the ANS is 30 * s TELL me

19.

If theta is the angle between the lines x/ y+ a/ b = 1 and x/ y+ b/ a=1 . Find the value of sin theta where a > b.

Answer»

Step-by-step EXPLANATION:

is the ANS is 30 * s TELL me

Discussion

20.	6. Ae) in a country, there are 215 highway accidents associated with drinking alcohol. Out ofthese, 113 are caused by excessive speed. Approximately what per cent of accidents arespeed related?ar(i) 47%(ii) 49%(iii) 51%(iv) 53%
Answer» Answer: The Non-cooperation movement was launched on 5th September, 1920 by MAHATMA Gandhi with the AIM of self-governance and OBTAINING full independence as the Indian National Congress (INC) withdrew its support for British reforms following the Rowlatt ACT of 21 March 1919, and the Jallianwala Bagh massacre of 13 April 1919 ...

20.

6. Ae) in a country, there are 215 highway accidents associated with drinking alcohol. Out ofthese, 113 are caused by excessive speed. Approximately what per cent of accidents arespeed related?ar(i) 47%(ii) 49%(iii) 51%(iv) 53%

Answer»

Answer:

The Non-cooperation movement was launched on 5th September, 1920 by MAHATMA Gandhi with the AIM of self-governance and OBTAINING full independence as the Indian National Congress (INC) withdrew its support for British reforms following the Rowlatt ACT of 21 March 1919, and the Jallianwala Bagh massacre of 13 April 1919 ...

Discussion

21.	a man bought 10 apples for a rupee and 18 apples for a rupee. he mixed them and sells it at 15 for a rupee. find his gain or loss per cent.
Answer» ANSWER: If you FOLLOW me I will TELL the answer

21.

a man bought 10 apples for a rupee and 18 apples for a rupee. he mixed them and sells it at 15 for a rupee. find his gain or loss per cent.

Answer»

ANSWER:

If you FOLLOW me I will TELL the answer

Discussion

22.	50 kg + 250 gm + 10750 gm? gm
Answer» Answer: 61000gm Step-by-step EXPLANATION: I HOPE it will be HELPFUL to you

22.

50 kg + 250 gm + 10750 gm? gm

Answer»

Answer:

61000gm

Step-by-step EXPLANATION:

I HOPE it will be HELPFUL to you

Discussion

23.	Pls answer it as soon as possible
Answer» ANSWER: HII GOOD AFTERNOON..........

23.

Pls answer it as soon as possible

Answer»

ANSWER:

HII GOOD AFTERNOON..........

Discussion

24.	Find the volume andsurface area of the cone with base radius 2.3cm and height 46cm
Answer» Surface area of CONE is 365.765 cm². Volume of cone is 81.1133 cm³. Step-by-step explanation: Given:- Base RADIUS of cone is 2.3 cm. Height of cone is 46 cm. To find:- Volume of cone. Surface area of cone. Solution:- Surface area of cone = πrl + πr² In which, l is slant height of cone. r is radius of cone. l = √r² + h² l = r + h l = 2.3 + 46 l = 48.3 cm r = 2.3 cm Put l and r in formula: ➜ 22/7 × 2.3 × 48.3 + 22/7 × 2.3 × 2.3 ➜ 2443.98/7 + 22/7 × 5.29 ➜ 2443.98/7 + 116.38/7 ➜ 2560.36/7 ➜ 365.765 Therefore, Surface area of cone is 365.765 cm². __________________________ Volume of cone = 1/3r²h r = 2.3 cm h = 46 cm Put the values of r and h in formula: ➜ 1/3 × 2.3 × 2.3 × 46 ➜ 243.34/3 ➜ 81.113 Volume of cone is 81.1133 cm³.

24.

Find the volume andsurface area of the cone with base radius 2.3cm and height 46cm

Answer»

Surface area of CONE is 365.765 cm².
Volume of cone is 81.1133 cm³.

Step-by-step explanation:

Given:-

Base RADIUS of cone is 2.3 cm.
Height of cone is 46 cm.

To find:-

Volume of cone.
Surface area of cone.

Solution:-

Surface area of cone = πrl + πr²

In which,

l is slant height of cone.
r is radius of cone.

l = √r² + h²

l = r + h

l = 2.3 + 46

l = 48.3 cm

r = 2.3 cm

Put l and r in formula:

➜ 22/7 × 2.3 × 48.3 + 22/7 × 2.3 × 2.3

➜ 2443.98/7 + 22/7 × 5.29

➜ 2443.98/7 + 116.38/7

➜ 2560.36/7

➜ 365.765

Therefore,

Surface area of cone is 365.765 cm².

__________________________

Volume of cone = 1/3r²h

r = 2.3 cm

h = 46 cm

Put the values of r and h in formula:

➜ 1/3 × 2.3 × 2.3 × 46

➜ 243.34/3

➜ 81.113

Volume of cone is 81.1133 cm³.

Discussion

25.	plese tell me answer
Answer» Step-by-step EXPLANATION: I THINK this ANSWER is HELPFUL for you

25.

plese tell me answer

Answer»

Step-by-step EXPLANATION:

I THINK this ANSWER is HELPFUL for you

Discussion

26.	If you give me some unique answer
Answer» ANSWER: where is the QUESTION....

26.

If you give me some unique answer

Answer»

ANSWER:

where is the QUESTION....

Discussion

27.	Find the zeros of the following polynomial and verify the relationship between the zeros and the coefficient.t²-15 ??please solve this
Answer» ANSWER: OK I am EXPLAIN U but first a FALL u follow me and mark as brainlist

27.

Find the zeros of the following polynomial and verify the relationship between the zeros and the coefficient.t²-15 ??please solve this

Answer»

ANSWER:

OK I am EXPLAIN U but first a FALL u follow me and mark as brainlist

Discussion

28.	Please give me my answer its very important for my assignment
Answer» ANSWER: bro I donot know I which language it is bro but do FOLLOW and MARK me as BRAINLIEST

28.

Please give me my answer its very important for my assignment

Answer»

ANSWER:

bro I donot know I which language it is bro but do FOLLOW and MARK me as BRAINLIEST

Discussion

29.	The fourth of a number exceeds it one third by 60 . The number is
Answer» Answer: 12 PLEASE FOLLOW me please follow me I'll INBOX you

29.

The fourth of a number exceeds it one third by 60 . The number is

Answer»

Answer:

12

PLEASE FOLLOW me please follow me I'll INBOX you

Discussion

30.	Find the area of an isosceles right triangle which is 21 cm base.
Answer» Step-by-step explanation: area of RIGHT ISOSCELES triangle =1/2b×h 1/2×21×21( isosceles Triangles have two sides EQUAL ) =441/2 =220.5sq. CM

30.

Find the area of an isosceles right triangle which is 21 cm base.

Answer»

Step-by-step explanation:

area of RIGHT ISOSCELES triangle =1/2b×h

1/2×21×21( isosceles Triangles have two sides EQUAL )

=441/2

=220.5sq. CM

Discussion

31.	Y= –x¹ + 2 this is linear or no?
Answer» ANSWER: no this is not LINEAR I THINK

31.

Y= –x¹ + 2 this is linear or no?

Answer»

ANSWER:

no this is not LINEAR I THINK

Discussion

32.	Factorise : 2x + x2 – 13x + 6
Answer» ANSWER: this can be WRITTEN as ${x}^{2} + 2x - 13x + 6$ ${x}^{2} - 11x + 6$ is the question correct or not

32.

Factorise : 2x + x2 – 13x + 6

Answer»

ANSWER:

this can be WRITTEN as

${x}^{2} + 2x - 13x + 6$

${x}^{2} - 11x + 6$

is the question correct or not

Discussion

33.	B) If distance is divided by seed we get
Answer» ANSWER: TIME is the answer of this QUESTION

33.

B) If distance is divided by seed we get

Answer»

ANSWER:

TIME is the answer of this QUESTION

Discussion

34.	←_← what is technology??
Answer» ANSWER: the USE of SCIENCE in EVERYDAY LIFE

34.

←_← what is technology??

Answer»

ANSWER:

the USE of SCIENCE in EVERYDAY LIFE

Discussion

35.	अपरिमय संख्या की व्याख्या क्या हे please give me answer fast
Answer» ANSWER: PLEASE TELL the QUESTION in ENGLISH...

35.

अपरिमय संख्या की व्याख्या क्या हे please give me answer fast

Answer»

ANSWER:

PLEASE TELL the QUESTION in ENGLISH...

Discussion

36.	If the HCF of 65 and 117 is expressible in the form of 65m – 117, then the value of m is
Answer» Answer: LET us find the HCF of 65 and 117, 117 = 1 × 65 + 52 65 = 1 × 52 + 13 52 = 4 ×13 + 0 therefore HCF of 65 and 117 is 13. 65m -117 = 13 65m = 117+13 = 130 m =130 / 65 =2 Now, 65 = 5 × 13 117 = 13 × 3 × 3 LCM of 65 and 117 = 5 × 13 × 3 × 3 = 585

36.

If the HCF of 65 and 117 is expressible in the form of 65m – 117, then the value of m is

Answer»

Answer:

LET us find the HCF of 65 and 117,

117 = 1 × 65 + 52

65 = 1 × 52 + 13

52 = 4 ×13 + 0

therefore HCF of 65 and 117 is 13.

65m -117 = 13

65m = 117+13 = 130

m =130 / 65 =2

Now, 65 = 5 × 13

117 = 13 × 3 × 3

LCM of 65 and 117 = 5 × 13 × 3 × 3 = 585

Discussion

37.	Prove that\|b²c² bc b+c\|\|c^2a^2 ca c+a\|\|a^2b^2 ab a+b\| =0
Answer» Given Question PROVE that $\rm \: \: \: \: \begin{gathered}\sf \left \| \begin{array}{ccc} {b}^{<klux>2</klux>} {c}^{2} &bc&b + c\\ {c}^{2} {a}^{2} &<klux>CA</klux>&c + a\\ {a}^{2} {b}^{2} &<klux>AB</klux>&a + b\end{array}\right \| \end{gathered} = 0$ Solution :- Consider, $\rm :\longmapsto\:\begin{gathered}\sf \left \| \begin{array}{ccc} {b}^{2} {c}^{2} &bc&b + c\\ {c}^{2} {a}^{2} &ca&c + a\\ {a}^{2} {b}^{2} &ab&a + b\end{array}\right \| \end{gathered}$ $\red{\rm :\longmapsto\:OP \: R_1 \to \: aR_1} \\ \red{\rm :\longmapsto\:OP \: R_2 \to \: bR_2} \\ \red{\rm :\longmapsto\:OP \: R_3 \to \: cR_3}$ $\: \: \rm = \: \: \begin{gathered}\sf \left \| \begin{array}{ccc} a{b}^{2} {c}^{2} &abc&ab + ac\\ b{c}^{2} {a}^{2} &bca&bc + ba\\ c{a}^{2} {b}^{2} &cab&ca + cb\end{array}\right \| \end{gathered}$ Take out abc common from Column 1 and column 2, we get $\: \: \rm = \: \: {a}^{2} {b}^{2} {c}^{2} \begin{gathered}\sf \left \| \begin{array}{ccc} {b}{c} &1&ab + ac\\ {c}{a} &1&bc + ab\\ {a}{b} &1&ac + bc\end{array}\right \| \end{gathered}$ $\red{\rm :\longmapsto\:OP \: C_3 \to \: C_3 + C_1}$ $\: \: \rm = \: \: {a}^{2} {b}^{2} {c}^{2} \begin{gathered}\sf \left \| \begin{array}{ccc} {b}{c} &1&ab + ac + bc\\ {c}{a} &1&bc + ab + ac\\ {a}{b} &1&ac + bc + ab\end{array}\right \| \end{gathered}$ Take out ab + bc + ca common from column 3, we get $\: \: \rm = \: \: {a}^{2} {b}^{2} {c}^{2}(ab + bc + ca) \begin{gathered}\sf \left \| \begin{array}{ccc} {b}{c} &1&1\\ {c}{a} &1&1\\ {a}{b} &1&1\end{array}\right \| \end{gathered}$ $\: \: \rm = \: \: {a}^{2} {b}^{2} {c}^{2}(ab + bc + ca) \times 0$ $\: \: \: \: \: \: \: \: \: \: \: \boxed{ \sf \: \because \: C_2 \: and \: C_3 \: are \: identical}$ $\: \: \rm = \: \: 0$ ${\boxed{\boxed{\bf{Hence, Proved}}}}$ Additional Information :- 1. The determinant remains unaltered if its rows are changed into columns and the columns into rows. This is known as the property of reflection. 2. If all the elements of a row (or column) are zero, then the determinant is zero. 3. If the all elements of a row (or column) are proportional (identical) to the elements of some other row (or column), then the determinant is zero. 4. The interchange of any two rows (or columns) of the determinant changes its sign. 5. If all the elements of a determinant above or below the main diagonal consist of zeros, then the determinant is EQUAL to the product of diagonal elements

37.

Prove that|b²c² bc b+c||c^2a^2 ca c+a||a^2b^2 ab a+b| =0

Answer»

Given Question

PROVE that

$\rm \: \: \: \: \begin{gathered}\sf \left | \begin{array}{ccc} {b}^{<klux>2</klux>} {c}^{2} &bc&b + c\\ {c}^{2} {a}^{2} &<klux>CA</klux>&c + a\\ {a}^{2} {b}^{2} &<klux>AB</klux>&a + b\end{array}\right | \end{gathered} = 0$

Solution :-

Consider,

$\rm :\longmapsto\:\begin{gathered}\sf \left | \begin{array}{ccc} {b}^{2} {c}^{2} &bc&b + c\\ {c}^{2} {a}^{2} &ca&c + a\\ {a}^{2} {b}^{2} &ab&a + b\end{array}\right | \end{gathered}$

$\red{\rm :\longmapsto\:OP \: R_1 \to \: aR_1} \\ \red{\rm :\longmapsto\:OP \: R_2 \to \: bR_2} \\ \red{\rm :\longmapsto\:OP \: R_3 \to \: cR_3}$

$\: \: \rm = \: \: \begin{gathered}\sf \left | \begin{array}{ccc} a{b}^{2} {c}^{2} &abc&ab + ac\\ b{c}^{2} {a}^{2} &bca&bc + ba\\ c{a}^{2} {b}^{2} &cab&ca + cb\end{array}\right | \end{gathered}$

Take out abc common from Column 1 and column 2, we get

$\: \: \rm = \: \: {a}^{2} {b}^{2} {c}^{2} \begin{gathered}\sf \left | \begin{array}{ccc} {b}{c} &1&ab + ac\\ {c}{a} &1&bc + ab\\ {a}{b} &1&ac + bc\end{array}\right | \end{gathered}$

$\red{\rm :\longmapsto\:OP \: C_3 \to \: C_3 + C_1}$

$\: \: \rm = \: \: {a}^{2} {b}^{2} {c}^{2} \begin{gathered}\sf \left | \begin{array}{ccc} {b}{c} &1&ab + ac + bc\\ {c}{a} &1&bc + ab + ac\\ {a}{b} &1&ac + bc + ab\end{array}\right | \end{gathered}$

Take out ab + bc + ca common from column 3, we get

$\: \: \rm = \: \: {a}^{2} {b}^{2} {c}^{2}(ab + bc + ca) \begin{gathered}\sf \left | \begin{array}{ccc} {b}{c} &1&1\\ {c}{a} &1&1\\ {a}{b} &1&1\end{array}\right | \end{gathered}$

$\: \: \rm = \: \: {a}^{2} {b}^{2} {c}^{2}(ab + bc + ca) \times 0$

$\: \: \: \: \: \: \: \: \: \: \: \boxed{ \sf \: \because \: C_2 \: and \: C_3 \: are \: identical}$

$\: \: \rm = \: \: 0$

${\boxed{\boxed{\bf{Hence, Proved}}}}$

Additional Information :-

1. The determinant remains unaltered if its rows are changed into columns and the columns into rows. This is known as the property of reflection.

2. If all the elements of a row (or column) are zero, then the determinant is zero.

3. If the all elements of a row (or column) are proportional (identical) to the elements of some other row (or column), then the determinant is zero.

4. The interchange of any two rows (or columns) of the determinant changes its sign.

5. If all the elements of a determinant above or below the main diagonal consist of zeros, then the determinant is EQUAL to the product of diagonal elements

Discussion

38.	-3/7×2/5+3/4-3/7×1/5
Answer» Step-by-step explanation: A COMPANY being a corporate a. Cannot sue b. Can sue c. Cannot be SUED d. A NATURAL pers

38.

-3/7×2/5+3/4-3/7×1/5

Answer»

Step-by-step explanation:

A COMPANY being a corporate

a. Cannot sue

b. Can sue

c. Cannot be SUED

d. A NATURAL pers

Discussion

39.	Solve thisa) 6√30+4√36-15-2√30b)4√144-4√54+5√96-5√36
Answer» Answer: 4 3 +5 2 Dividing NUMERATOR and DENOMINATOR by 48 − 18 = 48 + 18 ( 48 − 18 ) 4 3 +5 2 ( 48 − 18 ) = 48 48 − 18 18 4 3 48 −4 3 18 +5 2 48 −5 2 18 = 48−18 4×4 3 3 −4×3 3 2 +5×4 2 3 −5×3 2 2 = 30 4×4×3−4×3 6 +5×4 6 −5×3×2 = 30 48−12 6 +20 6 −30 = 30 18+8 6

39.

Solve thisa) 6√30+4√36-15-2√30b)4√144-4√54+5√96-5√36

Answer»

Answer:

4

3

+5

2

Dividing NUMERATOR and DENOMINATOR by

48

−

18

=

48

+

18

(

48

−

18

)

4

3

+5

2

(

48

−

18

)

=

48

−

18

4

3

48

−4

3

18

+5

2

48

−5

2

18

=

48−18

4×4

3

−4×3

3

2

+5×4

2

3

−5×3

2

=

30

4×4×3−4×3

6

+5×4

6

−5×3×2

=

30

48−12

6

+20

6

−30

=

30

18+8

6

Discussion

40.	3.The smallest 2-digit number is
Answer» Answer : The smallest two-digit NUMBER is 10 and the GREATEST is 99.

40.

3.The smallest 2-digit number is

Answer»

Answer :

The smallest two-digit NUMBER is 10 and the GREATEST is 99.

Discussion

41.	Show solution5×(25+((−4)×(16−8÷2)))
Answer» $\huge \mathbb\fcolorbox{black}{lavenderblush}{Answer♡}$ Step-by-step EXPLANATION: $5 \times (25 + ( - 4 \times (16 - 4))) \\ 5 \times (25 + ( - 4) \times 12) \\ 5 \times (25 + ( - 48)) \\ 5 \times (25 - 48) \\ 5 \times ( - 23) \\ = - 115$

41.

Show solution5×(25+((−4)×(16−8÷2)))

Answer»

$\huge \mathbb\fcolorbox{black}{lavenderblush}{Answer♡}$

Step-by-step EXPLANATION:

$5 \times (25 + ( - 4 \times (16 - 4))) \\ 5 \times (25 + ( - 4) \times 12) \\ 5 \times (25 + ( - 48)) \\ 5 \times (25 - 48) \\ 5 \times ( - 23) \\ = - 115$

Discussion

42.	Please answer this question correct.
Answer» ANSWER: no SUBTRACTION don't follow ASSOCIATIVE property ex: (2-4)-3= -2 -3 = -5 while 2-(4-3)=2-1 =1

42.

Please answer this question correct.

Answer»

ANSWER:

no SUBTRACTION don't follow ASSOCIATIVE property

ex: (2-4)-3= -2 -3

= -5

while 2-(4-3)=2-1

=1

Discussion

43.	Pls tell.this question
Answer» ANSWER: I THINK that the CORRECT answer is a)

43.

Pls tell.this question

Answer»

ANSWER:

I THINK that the CORRECT answer is a)

Discussion

44.	Z-7/z = 4z+5Is this a quadratic equation?
Answer» Answer: no this is not a quadratic EQUATION it's linear equation because the highest POWER is 1

44.

Z-7/z = 4z+5Is this a quadratic equation?

Answer»

Answer:

no this is not a quadratic EQUATION it's linear equation because the highest POWER is 1

Discussion

45.	X²-18+81=0 નાં બીજ સમાન છે
Answer» ANSWER: ?????????????????????

45.

X²-18+81=0 નાં બીજ સમાન છે

Answer»

ANSWER:

?????????????????????

Discussion

46.	1. ఒక సమకోణము నంటియున్న భుజములు 404, 383 ఆ కోణమున కెదుటనున్న భుజమెంత?
Answer» Answer: 404, 383 ఆ కోణమున కెదుటనున్న భుజమెంత

46.

1. ఒక సమకోణము నంటియున్న భుజములు 404, 383 ఆ కోణమున కెదుటనున్న భుజమెంత?

Answer»

Answer:

404, 383 ఆ కోణమున కెదుటనున్న భుజమెంత

Discussion

47.	Write three soultoin of each following equatoins ? 2x+y=7
Answer» Step-by-step EXPLANATION: THANK for the ANSWER ,FOLLOW

47.

Write three soultoin of each following equatoins ? 2x+y=7

Answer»

Step-by-step EXPLANATION:

THANK for the ANSWER ,FOLLOW

Discussion

48.	If a,b,c are in proportion,them...
Answer» Answer: CONTINUED PROPORTION: Three numbers a,B,c are said to be in continued proportion if a,b,b,c are in proportion. MEAN PROPORTIONAL: If abc are in continued proportion then b is called the mean proportional between aandc. Step-by-step explanation: HOPE it help U

48.

If a,b,c are in proportion,them...

Answer»

Answer:

CONTINUED PROPORTION: Three numbers a,B,c are said to be in continued proportion if a,b,b,c are in proportion. MEAN PROPORTIONAL: If abc are in continued proportion then b is called the mean proportional between aandc.

Step-by-step explanation:

HOPE it help U

Discussion

49.	Find the complementary angles of the following.i) 40° and. ii) 890
Answer» Step-by-step EXPLANATION: COMPLEMENTARY of 40° = 90° - 40° =50° Complementary of 89° = 90° - 89° = 1°

49.

Find the complementary angles of the following.i) 40° and. ii) 890

Answer»

Step-by-step EXPLANATION:

COMPLEMENTARY of 40° = 90° - 40° =50°

Complementary of 89° = 90° - 89° = 1°

Discussion

50.	Simplify the following 3/11+-7/22-5/33+-15/44
Answer» ANSWER: $- 71$ $\frac{3}{11?} + \frac{ - 7}{22?} - \frac{5}{33} + \frac{ - 15}{44}$

50.

Simplify the following 3/11+-7/22-5/33+-15/44

Answer»

ANSWER:

$- 71$

$\frac{3}{11?} + \frac{ - 7}{22?} - \frac{5}{33} + \frac{ - 15}{44}$

Discussion

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Please answer this question correct.

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