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ANSWER:

The molecular weight of glucose C

6

H

12

O

6

=6(12)+12(1)+6(16)=180 g/mol.

The number of moles of glucose =

180g/mol

0.625g

=0.00347moles

Mass of WATER =102.8g=0.1028kg

The molality of glucose m=

0.1028kg

0.00347moles

=0.0338mol/kg

The depression in the freezing point ΔT

f

=K

f

m=1.87Kkg/mol×0.0338mol/kg=0.0632K

Freezing point of water =273 K

The freezing point of the SOLUTION =273+0.0632=273.0632K

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Answer:

The VALUE of Ebullioscopic CONSTANT or BOILING point elevation constant depends on: AMOUNT of solute. nature of solute. amount of solvent.

ANSWER:

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Explanation:

Ions are FORMED when ATOMS lose or GAIN electrons in order to fulfill the octet rule and have full outer valence ELECTRON shells. When they lose electrons, they become positively charged and are named cations. When they gain electrons, they are negatively charged and are named ANIONS.

Given,

The concentration (w/w%) of COMMON salt = 10%

Mass of the solution = 200 grams

To FIND,

The concentration if 20 grams of water is added to the solution.

Solution,

Let,the mass of the solute or the common salt = x grams

[Assume, x as a VARIABLE to do the further mathematical CALCULATIONS.]

Now,we have to apply the w/w% concentration formula,

Concentration (w/w%) = 100 × Mass of solute/Mass of solution

10 = 100 × x/200

x/2 = 10

x = 20

Mass of solute = 20

Now, mass of the solution after water ADDITION = 200+20 = 220 grams

So,final concentration (w/w%) = 100 × 20/220 = 9.09%

Hence, the final concentration (w/w%) will be 9.09% or Option 3.

ANSWER:

I THINK so this is the answer

ANSWER:

true

Explanation:

CARBONDIOXIDE is made of CARBON and AIR

Answer:

Thus ,it can be used to detect the presence of moisture .

oxide which can act both as an acid and as a base is CALLED amphoteric oxides .

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Explanation:

The atomic number of an element which forms basic OXIDE is 19. The element is potassium. K2O is basic in NATURE and KOH is a strong base. Potassium is an alkali metal and all alkali metal oxides are basic in nature.

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ANSWER:

False

Explanation:

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ANSWER:

i THINK 2ND

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Explanation:

Chlorine is in group VII, the halogens - these elements are highly reactive. They have seven electrons in their valence shell so REACT readily with metals that will give up electrons to form an IONIC BOND. ... It is this ability to bind to other elements that make chlorine such a good DISINFECTANT.

ANSWER:

it is dobrenier's TRIAD (it is the LAW)

ANSWER:

the body of theory which explains the PHYSICAL properties of matter in TERMS of the motions of its constituent particles.

the kinetic theory a theory of gases POSTULATING that they consist of particles of negligible size MOVING at random and undergoing elastic collisionsIn full: the kinetic theory of gases

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The French began cultivating indigo in St Domingue in the Caribbean islands, the Portuguese in Brazil, the ENGLISH in JAMAICA, and the Spanish in Venezuela. Indigo PLANTATIONS also came up in many PARTS of NORTH America.

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ANSWER:

FREQUENCY =c/wavelength

=3×10 RAISED to 18/456×10 raised to

-9=6.57×10 raised to 24

PTFE is polymerized from the CHEMICAL COMPOUND TETRAFLUOROETHYLENE, or TFE.

ANSWER:

Explanation:

Saturated SOLUTION:

A solution that cannot dissolve any more quantity of solute in a GIVEN amount of solvent at a given temperature.

The saturated solution can also be made UNSATURATED by adding more solvent to it.

Unsaturated Solution:

The solution in which more solute can be added at given temperature is an unsaturated solution.

Supersaturated Solution:

A solution that contains more of the solute than what is present in its saturated solution at a PARTICULAR temperature.

Answer:

GRAHAMS LAW:

Rate of diffusion or EFFUSION of a gas at given CONDITIONS inversely proportional to the root of molecular mass & gas.

r

1

/r

2

=

M

2

/M

1

r

CH

4

r

He

=

M

He

M

CH

4

=

4

16

=2

Answer:

Here is your answer

EXPLANATION:

Halogens

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ANSWER:

CHAMAN........

EXPLANATION:

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Explanation:

The main differences between these molecules' IR spectra are in the

O

H

stretches and in the

C

=

O

stretches.

While the alcohol

O

H

stretch is broader, the carboxylic

O

H

stretch is less broad. While the aldehyde

C

=

O

stretch is SHARP and "well-defined", the carboxylic

C

=

O

stretch is broader and more "smeared".

COMPARING THE STRUCTURES

Follow the structural formulas from left to right to determine that the structures are:

Notice how the functional groups are CLEARLY different; the left compound has an alcohol hydroxyl and an aldehyde carbonyl group, while the right compound has a carboxylic hydroxyl and a carboxylic carbonyl group.

SIGNIFICANT VIBRATIONAL MOTIONS

To break it down further, consider the WAYS these compounds can stretch and bend.

It's a good rule of thumb to assume that single bonds can stretch and bend, and double bonds can stretch, but don't bend very well. Also, as an aside, alcohol bends aren't really necessary to consider because their stretches are so distinctive.

Here's what I see. I've bolded the unique motions, and put the frequencies in wavenumbers (Techniques in Organic Chemistry, Mohrig).

3-hydroxypropanal -

s

p

3

C

−

H

bend (alkane) ---

1480

~

1430

and

1395

~

1340 cm

−

1

; medium to weak; sharp

s

p

3

C

−

H

stretch (alkane) ---

2990

~

2850 cm

−

1

; medium to strong; sharp

C

=

O

stretch (aldehyde) ---

1740

~

1720

(saturated) and

1715

~

1680 cm

−

1

(conjugated); medium; sharp

C

−

H

stretch (aldehyde) ---

2900

~

2800

and

2800

~

2700 cm

−

1

; weak; sharp Fermi doublet

C

−

O

stretch (alcohol) ---

1300

~

1000 cm

−

1

; strong; sharp

O

−

H

stretch (alcohol) ---

3650

~

3550

and

3550

~

3200 cm

−

1

; medium to strong; broad

propanoic acid -

s

p

3

C

−

H

bend (alkane) ---

1480

~

1430

and

1395

~

1340 cm

−

1

; medium to weak; sharp

s

p

3

C

−

H

stretch (alkane) ---

2990

~

2850 cm

−

1

; medium to strong; sharp

C

=

O

stretch (carboxylic acid) ---

1725

~

1700

(saturated) and

1715

~

1680 cm

−

1

(conjugated); strong; sharp

C

−

O

stretch (carboxylic acid) ---

1300

~

1000 cm

−

1

; strong; sharp

O

−

H

stretch (carboxylic acid) ---

3200

~

2500 cm

−

1

; medium to weak; broad

You should eventually see that the significant differences in the frequencies given above are:

The carboxylic

C

=

O

stretch is generally stronger, slightly more upfield, and broader.

The carboxylic

C

=

O

stretch is less broad (spans a smaller range of frequencies near

3000 cm

−

1

)

ANSWER:

nosnjsjdjdjsj

Explanation:

mssjdkmjdkdkdkfk

GIVEN EQUATION is a BALANCED equation. No NEED to BALANCE again.

ANSWER:

Chemical equation between CO2 gas and bleaching POWDER:

CaOCl2 + CO2 = CaCO3 + Cl2

When exposed to air, bleaching powder gives a smell of CHLORINE. This is because bleaching powder REACTS with carbon dioxide from the atmosphere to produce calcium carbonate and chlorine.

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Answer:

7.95 G

=> 123.5 g of COPPER carbonate gives 79.5 g of copper oxide. Therefore, 12.35 g of copper carbonate will give 7.95 g of copper oxide.

ANSWER:

because they have atomic NUMBER less

EX Ne - 0 VALENCY

ANSWER:

ur AGE is 11

Explanation:

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ANSWER:

DEAR,what is your QUESTION

ANSWER:

Bill gates

Explanation:

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Answer:

to KYA kare humlog 2 GM HAI to

ANSWER:

• answer is the PART B. MARK as BRAINLIST

Answer:

7periods

Explanation:

All elements of period 7 are RADIOACTIVE. This period CONTAINS the actinides, which includes plutonium, the NATURALLY occurring element with the HEAVIEST NUCLEUS; subsequent elements must be created artificially

Answer:

As in ozonolysis double BOND between C and C BREAKS and the double bond between C & O forms. So product obtained after hydrolysis will be MIXTURE of CH

3

CHO, HCHO & CO

2

ANSWER:

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EXPLANATION:

PROUDLY ketosteroid Pepsi SLEEP type THOROUGHLY and I will be in the same as

ANSWER:

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Answer:

It should have a high calorific value and a moderate rate of combustion.

It should not produce any HARMFUL products on burning.

It should CAUSE minimum AIR pollution.

It should be cheap and READILY available.

It should be easy to store, transport and HANDLE.

ANSWER:

option ( A ). the ELEMENTS formed by ACIDIC oxide is lithium

I think you GOT the answer

Explanation:

a) Acidic in nature

b) DISSOCIATION of CARBON dioxide

ANSWER:

Answer. TOTAL VOLUME of SOLUTION = 5.6+75 = 80.6 ML.

Answer:

16.67

Explanation:

PERCENTAGE of SALT in mixture= amount of salt/ Total amount of the SOLUTION * 100

= 5/30 *100

=1/6*100

= 16.67%

Hence, 30 grams of the solution has 16.67% of salt which is 5 grams

Explanation:

• REACTION Information

Smithsonite = Zinc Oxide + Carbon Dioxide

• Reactants

Smithsonite - ZnCO3

ZnCO3 -Zinc Carbonate

Density- ‎3.5 g/cm3

Molecular Weight/ Molar Mass -125.38 g/mol

Stability -Stable but INCOMPATIBLE with acids

Boiling POINT- 333.6 °C at 760 mmHg

Melting Point- ~1970 °C

Chemical Formula -CO3Zn

ZnCO3————> ZnO+ CO2- decomposition

reaction

Answer:

Let us try to separate ACETONE and water from their mixture. ... Heat the mixture slowly keeping a close watch at the thermometer. The acetone vaporizes, condenses in the condenser and can be COLLECTED from the condenser OUTLET. Water is LEFT behind in the distillation flask.

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Explanation:

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Answer:

the weight of solution FORMED is

10+90=100g

in 100 g solution 5 g urea PRESENT

mass PRECENT of urea=5/100×100

=5

therefore 5% urea present in solution

ANSWER:

SULPHUR, Argon and Chlorine.

EXPLANATION:

Elements are :

Sulphur,Argon and Chlorine

Answer:

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EXPLANATION:

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