This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Calculate the bonding and antibonding electrons in ion on the basis of molecular orbital theory. |
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Answer» der:It is defined as the total number of covalent BONDS in the covalent molecule. In other words, it is equal to the half the DIFFERENCE between number of electrons which are INVOLVED in BONDING and anti-bonding in the molecular orbitals.We know that, To calculate the bond order of The electronic configuration of Here the number of bonding electrons = 8The number of anti-bonding electrons = 3Bond order |
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| 2. |
Depict the galvanic cell in which the reaction: takes place. Further show: (i) which of the electrode is negatively charged. (ii) the carriers of current in the cell. (iii) individual reaction at each electrode. |
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Answer» c cell converts chemical energy into electrical energy and it CONSISTS of two HALF cells, they are ANODE and cathode. The given Galvanic cell representation is as follows.i) Zn ELECTRODE is anode because it is negatively charged.ii) In the cell, current carried by ions, the flow of current from silver to zinc.iii) The reaction taking PLACE at the anodeThe reaction taking place at the cathode |
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| 3. |
Calculate the concentrations of hydrogen ion and hydroxide ion at 25°C in: (i) 0.15 M (ii) 0.01 M |
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Answer» that nitric acid HNO3 is strong acid and it DISSOCIATES completely. It is represented in the EQUATION as follows,If the concentration of GIVEN is 0.15M, then obviously is also 0.15MWe KNOW that, So, For Consider if is 0.01M then [OH-] is equal to |
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| 4. |
Give the reasons of the following: (a) Fluorine has less negative electron gain enthalpy than chlorine. (b) Noble gases tend to be less reactive. (c) First ionisation enthalpy of ‘Mg’ is more than that of ‘Na’ but second ionisation enthalpy of ‘Mg’ is less than that of ‘Na’. |
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Answer» to the small size of the fluorine atom there exists inter ionic repulsion between the electrons in the 2p orbitals, so the incoming electrons in the fluorine atom does not show much attraction. So, fluorine has less negative ELECTRON gain enthalpy than CHLORINE b) The noble gases already have most stable electronic configuration. They do not tend to lose or gain electron to attain stable configuration. Hence, they are less reactive or inert in NATURE c) The electronic configuration MAGNESIUM is whereas the electronic configuration of sodium is .During first ionization the electron removed from the outer shell is from the 3s orbital in both the cases. Here the charge of Magnesium is (+12) whereas it is (+11) for sodium. So, the first ionization ENERGY of magnesium is higher than that of sodium. Then for removal electron during second ionization, the electron is removed from 3s orbital for magnesium whereas in case of sodium it attains the inert gas configuration. So, more energy amount is required to remove an electron from sodium during second ionization. Hence first ionization enthalpy of magnesium is more than sodium whereas the second ionization enthalpy of magnesium is less than that of sodium . |
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| 5. |
Describe the industrial application of dependent on: (i) the heat liberated when its atoms are made to combine on the surface of a metal. (ii) its effect on unsaturated organic system is presence of catalyst. (iii) its ability to combine with under specific conditions. |
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Answer» hydrogen COMBINE with METAL surface, it liberates HEAT. Therefore, hydrogen is used in the welding/cutting torch.ii) In the exsistence of metal catalyst, hydrogen combine with unsaturated oils to form saturated organic compounds. In the exsistence of Nickel catalyst, hydrogen are mixed with unsaturated organic oils to produce vanaspati ghee.Due to this property, hydrogen is WIDELY used in the manufacturing of edible oils like soyabean OIL, seed oil, etc.iii) Under the specific conditions nitrogen combines to hydrogen to form ammonia. The reaction is as follows. |
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| 6. |
Calculate the amount of lime, , required to remove hardness of 50,000 litres of well water which has been found to contain 1.62 g of calcium bicarbonate per 10 litre. |
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Answer» 10 L of well water contains 1.62 gram of Calcium Bicarbonate Therefore, totally 50,000 L of well water contains 8100 of We know that, MOLAR Mass of Calcium Bicarbonate Molar Mass of lime water Then, NUMBER of moles of = Number of moles of m = 3700 G Therefore, the required mass of lime is 3700 g. |
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| 7. |
Define van der Waal’s radius of an atom. |
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Answer» der WAAL's radius is half the distance between two unbonded atoms when the electrostatic forces are balanced between them. The dimensions of Van Der Waal's forces are PICOMETERS (pm). The distance between two atoms reflects the action of intermolecular forces(e.g. dipole and dispersion forces) and is linked to the INTERACTIONS between Van der Waals. Vander Waals radius is HELPFUL in predicting the distance between two atoms which are LIES in the solid. |
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| 8. |
Calculate and compare the energies of two radiations one with a wavelength of 800 nm and other with wavelength of 400 nm. |
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Answer» the two energy of RADIATIONS with wavelength and We know that, E = energy h = PLANCK’s constant ν = frequency and C = Speed of light We also know, SUBSTITUTE in the equation, For For Finally, the wavelength is inversely PROPORTIONAL to energy, where the radiation with wavelength 400nm is higher than the radiation with wavelength 800nm. |
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| 9. |
Describe the change in hybridisation (if any) of the Al atom in the following reaction: |
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Answer» en chemical reaction is as follows.Electronic configuration of AlGround state electronic configuration =Excited electronic configuration =Hence in , Al undergoes hybridization to GIVE planar TRIANGULAR structure. In , the EMPTY 3p orbital is also INVOLVED so that there is hybridization in and its shape is tetrahedral. |
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| 10. |
Calcium carbonate reacts with aqueous HCl to give and according to the reaction: \longrightarrow What mass of CaCO3 is required to react completely with 25 mL of 0.75 M HCl? |
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Answer» ulating the mass of HCl in 25 ML of 0.75M HClWe know that,Mass of HCl = 0.6844 g II) Calculating of mass of From the above equation we know that, 2 mole of HCl reacts with 1 mole of . of HCl reacts with 100 g of .73 g of HCl reacts with 100 g of .1 g of HCl reacts with of .0.6844 g of HCl reacts with 0.9375 g of is required to react completely with 25ml of 0.75M HCl. |
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| 11. |
Describe the shapes of and . Assign the hybridisation of boron in these species. |
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Answer» n TENDS to produce monomeric covalent halides due to its “SMALL size” and “high electronegativity”. These halides have a triangular planar geometry. This triangular shape consists of the overlap between three HYBRIDIZED boron orbitals and the sp orbitals of three HALOGEN atoms. Boron have hybridization.(ii) The hybridization of boron-hydride ion is and geometry of is tetrahedral. |
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| 12. |
Derive how the free energy change is related to the total entropy change of a system. |
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Answer» bs free energy combines enthalpy and entropy in one value. It is the energy associated with a chemical REACTION that can be useful. It is EQUIVALENT to subtraction of enthalpy from temperature and system entropy. Free energy REFERS to the amount of energy available during a chemical reaction to do cellular work. Gibbs free energy equation If is negative, thus it is a forward reaction and is spontaneous. If is zero, the system is at equilibrium. If is POSITIVE, the reaction is spontaneous in the reverse direction. |
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| 13. |
Check the table is right or wrong |
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Answer» t's CORRECT........................... |
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| 14. |
Which method is useful to separate the component from mixture of acetone and water? |
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Answer» Distillation is the method which is USEFUL to SEPARATE the components from Acetone and water.Simple distillation is used to separate two immiscible LIQUIDS or a mixture of two liquids.Simple Distillation separate two MIXTURES of liquid by the help of their boiling POINTS. Both the liquid have their different boiling points.according to their boiling points, these two liquids are separated from mixture of immiscible liquids. |
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| 15. |
Bromine monochloride, BrCl decomposes into bromine and chlorine and reaches the equilibrium for which Kc = 32 at 500K. If initially pure BrCl is present at a concentration of 3.3 × mol , what is its molar concentration in the mixture at equilibrium ? |
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Answer» nitial CONCENTRATION of the MIXTURE At EQUILIBRIUM, Where, given at 500K is 32So, By simplifying the above equation, we GET 5.60At equilibrium, |
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| 16. |
Define the term 'elution' as applied to column chromatography. |
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Answer» ytical and organic chemistry, elution is the process of extracting ONE material from another by washing with a solvent; as in washing of loaded ion-exchange resins to remove captured ions.In a liquid chromatography experiment, for example, an analyte is generally adsorbed, or "bound to", an adsorbent in a liquid chromatography column. The adsorbent, a solid phase (stationary phase), is a powder which is coated onto a solid support. Based on an adsorbent's composition, it can have varying affinities to "hold" onto other molecules—forming a thin FILM on its surface. Elution then is the process of removing analytes from the adsorbent by running a solvent, called an "eluent", past the adsorbent/analyte complex. As the solvent molecules "elute", or travel down through the chromatography column, they can either PASS by the adsorbent/analyte complex or they can displace the analyte by binding to the adsorbent in its PLACE. After the solvent molecules displace the analyte, the analyte can be CARRIED out of the column for analysis. This is why as the mobile phase passes out of the column, it typically flows into a detector or is collected for compositional analysis.Predicting and controlling the order of elution is a key aspect of column chromatographic methods.PLEASE MARK IT AS BRAINLIEST. |
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| 17. |
Density of a gas is found to be 5.46 g/ at 27°C at 2 bar pressure. What will be its density at STP ? |
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Answer» ideal gas,From the given data,DENSITY = 5.46 PRESSURE = 2 atmTemperature = 300 K ............(1)At STP,..........(2)From (1) and (2) We get,Therefore, the density of the gas at STP will be |
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| 18. |
Between and which one will have a higher melting point. |
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Answer» ting point is DIRECTLY depends upon the intermolecular bonds that are present in the COMPOUND. The melting point of is 1290℃ and is 178℃. i) Aluminium fluoride is ionic in CHARACTER, due to its low polarisability of the fluoride ion, so it has a high melting point. ii) Aluminium chloride is COVALENT in nature due to the high polarising power of aluminium, so it has a low melting point. III) Aluminium chloride does not have a melting whereas it sublimes. |
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| 19. |
Calculate and the equilibrium constant for the formation of from NO and at 298K, where |
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Answer» e KNOW that, By simplifying, we GET Kc the equilibrium CONSTANT VALUE |
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| 20. |
Give the structure of the simplest hydrocarbon having all the four types of carbon atoms. Write down its IUPAC name too. |
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Answer» mplest hydrocarbon having all the FOUR types of carbon atom is as FOLLOWS, Assume Methane, it has a chemical formula of CH4. The four hydrogen in the methane is REPLACED by methyl GROUP then the resulted structure is a hydrocarbon. The IUPAC name of the above-mentioned compound is NEOPENTANE. This can also be named as (2, 2) Dimethylpropane. The structure is as follows; |
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| 21. |
Define Lattice energy. How is Lattice energy influenced by: (i) Charge on the ions. (ii) Size of the ions. |
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Answer» energy defined as the release of energy when a mole of CRYSTALLINE solid is formed by the combination of opposite charged ions under standard conditions. i) The INCREASE in magnitude of the charge on an ion will increase the force of inter-ionic attraction and HENCE, the value of lattice energy will be GREATER. ii) The SMALLER the size of ions, the inter-nuclear distance and the lattice energy will be higher. |
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| 22. |
Critical temperature for carbon dioxide and methane are 31.1°C and – 81.9°C respectively. Which of these has stronger intermolecular forces and why? |
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Answer» imum temperature is a temperature at which the gas is CONVERTED into liquid by increasing the pressure is CALLED its critical temperature. This MEANS that the attractive intermolecular FORCES between the gas molecules are directly proportional to their critical temperature. Critical temperature for carbon dioxide and methane are 31.1°C and - 81.9°C respectively. Intermolecular forces are high in carbon dioxide than compared to the methane. Therefore, carbon dioxide has high value of critical temperature. |
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| 23. |
Covalent bonds are called directional bonds while ionic bonds are called non–directional. Why? |
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Answer» t BONDS are called directional bonds WHEREAS ionic bonds are called non-directional? ... Hence covalent bond is directional. In ionic compounds, each ION is surrounded by a number of oppositely charged ions and hence there is no definite DIRECTION. |
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| 24. |
Give the structure of an anion which is isostructural with . |
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Answer» les which are having the same number of electrons are termed as iso-structural SPECIES. The number of valence electrons in anion is 24 The valence electrons for N is 5 =5 The valence electrons for O is 6 so 6 x3 = 18 Anion = 1 TOTAL = 24 electrons The number of valence electrons in molecule is 24 The valence electrons for B is 3 = 3 The valence electrons for F is 7 so 7 x 3= 21 Total = 24 electrons is iso-structural with . |
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| 25. |
Balance the following reaction: (alkaline medium) |
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Answer» he EQUATION skeleton.Assign oxidation numbers.Identify the redox couplesCombine redox couplesBalance all ATOMS expect hydrogen and OXYGEN atoms.Balance the chargeBalance oxygen atomsMake ELECTRON GAIN equivalent to electron lostAdd half cell reactionsSimplify the equationFinal equation is |
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| 26. |
designing electroplating the copper deposited on the plate connected to the negative terminal comes from the solution how this loss of copper from the solution is compensated |
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Answer» copper is compensated when an EQUAL amount of copper is DEPOSITED in the electrolytic solution as well as on the pure copper CONNECTED on the cathode. |
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| 27. |
Why are group 1 elements called alkali metals and group 17 are called halogens? |
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Answer» elements DISSOLVE in water to form ALKALIS and so they are called ALKALI metals.Group 17 elements are called halogens because they are "salt formers" and they have 7 VALENCE electrons in their outermost shells.HOPE IT HELPS YOU ✌ |
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| 28. |
Why Ga has smaller atomic radii than aluminium? |
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Answer» it is LEFT in the periodic table than aluminium.Thus it has SMALLER atomic radiiHope this HELP BRAINLIEST |
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| 29. |
Give the structure of the alkene () which adds on HBr in the presence and in the absence of peroxide to give the same product, . |
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Answer» ucture of ALKENE is isobutylene is in the figure. It has three carbon atoms and METHYL group have double BONDED to the center carbon atom. The ADDITION of HBr to isobutylene in the presence and absence of peroxide is given below:In the absence of peroxide: the bromine atom bonds with the center atom by BREAKING the double bond.In the presence of peroxide: the bromine atom bonds with the extreme atom and also breaking the double bond. |
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| 30. |
Describe with the help of chemical equations: (i) Anti-Markovnikov’s rule. (ii) Decarboxylation. |
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Answer» -Markovnikov's rule:This rule describes regiochemistry in which the “substituent” is connected to a "less SUBSTITUTED carbon" instead of a more substituted carbon. This rule's process is a unusual process, as carbon cations that are COMMONLY FORMED during "alkene" or "alkyne" reactions tend to favour the carbon that is substituted.ii) Decarboxylation:It is a "chemical reaction" that removes a "CARBOXYL GROUP" in an organic compound and releases “carbon dioxide”. |
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| 31. |
Define (i) Photo–electric effect (ii) Black body radiations. |
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Answer» ectric effect:When LIGHT HITS a metal surface, an electrical potential can be generated. This is KNOWN as photoelectric effect. This concept is used to produce electricity from light energy directly. Working of solar panels is based on this concept as a source of power and also used as a light source for our homes.Blackbody RADIATION:The term black body radiation or cavity radiation denotes to an object or body that ABSORBS all radiation incidents and re-radiates energy which is the only characteristic of this radiation system, not dependent on the type of radiation that occurs. |
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| 32. |
Calcium burns in nitrogen to produce a white powder which dissolves in sufficient water to produce a gas (A) and an alkaline solution. The solution on exposure to air produces a thin solid layer of (B) on the surface. Identify the components A and B. |
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Answer» metal when burns with nitrogen to form calcium nitride along with trace of calcium oxide is also formed which further ABSORBS moisture in the water to form AMMONIA gas and alkaline solution, calcium hydroxide. Calcium hydroxide which on further exposure to air to form THIN solid SURFACE of calcium carbonateA: Ammonia gasB: Calcium hydroxideC: Calcium carbonate |
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| 33. |
Covalent bonds possess some ionic character also, explain why? |
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Answer» d formed between any two atoms is not a purely IONIC bond. All BONDING INTERACTIONS have some covalent character because the electron DENSITY remains SHARED between the atoms. ... Bonds that fall in between the two extremes, having both ionic and covalent character, are classified as polar covalent bonds. |
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| 34. |
Boron occurs in nature in the form of two isotopes and in ratio of 81% and 19% respectively. Calculate its average atomic mass. |
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Answer» ccurs naturally in two isotopic forms. The natural abundance of BORON-10 is 19.9% with 10.013 AMU and Boron-11 is 80.1% with 11.009 amu.The atomic weight of Boron is 11In ORDER to CALCULATE the average atomic weight, |
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| 35. |
Consider the reactions: Why does the same reductant, thiosulphate react differently with iodine and bromine? |
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Answer» equations, ions are REDUCING AGENTS while and are oxidizing\quad agents. oxidizes more than . A stronger oxidizing AGENT is capable of bringing about the HIGHER OXIDATION state.Therefore, and react with differently. |
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| 36. |
The enthalpy of vapourisation of liquid diethyl ether, , is 26.0 kJ at its boiling point (35.0°C). Calculate ΔS for the conversion of liquid to vapour and vapour to liquid at 35.0°C. |
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| 37. |
Give the shapes of bonding and antibonding MOs formed by combination of: (i) two s-orbitals (ii) two p-orbitals (side to side) |
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Answer» s-orbitals – It is formed when a pair of ELECTRONS is shared AMONG two s-orbitals thus by making a sigma BOND ORBITAL between them.b) two p-orbitals (side by side) – it is an orbital formed when a pair of electrons is shared between two p-orbitals thus by making a pi-bond orbital. Also, the s-s orbital and p-p orbital overlap is given in the below figure |
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| 38. |
Copper oxide was prepared by the following methods: (a) In one case, 1.75 g of the metal were dissolved in nitric acid and igniting the residual copper nitrate yielded 2.19 g of copper oxide. (b) In the second case, 1.14 g of metal dissolved in nitric acid were precipitated as copper hydroxide by adding caustic alkali solution. The precipitated copper hydroxide after washing, drying and heating yielded 1.43g of copper oxide. (c) In the third case, 1.45 g of copper when strongly heated in a current of air yielded 1.83 g of copper oxide. Show that the given data illustrate the law of constant composition. |
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Answer» he FIRST experiment2.19 g of CuO contained 1.75 g of Cu100 g of CuO ------?b) In the second experiment1.43 g of CuO contained 1.14 g of Cu100 g of CuO ------?c) In the third experiment1.83 g of CuO contained 1.45 g of Cu100 g of CuO ------?From the above three experiments, nearly same AMOUNT of COPPER oxide.Hence, the above data ILLUSTRATE the Law of constant composition. |
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| 39. |
Consider the compounds, and . How will they behave with water? Justify. |
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Answer» with water to form boric acid and it easily UNDERGOES HYDROLYSIS being a LEWIS acid.But do not undergoes hydrolysis because of lack of vacant orbital in CARBON atom. Therefore, it does not readily accept the electrons from the water to form an intermediate.If we mixed with to form TWO different layer. Therefore, these are called as immiscible liquids. |
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| 40. |
Compressibility factor, Z, of a gas is given as . (i) What is the value of Z for an ideal gas ? (ii) For real gas what will be the effect on value of Z above Boyle’s temperature ? |
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Answer» pression factor is the ratio of the molar gas volume to the IDEAL gas volume. It is the measurement of the amount of gas deviates at similar pressure and temperature from its perfect behaviour. It is an important thermodynamic property used to change the law of ideal gas to TAKE the behaviour of real gas into ACCOUNT. When the gas is CLOSER to the change in phase, the DIFFERENCE between the gas and its ideal behaviour becomes more important. (i) Z = 1 for ideal gases (ii) For real Gas, Z > 1 above Boyle's temperature. |
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| 41. |
Let the solubility of an aqueous solution of mg(oh) be x, then its k sp |
| Answer» P is 4x³.......... | |
| 42. |
What do you understand by co-ordinate covalent bond? Give one example. |
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Answer» d FORMED by the mutual sharing of one or more PAIRS pairs of ELECTRON is called covalent bond.For EXAMPLE - HCL |
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| 43. |
Contrast the action of heat on the following and explain your answer: , . |
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Answer» tion on nitrate salts Most METAL nitrates break down to produce metal OXIDE, oxygen, and NITROGEN dioxide.In the PRESENCE of heat CALCIUM nitrate produce calcium oxide.In the presence of heat sodium nitrate produce sodium nitrite. |
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| 44. |
Balance the following equation using oxidation number method: |
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Answer» quation skeletonAssign oxidation numbersIdentify the redox couplesCombine the redox couplesBalance all atoms except oxygen and hydrogenBalance the chargeBalance the oxygen atomsMaking electron GAIN EQUIVALENT to electron lostAdd the half-cell reactionsSimplify the equationFinal reaction is as FOLLOWS, |
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| 45. |
Calculate (i) wave number (ii) frequency of yellow radiation having wavelength of . |
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Answer» Yellow wavelength having radiation of 5800 λ.We know that, Frequency Where, If we APPLY the VALUES in the FORMULA then,Frequency Frequency To find WAVE number, |
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| 46. |
Beryllium exhibits some similarities with aluminium. Point out three such properties. |
| Answer» RADIUS RATIO of is same to that of , hence they both exhibit some similarities in their propertiesii) Due to the presence of oxide film, they both remain UNAFFECTED by the acid attackiii) Hydroxides of both beryllium and aluminium dissolves in excess of alkaliiv) Chlorides of both beryllium and aluminium acts as Lewis acid and both of their CHLORIDE salts dissolves in organic solventsv) The ions of both beryllium and aluminium have tendency to form complexes. | |
| 47. |
Give reasons: (i) Unlike alkali metal compounds, compounds of Li are much less soluble in water. (ii) Although Li has highest I.E. in group –1 but it is the best reducing agent. (iii) Li differs from other members of its group. (iv) LiOH, , decompose readily on heating, whereas the other alkali metal hydroxides & carbonates not decompose readily on heating. (v) Alkali & some alkaline earth metals impart colour to bunsen flame. |
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Answer» compounds of LITHIUM are covalent in nature and the other alkali metals are "ionic in nature". Hence the lithium compounds are less soluble in water ii) From its highest Ionization energy, we MAY ASSUME that lithium is the weakest reducing agent of the alkali metals, but it has a strong standard electrode potential to ACT as a reducing agent iii) Due to small size, the lithium atom has high ionization energy. Such that, it stays inactive to air without moisture, slowly reacts with water, liquid bromine and forms a highly stable hydride unlike other alkali metals. iv) Lithium nitrates, carbonates and hydroxides decomposes readily on heating because they are less stable to heat and forms oxides readily with the liberation of carbon dioxide V) Alkali and some alkaline earth metals impart color to the Bunsen flame due to their low ionization enthalpies. |
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| 48. |
Out of zinc and copper vessel, which one will be more suitable to store 1M HCl solution? |
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Answer» will be more SUITABLE as zinc is REACTIVE and will READILY react with HCL to FORM ZnCl |
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| 49. |
Give reasons: (i) Alkaline earth metal hydroxides are less basic than alkali metal hydroxides. (ii) Alkali & alkaline earth metal hydrides are ionic in nature. (iii) Group 1 elements are called alkali metals. (iv) Be resembles Al. (v) The fluorides of alkaline earth & alkali metal are relatively less soluble than chlorides. |
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Answer» alkali earth metal hydroxides are less soluble in water COMPARED to the alkali metal hydroxides. Due to the higher enthalpies, smaller IONIC size and greater lattice energy the alkaline earth metal hydroxides are less basic than alkali metal hydroxidesii) Alkali & alkaline earth metal hydrides are ionic in nature because these compounds most actively FORM bond with hydrogen to form metal hydrides. These metal hydrides are also known as saline hydrides or pseudo-halidesiii) When the group I ELEMENTS react with water they form strong alkalis. Hence the six elements are grouped.iv) Due to the similarity in size of their ions, charge and radius ratio beryllium and aluminum show similar properties and they exhibit diagonal relationship.v) The chlorides, iodides and BROMIDES of alkaline earth metals are ionic in nature and hence they are soluble in water. Due to high lattice energy and low anion size of fluorides, it is relatively less soluble compared to other halides. |
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| 50. |
Give structures of all the alkyl groups and identify them as primary, secondary, or tertiary alkyl groups. |
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Answer» ures of all alkyl groupsAlkyl group: It is a functional group that has a carbon atom BONDED with hydrogen atom with a FORMULA .Primary alkyl groupsThe carbon which is bond to only ONE carbon is called primary carbonSecondary alkyl groupsThe carbon which is bond to two carbon ATOMS is called secondary carbonTertiary alkyl groupsThe carbon which is bond to three carbon atoms is called tertiary carbon |
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