52639 + Interview Questions in Secondary School in Chemistry

1.	Write electronic configuration of holmium (Z=67) what is it's stable oxidation state
Answer» ONG>ANSWER: fghxfxyjhtxyfm Explanation: ergryhxrsgXytkc

1.

Write electronic configuration of holmium (Z=67) what is it's stable oxidation state

Answer» ONG>ANSWER:

fghxfxyjhtxyfm

Explanation:

ergryhxrsgXytkc

Discussion

2.	Write the distribution of electrons and schematic atomic structure of carbon atom.
Answer» ong>Answer: The ATOMIC number of carbon is 6. The electronic configuration of carbon is C(Z = 6) = 1S2 2S2 2p2 The distribution of electrons in the carbon atom is as follows: In the first orbit or K-shell = 2 electrons In the SECOND orbit or L-shell = 4 electrons Or, we can write the distribution of electrons in a carbon atom as 2, 4.

2.

Write the distribution of electrons and schematic atomic structure of carbon atom.

Answer»

ong>Answer:

The ATOMIC number of carbon is 6. The electronic configuration of carbon is

C(Z = 6) = 1S2 2S2 2p2

The distribution of electrons in the carbon atom is as follows:

In the first orbit or K-shell = 2 electrons

In the SECOND orbit or L-shell = 4 electrons

Or, we can write the distribution of electrons in a carbon atom as 2, 4.

Discussion

3.	) A solution has 50g of salt in 320g of water. Calculate the mass percent of the salt in the solution. ii) Name any one Metalloid. iii) What type of change is cutting of wood.
Answer» ong>Answer: 2)- silicon 3)- the burning of WOOD lead to the FORMATION of new substance like ash (carbon),carbon DIOXIDE gas, water vapour, heat and light. This changes is irreversible and hence a chemical change. while CUTTING wood into smaller pieces is a physical change in the original composition of wood

3.

) A solution has 50g of salt in 320g of water. Calculate the mass percent of the salt in the solution. ii) Name any one Metalloid. iii) What type of change is cutting of wood.

Answer»

ong>Answer:

2)- silicon

3)- the burning of WOOD lead to the FORMATION of new substance like ash (carbon),carbon DIOXIDE gas, water vapour, heat and light. This changes is irreversible and hence a chemical change. while CUTTING wood into smaller pieces is a physical change in the original composition of wood

Discussion

4.	When Magnesium ribbon is burnt in air, write any two observations and name the type of the reaction.
Answer» ong>Answer: when the ribbon is burnt it burns with a brilliant white FLAME and also FORMS MAGNESIUM OXIDE magnesium plus OXYGEN forms magnesium oxide

4.

When Magnesium ribbon is burnt in air, write any two observations and name the type of the reaction.

Answer»

ong>Answer:

when the ribbon is burnt it burns with a brilliant white FLAME and also FORMS MAGNESIUM OXIDE

magnesium plus OXYGEN forms magnesium oxide

Discussion

5.	How many electrons can be accommodated in n=3 shell in Bohr model of atom.
Answer» ong>ANSWER: 18 ELECTRONS can be accommodated in n=3 shell (M-shell) in BOHR ATOMIC model Explanation: Do mark as Brainliest answer

5.

How many electrons can be accommodated in n=3 shell in Bohr model of atom.

Answer»

ong>ANSWER:

18 ELECTRONS can be accommodated in n=3 shell (M-shell) in BOHR ATOMIC model

Explanation:

Do mark as Brainliest answer

Discussion

6.	Define atomic mass unit.
Answer» ONG>Answer: a unit of mass used to express atomic and molecular WEIGHTS, equal to ONE TWELFTH of the mass of an atom of carbon-12.

6.

Define atomic mass unit.

Answer» ONG>Answer:

a unit of mass used to express atomic and molecular WEIGHTS, equal to ONE TWELFTH of the mass of an atom of carbon-12.

Discussion

7.	0. Define and explain normality with mathematical expression. Calculate the normality of 500 ml of solution containing5.3 gm of Na2CO3.
Answer» ong>Explanation: Molecular mass of Na 2 CO 3 =106 gmol −1 ∴ NUMBER of moles = 106 53 =0.05mol As 0.05 mol are dissolved in 500mL; Number of moles dissolved in 1000ML (1L) or molarity of TH solution = 500 0.05 ×1000=0.1M.

7.

0. Define and explain normality with mathematical expression. Calculate the normality of 500 ml of solution containing5.3 gm of Na2CO3.

Answer»

ong>Explanation:

Molecular mass of Na

2

CO

3

=106 gmol

−1

∴ NUMBER of moles =

106

53

=0.05mol

As 0.05 mol are dissolved in 500mL;

Number of moles dissolved in 1000ML (1L) or molarity of TH solution

=

500

0.05

×1000=0.1M.

Discussion

8.	धातु अधाते मे अंतर लिखिए
Answer» ong>Explanation: metal are HARD and non-metal is generally not hard. ( it is MAIN difference between metal and non-metal )

8.

धातु अधाते मे अंतर लिखिए

Answer»

ong>Explanation:

metal are HARD and non-metal is generally not hard.

( it is MAIN difference between metal and non-metal )

Discussion

9.	How many electrons can be accommodated in n=3 shell in bhor model of atom
Answer» ONG>Answer: 18 Explanation: PLEASE MARK as BRAINLIEST

9.

How many electrons can be accommodated in n=3 shell in bhor model of atom

Answer» ONG>Answer:

18

Explanation:

PLEASE MARK as BRAINLIEST

Discussion

10.	धातु अहाते मे अंतर लिखिए
Answer» . अधातु सभी धातू चामकीली होती है धातू कठोर होती है आधतु

10.

धातु अहाते मे अंतर लिखिए

Answer»

. अधातु

सभी धातू चामकीली होती है

धातू कठोर होती है आधतु

Discussion

11.	.We can identify the leackageof gas in our home.How can we explain this on the basis of diffusion.
Answer» ONG>Answer: by smell Explanation: pls MARK as BRILLIANT

11.

.We can identify the leackageof gas in our home.How can we explain this on the basis of diffusion.

Answer» ONG>Answer:

by smell

Explanation:

pls MARK as BRILLIANT

Discussion

12.	Ωнαт is Noun. Types of noun? plz give correct ans
Answer» N:- Noun is a word that FUNCTIONS as the name of a specific object or set of OBJECTS, such as living creatures, places, actions, qualities, states of existence, or ideas. Different types of noun are :- Common noun Proper noun Abstract noun Collective noun Countable Noun Non-countable Noun

12.

Ωнαт is Noun. Types of noun? plz give correct ans

Answer» N:-

Noun is a word that FUNCTIONS as the name of a specific object or set of OBJECTS, such as living creatures, places, actions, qualities, states of existence, or ideas.

Different types of noun are :-

Common noun
Proper noun
Abstract noun
Collective noun
Countable Noun
Non-countable Noun

Discussion

13.	Answer the 3,4,5,6,7,8 question
Answer» ong>Answer: 3. OPTION c 4. option c CaCO3 5. option c 6. option B 7. option c 8. option b

13.

Answer the 3,4,5,6,7,8 question

Answer»

ong>Answer:

3. OPTION c

4. option c CaCO3

5. option c

6. option B

7. option c

8. option b

Discussion

14.	Write the names of the following compounds.COCO2HBrSO2PCl3PCl5NO2
Answer» ONG>ANSWER: CO=carbon monoxide HBr=hydrogen bromide SO2= Sulphur DIOXIDE PCL3=Phrosphorus trichloride PCL5= Phrosphorus pentachloride NO2=nitrogen dioxide

14.

Write the names of the following compounds.COCO2HBrSO2PCl3PCl5NO2

Answer» ONG>ANSWER:

CO=carbon monoxide

HBr=hydrogen bromide

SO2= Sulphur DIOXIDE

PCL3=Phrosphorus trichloride

PCL5= Phrosphorus pentachloride

NO2=nitrogen dioxide

Discussion

15.	What is the necessity of formation of a chemical bond
Answer» ong>ANSWER: chemical bond is a lasting attraction between ATOMS, ions or molecules that ENABLES the formation of chemical compounds. The bond MAY result from the electrostatic FORCE of attraction between oppositely charged ions as in ionic bonds or through the sharing of electrons as in covalent bonds.

15.

What is the necessity of formation of a chemical bond

Answer»

ong>ANSWER:

chemical bond is a lasting attraction between ATOMS, ions or molecules that ENABLES the formation of chemical compounds. The bond MAY result from the electrostatic FORCE of attraction between oppositely charged ions as in ionic bonds or through the sharing of electrons as in covalent bonds.

Discussion

16.	* H C,H, 11IUPAC name of CH, -C-C-CH,1 1CH CH(a)(b)(c)3,4,4-tri methyl heptane2-ethyl-3,3-di methyl heptane3,4,4-tri methyl octane2-butyl-2-methyl-3-ethyl Butane7813/SCHJC11
Answer» ong>Answer: Answer: Answer: $\huge \bold \blue{Answer࿐}$ Width of rectangle is 25 cm. Step-by-step explanation: Given :- A wire bend in form of SQUARE of side 30 cm. Then wire is again bend in form of rectangle of length 35 cm. To FIND :- Width of the rectangle. Solution :- Here, Concept is : If we are bending wire in form of square than again bending it in rectangle. Than, perimeter of square will equal to perimeter of rectangle because we are not increasing length of wire by one measure we are bending it in square and RECTANGULAR shape. So, Perimeter of square = 4 × side ⟶ Perimeter = 4 × 30 ⟶ Perimeter = 120 Thus, Perimeter of square is 120 cm. According to concept, Perimeter of square and perimeter of rectangle are equal. So, Perimeter of rectangle is 120 cm. Let, BREADTH or width or rectangle be X cm. We know, Perimeter of rectangle = 2(Length + Breadth) ⟶ 120 = 2×(35 + x) ⟶ 120 = 70 + 2x \⟶ 120 - 70 = 2x ⟶ 50 = 2x ⟶ 50/2 = x ⟶ x = 25 We take, Width of rectangle be x. Therefore, Width of rectangle is 25 cm.

16.

* H C,H, 11IUPAC name of CH, -C-C-CH,1 1CH CH(a)(b)(c)3,4,4-tri methyl heptane2-ethyl-3,3-di methyl heptane3,4,4-tri methyl octane2-butyl-2-methyl-3-ethyl Butane7813/SCHJC11

Answer»

ong>Answer:

Answer:

$\huge \bold \blue{Answer࿐}$

Width of rectangle is 25 cm.

Step-by-step explanation:

Given :-

A wire bend in form of SQUARE of side 30 cm.

Then wire is again bend in form of rectangle of length 35 cm.

To FIND :-

Width of the rectangle.

Solution :-

Here, Concept is : If we are bending wire in form of square than again bending it in rectangle. Than, perimeter of square will equal to perimeter of rectangle because we are not increasing length of wire by one measure we are bending it in square and RECTANGULAR shape.

So,

Perimeter of square = 4 × side

⟶ Perimeter = 4 × 30

⟶ Perimeter = 120

Thus,

Perimeter of square is 120 cm.

According to concept, Perimeter of square and perimeter of rectangle are equal.

So, Perimeter of rectangle is 120 cm.

Let, BREADTH or width or rectangle be X cm.

We know,

Perimeter of rectangle = 2(Length + Breadth)

⟶ 120 = 2×(35 + x)

⟶ 120 = 70 + 2x

\⟶ 120 - 70 = 2x

⟶ 50 = 2x

⟶ 50/2 = x

⟶ x = 25

We take, Width of rectangle be x.

Therefore,

Width of rectangle is 25 cm.

Discussion

17.	सामान्य दाब पर एक पदार्थ का क्वानोक कमीके ताप से कम बिताएँ कि पशि की भौतिक अवस्थाकमा
Answer» align="ABSMIDDLE" alt="\huge\bold{\mathtt{\purple{A{\pink{ N{\green{S{\blue{W{\RED{E{\orange{R }}}}}}}}}}}}}" class="latex-formula" id="TexFormula1" SRC="https://tex.z-dn.net/?f=%5Chuge%5Cbold%7B%5Cmathtt%7B%5Cpurple%7BA%7B%5Cpink%7B%20N%7B%5Cgreen%7BS%7B%5Cblue%7BW%7B%5Cred%7BE%7B%5Corange%7BR%20%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D" title="\huge\bold{\mathtt{\purple{A{\pink{ N{\green{S{\blue{W{\red{E{\orange{R }}}}}}}}}}}}}">... एक निश्चित तापमान पर विलायक की एक ज्ञात मात्रा में घुलने वाली अधिकतम मात्रा इसकी घुलनशीलता है। एक ठोस की विलेयता बढ़ती तापमान के साथ आम तौर पर बढ़ जाती है।ग्लूकोज नाटकीय जैसे कई यौगिक बढ़ते तापमान के साथ इसकी घुलनशीलता बढ़ाते हैं। बाहरी दबाव का तरल पदार्थ और ठोस पदार्थों की घुलनशीलता पर बहुत कम प्रभाव पड़ता है। इसके विपरीत, गैसों की घुलनशीलता बढ़ जाती है क्योंकि एक समाधान से ऊपर गैस का आंशिक दबाव बढ़ जाता है 100% correct answer Hope it's helpful ✌️✌️ $\huge\color{red}\boxed{\colorbox{black}{please\:mark\:me\: brilliance}}$ $\huge\underline\purple{\underline {Follow\:Me}}$

17.

सामान्य दाब पर एक पदार्थ का क्वानोक कमीके ताप से कम बिताएँ कि पशि की भौतिक अवस्थाकमा

Answer»

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एक निश्चित तापमान पर विलायक की एक ज्ञात मात्रा में घुलने वाली अधिकतम मात्रा इसकी घुलनशीलता है।

एक ठोस की विलेयता बढ़ती तापमान के साथ आम तौर पर बढ़ जाती है।ग्लूकोज नाटकीय जैसे कई यौगिक बढ़ते तापमान के साथ इसकी घुलनशीलता बढ़ाते हैं।

बाहरी दबाव का तरल पदार्थ और ठोस पदार्थों की घुलनशीलता पर बहुत कम प्रभाव पड़ता है। इसके विपरीत, गैसों की घुलनशीलता बढ़ जाती है क्योंकि एक समाधान से ऊपर गैस का आंशिक

दबाव बढ़ जाता है

100% correct answer

Hope it's helpful ✌️✌️

$\huge\color{red}\boxed{\colorbox{black}{please\:mark\:me\: brilliance}}$

$\huge\underline\purple{\underline {Follow\:Me}}$

Discussion

18.	Which one of the following compound has the highest boiling point
Answer» ONG>EXPLANATION: ETHANOL is your ANSWER

Discussion

19.	Do the following with full steps
Answer» ong>Answer: H2SO4 + 2KOH = K2SO4 + 2H2O H2SO4 = SULPHURIC acid KOH = POTASSIUM hydroxide K2SO4 = Potassium SULPHATE

19.

Do the following with full steps

Answer»

ong>Answer:

H2SO4 + 2KOH = K2SO4 + 2H2O

H2SO4 = SULPHURIC acid

KOH = POTASSIUM hydroxide

K2SO4 = Potassium SULPHATE

Discussion

20.	explain with vapor pressure- temperature curves that the freezing point of solvent is lowered by dissolving a non volatile solute in to it give reason for such lowering of freezing of solvent
Answer» ONG>Answer: THUS, the separation of solvent MOLECULES in solution is more than that in pure solvent. Explanation: This results in decreasing the attractive forces between solvent molecules. Consequently, the temperature of the solution is lowered below the freezing point of the solvent to cause the phase change

20.

explain with vapor pressure- temperature curves that the freezing point of solvent is lowered by dissolving a non volatile solute in to it give reason for such lowering of freezing of solvent

Answer» ONG>Answer:

THUS, the separation of solvent MOLECULES in solution is more than that in pure solvent.

Explanation:

This results in decreasing the attractive forces between solvent molecules. Consequently, the temperature of the solution is lowered below the freezing point of the solvent to cause the phase change

Discussion

21.	Name the triangle whose sides are ABC-20° BCD-30° & CAB-10°. Refer to the following attachment..dont spam
Answer» align="ABSMIDDLE" ALT="\Huge{\mathscr{\fcolorbox {navy}{orange}{\color {darkblue}{Hlw!!}}}}" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%5CHuge%7B%5Cmathscr%7B%5Cfcolorbox%20%7Bnavy%7D%7Borange%7D%7B%5Ccolor%20%7Bdarkblue%7D%7BHlw%21%21%7D%7D%7D%7D" TITLE="\Huge{\mathscr{\fcolorbox {navy}{orange}{\color {darkblue}{Hlw!!}}}}"> scalene TRIANGLE as none of the sides are EQUAL..

21.

Name the triangle whose sides are ABC-20° BCD-30° & CAB-10°. Refer to the following attachment..dont spam

Answer»

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scalene TRIANGLE as none of the sides are EQUAL..

Discussion

22.	Hii guys I am new here can u explain how to work
Answer» ONG>ANSWER: hdlydoydoydpyd95e96r96r96r96do6dp6d

Discussion

23.	What is the molar mass of solute if a solution prepared by dissolving 0.822 g of it in 0.3 dm3 of water has an osmotic pressure of 149 mm Hg at 298 k
Answer» ONG>ANSWER: Identify the type of motion from the FOLLOWING. (A) CAR is not in motion (B) car is moving with uniform velocity (C) car is moving with uniform acceleration (D)None of the above

23.

What is the molar mass of solute if a solution prepared by dissolving 0.822 g of it in 0.3 dm3 of water has an osmotic pressure of 149 mm Hg at 298 k

Answer» ONG>ANSWER:

Identify the type of motion from the FOLLOWING.

(A) CAR is not in motion

(B) car is moving with uniform velocity

(C) car is moving with uniform acceleration

(D)None of the above

Discussion

24.	Q.15 Write molecular and structural formulae of:a) Dithionous acid b) oleum c) Dithionic acid
Answer» thionous acid is a sulfur oxoacid with the chemical formula H₂S₂O₄. It is unstable in pure form, but its salts, known as dithionites, are stable. It was initially assumed that the C₂ symmetric STRUCTURE HOS-SOH is the most stable among molecules with the formula H ₂S ₂O ₄ using ab initio calculations. b)Disulfuric acid or pyrosulfuric acid, ALSO NAMED oleum, is an oxyacid of sulfur. It is a major constituent of fuming sulfuric acid, oleum, and this is how most chemists encounter it c)Dithionic acid, H₂S₂O₆, is a chemical compound known only in solution. Hope it helps. Pls mark this BRAINLIEST

24.

Q.15 Write molecular and structural formulae of:a) Dithionous acid b) oleum c) Dithionic acid

Answer»

thionous acid is a sulfur oxoacid with the chemical formula H₂S₂O₄. It is unstable in pure form, but its salts, known as dithionites, are stable. It was initially assumed that the C₂ symmetric STRUCTURE HOS-SOH is the most stable among molecules with the formula H ₂S ₂O ₄ using ab initio calculations.

b)Disulfuric acid or pyrosulfuric acid, ALSO NAMED oleum, is an oxyacid of sulfur. It is a major constituent of fuming sulfuric acid, oleum, and this is how most chemists encounter it

c)Dithionic acid, H₂S₂O₆, is a chemical compound known only in solution.

Hope it helps.

Pls mark this BRAINLIEST

Discussion

25.	Complete the following reactions a) 2-Bromobutane ag Koh→ ?b) 2-Bromobutanealco KCN?Sochc) Ethanol
Answer» ER: EXPLANATION: EVEN I too don't KNOW the ANSWER

25.

Complete the following reactions a) 2-Bromobutane ag Koh→ ?b) 2-Bromobutanealco KCN?Sochc) Ethanol

Answer» ER:

EXPLANATION:

EVEN I too don't KNOW the ANSWER

Discussion

26.	Volume of EDTA (X ml) =
Answer» ong>Explanation: Several 200ML sample of total SOLUTION were titrated with 0.0100 M EDTA solution by METHOD of this experiment . The mean corrected titration volume was 13.65 ml.

26.

Volume of EDTA (X ml) =

Answer»

ong>Explanation:

Several 200ML sample of total SOLUTION were titrated with 0.0100 M EDTA solution by METHOD of this experiment . The mean corrected titration volume was 13.65 ml.

Discussion

27.	Varition on electronegativityhlσσѕчαgαt nhí krσgє hmαrα!?
Answer» ong>Answer: Hii, Explanation: $\huge\underline{\underline{\boxed{\mathbb\pink{ANSWER:-}}}}$ On the periodic table, electronegativity generally increases as you move from left to right across a PERIOD and decreases as you move down a group. As a result, the most electronegative elements are found on the top right of the periodic table, while the least electronegative elements are found on the bottom left. Electronegativity depends on the NUMBER of ELECTRONS REQUIRED to get octet configuration. It increases from left to right in a period, hence correct order is F>O>N>C. So, as you move down a group on the periodic table, the electronegativity of an element decreases because the increased number of energy levels puts the outer electrons very far away from the pull of the nucleus. Electronegativity increases as you move from left to right across a period on the periodic table. $\huge\underline{\underline{\boxed{\mathbb\red{HOPE \: IT \: WILL \: HELP \: YOU}}}}$ # XxLovingBoyxX ❤️

27.

Varition on electronegativityhlσσѕчαgαt nhí krσgє hmαrα!?

Answer»

ong>Answer:

Hii,

Explanation:

$\huge\underline{\underline{\boxed{\mathbb\pink{ANSWER:-}}}}$

On the periodic table, electronegativity generally increases as you move from left to right across a PERIOD and decreases as you move down a group. As a result, the most electronegative elements are found on the top right of the periodic table, while the least electronegative elements are found on the bottom left.

Electronegativity depends on the NUMBER of ELECTRONS REQUIRED to get octet configuration. It increases from left to right in a period, hence correct order is F>O>N>C.

So, as you move down a group on the periodic table, the electronegativity of an element decreases because the increased number of energy levels puts the outer electrons very far away from the pull of the nucleus. Electronegativity increases as you move from left to right across a period on the periodic table.

$\huge\underline{\underline{\boxed{\mathbb\red{HOPE \: IT \: WILL \: HELP \: YOU}}}}$

# XxLovingBoyxX ❤️

Discussion

28.	CH, COOH → CH, +CO,1
Answer» ong>ANSWER: ALDEHYDES, Ketones and Carboxylic ACIDS ... AIR #1Anita Barik. ATTEMPT ...

28.

CH, COOH → CH, +CO,1

Answer»

ong>ANSWER:

ALDEHYDES, Ketones and Carboxylic ACIDS ... AIR #1Anita Barik. ATTEMPT ...

Discussion

29.	CL2 + H2O --------------> HCL + O2 BALANCE IT
Answer» ONG>Answer: 2Cl2 + 2H2O ------> 4HCL + O2

Discussion

30.	1. What are enzymes? Describe briefly I.U.B. system of classificationwith examples.
Answer» > An enzyme is a substance that ACTS as a catalyst in living ORGANISMS, regulating the rate at which chemical reactions proceed WITHOUT itself being altered in the process. The biological processes that occur within all living organisms are chemical reactions, and most are regulated by enzymes.

30.

1. What are enzymes? Describe briefly I.U.B. system of classificationwith examples.

Answer»

>

An enzyme is a substance that ACTS as a catalyst in living ORGANISMS, regulating the rate at which chemical reactions proceed WITHOUT itself being altered in the process. The biological processes that occur within all living organisms are chemical reactions, and most are regulated by enzymes.

Discussion

31.	Where was Kalpana Chawla Born ?????
Answer» ong>Answer: KALPANA Chawla was born in Karnal, Haryana, INDIA on March 17, 1962. She received a Bachelor of Science degree in aeronautical ENGINEERING from Punjab Engineering COLLEGE in India in 1982. Explanation: have a great DAY

31.

Where was Kalpana Chawla Born ?????

Answer»

ong>Answer:

KALPANA Chawla was born in Karnal, Haryana, INDIA on March 17, 1962. She received a Bachelor of Science degree in aeronautical ENGINEERING from Punjab Engineering COLLEGE in India in 1982.

Explanation:

have a great DAY

Discussion

32.	Laryn is also called as
Answer» ong>Answer: hey there what's up can you be my friend :-) photosynthesis is a PROCESS by which the plants make FOOD by the PRESENCE of, SUNLIGHT,chlorophyll and CARBON dioxide above definition for formality

32.

Laryn is also called as

Answer»

ong>Answer:

hey there

what's up

can you be my friend :-)

photosynthesis is a PROCESS by which the plants make FOOD by the PRESENCE of, SUNLIGHT,chlorophyll and CARBON dioxide

above definition for formality

Discussion

33.	Nhi jarurat nhi h yr tum log kitne fast ho aur ye wale version mai toh bio bhi nhi likh sakte humpurana wala download karna padega muje Aur Rajul bro aap 10th mai gye ho abhi ya 11th mai jaaoge
Answer» ONG>Answer: out hello aise to baaye karname kaise majaa AAYE gaa YARR

Discussion

34.	Nitrogen dioxide gas and bromine gas both are brown in colour .How will you distinguish between them?kindly don't spam ! 5❤ = 20❤
Answer» m>For Br2 - add Br2 to liquid alkene , the BROMINE decolourises. For NO2 -There is no simple relatively unambiguous test. So just check for bromine and other one is NO2. . . . . . . #THE *GREAT* *SHREYA* ❤️

34.

Nitrogen dioxide gas and bromine gas both are brown in colour .How will you distinguish between them?kindly don't spam ! 5❤ = 20❤

Answer»

m>For Br2 - add Br2 to liquid alkene , the BROMINE decolourises. For NO2 -There is no simple relatively unambiguous test. So just check for bromine and other one is NO2.

.

#THE GREAT SHREYA ❤️

Discussion

35.	What is a Dreams ?????
Answer» ONG>ANSWER: DREAM is the sleep vision

Discussion

36.	What is the meaning of life???
Answer» > The MEANING of life is not happiness, love, success and FREEDOM, because all these qualities remain in this life and die together with the person. We are all afraid of dying, but if we start entering a higher degree through the question about the meaning of life, then we don’t die. Our SPIRIT continues developing. Physical death is given to us on purpose, so that we will ask ourselves about the meaning of life at LEAST once during our lives. If we are concerned about the elevation of our spirit, we reach a state where we attain the meaning of life in current lifetime.

36.

What is the meaning of life???

Answer»

>

The MEANING of life is not happiness, love, success and FREEDOM, because all these qualities remain in this life and die together with the person. We are all afraid of dying, but if we start entering a higher degree through the question about the meaning of life, then we don’t die. Our SPIRIT continues developing. Physical death is given to us on purpose, so that we will ask ourselves about the meaning of life at LEAST once during our lives. If we are concerned about the elevation of our spirit, we reach a state where we attain the meaning of life in current lifetime.

Discussion

37.	Explain formation of covalent bond in H2 , CL2 , CH4 , N2 .
Answer» ONG>ANSWER: I am not INTERESTED in CHEMISTRY.

Discussion

38.	Why is the phenonphthalein guide used in this experiment and not used?
Answer» ong>Answer: Phenolphthalein is used as INDICATOR for titrations. It has a weak acid that used, because it CHANGES COLOUR close to PH 7, the pH of the equivalence point of a strong acid with a strong base. The phenolphthalein has an EASY colour change, from colourless to pink. (Hope it helps)

38.

Why is the phenonphthalein guide used in this experiment and not used?

Answer»

ong>Answer:

Phenolphthalein is used as INDICATOR for titrations. It has a weak acid that used, because it CHANGES COLOUR close to PH 7, the pH of the equivalence point of a strong acid with a strong base. The phenolphthalein has an EASY colour change, from colourless to pink.

(Hope it helps)

Discussion

39.	What is ultra filter paper
Answer» ultrafilter PAPER can be made by SOAKING the filter paper in a colloidal solution, hardening by FORMALDEHYDE and then finally drying it. As this is slow process, pressure or SUCTION is applied to speed it up.

Discussion

40.	State the following: (a) Aufbau principle (b) Pauli exclusion principle. (c) Hund’s rule of maximum multiplicity.
Answer» ong>Answer: Aufbau Principle: LOWER energy orbitals fill before higher energy orbitals. Hund's Rule: one electron GOES into each until all of them are half full before PAIRING up. different spins

40.

State the following: (a) Aufbau principle (b) Pauli exclusion principle. (c) Hund’s rule of maximum multiplicity.

Answer»

ong>Answer:

Aufbau Principle: LOWER energy orbitals fill before higher energy orbitals. Hund's Rule: one electron GOES into each until all of them are half full before PAIRING up. different spins

Discussion

41.	The chemical symbol for sodium isa.SOb.SD c.Na d.NA
Answer» ong>ANSWER: sodium=Na EXPLANATION: HOPE it will help you

41.

The chemical symbol for sodium isa.SOb.SD c.Na d.NA

Answer»

ong>ANSWER:

sodium=Na

EXPLANATION:

HOPE it will help you

Discussion

42.	When magnesium ribbon is burnt, a dazzling white flame along with white compound X is seen. Write a balanced chemical equation, when X is dissolved in water.
Answer» ONG>ANSWER: Ash is the answer PLEASE MARK as branliest

42.

When magnesium ribbon is burnt, a dazzling white flame along with white compound X is seen. Write a balanced chemical equation, when X is dissolved in water.

Answer» ONG>ANSWER:

Ash is the answer

PLEASE MARK as branliest

Discussion

43.	A solution has 50g of salt in 320g of water. Calculate the mass percent of the salt in the solution. ii) Name any one Metalloid. iii) What type of change is cutting of wood.
Answer»

Discussion

44.	Balanced eq for Ethene with bromine.
Answer» ong>EXPLANATION: Explanation: Answer: $\huge \bold \blue{Answer࿐}$ Width of rectangle is 25 cm. Step-by-step explanation: Given :- A wire bend in form of square of side 30 cm. Then wire is again bend in form of rectangle of length 35 cm. To find :- Width of the rectangle. Solution :- Here, Concept is : If we are bending wire in form of square than again bending it in rectangle. Than, perimeter of square will equal to perimeter of rectangle because we are not increasing length of wire by one measure we are bending it in square and rectangular shape. So, Perimeter of square = 4 × side ⟶ Perimeter = 4 × 30 ⟶ Perimeter = 120 Thus, Perimeter of square is 120 cm. According to concept, Perimeter of square and perimeter of rectangle are equal. So, Perimeter of rectangle is 120 cm. Let, BREADTH or width or rectangle be x cm. We know, Perimeter of rectangle = 2(Length + Breadth) ⟶ 120 = 2×(35 + x) ⟶ 120 = 70 + 2x \⟶ 120 - 70 = 2x ⟶ 50 = 2x ⟶ 50/2 = x ⟶ x = 25 We take, Width of rectangle be x. Therefore, Width of rectangle is 25 cm.

44.

Balanced eq for Ethene with bromine.

Answer»

ong>EXPLANATION:

Explanation:

Answer:

$\huge \bold \blue{Answer࿐}$

Width of rectangle is 25 cm.

Step-by-step explanation:

Given :-

A wire bend in form of square of side 30 cm.

Then wire is again bend in form of rectangle of length 35 cm.

To find :-

Width of the rectangle.

Solution :-

Here, Concept is : If we are bending wire in form of square than again bending it in rectangle. Than, perimeter of square will equal to perimeter of rectangle because we are not increasing length of wire by one measure we are bending it in square and rectangular shape.

So,

Perimeter of square = 4 × side

⟶ Perimeter = 4 × 30

⟶ Perimeter = 120

Thus,

Perimeter of square is 120 cm.

According to concept, Perimeter of square and perimeter of rectangle are equal.

So, Perimeter of rectangle is 120 cm.

Let, BREADTH or width or rectangle be x cm.

We know,

Perimeter of rectangle = 2(Length + Breadth)

⟶ 120 = 2×(35 + x)

⟶ 120 = 70 + 2x

\⟶ 120 - 70 = 2x

⟶ 50 = 2x

⟶ 50/2 = x

⟶ x = 25

We take, Width of rectangle be x.

Therefore,

Width of rectangle is 25 cm.

Discussion

45.	Name the elements present in oxide ion
Answer» ong>Answer: An OXIDE (/ˈɒksaɪd/) is a CHEMICAL compound that CONTAINS at least one OXYGEN atom and one other element in its chemical formula. "Oxide" itself is the dianion of oxygen, an O2– (molecular) ion. Metal oxides thus typically contain an anion of oxygen in the oxidation STATE of −2.

45.

Name the elements present in oxide ion

Answer»

ong>Answer:

An OXIDE (/ˈɒksaɪd/) is a CHEMICAL compound that CONTAINS at least one OXYGEN atom and one other element in its chemical formula. "Oxide" itself is the dianion of oxygen, an O2– (molecular) ion. Metal oxides thus typically contain an anion of oxygen in the oxidation STATE of −2.

Discussion

46.	Calculate the magnetic moment of a divalent cation of atomic number 27
Answer» 7 BM .!!!!!!!!!!!!!!!

Discussion

47.	DuetoFranklindefectthedensityofionicsolid……………
Answer» ONG>ANSWER: -_-£-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_6_

Discussion

48.	calculate the pH of the solution obtained by mixing 100 ml 0.01( M )acetic acid and 20ml 0.01(M) KOH. Given PKa=4.74
Answer» ONG>Answer: 8.87 Explanation: "The pH of a solution obtained by mixing 100 ml" of 02. M of \mathrm{CH}_{3} \mathrm{COOH}CH3COOH with 100 ml of 0.2 M of NaOH will be 8.87. We can calculate this by using the FORMULA: 7+\frac{1}{2} P K a+\frac{1}{2} \log C7+21PKa+21logC We first need to calculate the value of C which is formed after the mixture is formed. The value C or final mixture concentration can be calculated as: C=\frac{\text {Total Moles Formed}}{\text {Total Volume}}C=Total VolumeTotal Moles Formed The moles formed for \mathrm{CH}_{3} \mathrm{COOH}CH3COOH and NaOH will be calculated as mass ÷ total volume in L =\frac{0.2}{10}=0.02=100.2=0.02 We use the EQUATION: \mathrm{CH}_{3} \mathrm{COOH}+\mathrm{NaOH} \rightarrow \mathrm{CH}_{3} \mathrm{COONA}+\mathrm{H}_{2} \mathrm{O}CH3COOH+NaOH→CH3COONa+H2O In this case, \mathrm{CH}_{3} \mathrm{COOH}CH3COOH is partially dissociated whereas NaOH is completely dissociated. The total moles dissociated would be 0.02 and the total volume is 200ml. C=\frac{0.02}{0.2}=0.1C=0.20.02=0.1 Now using the formula to calculate pH, we get p H=7+\frac{1}{2} P K a+\frac{1}{2} \log CpH=7+21PKa+21logC \begin{gathered}\begin{array}{c}{=7+\frac{1}{2}[P k+\log C]} \\ {=7+\frac{1}{2}[4.74+\log 0.1]} \\ {=7+\frac{1}{2}[4.74+(-1)]}\end{array}\end{gathered}=7+21[Pk+logC]=7+21[4.74+log0.1]=7+21[4.74+(−1)] \begin{gathered}\begin{array}{l}{=7+\frac{1}{2}[3.74]} \\ {=7+1.87} \\ {=8.87}\end{array}\end{gathered}=7+21[3.74]=7+1.87=8.87

48.

calculate the pH of the solution obtained by mixing 100 ml 0.01( M )acetic acid and 20ml 0.01(M) KOH. Given PKa=4.74

Answer» ONG>Answer:

8.87

Explanation:

"The pH of a solution obtained by mixing 100 ml" of 02. M of \mathrm{CH}_{3} \mathrm{COOH}CH3COOH with 100 ml of 0.2 M of NaOH will be 8.87.

We can calculate this by using the FORMULA: 7+\frac{1}{2} P K a+\frac{1}{2} \log C7+21PKa+21logC

We first need to calculate the value of C which is formed after the mixture is formed. The value C or final mixture concentration can be calculated as:

C=\frac{\text {Total Moles Formed}}{\text {Total Volume}}C=Total VolumeTotal Moles Formed

The moles formed for \mathrm{CH}_{3} \mathrm{COOH}CH3COOH and NaOH will be calculated as mass ÷ total volume in L

=\frac{0.2}{10}=0.02=100.2=0.02

We use the EQUATION: \mathrm{CH}_{3} \mathrm{COOH}+\mathrm{NaOH} \rightarrow \mathrm{CH}_{3} \mathrm{COONA}+\mathrm{H}_{2} \mathrm{O}CH3COOH+NaOH→CH3COONa+H2O

In this case, \mathrm{CH}_{3} \mathrm{COOH}CH3COOH is partially dissociated whereas NaOH is completely dissociated. The total moles dissociated would be 0.02 and the total volume is 200ml.

C=\frac{0.02}{0.2}=0.1C=0.20.02=0.1

Now using the formula to calculate pH, we get p H=7+\frac{1}{2} P K a+\frac{1}{2} \log CpH=7+21PKa+21logC

\begin{gathered}\begin{array}{c}{=7+\frac{1}{2}[P k+\log C]} \\ {=7+\frac{1}{2}[4.74+\log 0.1]} \\ {=7+\frac{1}{2}[4.74+(-1)]}\end{array}\end{gathered}=7+21[Pk+logC]=7+21[4.74+log0.1]=7+21[4.74+(−1)]

\begin{gathered}\begin{array}{l}{=7+\frac{1}{2}[3.74]} \\ {=7+1.87} \\ {=8.87}\end{array}\end{gathered}=7+21[3.74]=7+1.87=8.87

Discussion

49.	Tera dp bahut accha hai Nandu
Answer» ONG>Answer: Who is NANDU? HI! Whats your name?

49.

Tera dp bahut accha hai Nandu

Answer» ONG>Answer:

Who is NANDU?

HI!

Whats your name?

Discussion

50.	Solution P has a pH of 13,Q has a pH of 6 , R has a pH of 2 and S has a pH of 7.Which solution a) is a strong acid b) is neutral c) is a strong alkali d) is a week acid
Answer» ong>ANSWER: A) pH of 2 (R) B) pH of 7 (S) C) pH of 13 (P) D) pH of 6 (Q)

50.

Solution P has a pH of 13,Q has a pH of 6 , R has a pH of 2 and S has a pH of 7.Which solution a) is a strong acid b) is neutral c) is a strong alkali d) is a week acid

Answer»

ong>ANSWER:

A) pH of 2 (R)

B) pH of 7 (S)

C) pH of 13 (P)

D) pH of 6 (Q)

Discussion

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