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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 301. |
Statement-I: Borax bead test is applicable only to coloured salt. Statement-II: In borax bead test, voloured salts are decmosed to give coloured metal meta borates.A. If Assertion (A) and Reason (R ) both are correct and (R ) is the correct explanation of (A )B. If Assertion (A) and Reason (R ) both are correct but ® is not the correct explanation of (A)C. If (A) is correct but (R ) is incorrectD. If (A ) is incorrect but (R ) is correct. |
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Answer» Correct Answer - 3 `CH_(3)COCH_(2)OH+Ag_(2)Ooverset(Delta)(rarr)CH_(3)COCHO+underset("Silver mirror")(2Agdarr)+H_(2)O` |
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| 302. |
Which of the following can be used to precipitated lead saltA. `K_(2)CrO_(4)`B. KIC. dil. `H_(2)SO_(4)`D. All |
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Answer» Correct Answer - 4 `Pb^(+2)+SO_(4)^(-2)rarrPbSO_(4)underset(("white"))(darr)` `Pb^(+2)+CrO_(4)^(-2)rarr PbCrO_(4)underset(("yellow"))(darr)` `Pb^(+2)+I^(-1)rarr PbI_(2)underset(("yellow"))(darr)` |
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| 303. |
What will happen ?(Also write the chemical equations). (a)When a filter paper moistened with potassium iodate and starch solution is brought in contact with sulphur dioxide gas. (b)When `H_(2)S` gas is made to react with sodium tetrahydroxidoplumbate `(II)` solution. |
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Answer» (a)Blue colouration develops due to the formation of iodine gas. `5 SO_(2)+2lO_(3)^(-)+4 H_(2)Otol_(2)+5 SO_(4)^(2-)+2 H^(+)` `I_(2)` +"starch"to "Blue"("starch iodine absorption complex") (b)Black precipitate is formed owing to the formation of `PbS`. `[Pb(OH)_(4)]^(2-)+H_(2)StoPbSdarr+2OH^(-)+2 H_(2)O` |
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| 304. |
In fifth group, `(NH_(4))_(2)CO_(3)` is added to precipitate out the carbonates. We do not add `Na_(2)CO_(3)` because:A. `CaCO_(3)` is soluble in `Na_(2)CO_(3)`B. `Na_(2)CO_(3)` increases the solubility of fifth group carbonatesC. `MgCO_(3)` will be precipitated out in fifth groupD. none |
| Answer» Correct Answer - C | |
| 305. |
A brown gas which itensifies on adding cu-turnings in conc.`H_(2)SO_(4)` test is` NO_(2)` Copper reacts with conc.`HNO_(3)` to give `NO_(2)` |
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Answer» Correct Answer - A On adding cu turning brown colour intensified because it also convert `HNO_(3)` into `NO_(2)`. |
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| 306. |
Which basic radicals form `o x o`-cations in aqueous solutions ? |
| Answer» Correct Answer - `Bi^(3+)` gives `BiO^(+)` ions and `Sb^(3+)` gives `Sb^(3+)` ion.`Bl^(3+) + Cl^(-) +H_(2)O to BiO.Cl darr + 2H^(+)` | |
| 307. |
Which of the following pairs of compounds contain species that react with each other on mixing their aqueous solutions to give yellow precipitate ?A. NaI and NaClB. NaCl and `I_(2)`C. `AgNO_(3)` and NalD. `Pb(NO_(3))_(2)` and Nal |
| Answer» Correct Answer - C,D | |
| 308. |
`Fe^(2+) (aq)+NO_(3)^(-) (aq)+H_(2)SO_(4) (conc.) to` Brown ring The brown ring is due to the formation of complex, `[Fe(H_(2)O)_(5)NO]SO_(4)`. What is the oxidation state of iron in the complex ? |
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Answer» Correct Answer - 1 Here `NO` is `NO^(+)`, so in `[Fe(H_(2)O)_(5)NO^(+)]^(2+)`, the oxidation state of iron is `+1` |
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| 309. |
The brown ring test for `NO_(2)^(-)` and `NO_(3)^(-)` is due to the formation of complex ion with formula `:`A. `[Fe(H_(2)O)_(6)]^(2+)`B. `[Fe(NO)(CN)_(5)]^(2-)`C. `[Fe(H_(2)O)_(5)(NO)]^(2+)`D. `[Fe(H_(2)O)(NO)_(5)]^(2+)` |
| Answer» Correct Answer - C | |
| 310. |
Statement-1 :`V` group basic radicals are precipitated as their carbonates by `(NH_(4))_(2)CO_(3)` in presence of ammonia or ammonium chloride. Statement-2 :Aqueous ammonia maintains the `pH` of the solution basic.A. STATEMENT-1 is true, STATEMENT-2 is true and STATEMENT-2 is correct explanation for STATEMENT-1B. STATEMENT-1 is true, STATEMENT-2 is true and STATEMENT-2 is not correct explanation for STATEMENT-2C. STATEMENT-1 is true, STATEMENT-2 is falseD. STATEMENT-1 is false, STATEMENT-2 is true |
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Answer» Correct Answer - B Statement-1 :In the presence of `NH_(4)^(+)` salts, no precipitation of `Mg^(2+)` occurs because the equilibrium `NH_(4)^(+) + CO_(3)^(2-) hArr NH_(3) +HCO_(3)^(-)` is shifted towards the formation of `HCO_(3)^(-)` ions. `K_(sp)` of the precipitate being high (`K_(sp)` of pure `MgCO_(3)` is `1xx10^(-5)`), the concentration of carbonate ions necessary to produce a precipitate is not attained. Statement-2 :`NH_(4)OH` turns red litmus blue.`NH_(4)OH hArr NH_(4)^(+) +OH^(-)` |
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| 311. |
Statement-1 :White precipitate of `Mg(OH)_(2)` is insoluble in excess of sodium hydroxide but readily soluble in solution of ammonium salts. Statement-2 :`Mg(OH)_(2)` is very sparingly soluble in water.A. STATEMENT-1 is true, STATEMENT-2 is true and STATEMENT-2 is correct explanation for STATEMENT-1B. STATEMENT-1 is true, STATEMENT-2 is true and STATEMENT-2 is not correct explanation for STATEMENT-2C. STATEMENT-1 is true, STATEMENT-2 is falseD. STATEMENT-1 is false, STATEMENT-2 is true |
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Answer» Correct Answer - B Statement-1: In presence of ammonium salts the reaction proceeds in backward direction forming ammonia gas. Statement-2 :`Mg(OH)_(2) darr` is insoluble in water. |
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| 312. |
What is the group reagent of `III^(rd)` gp of basic radicals |
| Answer» `NH_(4)OH` in presence of `NH_(4)Cl` | |
| 313. |
A metal chloride original solution (i.e. `O.S`) on mixing with `K_(2)CrO_(4)` solution give a yellow precipitate soluble in aqueous sodium hydroxide.The metal may be:A. mercuryB. ironC. silverD. lead |
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Answer» Correct Answer - D `Pb^(2+)+CrO_(4)^(2-)toPbCrO_(4)darr("yellow"),PbCrO_(4)darr+4OH^(-)to[Pb(OH)_(4)]^(2-)+CrO_(4)^(2-)` |
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| 314. |
Statement-1 : In dilute solution of strontium ions, yellow precipitate of `SrCrO_(4)` is formed with `CrO_(4)^(2-)` ions. Statement-2 :The `SrCrO_(4)` precipitate is appreciably soluble in water, therefore, no precipitation occurs when water is taken in large quantity.A. STATEMENT-1 is true, STATEMENT-2 is true and STATEMENT-2 is correct explanation for STATEMENT-1B. STATEMENT-1 is true, STATEMENT-2 is true and STATEMENT-2 is not correct explanation for STATEMENT-2C. STATEMENT-1 is true, STATEMENT-2 is falseD. STATEMENT-1 is false, STATEMENT-2 is true |
| Answer» Correct Answer - D | |
| 315. |
Both `NO_(2)` and `Br_(2)` are brown gases. How can they be identified if placed separately in two containers? |
| Answer» Water is added in both the container.The yellowish solution confirms `Br_(2)` in container where colourless solution confirms `NO_(2)` in container. | |
| 316. |
A white coloured carbonate which gives apple green color in the flame test.Give formula of that carbonate |
| Answer» Correct Answer - `BaCO_(3)` | |
| 317. |
The reagment (s) that can selectively precipitate `S^(2-)` from a mixture of `S^(2-)` and `SO_(4)^(2-)` in aqueous solution is (are)A. `CuCl_(2)`B. `BaCl_(2)`C. `Pb(O OC CH_(3))_(2)`D. `Na_(2)[Fe(CN)_(5)NO]` |
| Answer» Correct Answer - A::C | |
| 318. |
Consider the following observation: `M_(n+) + HCl` (dilute) `to` white precipitate `overset(Delta)to` water soluble `overset(CrO_(4)^(2-)`yellow precipitate. The metal ion `M^(n+)` will be:A. `Hg^(2+)`B. `Ag^(+)`C. `Pb^(2+)`D. `Sn^(2+)` |
| Answer» Correct Answer - C | |
| 319. |
Name the three chlorides which are insoluble in dilute `HCl`.name one chloride, which is soluble in hot water but insoluble in cold water. |
| Answer» `PbCl_(3),AgCl,Hg_(2)Cl_(2),PbCl_(2)` is soluble is hot water. | |
| 320. |
`S^(2-)` and `SO_(3)^(2-)` can be distinguished by usingA. `(CH_(3)COO)_(2)Pb`B. `Na_(2)[Fe(CN)_(5)NO]`C. both 1 and 2D. none of these |
| Answer» Correct Answer - 3 | |
| 321. |
`S^(2-) " and" SO_(3)^(2-)` can be distinguished by :A. `(CH_(3)CO O)_(2) Pb`B. `Cr_(2)O_(7)^(2-)// H^(+)`C. `Na_(2)[Fe (CN)_(5)NO]`D. `Zn + " dil." H_(2)SO_(4)` followed by `(CH_(3)CO O)_(2)Pb` |
| Answer» Correct Answer - A::B::C | |
| 322. |
Assertion `Ca^(2+)` and `Ba^(2+)` can be distinguished by treatment with `Na_(2)C_(2)O_(4)` solution. Reason `CaC_(2)O_(4)` is soluble in dilute acetic acid while `BaC_(2)O_(4)` is insoluble in dilute acetic acid solution. |
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Answer» Correct Answer - C |
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| 323. |
`Na_(2)SO_(4)` and `Na_(2)S` can be distinguished from each other by using:A. dilute `H_(2)SO_(4)`B. acidified `KMnO_(4)` solutionC. sodium nitroprusside solutionD. cadmium acetate solution |
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Answer» Correct Answer - A,B,C,D (A)`Na_(2)S+H^(+)toH_(2)Suarr+2Na^(+).,Na_(2)SO_(4)` gives no reaction with `H_(2)SO_(4)` (B)`2MnO_(4)^(-)`(pink solution)+`5H_(2)S+6H^(+) to 2Mn^(2+)` (colourless) +`5S darr +8H_(2)O` No colour change is observed with `Na_(2)SO_(4)` ( C)`S^(2-)+[Fe(CN)_(5)NO]^(2-) to [Fe(CN)_(5)NOS]^(4-)` (purple or violet colouration) No colour change is observed with `Na_(2)SO_(4)` (D)`S^(2-)+Cd^(2+) to CdS darr` (yellow). `Na_(2)SO_(4)` forms `CdSO_(4)` which is water soluble. |
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| 324. |
Which of the following pairs of cations cannot be separated by adding `NH_(4)Cl` and `NH_(4)OH` to the mixture and then passing `H_(2)S` through it?A. `Fe^(+3),Zn^(+2)`B. `Ca^(+2),Ni^(+2)`C. `Co^(+2),Mn^(+2)`D. `Co^(+2),Al^(+3)` |
| Answer» Correct Answer - 3 | |
| 325. |
Which of the following pairs is not distinguished by passing `H_(2)S` ?A. `Hg^(2+),Pb^(2+)`B. `Cd^(2+),Pb^(2+)`C. `Sb^(2+),Cd^(2+)`D. `Zn^(2+),Mn^(2+)` |
| Answer» Correct Answer - 1 | |
| 326. |
Which of these is the correct group reagent for group cations ?A. `Mn^(2+)Co^(2+)Zn^(2+)Ni^(2+),"dil"HCl`B. `Mn^(2+)Co^(2+)Zn^(2+)Ni^(2+),NH_(4)Cl+NH_(4)OH+H_(2)S`C. `Mn^(2+)Co^(2+)Zn^(2+)Ni^(2+),NH_(4)Cl+NH_(4)OH`D. `Mn^(2+)Co^(2+)Zn^(2+)Ni^(2+),HCl+H_(2)S` |
| Answer» Correct Answer - B | |
| 327. |
On addition of aqueous NaOH to a salt solution, a white gelatinous precipitate is formed, which dissolves in excess of alkali. The salt solution containsA. Aluminium ionsB. Barium ionsC. Ferric ionsD. Calcium ions |
| Answer» Correct Answer - A | |
| 328. |
An inorganic salt in its aqueous solution produced a white ppt. with NaOH which dissolves in excess of NaOH. Also its aqueous solution produced light yellow ppt., with `AgNO_(3)` sparingly soluble in `NH_(4)OH`. The probable salt isA. `AlBr_(3)`B. `AlI_(3)`C. `AlCl_(3)`D. `ZnCl_(2)` |
| Answer» Correct Answer - A | |
| 329. |
Statement 1 `:` When KI is added to `HgCl_(2)`, a scarlet red ppt comes which dissolves in excess KI because Statement 2 `: HgCl_(2)` reacts with KI to form scarlet red coloured ppt. of `HgI_(2)` which further reacts with excess KI to produce `K_(2)HgI_(4)` a soluble complex. |
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Answer» Correct Answer - A `HgCl_(2)+2KI rarr underset(("Scarlet red ppt."))(HgI_(2)darr)+2KCl` `underset(("Colourless soluble complex"))(HgI_(2)+2KI rarrK_(2)HgI_(4))` |
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| 330. |
A pale green crystalline metal salt of M dissolves freely in water. It gives a brown precipitate on addition of aqueous NaOH. The metal salt solution also gtives a black precipitate on bubbling `H_2 S` in aqueous medium. An aqueous solution of the metal salt decolourizes the pink colour of the premanganate solution. The metal in the metal salt solution isA. CopperB. aluminiumC. lead nitrateD. Iron |
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Answer» Correct Answer - D `FeCl_(2)+"aq."NaOH"rarrunderset(FeOyellow) underset( darr air) (Fe(OH)_(2)(green))` `FeO+MnO_(4)^(-)rarrFe_(2)O_(3)+Mn^(+2)` |
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| 331. |
If NaOH is added to an aqueous solution of zinc ions a white ppt appears and on adding excess `NaOH`, the ppt dissolves. In this solution zinc exist in theA. cationic partB. anionic partC. both in cationic and anionic partsD. there is no zinc ion in the solution |
| Answer» Correct Answer - B | |
| 332. |
Statement-1 :A solution of `BiCl_(3)` in concentrated `HCl` when diluted with water gives white precipitate. Statement-2 :`BiCl_(3)` forms insoluble `BiO^(+)Cl^(-)` when diluted with a large quantity of water.A. STATEMENT-1 is true, STATEMENT-2 is true and STATEMENT-2 is correct explanation for STATEMENT-1B. STATEMENT-1 is true, STATEMENT-2 is true and STATEMENT-2 is not correct explanation for STATEMENT-2C. STATEMENT-1 is true, STATEMENT-2 is falseD. STATEMENT-1 is false, STATEMENT-2 is true |
| Answer» Correct Answer - A | |