Calculate the time to deposit 1.27g of copper at cathode when a curren

1.	Calculate the time to deposit 1.27g of copper at cathode when a current of 2A was passed through the solution of cuso4
Answer» W = (A X I X t) ÷ n x 96500 1.27 = (63.5 x 2 x t) ÷ 2 x 96500 t = (1.27 x 2 x 96500) ÷ (2 x 63.5) = 1930 SECONDS

Calculate the time to deposit 1.27g of copper at cathode when a current of 2A was passed through the solution of cuso4

Answer»

W = (A X I X t) ÷ n x 96500

1.27 = (63.5 x 2 x t) ÷ 2 x 96500

t = (1.27 x 2 x 96500) ÷ (2 x 63.5) = 1930 SECONDS