52639 + Interview Questions in Secondary School in Chemistry

1.	A charge q is kept at centre of circle of radius r .If permitvity of free space is e0 then the work done in carrying a charge q along the diameter of circle will be
Answer» FINAL Answer : 0 Understanding : 1) We observe the motion of charge as shown in pic . 2) As we see, we get that Force is perpendicular to DIRECTION of displacement. 3) Hence, There is no contribution of WORK by the force on motion of this charge particle . For Mathematical proof, see pic

1.

A charge q is kept at centre of circle of radius r .If permitvity of free space is e0 then the work done in carrying a charge q along the diameter of circle will be

Answer»

FINAL Answer : 0

Understanding :

1) We observe the motion of charge as shown in pic .

2) As we see, we get that Force is perpendicular to DIRECTION of displacement.

3) Hence, There is no contribution of WORK by the force on motion of this charge particle .

For Mathematical proof, see pic

Discussion

2.	An increase in the nh3/co2 ratio in urea manufacture results in
Answer» Answer: Explanation: NH3 and CO2 are converted to urea via AMMONIUM carbamate at a pressure of APPROXIMATELY 140bar and a temperature of 180-185°C. The MOLAR NH3/CO2 ratio applied in the reactor is 2.95. This RESULTS in a CO2 conversion of about 60% and an NH3 conversion of 41%.

2.

An increase in the nh3/co2 ratio in urea manufacture results in

Answer»

Answer:

Explanation:

NH3 and CO2 are converted to urea via AMMONIUM carbamate at a pressure of APPROXIMATELY 140bar and a temperature of 180-185°C. The MOLAR NH3/CO2 ratio applied in the reactor is 2.95. This RESULTS in a CO2 conversion of about 60% and an NH3 conversion of 41%.

Discussion

3.	What is atomic mass of hydrogen
Answer» Answer: 1.00784 U is the ATOMIC MASS of Hydrogen. HOPE it helps

3.

What is atomic mass of hydrogen

Answer»

Answer:

1.00784 U is the ATOMIC MASS of Hydrogen.

HOPE it helps

Discussion

4.	The electronegativities of two elements are 1.0 and 3.5 .Bond formed btw them is?
Answer» Explanation: REFER to the table below: Electronegativity TYPE of Difference BOND Formed 0.0 to 0.2 nonpolar covalent 0.3 to 1.4 polar covalent > 1.5. ionic hope it HELPS you

4.

The electronegativities of two elements are 1.0 and 3.5 .Bond formed btw them is?

Answer»

Explanation:

REFER to the table below:

Electronegativity TYPE of

Difference BOND Formed

0.0 to 0.2 nonpolar covalent

0.3 to 1.4 polar covalent

> 1.5. ionic

hope it HELPS you

Discussion

5.	Study of the shift in equilibrium between ferric ions and thiocyanate ions by increasing/ decreasing the concentration of their ions.
Answer» ANSWER: skskfkbkbbjbsskvlcalcbifkweoyqeuiljdwsbmgakwkbknbkdmdhdkdd skskff, EXPLANATION: dmffkbjskajfbjvjshsmshcchchcmccmvmcmcmcmcmcmcmcdmdjfibmwbfjvmdmqiqqqqirigibjcmsskskfkfckckcbkffkfkfkffkfkfkkffkfkfjfjbmddjbhvsmsms jsdkfkfkbbjfkfmfmfmfmfmfkfkfkfkfkffffmfmfkfmfmbvjdmhbnmggibjfmwmejbbkqiqoqoqpqodlrkgbkwkbkfrjbcidrjtubdjwjfjvmrkfbkf, akdkf, vkscjcjfdkdmfhfmff, FMFM

5.

Study of the shift in equilibrium between ferric ions and thiocyanate ions by increasing/ decreasing the concentration of their ions.

Answer»

ANSWER:

skskfkbkbbjbsskvlcalcbifkweoyqeuiljdwsbmgakwkbknbkdmdhdkdd

skskff,

EXPLANATION:

dmffkbjskajfbjvjshsmshcchchcmccmvmcmcmcmcmcmcmcdmdjfibmwbfjvmdmqiqqqqirigibjcmsskskfkfckckcbkffkfkfkffkfkfkkffkfkfjfjbmddjbhvsmsms

jsdkfkfkbbjfkfmfmfmfmfmfkfkfkfkfkffffmfmfkfmfmbvjdmhbnmggibjfmwmejbbkqiqoqoqpqodlrkgbkwkbkfrjbcidrjtubdjwjfjvmrkfbkf, akdkf, vkscjcjfdkdmfhfmff, FMFM

Discussion

6.	पूरक मात्रक को इंग्लिश में क्या लिखते है
Answer» ANSWER: SUPPLEMENTARY UNIT

6.

पूरक मात्रक को इंग्लिश में क्या लिखते है

Answer»

ANSWER:

SUPPLEMENTARY UNIT

Discussion

7.	Structure of Atom14. Number of spectral line in Balmer series when anelectron return from 7th orbit to 1st orbit of hydrogenatom are(1) 5(3) 21(4) 8(2) 6
Answer» Answer: 2 Explanation: It COMES after..the ..

7.

Structure of Atom14. Number of spectral line in Balmer series when anelectron return from 7th orbit to 1st orbit of hydrogenatom are(1) 5(3) 21(4) 8(2) 6

Answer»

Answer:

2

Explanation:

It COMES after..the ..

Discussion

8.	Do any object is made up of entirely ions?
Answer» Hope it may be HELPFUL plz MARK as brainliest Be happy GOOD LUCK

8.

Do any object is made up of entirely ions?

Answer»

Hope it may be HELPFUL

plz MARK as brainliest

Be happy

GOOD LUCK

Discussion

9.	A + 2 b + 36 gives a b to c three reaction of 6 gram of a 6 into 10 raise to power 23 atom of b and 0.036 mole of c = 4.8 gram of compound ab2 c3
Answer» ANSWER: Here is your answer Explanation: ATOMIC mass of A = 60 g/MOL Atomic mass of A = 60 g/molAtomic mass of B = x g/mol Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/mol Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/molMoles =\frac{\TEXT{given mass}}{\text{molar mass}} Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/molMoles =\frac{\text{given mass}}{\text{molar mass}}Moles of A = \frac{6 g}{60 g/mol}=0.1 mol Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/molMoles =\frac{\text{given mass}}{\text{molar mass}}Moles of A = \frac{6 g}{60 g/mol}=0.1 molMoles of C = 0.036 mol Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/molMoles =\frac{\text{given mass}}{\text{molar mass}}Moles of A = \frac{6 g}{60 g/mol}=0.1 molMoles of C = 0.036 mol6\times 10^{23} atoms of B Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/molMoles =\frac{\text{given mass}}{\text{molar mass}}Moles of A = \frac{6 g}{60 g/mol}=0.1 molMoles of C = 0.036 mol6\times 10^{23} atoms of B1 mol=6.022\times 10^{23}\approx 6\times 10^{23} atoms Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/molMoles =\frac{\text{given mass}}{\text{molar mass}}Moles of A = \frac{6 g}{60 g/mol}=0.1 molMoles of C = 0.036 mol6\times 10^{23} atoms of B1 mol=6.022\times 10^{23}\approx 6\times 10^{23} atoms Moles of B = 1 mol Hope this would be helpful to you.

9.

A + 2 b + 36 gives a b to c three reaction of 6 gram of a 6 into 10 raise to power 23 atom of b and 0.036 mole of c = 4.8 gram of compound ab2 c3

Answer»

ANSWER:

Here is your answer

Explanation:

ATOMIC mass of A = 60 g/MOL

Atomic mass of A = 60 g/molAtomic mass of B = x g/mol

Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/mol

Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/molMoles =\frac{\TEXT{given mass}}{\text{molar mass}}

Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/molMoles =\frac{\text{given mass}}{\text{molar mass}}Moles of A = \frac{6 g}{60 g/mol}=0.1 mol

Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/molMoles =\frac{\text{given mass}}{\text{molar mass}}Moles of A = \frac{6 g}{60 g/mol}=0.1 molMoles of C = 0.036 mol

Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/molMoles =\frac{\text{given mass}}{\text{molar mass}}Moles of A = \frac{6 g}{60 g/mol}=0.1 molMoles of C = 0.036 mol6\times 10^{23} atoms of B

Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/molMoles =\frac{\text{given mass}}{\text{molar mass}}Moles of A = \frac{6 g}{60 g/mol}=0.1 molMoles of C = 0.036 mol6\times 10^{23} atoms of B1 mol=6.022\times 10^{23}\approx 6\times 10^{23} atoms

Atomic mass of A = 60 g/molAtomic mass of B = x g/molAtomic mass of C = 80 g/molMoles =\frac{\text{given mass}}{\text{molar mass}}Moles of A = \frac{6 g}{60 g/mol}=0.1 molMoles of C = 0.036 mol6\times 10^{23} atoms of B1 mol=6.022\times 10^{23}\approx 6\times 10^{23} atoms Moles of B = 1 mol Hope this would be helpful to you.

Discussion

10.	According to bronsted theory, what will act as both acid and base
Answer» I HOPE this HELPS for your WORK. ..... .... ..., ..... ...

10.

According to bronsted theory, what will act as both acid and base

Answer»

I HOPE this HELPS for your WORK. .....

....

...,

.....

...

Discussion

11.	How to take out the mass of hydrogen by comparing it to 1/12 mass of carbon
Answer» EXPLANATION: An atomic mass unit (symbolized AMU or amu) is defined as precisely 1/12 the mass of an atom of carbon-12. The carbon-12 (C-12) atom has six protons and six neutrons in its NUCLEUS. In imprecise TERMS, one AMU is the average of the proton rest mass and the NEUTRON rest mass. HOPE IT HELPS U

11.

How to take out the mass of hydrogen by comparing it to 1/12 mass of carbon

Answer»

EXPLANATION:

An atomic mass unit (symbolized AMU or amu) is defined as precisely 1/12 the mass of an atom of carbon-12. The carbon-12 (C-12) atom has six protons and six neutrons in its NUCLEUS. In imprecise TERMS, one AMU is the average of the proton rest mass and the NEUTRON rest mass.

HOPE IT HELPS U

Discussion

12.	List the pollutants produced by burning of carbon containing fuels.answer in detail please.
Answer» Products formed during combustion of fossil fuels. The primary POLLUTANTS are Carbon Monoxide (CO), Carbon Dioxide (CO2), SULFUR (SO2), NITROGEN Dioxide (NOx), Nitric Oxide (N2O), Volatile organic compounds (VOCs), and HYDROCARBONS (HCs).

12.

List the pollutants produced by burning of carbon containing fuels.answer in detail please.

Answer»

Products formed during combustion of fossil fuels.

The primary POLLUTANTS are Carbon Monoxide (CO), Carbon Dioxide (CO2), SULFUR (SO2), NITROGEN Dioxide (NOx), Nitric Oxide (N2O), Volatile organic compounds (VOCs), and HYDROCARBONS (HCs).

Discussion

13.	Why should we not burn coal in a closed room ?
Answer» EXPLANATION: The reason BEHIND this is that Due to the BURNING the available OXYGEN GETS depleted and it leads to incomplete burning of coal and it leads to formation of carbon mono oxide which is very poisonous. ..

13.

Why should we not burn coal in a closed room ?

Answer»

EXPLANATION:

The reason BEHIND this is that Due to the BURNING the available OXYGEN GETS depleted and it leads to incomplete burning of coal and it leads to formation of carbon mono oxide which is very poisonous. ..

Discussion

14.	Why is combustion considered to be a chemical change ?
Answer» Combustion reactions always involve molecular oxygen O2. Anytime anything BURNS (in the usual sense), it is a combustion reaction. Combustion reactions are almost always exothermic (i.e., they give off heat). ... When ORGANIC MOLECULES combust the reaction products are CARBON dioxide and water (as WELL as heat).

Discussion

15.	9.The ionisation energy of H-atom (in the groundstate) is x kJ. The energy required for an electronto jump from 2nd to 3rd orbit will be(1) x/6(2) 56x-3) 7.2x(4) 5x/36
Answer» Answer: EXPLANATION: PLEASE use this formulae E = -RH ( 1 / (N FINAL)^2 - 1/ (n initial)^2

15.

9.The ionisation energy of H-atom (in the groundstate) is x kJ. The energy required for an electronto jump from 2nd to 3rd orbit will be(1) x/6(2) 56x-3) 7.2x(4) 5x/36

Answer»

Answer:

EXPLANATION: PLEASE use this formulae

E = -RH ( 1 / (N FINAL)^2 - 1/ (n initial)^2

Discussion

16.	Decomposition of CaCO obtained if we take 100kg of CaCO3.1.what is the molar ratio of CaO and CO2 formed?
Answer» Answer: So, we don't have to do much in this question!!! Now, we know , CaCO3 (by HEATING)→CaO + CO2 (↑) therefore, 1 mole of CaCO3 gives 1 mole of CaO….. So, 1 mole of CaCO3 = 100g of CaCO3 AND 1 mole of CaO = (40+16)g=56g of CaO So, 100g of CaCO3 gives 56 g of CaO on heating …. Explanation:

16.

Decomposition of CaCO obtained if we take 100kg of CaCO3.1.what is the molar ratio of CaO and CO2 formed?

Answer»

Answer:

So, we don't have to do much in this question!!!

Now, we know ,

CaCO3 (by HEATING)→CaO + CO2 (↑)

therefore, 1 mole of CaCO3 gives 1 mole of CaO…..

So, 1 mole of CaCO3 = 100g of CaCO3

AND 1 mole of CaO = (40+16)g=56g of CaO

So, 100g of CaCO3 gives 56 g of CaO on heating ….

Explanation:

Discussion

17.	If r, is the radius of the first orbit of hydrogen atomthen the radii of second, third and fourth orbits iterm of r, are(2) 4 r., 9., 160,(4) 2r, 6 r 8 r.(3) 8 r., 271, 64 r.
Answer» Answer: The radii of second, THIRD and fourth orbits in term of first orbit is: Explanation: Formula used for the radius of the orbit will be, (in PM) where, = radius of orbit n = number of orbit Z = ATOMIC number Radius of first orbit, n=1 ..(1) Radius of second orbit, n=2 (from(1)) Radius of third orbit, n=3 (from(1)) Radius of forth orbit, n=4 (from(1)) MARK as brainliest

17.

If r, is the radius of the first orbit of hydrogen atomthen the radii of second, third and fourth orbits iterm of r, are(2) 4 r., 9., 160,(4) 2r, 6 r 8 r.(3) 8 r., 271, 64 r.

Answer»

Answer:

The radii of second, THIRD and fourth orbits in term of first orbit is:

Explanation:

Formula used for the radius of the orbit will be,

(in PM)

where,

= radius of orbit

n = number of orbit

Z = ATOMIC number

Radius of first orbit, n=1

..(1)

Radius of second orbit, n=2

(from(1))

Radius of third orbit, n=3

(from(1))

Radius of forth orbit, n=4

(from(1))

MARK as brainliest

Discussion

18.	In our atmosphere there are many molecules of water but why don't it feel on our body
Answer» ANSWER: because the MOLECULES are very SMALL in SIZE.

18.

In our atmosphere there are many molecules of water but why don't it feel on our body

Answer»

ANSWER:

because the MOLECULES are very SMALL in SIZE.

Discussion

19.	Why it is necessary to attain the ignition temperature of the fuel ?
Answer» $\mathfrak{\huge{\pink{ANSWER}}}$ ✿★Supply of air – Oxygen HELPS incombustion. ✿★Air contains about 29% of oxygen, thus supply of air makes the oxygen available which helps incombustion. ✿★Without oxygen,combustion will not take place. Ignition temperature – For CATCHING FIRE, a combustible SUBSTANCE mustreach its ignition temperature.

19.

Why it is necessary to attain the ignition temperature of the fuel ?

Answer»

$\mathfrak{\huge{\pink{ANSWER}}}$

✿★Supply of air – Oxygen HELPS incombustion.

✿★Air contains about 29% of oxygen, thus supply of air makes the oxygen available which helps incombustion.

✿★Without oxygen,combustion will not take place. Ignition temperature – For CATCHING FIRE, a combustible SUBSTANCE mustreach its ignition temperature.

Discussion

20.	If the energy difference between the ground state of an atom and excited state is 4.4 x 10-19 J. Thewave length of photon required to produce thistransition is(1) 4.5 x 10-7 m (2) 4.5 x 10-7 nm(3) 4.5 x 10-7 H I (4) 4.5 x 10-7 cm
Answer» ANSWER: EXPLANATION: E = hc/lambda

20.

If the energy difference between the ground state of an atom and excited state is 4.4 x 10-19 J. Thewave length of photon required to produce thistransition is(1) 4.5 x 10-7 m (2) 4.5 x 10-7 nm(3) 4.5 x 10-7 H I (4) 4.5 x 10-7 cm

Answer»

ANSWER:

EXPLANATION:

E = hc/lambda

Discussion

21.	Plz help me.state de broglies htpothesis calculate the de broglies wave length of ab electron mass(9.110–³¹kg) moving at 1% speed of light (h=6.6310-³⁴kg m² s-¹)
Answer» ANSWER: EXPLANATION: LAMBDA = H / MC

21.

Plz help me.state de broglies htpothesis calculate the de broglies wave length of ab electron mass(9.110–³¹kg) moving at 1% speed of light (h=6.6310-³⁴kg m² s-¹)

Answer»

ANSWER:

EXPLANATION:

LAMBDA = H / MC

Discussion

22.	What is the name for element As?
Answer» $\mathfrak{\huge{\red{ANSWER}}}$ ♥ARSENIC

22.

What is the name for element As?

Answer»

$\mathfrak{\huge{\red{ANSWER}}}$

♥ARSENIC

Discussion

23.	The container where the process of electrolysis is carried out.
Answer» ANSWER: ELECTROLYTIC CELL is the answer

23.

The container where the process of electrolysis is carried out.

Answer»

ANSWER:

ELECTROLYTIC CELL is the answer

Discussion

24.	PLS answer my question I will make you brianliest
Answer» Answer: P1V1/T1=P2V2/T2 So V2=V1(P1/P2)T2 =400100/125T2/T1 =(400/1.25)1 as T2=T1 =(40000/125)CC =2516100/(255) =1600/5 =320 cc ANSWER

24.

PLS answer my question I will make you brianliest

Answer»

Answer:

P1V1/T1=P2V2/T2

So V2=V1*(P1/P2)*T2

=400*100/125*T2/T1

=(400/1.25)*1 as T2=T1

=(40000/125)CC

=25*16*100/(25*5)

=1600/5

=320 cc ANSWER

Discussion

25.	Which law is confirmed by finding ratio by weight between hydrogen and oxygen in different water samples obtained from different sources ?
Answer» Answer: "LAW of constant proportion " is confirmed by finding ratio of MASSES of HYDROGEN and oxygen in various SAMPLES of water obtained from various sources. Jai shree Radhe radhe

25.

Which law is confirmed by finding ratio by weight between hydrogen and oxygen in different water samples obtained from different sources ?

Answer»

Answer:

"LAW of constant proportion " is confirmed by finding ratio of MASSES of HYDROGEN and oxygen in various SAMPLES of water obtained from various sources.

Jai shree Radhe radhe

Discussion

26.	an electron beam emerged from an accelerator with kinetic energy of 100ev.what is its de-broglie wavelength?
Answer» ANSWER: DE broglie wavelength=1.23×10^-10 m/1.23A° Explanation: Given:K.E=100ev =1.6×10^-17J[1ev=1.6×10^-19J] de broglie wavelength=h/mv =6.67×10^-34/p[p=mv] =6.67 ×10^-34/√2mK.E [square root of 2M K.E] =6.67×10^-34/√2×9.1×10^-31×1.6×10^-17[square root of 2×9.1×10^-31×1.6×10^-17] =6.67 ×10^-33/5.40 ×10-24 =1.23 ×10^-10 =1.23A°

26.

an electron beam emerged from an accelerator with kinetic energy of 100ev.what is its de-broglie wavelength?

Answer»

ANSWER:

DE broglie wavelength=1.23×10^-10 m/1.23A°

Explanation:

Given:K.E=100ev

=1.6×10^-17J[1ev=1.6×10^-19J]

de broglie wavelength=h/mv

=6.67×10^-34/p[p=mv]
=6.67 ×10^-34/√2mK.E [square root of 2M K.E]
=6.67×10^-34/√2×9.1×10^-31×1.6×10^-17[square root of 2×9.1×10^-31×1.6×10^-17]
=6.67 ×10^-33/5.40 ×10-24
=1.23 ×10^-10
=1.23A°

Discussion

27.	in a reaction to k MnO 2 + 16 HCL changes into to 2KCL + 2 Mncl2 + 8 H2O + 5 cl2. reduction product in a given reaction is which one (also give reason) show change in oxidation states plz
Answer» Answer: HCl + KMnO4 → KCl + MnCl2 + H2O + Cl2 ... oxidation, and one for the reduction (see: DIVIDE the REDOX reaction into two HALF- reactions).

27.

in a reaction to k MnO 2 + 16 HCL changes into to 2KCL + 2 Mncl2 + 8 H2O + 5 cl2. reduction product in a given reaction is which one (also give reason) show change in oxidation states plz

Answer»

Answer:

HCl + KMnO4 → KCl + MnCl2 + H2O + Cl2 ... oxidation, and one for the reduction (see: DIVIDE the REDOX reaction into two HALF- reactions).

Discussion

28.	Volume of gas at stp is 1.2 ×10^-8 cm^3.The number of molecules present in it is?First answer gets brainliest
Answer» Answer: 1.2×10^-8×6.022×10^23

28.

Volume of gas at stp is 1.2 ×10^-8 cm^3.The number of molecules present in it is?First answer gets brainliest

Answer»

Answer:

1.2×10^-8×6.022×10^23

Discussion

29.	Diagrame of sublimation of ammonium chloride
Answer» ANSWER: hey buddy Explanation: these DIAGRAM on ur book ..CLASS 10... chapter 1 CHEMISTRY... hope it will help u.... mark as Brain LIST

29.

Diagrame of sublimation of ammonium chloride

Answer»

ANSWER:

hey buddy

Explanation:

these DIAGRAM on ur book ..CLASS 10... chapter 1 CHEMISTRY...

hope it will help u....

mark as Brain LIST

Discussion

30.	Please answer my question frndss
Answer» ANSWER: I'm in 9TH I don't KNOW this

30.

Please answer my question frndss

Answer»

ANSWER:

I'm in 9TH I don't KNOW this

Discussion

31.	The normality of 03M phosphorus acid (H2PO2) is
Answer» Answer: when you will study chemical bonding in chemistry then you will learn some concept which will help you in determining and n factor. and that n factor will help you to obtain normality out of molarity and n factor. one such concept is that when the side atoms are Oxygen and there is a charge over a compound then that charge goes along with oxygen and if the sides ATOM is not oxygen then the charge goes along the LEAST electronegative element present in the compound. the picture given above shows the arrangement of molecules in in H2PO2 ion or H2PO3 molecule. H2PO2 to EXIST as form of of charged compound having a charge of -1. *one more concept of chemical bonding is that only the hydrogen which is connected with oxygen will decide the n factor of compound. so as you could see that there is only one hydrogen which is connected to oxygen the n factor of the compound becomes 1 • • • normality* = n factor x *molarity* *normality***= 1x 03M = 3M

31.

The normality of 03M phosphorus acid (H2PO2) is

Answer»

Answer:

when you will study chemical bonding in chemistry then you will learn some concept which will help you in determining and n factor.

and that n factor will help you to obtain normality out of molarity and n factor.

one such concept is that

when the side atoms are Oxygen and there is a charge over a compound then that charge goes along with oxygen

and if the sides ATOM is not oxygen then the charge goes along the LEAST electronegative element present in the compound.

the picture given above shows the arrangement of molecules in in H2PO2 ion or H2PO3 molecule.

H2PO2 to EXIST as form of of charged compound having a charge of -1.

one more concept of chemical bonding is that only the hydrogen which is connected with oxygen will decide the n factor of compound.

so as you could see that there is only one hydrogen which is connected to oxygen

the n factor of the compound becomes 1

• •

•

normality = n factor x molarity

*normality***= 1x 03M = 3M

Discussion

32.	Ques: Phosphorus reacts with air(oxygen) but it is kept in water as water also contains molecules of oxygen.Why?
Answer» ANSWER: For this REASON, it is even used as a weapon. It forms diphosphorus pentoxide, . However, white phosphorus is only SLIGHTLY soluble in water, and does not react with it, even though water contains oxygen as one of its TWO elements. ... That REACTION uses up the oxygen quickly

32.

Ques: Phosphorus reacts with air(oxygen) but it is kept in water as water also contains molecules of oxygen.Why?

Answer»

ANSWER:

For this REASON, it is even used as a weapon. It forms diphosphorus pentoxide, . However, white phosphorus is only SLIGHTLY soluble in water, and does not react with it, even though water contains oxygen as one of its TWO elements. ... That REACTION uses up the oxygen quickly

Discussion

33.	How do metals form molecule?
Answer» heya mate Yes, atoms of the same metal can form a HOMOGENEOUS MOLECULE by forming COVALENT bonds- this is called metal-metal covalent bond. However, atoms of different metals cannot form covalent bonds, Alloys are FORMED by interstitial BONDING

33.

How do metals form molecule?

Answer»

heya mate

Yes, atoms of the same metal can form a HOMOGENEOUS MOLECULE by forming COVALENT bonds- this is called metal-metal covalent bond. However, atoms of different metals cannot form covalent bonds, Alloys are FORMED by interstitial BONDING

Discussion

34.	Why is hydrogen not used as a fuel though it has the highest calofiric value?
Answer» hydrogen is HIGHLY combustible and it REACTS with air INSTANTLY that's why why hydrogen is not USED as a fuel

Discussion

35.	What happens when water is added to quicklime?What kind of change is it?
Answer» Answer: it is a CHEMICAL change as NEW product is formed.the COLOUR of lime GRADUALLY CHANGES.

35.

What happens when water is added to quicklime?What kind of change is it?

Answer»

Answer:

it is a CHEMICAL change as NEW product is formed.the COLOUR of lime GRADUALLY CHANGES.

Discussion

36.	An oxide of nitrogen contains 25.9% of nitrogen. What is its empirical formula
Answer» ANSWER: Explanation: N2 =25.9 ÷ 14 = 1.85 O2 = 74.1 ÷ 16 = 4.63 N2 = 1.85 ÷ 1.85 = 1 Oxygen = 4.63 ÷ 1.85 = 2.5 N2O5 is he empirical formula PLEASE MARK BRAINLIEST

36.

An oxide of nitrogen contains 25.9% of nitrogen. What is its empirical formula

Answer»

ANSWER:

Explanation:

N2 =25.9 ÷ 14 = 1.85

O2 = 74.1 ÷ 16 = 4.63

N2 = 1.85 ÷ 1.85 = 1

Oxygen = 4.63 ÷ 1.85 = 2.5

N2O5 is he empirical formula

PLEASE MARK BRAINLIEST

Discussion

37.	Number of chiral center present in above compounds are:(a) 1,2(b) 2,2(c) 2,1
Answer» B is a CORRECT ANSWER its 2, NUMBER 2

37.

Number of chiral center present in above compounds are:(a) 1,2(b) 2,2(c) 2,1

Answer»

B is a CORRECT ANSWER its 2, NUMBER 2

Discussion

38.	Find the pair of elements having similarproperties by applying Newlands law ofOctaves (Example: Mg & Ca):Set 1: F, Mg, C, O, BSet II: Al, Si, S, CI, Ca
Answer» ANSWER: According to Newlands law of Octaves, ATOMS are arranged according to their atomic WEIGHTS in increasing order and every eighth atom has the same properties to the properties of first atom. There are TOTAL 56 atoms were discovered at the time of Newlands. According to this law following sets of atoms having SIMILAR properties; F = Cl Mg = Ca C = Si O = S B = Al

38.

Find the pair of elements having similarproperties by applying Newlands law ofOctaves (Example: Mg & Ca):Set 1: F, Mg, C, O, BSet II: Al, Si, S, CI, Ca

Answer»

ANSWER:

According to Newlands law of Octaves, ATOMS are arranged according to their atomic WEIGHTS in increasing order and every eighth atom has the same properties to the properties of first atom. There are TOTAL 56 atoms were discovered at the time of Newlands.

According to this law following sets of atoms having SIMILAR properties;

F = Cl

Mg = Ca

C = Si

O = S

B = Al

Discussion

39.	What is differ between bar and atmosphere ???
Answer» The DIFFERENT SCALES of MEASUREMENTS. Their PRETTY MUCH same.

Discussion

40.	When an object made of material P is kept immersed in the blue coloured solution Q. then a chemical changetakes place to form a green coloured solution R and a brown layer of substance S is deposited on the objectis used for making nails and S is used for making electric wires.a. Identify the material P and S?b. Name the solution Q and R.c. Write a balanced chemical equation for the above reaction.PLEASE TELL THE ANSWER....
Answer» <P>1)P is IRON Q is COPPER sulphate solution 2) Q is copper sulphate solution R is ferrous sulphate 3) Fe+CuSo4→FeSO4+Cu

40.

When an object made of material P is kept immersed in the blue coloured solution Q. then a chemical changetakes place to form a green coloured solution R and a brown layer of substance S is deposited on the objectis used for making nails and S is used for making electric wires.a. Identify the material P and S?b. Name the solution Q and R.c. Write a balanced chemical equation for the above reaction.PLEASE TELL THE ANSWER....

Answer»

<P>1)P is IRON

Q is COPPER sulphate solution

2) Q is copper sulphate solution

R is ferrous sulphate

3) Fe+CuSo4→FeSO4+Cu

Discussion

41.	What is the oxidation number of azide ion
Answer» Aside ion N3 has a CHARGE of -1. HENCE it's oxidation number is -1.

Discussion

42.	Determination of melting point of a sold substance or low melting point ( below 100°C) glass capillary tube method( Paraffin oil may be used as bath).
Answer» ANSWER: i .................................................. EXPLANATION:

42.

Determination of melting point of a sold substance or low melting point ( below 100°C) glass capillary tube method( Paraffin oil may be used as bath).

Answer»

ANSWER:

i ..................................................

EXPLANATION:

Discussion

43.	Hey follow me fast plzzz
Answer» ANSWER: ok I will try Explanation: but not SURE

43.

Hey follow me fast plzzz

Answer»

ANSWER:

ok

I will try

Explanation:

but not SURE

Discussion

44.	Why should the atomic size be small for the easy formation of anion
Answer» Answer: The size of an anion is larger than its parent atom because anions are FORMED due to the gain of electrons. When the electrons INCREASE, there are still the same number of protons. The attractive FORCE is thus reduced as there are the same number of protons ATTRACTING an increased number of electrons.

44.

Why should the atomic size be small for the easy formation of anion

Answer»

Answer:

The size of an anion is larger than its parent atom because anions are FORMED due to the gain of electrons. When the electrons INCREASE, there are still the same number of protons. The attractive FORCE is thus reduced as there are the same number of protons ATTRACTING an increased number of electrons.

Discussion

45.	Perparation of dilute solution of known concentration of sulphuric acid, hydrochloric acid and nitric acid.
Answer» Answer: First calculate the VOLUME of concentrated acid and water REQUIRED. Take about 50 mL of distilled water in a 100 mL standard flask. ... MIX the solution by tilting the flask upside down. For the PREPARATION of dilute solution of sulphuric and nitric ACIDS, follow the same procedure.

45.

Perparation of dilute solution of known concentration of sulphuric acid, hydrochloric acid and nitric acid.

Answer»

Answer:

First calculate the VOLUME of concentrated acid and water REQUIRED. Take about 50 mL of distilled water in a 100 mL standard flask. ... MIX the solution by tilting the flask upside down. For the PREPARATION of dilute solution of sulphuric and nitric ACIDS, follow the same procedure.

Discussion

46.	❄9⃣ ☺What happens when an acid reacts with a base? Explain by taking the example of hydrochloric acid andsodium hydroxide. Give equation of the chemical reaction which takes place. What is the special name ofsuch a reaction ?
Answer» ANSWER:It FORMS SALT and water Explanation:

46.

❄9⃣ ☺What happens when an acid reacts with a base? Explain by taking the example of hydrochloric acid andsodium hydroxide. Give equation of the chemical reaction which takes place. What is the special name ofsuch a reaction ?

Answer»

ANSWER:It FORMS SALT and water

Explanation:

Discussion

47.	What is the chemical formula of ‘Sodium Hydroxide’?
Answer» ANSWER: CHEMICAL FORMULA Of SODIUM HYDROXIDE is: NaOH Explanation: *Hope* it *helps* *you*

47.

What is the chemical formula of ‘Sodium Hydroxide’?

Answer»

ANSWER:

CHEMICAL FORMULA Of SODIUM HYDROXIDE is:

NaOH

Explanation:

Hope it helps you

Discussion

48.	What is Linear combination of atomic orbitals?
Answer» DescriptionA linear COMBINATION of ATOMIC orbitals or LCAO is a QUANTUM superposition of atomic orbitals and a technique for calculating molecular orbitals in quantum chemistry. In quantum MECHANICS, ELECTRON configurations of atoms are described as wavefunctions

Discussion

49.	Calculate the percentage of magnesium in Mgso4
Answer» to CALCULATE the mass %in Mgso4 we should know the FORMULA mass% =( mass of atoms in the compound )/mass of compound×100 =mass of mg in compound is 24 GRAM and mass of compound is 120gram mass%=24 / 120×100 =20% so the answer is 20% please mark me as brainliest

49.

Calculate the percentage of magnesium in Mgso4

Answer»

to CALCULATE the mass %in Mgso4 we should know the FORMULA

mass% =( mass of atoms in the compound )/mass of compound×100

=mass of mg in compound is 24 GRAM and mass of compound is 120gram

mass%=24 / 120×100

=20%

so the answer is 20%

please mark me as brainliest

Discussion

50.	which of the following has least Vapour pressure and why A 0.01M glucose B 0.01M Na3PO4 with reason
Answer» Answer: Explanation: vp is INVERSELY PROPORTIONAL to no . solute particles for glucose we have 1/2 for NA3PO4 we have 4 so na3po4 has least VAPOUR PRESSURE

50.

which of the following has least Vapour pressure and why A 0.01M glucose B 0.01M Na3PO4 with reason

Answer»

Answer:

Explanation:

vp is INVERSELY PROPORTIONAL to no . solute particles

for glucose we have 1/2

for NA3PO4 we have 4

so na3po4 has least VAPOUR PRESSURE

Discussion

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