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A neutralization reaction is when an ACID and a base react to form water and a salt and involves the combination of H+ IONS and OH- ions to GENERATE water. The neutralization of a strong acid and strong base has a pH EQUAL to 7.

Answer:

ATOMIC WT. is 28.05

valency is 4

Explanation:

now for 1gm of the chloride Cl is of 0.835gm which is of 83.5% of the weight then the metal would be (100-83.5)%=16.5% THEREFORE the atomic wt of the metal would be the same 16.5% of the chloride's molecular weight .

hence the molecular weight of the metal is 16.5% of 170amu which is 28.05amu which is NOTHING but the element "Silicon." whose valency is 4

Answer:

as gas PARTICLES are FREE and move freely when it kept in WALL of container then gas particle START moving here and there due to that movement gas particle hit wall of container and exert a pressure

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this my first answer of this app

ANSWER:

RESPIRATION in PLANTS

M. No... 24

A.no.....12

Explanation:

ANSWER:

this is a SUSPENSION of SOLID+GAS

ANSWER:

CH4 is the FORMULA of METHANE

Answer:

In all other aldehydes, the carbonyl GROUP is bonded to one hydrogen and one carbon group. In CONDENSED structural formulas, the carbonyl group of an aldehyde is commonly represented as ―CHO. Using this convention, the formula of FORMALDEHYDE is HCHO and that of ACETALDEHYDE is CH3CHO

Explanation:

ANSWER:

Here, is your above answer.

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Answer:

Sorry There was is the MAIN 1 on your QUESTION BACK to in

Answer:

This is because on HEATING copper it reacts with the atmospheric oxygen to FORM a coating of copper oxide (CuO) which is black in COLOR ( the REACTION is oxidation)

2Cu + O2 ------heating-------> 2CuO

(black coloured)

Explanation:

A saturated compound is a CHEMICAL compoundthat has a chain of carbon atoms linked together by single bonds and has hydrogen atoms FILLING all of the other bonding ORBITALS of the carbon atoms.

An unsaturatedcompound is a chemical compound that contains carbon-carbon DOUBLE bonds or TRIPLE bonds

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<P>Answer:

Pnictogens- Group 15 (VA) The pnictogen group, or nitrogen group, is located in column 15 of the periodic table. This family consists of the ELEMENTS nitrogen, PHOSPHORUS, arsenic, antimony, bismuth, and ununpentium (N, P, As, Sb, BI, and Uup, respectively). Each member of this family contains five valence electrons.

Explanation:

Answer:

A homogeneous mixture is a solid, liquid, or gaseous mixture that has the same proportions of its components throughout any given sample. CONVERSELY, a heterogeneous mixture has components whose proportions vary throughout the sample. "Homogeneous" and "heterogeneous" are not absolute terms but depend on context and the size of the sample. In chemistry, a homogeneous suspension of material means that when DIVIDING the VOLUME in half, the same AMOUNT of material is suspended in both halves of the substance; however, it might be possible to see the particles under a microscope. An EXAMPLE of a homogeneous mixture is air

A MOLE ratio is the ratio between the AMOUNTS in moles of any two compounds involved in a chemical reaction. Mole ratios are used as conversion factors between PRODUCTS and REACTANTS in MANY chemistry problems.

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Answer:

The RATE of EVAPORATION is affected by the following factors:

1. Temperature:

The rate of evaporation increases with an INCREASE in temperature.

2.Surface area:

The rate of evaporation increases with an increase in surface area.

3.Humidity:

The amount of water vapour PRESENT in the AIR is called humidity

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ANSWER:

EXPLANATION: Fiber X is Jute. it is used as it is strong and can TAKE heavy load

Fiber y is linin

Answer:

Explanation:

Let the ELEMENT be “X”

CASE 1:

Valency of X= +3

Valency of Oxide “O”= -2

Therefore, the FORMULA for the oxides of the element X= X2O3

Case 2:

Valency of X= +5

Valency of O= -2

Therefore, the formula for the oxides of the element X= X2O5

ANSWER:

a

Explanation:

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Answer:

125 m is the REQUIRED WAVELENGTH

Explanation:

SEPARATION of CREAMS from milk is DONE by centrifugation

W = (A X I X t) ÷ n x 96500

1.27 = (63.5 x 2 x t) ÷ 2 x 96500

t = (1.27 x 2 x 96500) ÷ (2 x 63.5) = 1930 SECONDS

Answer:

The centers of the matrix groups U(n) and SU(n)

This note proves an assertion in the hints for one of the Additional Exercises for Chapter 7.

THEOREM. Let U(n) be the group of unitary n×n MATRICES (the entries are complex numbers,

and the inverse is the conjugate of the transpose), and let SU(n) be the kernel of the determinant

homomorphism U(n) → C − {0}. Then the centers of both subgroups are the matrices of the form

cI, where (as usual) I denotes the identity matrix and |c | = 1. In particular, the CENTER of SU(n)

is a finite cyclic group of order n.

The argument relies heavily on the Spectral Theorem, which implies that for every unitary

matrix A there is a unitary matrix P such that PAP −1

is diagonal.

Proof. We shall first prove the result for U(n). If A lies in the center then for each unitary

matrix P we have A = PAP −1

. SINCE the Spectral Theorem implies that some matrix PAP −1

is diagonal, it follows that A must be diagonal. We claim that all the diagonal entries of A must

be equal. Suppose that aj,j 6= ak,k. If P is the matrix formed by interchanging the j

th and k

th

columns of the identity matrix, then P is a unitary matrix and B = PAP −1

is a diagonal matrix

with aj,j = bk,k and bj,j = ak,k. But this means that A does not lie in the center of U(n). Therefore

the only matrices which can lie in the center of U(n) have the form cI, and since we are working

with unitary matrices it follows that |c | must be 1.

We now turn to the case of SU(n). If D ⊂ U(n) is the subgroup of diagonal matrices, then

of course D is central and we have U(n) = D · SU(n); in other words, every unitary matrix is the

product of a matrix in SU(n) and a diagonal matrix. Suppose now that A ∈ SU(n) lies in the

center of SU(n); then the observations in the preceding sentence imply that A lies in the center of

U(n), so it follows that the center of SU(n) is equal to D ∩ SU(n). Therefore the determination of

the center reduces to specifying which diagonal matrices cI (where |c | = 1) have determinant equal

to 1. But the determinant of cI is c

n, so the center consists of all matrices cI such that c

n = 1;

i.e., the center consists of all matrices cI such that c is a complex n

th root of 1. Since the set of all

such matrices is isomorphic to Zn, we see that the center of SU(n) is a cyclic group of order n.

Explanation:

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Answer:

NA2CO3 + H2SO4 -> NA2SO4 + H2O + CO2 (gas)

Answer:

Yes, just consider the example of most nitrates and explosive compounds in general. After melting (endothermal) and SOMETIMES phase CHANGES (also endothermal), decomposition occurs and is very EXOTHERMIC.

This may occur each time the resultant compounds after decomposition are more stable than the INITIAL compound.

If your TG ios carried out in air, it can also be a rapid oxidation (like burning) of your sample, indeed PRODUCING both exothermic peak and mass loss.

ANSWER:

EXPLANATION:

The number of ions present in 5.85 G of SODIUM CHLORIDE.

Answer:

Explanation:

The steam molecules are at 100°C which have more energy than liquid WATER at 100°C because "latent heat of vaporization" is added to liquid molecules for the CONVERSION to VAPOR STATE. Overall the particles of steam have HIGHER energy than the molecules of liquid water due to "latent heat of vaporization".

Answer:

In this REACTION sodium loses ONE electron so it BECOMES Na+ and ACTS as an oxidizing agent. Chlorine gains one electron so it becomes Cl- and this chlorine acts as a reducing agent.

Answer:

Five nitrogenous bases are found in nucleic acids (Fig. 4); adenine (A), guanine (G), and cytosine (C) are in both DNA and RNA, WHEREAS thymine (T) is almost exclusively found in DNA, and uracil (U) almost exclusively in RN A. DNA and RNA are quantified by their absorption of UV light at 260 nm.

Answer:

1. Saturated solution-

depend upon the amount of solute present in solvent, it is called dilute concentration for a saturated solution

2. PURE substance-

pure substance it means that all the when particle of the substance are the same in chemical teacher .it is present in fixed proportion

3. colloid-

soil is a HETEROGENEOUS mixture but it appears as homogeneous, it cannot be seen by nacked eyes do not SETTLE down

4. suspension-

it is a heterogeneous mixture in which solute particles do not dissolve it can be classified by naked eyes settle down when kept undisturbed

Q5）soda water,air,vinegar, filtered tea =homogeneous

wood,soil=heterogeneous

Q6） water is a pure liquide because it propertion of molecule is everytime fixed

Q7） ice,iron,hydrochloric acid,CALCIUM oxide, murcury =pure substance

milk,brick,wood,air=impure substance

Answer:

directly proportional

Explanation:

if PRESSURE increase, volume decrease (according to boyles LAW)

decreased in volume cause increase in density(according to formula; d=m/v)

so in this WAY pressure INCREASES, density also increases....

also,

density= PM/RT

P_pressure

M_molecular mass

R_general gas CONSTANT

T_absolute temperature

Answer:

Explanation:

The LAW of reciprocal proportions was proposed by Jeremias Ritcher in 1792. It states that, "If two different elements combine separately with the same WEIGHT of a third element, the ratio of the masses in which they do so are either the same or a simple MULTIPLE of the MASS ratio in which they combine."

Answer:

BHAI me TERI class me NAHI HO gand me loada aayeaga

ANSWER:

they are SOUR in TASTE.....................

ANSWER:

Na²CO³+2HCl=2NaCl+H²CO³

Answer:

1. Calcium CARBONATE- CaCO₃

2. Calcium OXIDE- CaO

3. Zinc carbonate- ZnCO₃

4. Zinc oxide- ZnO

5. Lead oxide- PbO

Explanation:

Answer:

the law

of cloths

Silk/cotton fabric is a blend of both fibers, combining POSITIVE characteristics of each into a SINGLE textile. A lightweight, silky and comfortable weave, silk cotton fabric has a soft hand-feel and a STURDY, silken drape, along with a versatility that makes it suitable for an extended variety of garment USES.

ANSWER:

due to dipole MOMENT.

Explanation:

HALOALKANES has more dipole moment than chlorobenzene ...

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Answer:

When we HEAT the MILK at a CERTAIN TEMPERATURE then cream in the milk becomes up and it is separated EASILY.

When electrons are gained by ELEMENTS then it is SAID to be oxidation.

When elements LOSS the electrons then it is said to be reduction.

ANSWER:

Oxidation no. of OXYGEN in normal oxide is generally taken -2, in peroxide it is taken -1 and in SUPEROXIDE it is taken as -0.5

Explanation:

Answer:

Substance X is COPPER.

Substance Y is copper oxide.

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Answer:

1 MOLE of CALCIUM CARBONATE

Answer:

We can SOLVE this PROBLEM by USING the Ideal Gas LAW

how can u say magnesium has small atomic size?

Sodium has 11 protons and electrons, while magnesium has 12.

• This RESULTS in a higher Z EFFECTIVE of the protons of Mg than of NA.

ANSWER: 300 ml

Explanation:

The SI UNITS of WAVE NUMBER is?

=> m2

Total suspended solids (TSS) is that portion of the Total Solids that are retained on a no-ash glass fiber filter disc of approximately 0.45 mm pore size. The wetted and weighed filter disc is placed in a filtering apparatus and a suction is applied A measured VOLUME of wastewater is passed through the filter. The filter containing the residue is then dried in an oven for one hour at 103 to 105°C. The sample is then COOLED and weighed. The difference in weight of the dry filter before and after solids are passed through is the TSS MILLIGRAMS (mg) of suspended solids per liter (l) of wastewater filtered Suspended Solids Filtering Apparatus

This inexpensive TSS test TELLS much about the wastewater character and can be run in less than two hours with fairly inexpensive equipment. The TSS test indicates whether it is likely that solids suspended in a wastewater can be removed by settling, floating or filtering. In order to remove all solids that were removed in the TSS Test, a filter similar to the TSS Filter paper (0.45 mm) must be used in full scale.

Total Dissolved Solids. The total dissolved solids (TDS) are the solids in the filtrate from the TSS test. The liquid which passes through the TSS filter is collected in a weighed dish and evaporated for an hour at 180°C ± 2°C. The dish is then re-weighed with the TDS equaling the difference between the dish weight before and after FILLING with filtrate and drying, in mg per liter of filtrate.Again, this inexpensive test can be run in less than two hours and will indicate the chemical or biological solids in a wastewater which cannot be removed through settling, floating or filtration.

Answer:

A 20.8G I THINK this is RIGHT and I am not sure please CHECK in GOOGLE