Saved Bookmarks
| 1. |
Statement 1 `:` When KI is added to `HgCl_(2)`, a scarlet red ppt comes which dissolves in excess KI because Statement 2 `: HgCl_(2)` reacts with KI to form scarlet red coloured ppt. of `HgI_(2)` which further reacts with excess KI to produce `K_(2)HgI_(4)` a soluble complex. |
|
Answer» Correct Answer - A `HgCl_(2)+2KI rarr underset(("Scarlet red ppt."))(HgI_(2)darr)+2KCl` `underset(("Colourless soluble complex"))(HgI_(2)+2KI rarrK_(2)HgI_(4))` |
|