Neopentyl alcohol on reaction with conc. forms two alkenes A & B in the ratio 85:15. then alkenes A & B respectively are:?

Neopentyl alcohol on reaction with conc. forms two alkenes A & B in t

1.	Neopentyl alcohol on reaction with conc. forms two alkenes A & B in the ratio 85:15. then alkenes A & B respectively are:?
Answer» tion:Neopentyl alcohol (2,2-dimethylpropan-1-ol) on reaction with conc. H2SO4 FORMS two Alkene A & B. The two Alkene formed in the reaction are -Alkene A = 2-methyl But-2-ene (major) [saytzeff's product]Alkene B = 2-methyl But-1-ene (minor) [Hoffman's product]Hoffman's product -In this product Hydrogen GOES from that β-C, where H is more. Saytzeff's product -In this product Hydrogen goes from that β-C, where H is less.