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0.01 V is the CELL Potential. EXPLANATION:Refer attachment for explanation!!!

IF IT HELPS PLZ MARK IT AS BRAINLIESTExplanation:Zone refining is based on the difference in SOLUBILITY of impurities in molten and SOLID state of the METAL. Semiconductor like Si,Ge and GA are purified by this METHOD.

Metals that are more REACTIVE than CARBON are GENERALLY extracted by ELECTROLYSIS because they can't be reduced with carbon.

st step (which involves electrophilic attack by bromine on the double bond) produces a bromide ion and a carbocation, as shown in Equation 10-1.1As we know from our study of SN1 reactions (Section 8-4), carbocations react readily with nucleophilic reagents. Therefore in the second step of the bromine-addition mechanism, shown in Equation 10-2, the bromoethyl cation is expected to combine rapidly with bromide ion to give the dibromo compound. However, if other nucleophiles, such as Cl⊖ or CH3OH, are present in SOLUTION, they should be able to compete with bromide ion for the cation, as in EQUATIONS 10-3 and 10-4, and mixtures of products will RESULT:To account for the All of the hydrogen halides HF, HCl, HBr, and HI) will add to alkenes. Addition of hydrogen fluoride, while facile, is easily reversible. However, a solution of 70% anhydrous hydrogen fluoride and 30% of the weak organic base, pyridine, which is about 1/10,000 times as strong as ammonia, works better, and with cyclohexene gives fluorocyclohexane. With hydrogen iodide, care must be taken to prevent I2 addition products resulting from iodine formed by oxidation reactions such as4HI+O2→2I2+2H2OWith hydrogen bromide, radical-chain addition may intervene unless the reaction conditions are controlled asonably reactive alkenes, although by no means as effectively as does concentrated sulfuric acid. The carbocation formed then is attacked rapidly by a nucleophilic water molecule to give the alcohol as its conjugate acid,2 which acts readily with water in a second step to give ethanol:10-3F AQUEOUS versus Nonaqueous Acids. Acid StrengthsOne of the more confusing features of organic chemistry is the multitude of conditions the H3O⊕ concentration, because H3O⊕ is where the protons are.Now, if we use poorer proton acceptors as solvent we find the proton-donating powers of various "strong" acids begin to spread out immensely. Furthermore, new things begin to happen. For example, ethene is not hydrated appreciably by dilute aqueous acid; it just is too hard to transfer sulfuric acid is virtually all converted to H3O⊕, which is non-nucleophilic!H2SO4+H2O→H3O⊕+HSO−4id is a very good proton donor) and SbF−6 is an extremely poor nucleophile. If we add ethene to such a solution, a stable solution of CH3CH+2SbF−6 is formed. The reason is that there is no better proton acceptor present than CH2=CH2 and no nucleophile good enough to combine with the

it FORMS ACETYLENE is ANSWER

A tough malleable form of iron suitable for forging or rolling rather than CASTING, obtained by puddling pig iron while molten. It is nearly pure but contains some SLAG in the form of filaments.Plz FOLLOW me friend and MARK this ANSWER as a brainlist answer

Explanation:CO2 REACTS with the Na and ALUMINIUM COMPLEX to give hydrated ALUMINA which is then HEATED to give pure alumina

hope it HELPS......if it helps MARK IT AS BRAINLIESTExplanation:The main application of Ellingham diagrams is in the extractive metallurgy industry, where it helps to select the best reducing agent for various ores in the extraction process, purification and grade setting for steel manufacturing.We shall consider the following reactions on the Ellingham diagram below: the oxidation of SILVER to form Ag2O (s); and the oxidation of cobalt to form CoO (s) and Co3O4: 4Ag (s) + O2 = 2Ag2O (s); 2Co + O2 (g) = 2CoO (s) 3Co + 2O2 (g) = Co3O4 (s). Example Ellingham Diagram for Co - Ag system The graph consists of lines of ΔG∘=ΔH∘−TΔS∘ Although ΔS and ΔH vary with temperature (see here to see why), the changes are so small as to be negligible, and so the lines are approximately straight. This means that they are of the form y=mx+c We can IMMEDIATELY see that the standard free energy change is greater (more negative) for the cobalt reaction relative to that of silver at all temperatures. This means that at all temperatures the equilibrium constant is larger for the cobalt reaction-the composition is further weighted towards the products of the reaction. This is the reason that metals that appear higher up on the diagram are more stable than those metals that appear lower down, and are more likely to be found in their pure solid form. The gradient of the two lines is approximately the same. We can see that the gradient of the lines is simply the standard entropy change for the reactions; ∂ΔG∘∂T=−ΔS∘ This is evident from the reactions, which both involve the ELIMINATION of one mole of gas - a large decrease in entropy. This is the reason for the positive slope of the lines. The reason for the change in slope is the change in phase of a component of the system, which alters the entropy change. As the standard free energy change for both reactions is still negative (below 460K) the large decrease in entropy MUST be counteracted by a large enthalpy of reaction. This is indeed the case. The intercept of the lines with 0K gives the enthalpy of the reaction: ΔG∘|0K=ΔH∘ We can hence see that the relative stability of the oxide of cobalt compared with the oxide of silver is due to the much larger standard enthalpy of reaction.

E HERES UR ANSANSWERDuring extraction of Zn from ZINC BLENDE (ZnS), following reactions OCCUR:(i) ZnS is roasted in excess air at 1200 K to form ZnO.2ZnS+2O 2 Δ 2ZnO+2SO 2 (ii) ZnO is heated with crushed COKE at 1673 K, where it is reduced to Zn.ZnO+C 1676K Zn+CO(iii) Electrorefining is carried out for refining of impure zinc. Anode is impure zinc and cathode is pure zinc. Electrolyte is a mixture of zinc sulphate and dilute sulphuric acid (small amount). When current is passed, zinc is deposited on cathode and is collected.At anode : Zn→Zn 2+ +2e − At cathode: Zn 2+ +2e − →Zn

here below is your answer.Explanation:Enantiomers, also KNOWN as OPTICAL ISOMERS, are two stereoisomers that are related to each other by a reflection: they are mirror IMAGES of each other that are non-superposable. Human hands are a macroscopic analog of this. Every stereogenic center in one has the opposite CONFIGURATION in the other.

1.108 mExplanation:REFER ATTACHMENT for EXPLANATION!!!

You have to check alphabetics too...If there are no functional groups in the given chain... follow this a) Lowest LOCANT rule.. means the substitution if u are counting it from 2 DIFFERENT sides left to right and VICEVERSA ,, the substitution should get lowest position.. in dat direction u HAV to give numbering..if locants are same then go for b) lowest sum rule,, ADD all the locants... which will get lowest sum follow that order...if it is also same then check c) alphabetic order.. which has lowest alphabet give it more preference Here we give preference more to a than b than c

(2) O2 (3) CH4,CO (C)1.TEMPERATURE. 2.MOLECULAR MASS OF A GAS.Explanation:

0.019 M is the RIGHT ANSWER!!EXPLANATION:REFER ATTACHMENT for explanation!!

the branch of SCIENCE and technology CONCERNED with the use of high temperatures to EXTRACT and purify metals.

----> ZNO +CO2

44g is the MOLECULAR MASS of the compound. EXPLANATION:Refer ATTACHMENT for explanation!!

carbon in the form of coke is used to reduce METAL oxides to metals but sometimes displacement REACTION is also used..... ZnO(s) + C(s) → Zn(s) + CO(g)

i) If the metal is found in the form of sulphides, They are roasted (ROASTING is the process of heating[less than the melting point of metal] metals sulphides  (metal sulphides) to remove sulphur gas from the metal,. and the metal is converted to metal oxide as a STEP of purification ), and REDUCED to oxide form,. Eg: copper is found as copper sulphide so, they are roasted to form copper oxide. Cu2 S + 3O2(g)  → 2Cu2 O(s)  +2SO2(g)  (Heat is SUPPLIED)

0.02 MExplanation:The molar mass of sodium carbonate is 106g/mol. The number of moles of sodium carbonate is 21.2/106 = 0.2 molTo FIND the molarity of the SOLUTION, DIVIDE the moles of SOLUTE by the volume of solution:0.2/10 = 0.02 M

Methane EXISTS as a gas and HEXANE in liquid form at room temperature because intermolecular forces affect the molecules of these SUBSTANCES differently.

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oxygenExplanation:HOPE it's HELPFUL ♥️✌️

can't KNOW the ANSWER of yours

which can be attracted by the magnetic FIELD can be CONCENTRATED by the PROCESS of magnetic separation. Among the ores MENTIONED in table 6.1, the ores of iron such as haematite (Fe2O3), magnetite (Fe3O4), siderite (FeCO3), and iron pyrites (FeS2) can be separated by the process of magnetic separation.

Fe2O4Zn is the FORMULA of CALAMINE

During EXTRACTION of silver, the finely POWDERED silver ORE is treated with dilute KCN solution to form a cyano COMPLEX of silver. This complex is WATER soluble. Then zinc is added to the solution. More electropositive zinc displaces silver from the complex.Explanation:

falseExplanation:PLEASE MARK as BRAINLY

>> It's FROTH FLOATATION PROCESS......................!

The only COLOR which sapphire cannot be is red – as red-coloured corundum is called ruby. Rubies are crystalline FORMS of aluminium oxide, which are red due to the PRESENCE of CHROMIUM as an impurity.Explanation:

A and R are correct ,R explains A.Explanation:According to Pauling scale, if the ELECTRONEGATIVITY is GREATER than 1.7 , the BOND is considered to be IONIC. Electronegativity of H = 2.1 Electronegativity of F = 4.0 we get, Electronegativity of HF = 6.1Hope this will helps youPlz follow and support my ANSWER.

what do you MEANT by this

1/12Explanation:Mole fraction= MOLES of solute/total molesMoles of H2SO4= 34/98= 0.5Moles of water = 100/18By CALCULATING we GET 1/12

(A)EXPLANATION:Statement-1 is TRUE, Statement-2 is True, Statement-2 is a CORRECT explanation for Statement-1.

The blank will be FILLED by PbO In chemicall REACTION , PbS + O2 ==> PbO + SO2 It is a redox reaction because lead is GETTING oxidised.

(i) and (III) are the correct options.Explanation:Lower the melting point of Al2O3:  increase the conductivity of molten MIXTURE. REDUCE Al3+ (AQ) into Al(s): ACT as catalyst.

(a) and (C) is correct.MARK AS BRAINLIEST

(B) ZINC OXIDE can be REDUCED by graphite.mark as BRAINLIEST