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In chemistry, an IONIC compound is a chemical compound composed of IONS held together by electrostatic forces termed ionic bonding. The compound is neutral OVERALL, but consists of positively charged ions called cations and negatively charged ions called anions.They form crystals. ...They have higher enthalpies of FUSION and vaporization than molecular compounds.They are hard.They are brittle.They have high melting POINTS and also high boiling points.They conduct electricity but only when they are dissolved in water

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iven MASS/MOLECULAR massmoles =Avogadro's number *GIVEN mass /gram molecular massmoles =pv/rt. ideal gas

s have the same atomic number, while ISOBARS have the same atomic mass. ISOTOPES : Isotopes are ATOMS that have same atomic number but different mass numbers. Isotopeshave the same atomic number because the number of PROTONS inside their nuclei remains the same.Plz mark as brsinliast

ate !!!!!!!!!!Here is your answer .......The ELEMENTS have same atomic numbers but different atomic MASS. The physical properties of isotopes are all most same because they are same ELEMENT... only they have more number of NEUTRONS in their atom. For example :- CL have atomic number = 17 But have mass = 35u and 37u.HOPE THIS WILL HELP YOU......

the NUCLEUS, there are PROTONS and NEUTRONS.#BeBrainly ❤️

Fluorine is the most REACTIVE halogen element.Explanation:Elements BELONGING to group 7 are known as HALOGENS. It is known that on moving down the group size of atom increases and electronegativity of the atoms decreases. Similarly, in halogens fluorine is the most electronegative atom. Therefore, it is most reactive in NATURE as it needs only ONE electron to complete its octet so, it readily reacts. On the other hand, astatine being the largest is least reactive.Thus, fluorine is highly reactive in nature.

is because it SAYS about LAW of CONSERVATION so there is CONSTANT COMPOSITION

is TRUE it RESEMBLES the law of CONSERVATION do it is having CONSTANT composition

RE! HERE'S YOUR ANSWER....Used in purifying processes,used in making naphthalene balls,used in ROOM freshners and in DRYING processes WITHOUT leaving any residueHOPE IT HELPS:-)

सफेद क्यूबिक क्रिस्टल है। जब नमक शुद्ध होता है तो यह स्पष्ट होता है। शुद्धता के आधार पर यह सफेद, भूरे या भूरे रंग में भी दिखाई देता है।यह गंधहीन होता है लेकिन इसमें नमकीन स्वाद होता है।पानी में घुलनशीलता विभिन्न तापमानों पर भिन्न होती है।हाइग्रोस्कोपिक (किसी पदार्थ को आसपास से पानी के अणुओं को आकर्षित करने और पकड़ने की क्षमता)।नमक का पिघलने बिंदु 800.8 डिग्री सेल्सियस है।नमक का क्वथनांक 1465 डिग्री सेल्सियस है।

ucose reacts with BROMINE WATER, it FORM gluconic acidPlease find the ATTACHED pictureHope it HELPS

4 and 210^x84 because they have same atomic NUMBER But DIFFERENT atomic masses. HOPE it HELPS

all chemicals are not OK to handle without CHECKING substance a disaster can cause like fire .some substance are radio active,highly reactive.which are not ok to handle with normal hands.it has to handle with care.it is nessasary for health of HUMAN.

hanoic acid on cooling CHANGE into CRYSTAL which look like a GLACIER so, ethanoic acid is called glacial..It may help you..

I THINK OPTION A IS CORRECT.

te down your given equation. For this example, you will use:C3H8 + O2 --> H2O + CO2This reaction occurs when propane (C3H8) is BURNED in the presence of oxygen to produce water and carbon dioxide.2---Write down the number of atoms per element. Do this for each side of the equation. Look at the subscripts next to each atom to find the number of atoms in the equation. When writing it out, it's a good idea to connect it back to the original equation, noting how each element appears. For example, you have 3 oxygen atoms on the right side, but that total results from addition. Left side: 3 carbon (C3), 8 HYDROGEN (H8) and 2 oxygen (O2).Right side: 1 carbon (C), 2 hydrogen (H2) and 3 oxygen (O + O2).3---Save hydrogen and oxygen for last, as they are often on both sides.Hydrogen and oxygen are both common in molecules, so it's likely that you'll have them on both sides of your equation. It's best to balance them last.You'll need to recount your atoms before balancing the hydrogen and oxygen, as you'll likely need to use coefficients to balance the other atoms in the equation.4----Start with single elements. If you have more than one element left to balance, select the element that appears in only a single MOLECULE of reactants and in only a single molecule of products. This means that you will need to balance the carbon atoms first.5----Use a coefficient to balance the single carbon atom. Add a coefficient to the single carbon atom on the right of the equation to balance it with the 3 carbon atoms on the left of the equation.C3H8 + O2 --> H2O + 3CO2The coefficient 3 in front of carbon on the right side indicates 3 carbon atoms just as the subscript 3 on the left side indicates 3 carbon atoms.In a chemical equation, you can change coefficients, but you must never alter the subscripts.6---Balance the hydrogen atoms next.Since you have balanced all atoms besides the hydrogen and oxygen, you can ADDRESS the hydrogen atoms. You have 8 on the left side. So you'll need 8 on the right side. Use a coefficient to achieve this.C3H8 + O2 --> 4H2O + 3CO2On the right side, you now added a 4 as the coefficient because the subscript showed that you already had 2 hydrogen atoms.When you multiply the coefficient 4 times by the subscript 2, you end up with 8.The other 6 atoms of oxygen come from 3CO2.(3x2=6 atoms of oxygen+ the other 4=10)7----Balance the oxygen atoms. Remember to account for the coefficients that you've used to balance out the other atoms. Because you've added coefficients to the molecules on the right side of the equation, the number of oxygen atoms has changed. You now have 4 oxygen atoms in the water molecules and 6 oxygen atoms in the carbon dioxide molecules. That makes a total of 10 oxygen atoms.Add a coefficient of 5 to the oxygen molecule on the left side of the equation. You now have 10 oxygen atoms on each side.C3H8 + 5O2 --> 4H2O + 3CO2.The carbon, hydrogen, and oxygen atoms are balanced. Your equation is complete.

because that MELTING POINT of mercury is LESS than ROOM TEMPERATURE

mix barium HYDROXIDE with AMMONIUM chloride, the bottom of the test TUBE becomes cold due to ABSORPTION of heat. So, it is an endothermic reaction.This reaction absorbs heat from its environment to be completed, so it is an endothermic reaction.Ba(OH)+NH4cl=BaCl2+NH4OH

t is GIVEN as benzene derivative, a benzene ring () must be present. (Here n refers to the number of substituent/s present).Out of the total 8 CARBON atoms 6 are present in the ring. The other TWO carbon atoms may be present in the same substituent or two SUBSTITUENTS (1+1). The benzene derivative having the molecular formula can be an ethyl derivative or dimethyl derivative. Thus, the POSSIBLE isomers are ethylbenzene () and dimethylbenzene[] with the methyl substituents at ortho, para and meta positions.

chemical series is an ARRANGEMENT of various redox equilibria in the ORDER of their ELECTRODE potential. If a metal (A) is above another metal (B) in the electrochemical series then it can easily reduce ions to metal B by releasing electrons. E⁰ and E⁰The E⁰ values INDICATE that Ni (A) is above AG (B) in electrochemical series and hence the given redox reaction is feasible.

fects of WATER pollution can LEAD to this. Eutrophication is one such EFFECT

t give white precipitate of AgCl on heating it with silver nitrate. A precipitate is an INSOLUBLE substance formed when TWO solutions CONTAINING ionic solutes are mixed. Exchange of ions TAKES place and an insoluble salt is formed in aqueous solution. In other WORDS, precipitation reaction changes the ions into insoluble salt in aqueous solution. Since is a covalent compound, it does not give ions in solution and cannot form white precipitate of AgCl on heating it with silver nitrate.

e source giving the spectrum is placed in a magnetic field atomic level splitting takes place which is known as Zeeman EFFECT. Due to the interaction of degenerate electrons with magnetic field displacement from degeneracy occurs.  This results in extra lines appearing. As the angular momentum state has associated magnetic DIPOLE moment, magnetic field separates these states into different ENERGY levels- i) one state elevating the energy ii) another lowering the energy and iii) one remaining at the same energy level. Hence in ADDITION to original lines we find more lines.

"same mass" of "diamond and graphite" are "burnt" in the oxygen, the heat produced is different. Because "diamond" has "three dimensional" structure whereas graphite has hexagonal rings in each LAYER.(b) Yes.During the dissolution of "AMMONIUM chloride" in water, entropy increases. That is is POSITIVE. We know that is positive here.But if ,Then, According to above equation  G will be negative.Hence, the process is spontaneous.(c) DUE to the "presence of defects", a real crystal can have some DISORDER. But the ideal crystal has no disorder. That is why "real crystal" has "more entropy" than "ideal crystal". "

nce Silicon uses the empty 3d ATOMIC orbitals and shows the coordination number greater than four. Silicon can EXPAND its octet beyond the eight electrons. Thus, silicon can FORM compounds with coordination number five and six. (b) In Si-F bond, there is dative pi binding which involves filled p-atomic orbitals of fluorine and also d-atomic orbitals of silicon. Although Silicon is LARGER in size than Carbon, due to the presence of pi binding of fluorine and empty orbitals of silicon, "Si-F bond" is "stronger" than "C-F bond"."

ism of Markovnikov addition. Example: HYDROGEN BROMIDE gives an electrophile . It attacks the double bond to form the carbocation. 1. Thus, the secondary carbocation in (b) part is more stable than the primary carbocation in (a) part. The former is predominated since it is formed faster than the latter. 2. The carbocation in part (b) is attacked by ION and form the following product shown in second PICTURE. "

e alkali METALS have more free IONS in comparison to the ALKALINE EARTH metals......

n peroxide is a highly unstable compound. Even in dilute quantity it decomposes. This is because of the presence of weak bond between the oxygen atoms. In the presence of sunlight it readily BREAKS up as follows: Since the resultant species are free radicals they are highly reactive. It is also one of the causes for the FORMATION of photochemical smog. UNBURNED hydrocarbon fuel molecules are attacked by the free radicals forming molecules. These molecules cause irritation of nose and eyes. In order to prevent this cause, the bottle containing hydrogen peroxide is cooled before opening to lower the vapour pressure INSIDE the bottle. Hydrogen peroxide liquid remains in its original STATE.

en peroxide" acts as oxidising agents in "both" acidic and basic medium. It ALSO acts as a "reducing agent" in "both" "acidic and basic" medium. It is used as a "bleaching agent" for the paper PULP, TEXTILES, preparation of sodium PER borate and DEUTERIUM compounds, and automobile fuel.Example to show "Hydrogen peroxide" acts as oxidising agents in acidic medium."

osphere of Earth is sectioned into LAYERS depending on their altitudes. The five layers from the highest altitude to the lowest altitude areExosphere: 700 km  to 10,000 km i.e., ‘440 miles to 6200 miles’.Thermosphere: 80 km  to 700 km i.e., '50 miles to 440 miles’.MESOSPHERE: 50 km  to 80 km i.e., '31 miles to 50 miles’.STRATOSPHERE: 12 km to 50 km i.e., ‘7 miles to 31 miles’.Troposphere: 0 km  to 12 km i.e., ‘0 miles to 7 miles’.

the organic compound can be dried USING sodium metal and not depends on, whether the given compound CHEMICALLY reacts with sodium metal or not. In the case of ALCOHOLS, the functional group has a hydrogen ATOM attached to highly electronegative oxygen atom. Thus the electron cloud of hydrogen is pulled more towards the oxygen atom. Hence it can be very easily replaced by more electropositive sodium atoms. Hence alcohols cannot be dried with sodium metal. In ethers oxygen atom is bonded on either side with the carbon atoms of the ALKYL group present. No chemical reaction takes place. Thus sodium metal can be used for drying ether.

m atom loose electrons to FORM first ionization energy  The "second ionization energy" is the energy REQUIRED to eliminate a "second ELECTRON" to form "2+ CATIONS" from "1+ cations". The third ionization energy is the "energy required" to form 3+ cations. The "second ionization energy" is larger than the first ionization energy, since it REQUIRES more energy to eliminate an "electron" from a cation than it is from a "neutral atom". Likewise, the "third ionization energy" is "larger" than the "second ionization energy". The has the highest ionization energy"."

tioned metals are ALKALINE earth metals. The size of the METAL atom plays an important role in the formation of products when heated. The size of the metal atom is inversely related to the TENDENCY to FORM halide hydrates. In other words tendency to form alkaline earth halide hydrates gradually decreases down the group. This favours the dehydration of those halides with bigger cation  (Ca, Sr and Ba) when heated. Smaller the cation (Be and Mg) greater is the tendency to form the halide hydrates. Hence when heated they SUFFER hydrolysis.

pound carbide is composed of a carbon and also an element with less electronegative element. Carbides are divided into three TYPES based on their chemical bonding. GROUP 13 metals (includes Lanthanum, Scandium and Yttrium), alkaline earth metals, alkali metals are high electropositive elements forms the saline carbides.       Aluminium forms carbides from the Group 13 on heated above 1275k whereas the other elements like Gallium, Thallium and Indium does not form the carbides. Since these elements does not combine with the carbon in the starting STAGE, that is why they cannot form carbides NORMALLY.