1.

If the HCF of 65 and 117 is expressible in the form of 65m – 117, then the value of m is​

Answer»

Answer:

LET us find the HCF of 65 and 117,

117 = 1 × 65 + 52

65 = 1 × 52 + 13

52 = 4 ×13 + 0

therefore HCF of 65 and 117 is 13.

65m -117 = 13

65m = 117+13 = 130

m =130 / 65 =2

Now, 65 = 5 × 13

117 = 13 × 3 × 3

LCM of 65 and 117 = 5 × 13 × 3 × 3 = 585


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