an electron beam emerged from an accelerator with kinetic energy of 10

1.	an electron beam emerged from an accelerator with kinetic energy of 100ev.what is its de-broglie wavelength?
Answer» ANSWER: DE broglie wavelength=1.23×10^-10 m/1.23A° Explanation: Given:K.E=100ev =1.6×10^-17J[1ev=1.6×10^-19J] de broglie wavelength=h/mv =6.67×10^-34/p[p=mv] =6.67 ×10^-34/√2mK.E [square root of 2M K.E] =6.67×10^-34/√2×9.1×10^-31×1.6×10^-17[square root of 2×9.1×10^-31×1.6×10^-17] =6.67 ×10^-33/5.40 ×10-24 =1.23 ×10^-10 =1.23A°

an electron beam emerged from an accelerator with kinetic energy of 100ev.what is its de-broglie wavelength?

Answer»

DE broglie wavelength=1.23×10^-10 m/1.23A°

Explanation:

Given:K.E=100ev

=1.6×10^-17J[1ev=1.6×10^-19J]