1.

0. Define and explain normality with mathematical expression. Calculate the normality of 500 ml of solution containing5.3 gm of Na2CO3.​

Answer»

ong>Explanation:

Molecular mass of Na

2

CO

3

=106 gmol

−1

NUMBER of moles =

106

53

=0.05mol

As 0.05 mol are dissolved in 500mL;

Number of moles dissolved in 1000ML (1L) or molarity of TH solution

=

500

0.05

×1000=0.1M.



Discussion

No Comment Found