This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 2. |
Instant will be 1)-0.02 mol4) 0.17g3) 0.1132g2) Zero199. For N2 + 3H2 A 2NH3 rate of disappearance of H2 is 0.01 M min- The amount of NH3 form |
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Answer» ANSWERThe given reaction is:2N 2 O 5 ⟶4NO 2 +O 2 The unit of rate constant indicates its first-order reaction.Rate=K[N 2 O 5 ] (Rate LAW)where K= Rate constantGiven that, K=3×10 ^−5 sec ^−1 Rate=2.4×10 ^−5 MOLL ^−1 s ^−1 Putting the given VALUES in rate law:-2.4×10 −5 =3.0×10 −5 [N 2 O 5 ]⇒ 108 =[N 2 O 5 ] ⇒[N 2 O 5 ]=0.8 molL −1 |
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| 3. |
Water can exist in all 3 states of matter that is solid liquid and gas is it because it has a high boiling point? |
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Answer» ter can EXIST in all 3 STATES of matter that is SOLID liquid and gas is it because it has a HIGH boiling POINT. |
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| 4. |
10% aqueous solution of glucose can be prepared by dissolving 10 g glucose in 100 g of water true or false |
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Answer» Yes, 10% AQUEOUS solution of glucose can be prepared by dissolving 10 g glucose in 100 g of water.In a 10% by mass glucose solution, this means there are 10 g of glucose for every 100 g solution. To make 10% aqueous solution of glucose, add 10 ML of 50% glucose solution per 100 ml of 5% glucose solution to obtain a 10% glucose solution. |
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| 5. |
When nitric acid is added to the eggshell , the eggshell slowly dissolves in nitric acid and releases hydrogen gas. TrueFalse |
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| 6. |
12.18 Give plausible explanation for each of the following: (1) Cyclohexanone forms cyanohydrin in good yield but 2,2,6-trimethylcyclo-hexanone does not.(ii) There are two -NH, groups in semicarbazide. However, only one is involvedin the formation of semicarbazones.(ii) During the preparation of esters from a carboxylic acid and an alcohol inthe presence of an acid catalyst, the water or the ester should be removedas soon as it is formed. |
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| 8. |
Acid which helps in digestion of proteins |
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Answer» Pepsin is a stomach enzyme that serves to digest PROTEINS found in ingested food.Explanation:HOPE it will HELP youJai HIND |
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| 11. |
हाउ विल यू कन्वर्ट aniline इनटू 4 bromoaniline |
| Answer» TION:i can't UNDERSTAND your LANGUAGE | |
| 12. |
iron exhibits +2 and +3 oxidation state, write their electronic configuration, which will be more stable?why? |
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Answer» +3 , due to PARTIALLY filled d ORBITAL ..that is more stable than +2 oxidation STATE |
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| 13. |
Please ans this fast |
| Answer» B is your answer Explanation:PLEASE MARK this BRAINLIEST and follow me | |
| 14. |
300ml of a gas at 27°C is cooled to 7°C at constant pressure the final volume will be |
| Answer» ANATION:If 300ML of a gas at 27∘ is cooled to 7∘ at constant pressure, then its FINAL VOLUME will be. ⇒V1V2=T1T1⇒V2=V1T2T1=300×280300=280ml. | |
| 15. |
The polarising power of which of the following pair is similar(A) Li, Mg(B) Li+, Mg2+(C) Li2+, Mg2+(D) Li+, Mg+ |
| Answer» FOLLOW me PLEASE | |
| 16. |
For ns orbital, the magnetic quantum number has valueA) 2B) 4C)-1D)0 |
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Answer» m=0 for s ORBITALS.... |
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| 18. |
With increase of C3. Match the two columns:Column A1. Colour change on ripening of fruit2. Increase in the height of a child3. Solubility of gases4. Solubility of solids5. SoluteColumn B(i) Decreases with temperature(ii) Present in small amount in solution(iii) Irreversible change(iv) Increases with temperature(v) Slow changeC4. Multiple Choice Questionol |
| Answer» 1. 42. 13.24. 55.3Explanation:HOPE it HELPS you | |
| 19. |
38. The values of n1 and n2 for the third spectral line of Brackett series of Hydrogenspectrum(A) 7 and 4(B) 5 and 8(C) 3 and 6(D) 4 and 7 |
| Answer» C is a CORRECT ANSWER ....... | |
| 20. |
What is the volume of Oxygen gas at NTP required to burn 30 gm of methane gas |
| Answer» TION:TRY to SOLVE your QUESTION liks this | |
| 21. |
A sample of gas occupies 100cm³at 27°C and 740 mm pressure . when volume change to cm³ at 740mm pressure the temperature of the gas will be |
| Answer» GIVEN :V 1 =100mL,T 1 =27 ∘ C=300K.P 1 =740V 2 =80ML, T 2 =?P 2 =740mmWe know, T 1 V 1 = T 2 V 2 ∴T 2 = V 1 V 2 ×T 1 = 10080×300 =240KT 2 =−33 ∘ CTherefore, the correct option is CExplanation: please mark me as branlist | |
| 22. |
Ount 10. The friction of the air causes a verticalretardation equal to 10% of the accelerationdue to gravity. Take g=10m/s. Themaximum height and time to reach themaximum height will be decreased by1) 9%, 9%2) 11%, 11%359%, 10%4) 11%,9% |
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Answer» correct OPTION is B.Given,RETARDATION =10%If there is no friction then,By the equation of the motion,v2=u2+2ghv=0h=2gu2Now,When there is air resistance 10% of the gravity.geff=g+0.1g=1.1gThe maximum HEIGHT will be,h1=2gefu2Therefore, the difference is h1−hu22gef−2gu2So,Change in height is:2gu2−2gefu2=2gu2−2gu2(1−1011)THUS the PERCENTAGE change in height is:=2gu2 |
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| 23. |
Molar से आप क्या समझते हैं हिंदी में |
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Answer» दाढ़ के दांत मुंह के पीछे बड़े, सपाट दांत होते हैं। वे स्तनधारियों में अधिक विकसित होते हैं। वे मुख्य रूप से चबाने के दौरान भोजन को पीसने के लिए उपयोग किया जाता है। मोलर नाम लैटिन से निकला है, मोलारिस डेन्स, जिसका अर्थ है "मिलस्टोन टूथ", मोला, मिलस्टोन और डेंस, दांत से। |
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| 24. |
what mass of a gas of molecular mass 30 occupies a volume of 80ml . at 27°C and under 3atm pressure? (R=0.082Latm/k mol) |
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Answer» The ideal GAS equation relating PRESSURE (P), volume (V), and absolute temperature (T) is given as:PV = nRTWhere, R is the universal gas CONSTANT =8.314Jmol −1 K −1 n = Number of moles = 1T = Standard temperature = 273 KP = Standard pressure = 1 atm =1.013×10 5 Nm −2 ∴V=nRT/P=1×8.314×273/(1.013×10 5 )=0.0224m 3 =22.4 litresHence, the molar volume of a gas at STP is 22.4 litres. |
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| 25. |
The energy associated with the first orbit of hydrogen atom is -2.17 x 10⁻¹⁸ J/atom. What is the energy associated with third orbit. First to answer marked as brainliest |
| Answer» PLEASE SEE the ATTACHMENT | |
| 26. |
3. What weight of calcium bicarbonate should be heated to obtain 2.4 x (10)23 molecules of co2. |
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Answer» ANSWERChemical REACTION involved is:CaCO 3 →CaO+CO 2 Molar mass of CaCO 3 =40+12+16×3=100 gAccording to the BALANCED reaction 100 G of CaCO 3 PRODUCES 1 mol of CO 2 i.e. 22.4 L at STP.∴50 g CaCO 3 will produce 10022.4 ×50=11.2 L CO 2 |
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| 27. |
Calculate the distance of seperation between first and second orbits of hydrogen atom |
| Answer» FIVE IDK I just guesedodijdkddi | |
| 28. |
'The valencies or charges on the ion must balance' What is the meaning of this sentence?Please explain. |
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Answer» To balance means to EQUATE so that both the entities in question have equal amounts. So balancing valencies and CHARGES means making the number of both positive and negative charges equal. This statement has been used in reference to writing the chemical formula of a COMPOUND. |
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| 29. |
The correct statement about probability density (except at infinite from nucleus ) is: a) it can be negative for 2p. (b) .it can be zero for 3p. (c) it can be zero for 1s. (d) it can never be zero for 2s.please answer with explanation |
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Answer» What is a Probability Distribution Discrete Distributions The mathematical definition of a discrete probability function, p(x), is a function that satisfies the following properties. The probability that x can take a specific value is p(x). That is P[X=x]=p(x)=px p(x) is non-negative for all REAL x. The sum of p(x) over all possible values of x is 1, that is ∑jpj=1 where j represents all possible values that x can have and pj is the probability at xj. One consequence of properties 2 and 3 is that 0 <= p(x) <= 1. What does this actually mean? A discrete probability function is a function that can take a discrete NUMBER of values (not necessarily finite). This is most often the non-negative integers or some subset of the non-negative integers. There is no mathematical restriction that discrete probability functions only be DEFINED at integers, but in practice this is usually what makes sense. For example, if you toss a coin 6 times, you can get 2 heads or 3 heads but not 2 1/2 heads. Each of the discrete values has a certain probability of occurrence that is between zero and one. That is, a discrete function that allows negative values or values greater than one is not a probability function. The condition that the probabilities sum to one means that at least one of the values has to occur. Continuous Distributions The mathematical definition of a continuous probability function, f(x), is a function that satisfies the following properties. The probability that x is between two points a and b is p[a≤x≤b]=∫baf(x)dx It is non-negative for all real x. The integral of the probability function is one, that is ∫∞−∞f(x)dx=1 What does this actually mean? SINCE continuous probability functions are defined for an infinite number of points over a continuous interval, the probability at a single point is always zero. Probabilities are measured over intervals, not single points. That is, the area under the curve between two distinct points defines the probability for that interval. This means that the height of the probability function can in fact be greater than one. The property that the integral must equal one is equivalent to the property for discrete distributions that the sum of all the probabilities must equal one. Probability Mass Functions Versus Probability Density Functions Discrete probability functions are referred to as probability mass functions and continuous probability functions are referred to as probability density functions. The term probability functions covers both discrete and continuous distributions. There are a few occasions in the e-Handbook when we use the term probability density function in a generic sense where it may APPLY to either probability density or probability mass functions. It should be clear from the context whether we are referring only to continuous distributions or to either continuous or discrete distributions.Explana |
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| 30. |
4. Calculate the mass of ratio obtained when 55.2 g of Ag2co3 is heated. Also calculate the total volume ofgasesobtained at STP. |
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Answer» 2.16 GAG 2 CO 3 (s)→2Ag(s)+CO 2 (g)+ 21 O 2 (g)Molecular WEIGHT of Ag 2 CO 3 =276 gAnd, molecular weight of Ag=2×108=216 g276 g of Ag 2 CO 3 GIVE 216 g Ag.Therefore, 2.76 g of Ag 2 CO 3 on heating will give 276216 ×2.76 g=2.16 g Ag as residue.Explanation:Thanks kar diyo |
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| 31. |
3. A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with conc. H,SO. The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be (a) 1.4 (b) 3.0 (c) 2.8 (d) 4.4 |
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Answer» (B )3.0Explanation:vbjkxdfgv the GIVEN below PROCESS of GETTING a |
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| 32. |
Classify the following as element and compound. i. mercuric oxide ii. helium gas iii. water iv.table salt v. iodine vi. mercury vii. oxygenviii. nitrogen |
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Answer» CURIC OXIDE (HGO)MERCURIC oxide is a compound.(II) HELIUM GAS (He) Helium gas is a element. (III) WATER (H₂O) Water is a compound.(IV) TABLE SALT (NaCl)Table salt is a compound.(V) IODINE (I)Iodine is a element.(VI) MERCURY (Hg)Mercury is a element.(VII) OXYGEN (O)Oxygen is a element.(VIII) NITROGEN (N)Nitrogen is a element.ELEMENT :Element is a pure chemical substance which cannot be BROKEN down further by reactions COMPOUND :Compound is a substance of COMBINATION of Two (or) more elements bonded together and can be broken down into simpler substances |
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| 33. |
Which has a highter freezing point oxygen and ethanol |
| Answer» OXYGEN have a HIGHER FREEZING POINT. | |
| 34. |
3. A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with conc. H,SO. The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be (a) 1.4 (b) 3.0 (c) 2.8 (d) 4.4 |
| Answer» HII, I am adahExplanation:WHATS your NAME | |
| 35. |
Explain the following: a. Pauli’s exclusion principal b. Hund’s rule of maximum multiplicity c. Aufbau’s principle. |
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Answer» s orbitals can hold two electrons and P orbital holds 2 electrons by following HUND's rule of highest multiplicity. Hund's rule. According to this PRINCIPLE, for a given ELECTRONIC configuration, the paring of the particle is done after each subshell is filled with a single electron. |
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| 36. |
Calculate distance of seperation between second and third orbits of hydrogen |
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Answer» e between the 2nd and the 3rd ORBITS = DISTANCE of 3rd orbit – diistnace of SECOND orbit from the nucleus. = 2.645 X 10-10 m is the distance between the 2nd the 3rd orbits.HOPE YOU LIKE THIS ANSWERPLEASE MARK IT AS BRAINLIEST |
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| 37. |
3. What weight of calcium bicanbonate should be heated to obtain 2.4 x 10 to the power 23 molecules of CO₂. |
| Answer» TION:Chemical reaction involved is:CaCO 3 →CaO+CO 2 MOLAR mass of CaCO 3 =40+12+16×3=100 gAccording to the balanced reaction 100 g of CaCO 3 PRODUCES 1 mol of CO 2 i.e. 22.4 L at STP.∴50 g CaCO 3 will produce 10022.4 ×50=11.2 L CO 2 at STP. | |
| 38. |
MULTIPLE CHOICE QUESTION: [5Q X i = 5 MARKS]Q15. Evaporation is called asa) Surface phenomenon b) Bulk phenomenon c) Both a and b d) Unique phenomenonQ16. The state of matter which is found to be more stable at lower temperatureb) Liquidc) Gasd) BECQ17. What happens when a saturated solution is cooled?a) It becomes unsaturated. b) It becomes supersaturated. c) It becomes transparent. d) Il remains unaffected.Q18. Which of the following is an aqueous solution?a) Sulphur in carbon disulphide b) Iodine in alcohol. c) Iodine in carbon tetrachloride. d) Sodium chloride in water.Q19. Chromatography is the technique which is used for separation of those solutes thata) Dissolves in the same solvent. b) Get absorbed to same extent. c) Get absorbed at the same speed. d) are soluble indifferent medium. |
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| 39. |
Write the IUPAC name ofCICH |
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Answer» loride ION.......... |
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| 40. |
Neopentyl alcohol on reaction with conc. forms two alkenes A & B in the ratio 85:15. then alkenes A & B respectively are:? |
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Answer» tion:Neopentyl alcohol (2,2-dimethylpropan-1-ol) on reaction with conc. H2SO4 FORMS two Alkene A & B. The two Alkene formed in the reaction are -Alkene A = 2-methyl But-2-ene (major) [saytzeff's product]Alkene B = 2-methyl But-1-ene (minor) [Hoffman's product]Hoffman's product -In this product Hydrogen GOES from that β-C, where H is more. Saytzeff's product -In this product Hydrogen goes from that β-C, where H is less. |
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| 41. |
An element has electronic configuration 1s22s²2p 3st in its +2 oxidation state. The formula of its sulphide is. |
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Answer» The compound SHOWN here is aluminium so formula of its SULPHIDE should be M2S3I HOPE this WOULD HELP you out..☺️ |
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| 42. |
Why metal standards are kept in plastic bottles |
| Answer» NEED to be filled in metal containers as STATIC ELECTRICITY generated will be conducted by the metal & dissipated. Water soluble solvents in general do not develop static electricity and are QUIET safe to be KEPT in plastic containers. | |
| 43. |
Number of electrons having (m+l) value equal to zero in z=30 is |
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Answer» two electronsKindly mark me as brainliest...plzzzhope U like my ANSWER.. |
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| 44. |
(b )rams Of WaterPragya makes a saturated solution of potassium chloridein water at 353 K and leaves the solution to cool at roomtemperature. What would she observe as the solutioncools? Explain. |
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Answer» The AMOUNT of POTASSIUM chloride that should be dissolved in water to MAKE saturated solution increases with temperature. Thus when the solution COOLS some of potassium chloride will precipitate out of the solution. |
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| 45. |
What is mean by dilution of an acid? how can a strong acid to be dilute? |
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Answer» tion:Dilute ACIDS contain a large amount of water. A concentrated acid can be diluted with the addition of water. ... Hence, acid is defined as “a substance which GIVES out hydrogen ions when dissolved in water”. Acids that release many hydrogen ions in water are strong acids.pls MARK me as BRAINLIEST |
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| 46. |
F20= 102"H2O =>کر2 104 28°HC 2₂0 = = 11Explain why it happens. |
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Answer» heioorjxjx hgirl vhfhdgzfuysurjtzttjjtz,gExplanation: |
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| 47. |
Which of the following pair of elements has similar properties ? A:Ca,Cl B:H,He. C:No,k D:k,Al |
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Answer» tion:The transition elements or transition metals occupy the short columns in the center of the periodic table, between Group 2A and Group 3A. They are sometimes called the d-block elements, since in this region the d-orbitals are being filled in, and are also referred to as B-group elements since in most numbering systems of the columns on the periodic table the numerals of these groups are followed by the letter B. The period 4 transition metals are scandium (Sc), titanium (Ti), vanadium (V), chromium (Cr), manganese (Mn), iron (Fe), cobalt (Co), nickel (Ni), copper (Cu), and ZINC (Zn). The period 5 transition metals are yttrium (Y), zirconium (Zr), niobium (Nb), molybdenum (Mo), technetium (Tc), ruthenium (Ru), rhodium (Rh), palladium (Pd), silver (Ag), and cadmium (Cd). The period 6 transition metals are lanthanum (La), hafnium (Hf), tantalum (Ta), tungsten (W), rhenium (Re), osmium (Os), iridium (Ir), PLATINUM (Pt), gold (Au), and mercury (Hg). The period 7 transition metals are the naturally-occurring actinium (Ac), and the artificially produced elements rutherfordium (Rf), dubnium (Db), SEABORGIUM (Sg), bohrium (Bh), hassium (Hs), MEITNERIUM (Mt), darmstadtium (Ds), roentgenium (Rg), and the as-yet unnamed ununbiium (Uub).The elements which FOLLOW lanthanum (Z=57) and actinium (Z=89) are called the lanthanides and actinides, respectively, and |
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| 48. |
In an experiment to verify the law of conservation of mass in a chemical reaction, when can the weighing or flask be done |
| Answer» YES DONE in an experimentExplanation:because in an EXPERIMENT to VERIFY the LAW | |
| 49. |
Calulate the number of moles in 5.75g of sodium ( given atomic mass -23) |
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Answer» IS 2.50 LETS US CONSIDER THE NUMBER OF MOLES AS X (5.75 G)IN 1 MOLE OF SODIUM THERE WILL BE 23 G OF SODIUM THEREFORE IN X MOLE THERE WILL 5.75/23 WHICH WILL BE APPROX 2.50 |
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