98971 + Interview Questions in Primary School in Math

1.	You are washing a coat convert passive
Answer» ONG>ANSWER: A COAT is being WASHED by you.

Discussion

2.	Find the x in each of the following :pls pls help me it's very urgent
Answer» ong>Answer: given: X%of 1800=81 x/1001800=81 18x=81 x=81/18 x=4.5 thus, x = 4.5% 4.5%of 1800= 81 therefore eq. satisfied. Step-by-step explanation:* BRAINLIEST

2.

Find the x in each of the following :pls pls help me it's very urgent

Answer»

ong>Answer:

given: X%of 1800=81

x/100*1800=81

18x=81

x=81/18

x=4.5

thus, x = 4.5%

4.5%of 1800= 81

therefore eq. satisfied.

Step-by-step explanation:

BRAINLIEST

Discussion

3.	8)If 10 less than a number is 65,then the number is_______
Answer» ong>Answer: Let the number be X. According to QUESTION, x - 10 = 65 x = 65 + 10 x = 75 Hence the number is 75. HOPE IT HELPS✌

3.

8)If 10 less than a number is 65,then the number is_______

Answer»

ong>Answer:

Let the number be X.

According to QUESTION,

x - 10 = 65

x = 65 + 10

x = 75

Hence the number is 75.

HOPE IT HELPS✌

Discussion

4.	AN OBJECT OF 0.75 m COSTS RUPEES 5625 . WHAT IS THE COST OF AN OBJECT OF 1m ?
Answer» $\huge{\underline{\pink{\bold{\underline{\mathrm{«ANS{\orange{WER»}}}}}}}}$ $0.75 = 5625 \\ \: 1m = \frac{5625}{0.75} = 7500$

4.

AN OBJECT OF 0.75 m COSTS RUPEES 5625 . WHAT IS THE COST OF AN OBJECT OF 1m ?

Answer»

$\huge{\underline{\pink{\bold{\underline{\mathrm{«ANS{\orange{WER»}}}}}}}}$

$0.75 = 5625 \\ \: 1m = \frac{5625}{0.75} = 7500$

Discussion

5.	If PA and PB are tangents from an outside point P such that PA = 6 cm and angle APB = 60° .find the length of the chord AB.
Answer» align="absmiddle" alt="\large\red{\bf{\underline{Question:-}}}" CLASS="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%5Clarge%5Cred%7B%5Cbf%7B%5Cunderline%7BQuestion%3A-%7D%7D%7D" title="\large\red{\bf{\underline{Question:-}}}"> If PA and PB are tangents from an outside point P such that PA = 6 cm and angle APB = 60° .find the length of the CHORD AB. $\large\red{\bf{\underline{Solution:-}}}$ Given:- PA and PB are tangents of a circle, PA = 10 cm and ∠APB = 60° To find:- Length Of Chord AB. Step By Step Explanation:- Let O be the center of the given circle and C be the point of intersection of OP and AB. In ΔPAC and ΔPBC, 》PA = PB (Tangents from an external point are equal) 》∠APC = ∠BPC (Tangents from an external point are equally inclined to the segment joining center to that point) 》PC = PC (COMMON) Thus, ΔPAC is congruent to ΔPBC (By SAS congruency rule) ..........(1) ∴ AC = BC Also ∠APB = ∠APC + ∠BPC ∠APC= ${\frac{1}{2}}$ ∠APB. [Since,∠APC = ∠BPC] ${\frac{1}{2}}$ ×60° = 30° ∠ACP + ∠BCP = 180°. {∠ACP =∠BCP} ∠ACP = ${\frac{1}{2}}$ × 180° Now, In right triangle ACP, sin30° = ${\frac{AC}{AP}}$ ${\frac{1}{2}}$ = ${\frac{AC}{10}}$ AC = ${\frac{1}{2}}$ × 10 = 5 ∴ AB = AC + BC = AC + AC (AC = BC) ⇒ AB = 5CM + 5cm ⇒ AB = 10CM. ${\huge{\underline{\small{\mathbb{\blue{HOPE\:HELP\:U\:BUDDY :)}}}}}}$ ${\huge{\underline{\small{\mathbb{\pink{~cαndчflσѕѕ♡ :)}}}}}}$

5.

If PA and PB are tangents from an outside point P such that PA = 6 cm and angle APB = 60° .find the length of the chord AB.

Answer»

align="absmiddle" alt="\large\red{\bf{\underline{Question:-}}}" CLASS="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%5Clarge%5Cred%7B%5Cbf%7B%5Cunderline%7BQuestion%3A-%7D%7D%7D" title="\large\red{\bf{\underline{Question:-}}}">

If PA and PB are tangents from an outside point P such that PA = 6 cm and angle APB = 60° .find the length of the CHORD AB.

$\large\red{\bf{\underline{Solution:-}}}$

Given:-

PA and PB are tangents of a circle, PA = 10 cm and ∠APB = 60°

To find:-

Length Of Chord AB.

Step By Step Explanation:-

Let O be the center of the given circle and C be the point of intersection of OP and AB.

In ΔPAC and ΔPBC,

》PA = PB (Tangents from an external point are equal)

》∠APC = ∠BPC (Tangents from an external point are equally inclined to the segment joining center to that point)

》PC = PC (COMMON)

Thus, ΔPAC is congruent to ΔPBC (By SAS congruency rule) ..........(1)

∴ AC = BC

Also ∠APB = ∠APC + ∠BPC

∠APC= ${\frac{1}{2}}$ ∠APB.

[Since,∠APC = ∠BPC]

${\frac{1}{2}}$ ×60° = 30°

∠ACP + ∠BCP = 180°. {∠ACP =∠BCP}

∠ACP = ${\frac{1}{2}}$ × 180°

Now, In right triangle ACP,

sin30° = ${\frac{AC}{AP}}$

${\frac{1}{2}}$ = ${\frac{AC}{10}}$

AC = ${\frac{1}{2}}$ × 10 = 5

∴ AB = AC + BC = AC + AC (AC = BC)

⇒ AB = 5CM + 5cm

⇒ AB = 10CM.

${\huge{\underline{\small{\mathbb{\blue{HOPE\:HELP\:U\:BUDDY :)}}}}}}$

${\huge{\underline{\small{\mathbb{\pink{~cαndчflσѕѕ♡ :)}}}}}}$

Discussion

6.	Following table shows the points of each player scored in four games: PlayerGameGameGameGame1234k1081610B064С811Did not13PlayNow answer the following questions:(i) Find the mean to determine A's average number of points scored per game,(i) To find the mean number of points per game for C, would you divide the topoints by 3 or by 4? Why?(m) B played in all the four games. How would you find the mean?(iv) Who is the best performer?by a group of students in a science test are 8
Answer» ong>ANSWER: Following table SHOWS the points of each player scored in four games: Player Game Game Game Game 1 2 3 4 k 10 8 16 10 B 0 6 4 С 8 11 Did not 13 Play Now answer the following questions: (i) Find the mean to determine A's average number of points scored per game, (i) To find the mean number of points per game for C, would you DIVIDE the to points by 3 or by 4? Why? (m) B played in all the four games. How would you find the mean? (iv) Who is the best performer? by a group of STUDENTS in a science test are 8

6.

Following table shows the points of each player scored in four games: PlayerGameGameGameGame1234k1081610B064С811Did not13PlayNow answer the following questions:(i) Find the mean to determine A's average number of points scored per game,(i) To find the mean number of points per game for C, would you divide the topoints by 3 or by 4? Why?(m) B played in all the four games. How would you find the mean?(iv) Who is the best performer?by a group of students in a science test are 8

Answer»

ong>ANSWER:

Following table SHOWS the points of each player scored in four games:

Player

Game

1

2

3

4

k

10

8

16

10

B

0

6

4

С

8

11

Did not

13

Play

Now answer the following questions:

(i) Find the mean to determine A's average number of points scored per game,

(i) To find the mean number of points per game for C, would you DIVIDE the to

points by 3 or by 4? Why?

(m) B played in all the four games. How would you find the mean?

(iv) Who is the best performer?

by a group of STUDENTS in a science test are 8

Discussion

7.	Half a number added to the number gives 111. What is the number?and not only the answer,but also the explanation
Answer» ONG>Answer: MARK me as the brainliest and FOLLOW me... Step-by-step EXPLANATION: see the ATTACHED file

7.

Half a number added to the number gives 111. What is the number?and not only the answer,but also the explanation

Answer» ONG>Answer:

MARK me as the brainliest and FOLLOW me...

Step-by-step EXPLANATION:

see the ATTACHED file

Discussion

8.	Find the area of rectangle ABCD whose : AB = 28m, BC=5.6
Answer» ONG>Answer: 2x 28+2x5.6 = 36+11.2 =47.2

8.

Find the area of rectangle ABCD whose : AB = 28m, BC=5.6

Answer» ONG>Answer:

2x 28+2x5.6

= 36+11.2

=47.2

Discussion

9.	Find the product by suitable rearrangement 8x391x125
Answer» ong>ANSWER: first we MULTIPLY 8×wet we get 100 then we multiply 1000×391 Ans:391000

9.

Find the product by suitable rearrangement 8x391x125

Answer»

ong>ANSWER:

first we MULTIPLY

8×wet we get 100

then we multiply 1000×391

Ans:391000

Discussion

10.	Q16. Acar travels 432 km on 48 litres of petrol-How far would it travel on 20 litres of petrol
Answer» ONG>ANSWER: 180 Step-by-step explanation: 432/48 = 9 20×9= 180 so that is the answer

10.

Q16. Acar travels 432 km on 48 litres of petrol-How far would it travel on 20 litres of petrol

Answer» ONG>ANSWER:

180

Step-by-step explanation:

432/48 = 9

20×9= 180

so that is the answer

Discussion

11.	Pls pls help me it's very urgent
Answer» ONG>Step-by-step EXPLANATION: $\sf\large\underline\purple{Answer:-}$ $\displaystyle \sf \longrightarrow \: 30\% \times x = 54 \\ \\ \displaystyle \sf \longrightarrow \frac{30}{100} \times x = 54 \\ \\ \displaystyle \sf \longrightarrow x = \frac{5400}{30} = 180$

11.

Pls pls help me it's very urgent

Answer» ONG>Step-by-step EXPLANATION:

$\sf\large\underline\purple{Answer:-}$

$\displaystyle \sf \longrightarrow \: 30\% \times x = 54 \\ \\ \displaystyle \sf \longrightarrow \frac{30}{100} \times x = 54 \\ \\ \displaystyle \sf \longrightarrow x = \frac{5400}{30} = 180$

Discussion

12.	(6p -⅓)³ expand plzz give me this answer I want
Answer» ASE MARK me as BRAINLIEST and PLEASE FOLLOW me

Discussion

13.	Write the simplest form of -78/28
Answer» ONG>Answer: -39/14 Step-by-step EXPLANATION: make me BRANLIST

13.

Write the simplest form of -78/28

Answer» ONG>Answer:

-39/14

Step-by-step EXPLANATION:

make me BRANLIST

Discussion

14.	If marked price = Rs 2300 , selling price = Rs 1684, then discount is
Answer» ONG>Answer: Marked PRICE = RS.2300 Selling price = Rs.1684 Discount = Rs.(2300-1684) = Rs.616

14.

If marked price = Rs 2300 , selling price = Rs 1684, then discount is

Answer» ONG>Answer:

Marked PRICE = RS.2300

Selling price = Rs.1684

Discount = Rs.(2300-1684) = Rs.616

Discussion

15.	Fill in the blank by finding the numerator:1) 5/4 = /16
Answer» ONG>Answer: 5 Step-by-step explanation: 5/4jsieifjtrorrkrkejedd

15.

Fill in the blank by finding the numerator:1) 5/4 = /16

Answer» ONG>Answer:

5

Step-by-step explanation:

5/4jsieifjtrorrkrkejedd

Discussion

16.	A van moves 100 miles in 2 hours. What is its average speed in miles per hour?
Answer» ong>Answer: 50 Step-by-step explanation: if it travceled 100MILES in 2 hours DIVIDE the hundred by 2 and you get 50 your answer

16.

A van moves 100 miles in 2 hours. What is its average speed in miles per hour?

Answer»

ong>Answer:

50

Step-by-step explanation:

if it travceled 100MILES in 2 hours DIVIDE the hundred by 2 and you get 50 your answer

Discussion

17.	Verify .[-30]×[13+[-3]={[-30]×13]+{[-30]×[-3]
Answer» align="absmiddle" alt="\Huge\red{\MATHBB{ HEYA \: BUDDY }}" class="latex-formula" id="TexFormula1" SRC="https://tex.z-dn.net/?f=%5CHuge%5Cred%7B%5Cmathbb%7B%20HEYA%20%5C%3A%20BUDDY%20%7D%7D" title="\Huge\red{\mathbb{ HEYA \: BUDDY }}"> $\large\green{\bf{Solution}}$ [−30] × 13 + [−3] = [−30] × 13 + [−30] × [−3] [-30] × [13-3] = ([-30] × 13) + ([-30] × [-3]) [−30] × 10 = (-390) + 90 (-300) = (-300). HENCE, both sides are proved equally. ${\huge{\underline{\small{\mathbb{\blue{HOPE\:HELP\:U\:BUDDY :)}}}}}}$ ${\huge{\underline{\small{\mathbb{\pink{~cαndчflσѕѕ♡ :)}}}}}}$

17.

Verify .[-30]×[13+[-3]={[-30]×13]+{[-30]×[-3]

Answer»

align="absmiddle" alt="\Huge\red{\MATHBB{ HEYA \: BUDDY }}" class="latex-formula" id="TexFormula1" SRC="https://tex.z-dn.net/?f=%5CHuge%5Cred%7B%5Cmathbb%7B%20HEYA%20%5C%3A%20BUDDY%20%7D%7D" title="\Huge\red{\mathbb{ HEYA \: BUDDY }}">

$\large\green{\bf{Solution}}$

[−30] × 13 + [−3] = [−30] × 13 + [−30] × [−3]

[-30] × [13-3] = ([-30] × 13) + ([-30] × [-3])

[−30] × 10 = (-390) + 90

(-300) = (-300).

HENCE, both sides are proved equally.

${\huge{\underline{\small{\mathbb{\blue{HOPE\:HELP\:U\:BUDDY :)}}}}}}$

${\huge{\underline{\small{\mathbb{\pink{~cαndчflσѕѕ♡ :)}}}}}}$

Discussion

18.	Solve it by yourself7+3-3=
Answer» ONG>ANSWER: $7 + 3 - 3$ $= > 10 - 3$ $= > 7$

18.

Solve it by yourself7+3-3=

Answer» ONG>ANSWER:

$7 + 3 - 3$

$= > 10 - 3$

$= > 7$

Discussion

19.	) n + 12 = 30, if n = 18
Answer» ong>ANSWER: It's SIMPLE . You have already written the answer. n+12 = 30 18+12 = 30

19.

) n + 12 = 30, if n = 18

Answer»

ong>ANSWER:

It's SIMPLE .

You have already written the answer.

n+12 = 30

18+12 = 30

Discussion

20.	फाइंड द प्रोडक्ट बाय सूटेबल रिअरेंजमेंट
Answer» ONG>ANSWER: ????????????? sorry all the BEST

20.

फाइंड द प्रोडक्ट बाय सूटेबल रिअरेंजमेंट

Answer» ONG>ANSWER:

?????????????

sorry

all the BEST

Discussion

21.	2. Find the measures of x, y and z in the figure where l \|\| AC.
Answer» ONG>ANSWER: z = 55 ( alternate angle ) x = 65 (alternate angle ) y = 180 - x - z ( angle sum property of TRIANGLE ) y = 180 - 120 y = 60

21.

2. Find the measures of x, y and z in the figure where l || AC.

Answer» ONG>ANSWER:

z = 55 ( alternate angle )

x = 65 (alternate angle )

y = 180 - x - z ( angle sum property of TRIANGLE )

y = 180 - 120

y = 60

Discussion

22.	3x/5x+2=-4 tell answer
Answer» ONG>Step-by-step explanation: 3x/5x+2=-4 3x=-4(5x+2) 3x=-20x-8 3x+20x=-8 23x=-8 x=-8/23

22.

3x/5x+2=-4 tell answer

Answer» ONG>Step-by-step explanation:

3x/5x+2=-4

3x=-4(5x+2)

3x=-20x-8

3x+20x=-8

23x=-8

x=-8/23

Discussion

23.	Plz compare the fraction and tell answer fast plz
Answer» ONG>Answer: 7/5 is greater Step-by-step EXPLANATION: TAKE the lcm of DENOMINATOR and then compare

23.

Plz compare the fraction and tell answer fast plz

Answer» ONG>Answer:

7/5 is greater

Step-by-step EXPLANATION:

TAKE the lcm of DENOMINATOR and then compare

Discussion

24.	X2 − 3x2y − 4x+ 7 if x= −2, y= 2
Answer» ONG>Step-by-step EXPLANATION: hshehjrjshhrjtrjkrzhhxzhhxs gxhdbdnfdjhxjftkfjdjdjtmrjzhjenfktiehsjdnguwdhdhdjnddjxhxnfndndndbdbdnfnnddndbd

Discussion

25.	If a transversal intersect two parallel lines such that the ratio between the interior angles on one of its side is 3:7,then find the measure of the smaller angle *
Answer» ong>Answer: Given:- AB parallel to CD and T is the transversal. Angles 1 and 2 are TWO angles on the same side of transversal in ration 3:7 Angle 1 : 3x Angle 2 : 7x We know that angle 1 + 2 = 180 DEGREES [angles are supplementry] So, 3x + 7x = 180 10x = 180 x = 18 So, angle 1 = 3x = 3 × 18 = 54 degree angle 2 = 7x = 7 × 18 = 126 degree Therefore, Smaller angle = 54 degree! HOPE it helps you :)

25.

If a transversal intersect two parallel lines such that the ratio between the interior angles on one of its side is 3:7,then find the measure of the smaller angle *

Answer»

ong>Answer:

Given:-

AB parallel to CD and T is the transversal.

Angles 1 and 2 are TWO angles on the same side of transversal in ration 3:7

Angle 1 : 3x

Angle 2 : 7x

We know that angle 1 + 2 = 180 DEGREES

[angles are supplementry]

So, 3x + 7x = 180

10x = 180

x = 18

So, angle 1 = 3x = 3 × 18 = 54 degree

angle 2 = 7x = 7 × 18 = 126 degree

Therefore,

Smaller angle = 54 degree!

HOPE it helps you :)

Discussion

26.	If one of the zero of the polynomial x²+3x+k is 2 then the value of k is
Answer» align="absmiddle" alt="\huge\purple{\MATHBB{HEYA \: BUDDY}}" class="latex-formula" ID="TexFormula1" src="https://tex.z-dn.net/?f=%20%5Chuge%5Cpurple%7B%5Cmathbb%7BHEYA%20%5C%3A%20BUDDY%7D%7D" title="\huge\purple{\mathbb{HEYA \: BUDDY}}"> $\large\red{\sf{Question:-}}$ If one of the zero of the polynomial x²+3x+k is 2 then the value of k is? $\large\red{\sf{Answer:-}}$ Since 2 is one of the zero of the polynomial ${x}^{2} + 3x + k$ Therefore, putting value of x = 2 in the above equation, we get, $\text{[math]}$ ${2}^{2} + 3(2) + k$ => 4 + 6+ k = 0 => 10 + k = 0 => k = -10. Which is the required answer. ${\huge{\underline{\small{\mathbb{\blue{HOPE\:HELP\:U\:BUDDY :)}}}}}}$ ${\huge{\underline{\small{\mathbb{\pink{~cαndчflσѕѕ♡ :)}}}}}}$

26.

If one of the zero of the polynomial x²+3x+k is 2 then the value of k is

Answer»

align="absmiddle" alt="\huge\purple{\MATHBB{HEYA \: BUDDY}}" class="latex-formula" ID="TexFormula1" src="https://tex.z-dn.net/?f=%20%5Chuge%5Cpurple%7B%5Cmathbb%7BHEYA%20%5C%3A%20BUDDY%7D%7D" title="\huge\purple{\mathbb{HEYA \: BUDDY}}">

$\large\red{\sf{Question:-}}$

If one of the zero of the polynomial x²+3x+k is 2 then the value of k is?

$\large\red{\sf{Answer:-}}$

Since 2 is one of the zero of the polynomial

${x}^{2} + 3x + k$

Therefore, putting value of x = 2 in the above equation, we get,

$\text{[math]}$

${2}^{2} + 3(2) + k$

=> 4 + 6+ k = 0

=> 10 + k = 0

=> k = -10.

Which is the required answer.

${\huge{\underline{\small{\mathbb{\blue{HOPE\:HELP\:U\:BUDDY :)}}}}}}$

${\huge{\underline{\small{\mathbb{\pink{~cαndчflσѕѕ♡ :)}}}}}}$

Discussion

27.	X³-114x plz tell ans
Answer» ONG>Step-by-step explanation: HOPE it HELPS PLS mark me as branliest

27.

X³-114x plz tell ans

Answer» ONG>Step-by-step explanation:

HOPE it HELPS

PLS mark me as branliest

Discussion

28.	a man bought a refrigerator for rupees 356 15 and paid rupees 125 18 transportation is called it for 33953 find his gain or loss percent
Answer» ONG>Step-by-step explanation: 356 15 - 125 18 =23,097 LOSS

Discussion

29.	sumitra has 34 rupees in 50 paise and 25 paise coins.If the number of 25 paise coins is twice the number of 50 paise coins, how many coins of each kind does she have?
Answer» ong>Step-by-step explanation: ANSWER Let SUMITRA has ′ x ′ 50-paise COINS and ′ y ′ 25-paise coins She has Rs34 Since Rs1=100paise Rs34=34×100=3400paise

29.

sumitra has 34 rupees in 50 paise and 25 paise coins.If the number of 25 paise coins is twice the number of 50 paise coins, how many coins of each kind does she have?

Answer»

ong>Step-by-step explanation:

ANSWER

Let SUMITRA has

′

x

′

50-paise COINS and

′

y

′

25-paise coins

She has Rs34

Since Rs1=100paise

Rs34=34×100=3400paise

Discussion

30.	Genius answer it in copy!
Answer» ong>ANSWER: TRAPEZIUM area=a+b/2h =[{24+15/212}+{21+15/210}]cm^2 ={234+180}cm^2 =414cm^2

30.

Genius answer it in copy!

Answer»

ong>ANSWER:

TRAPEZIUM area=a+b/2h

=[{24+15/2*12}+{21+15/2*10}]cm^2

={234+180}cm^2

=414cm^2

Discussion

31.	2 − 32 − 4 + 7 if = −2, = 2
Answer» ONG>ANSWER: I don't no Step-by-step EXPLANATION: please MARK me BRANLIEST

31.

2 − 32 − 4 + 7 if = −2, = 2

Answer» ONG>ANSWER:

I don't no

Step-by-step EXPLANATION:

please MARK me BRANLIEST

Discussion

32.	Find the value of 6¼ of 800
Answer» ONG>Step-by-step explanation: 25/4 of 800 = 25/4×800 = 5000 THIS IS UR ANSWER MATE.......✌ BRAINLIEST PLZ

32.

Find the value of 6¼ of 800

Answer» ONG>Step-by-step explanation:

25/4 of 800

= 25/4×800

= 5000

THIS IS UR ANSWER MATE.......✌

BRAINLIEST PLZ

Discussion

33.	100
Answer» ONG>Answer: sorry Step-by-step EXPLANATION: i can't remember your questions

33.

100

Answer» ONG>Answer:

sorry

Step-by-step EXPLANATION:

i can't remember your questions

Discussion

34.	If equal ade of isoceles right angled triangle is 12cm then find area
Answer» ong>Answer: 4.9 Step-by-step explanation: Let ABC be the given triangle right angled at B with AB=BC — (1) AREA OF TRIANGLE = $12cm^{2}$ Area of triangle = $\frac{1}{2}$ bh ==》 $\frac{1}{2}$ × BC × AB = 12 ==》 $\frac{1}{2}$ × BC × BC = 12 ==》 $\frac{1}{2}$ × $BC^{2}$ = 12 $BC^{2}$ = 24 BC = 4.9CM (APPROX ) Length of the base= 4.9 cm (approx ) Hope It Helps Please MARK As The Brainliest

34.

If equal ade of isoceles right angled triangle is 12cm then find area

Answer»

ong>Answer:

4.9

Step-by-step explanation:

Let ABC be the given triangle right angled at B with AB=BC — (1)

AREA OF TRIANGLE = $12cm^{2}$

Area of triangle = $\frac{1}{2}$ bh

==》 $\frac{1}{2}$ × BC × AB = 12

==》 $\frac{1}{2}$ × BC × BC = 12

==》 $\frac{1}{2}$ × $BC^{2}$ = 12

$BC^{2}$ = 24

BC = 4.9CM (APPROX )

Length of the base= 4.9 cm (approx )

Hope It Helps

Please MARK As The Brainliest

Discussion

35.	Chapter Indices questions and answers std 7
Answer» ong>ANSWER: okk Step-by-step explanation: THNX for POINTS. ..

35.

Chapter Indices questions and answers std 7

Answer»

ong>ANSWER:

okk

Step-by-step explanation:

THNX for POINTS. ..

Discussion

36.	12(x -2 y -3)0=___a. 0 b. 12 c. 120 d. -12
Answer» ong>Answer: 12(x-2 y-2) 12x-24 12y-24 12x-12y Step-by-step EXPLANATION: it is RI8 ans please follow me for more INFORMATION

36.

12(x -2 y -3)0=___a. 0 b. 12 c. 120 d. -12

Answer»

ong>Answer:

12(x-2 y-2)

12x-24 12y-24

12x-12y

Step-by-step EXPLANATION:

it is RI8 ans please follow me for more INFORMATION

Discussion

37.	Draw a line segment AB of length 5 cm. At A and B, construct lines perpendicular to AB.Also, draw the perpendicular bisector of AB.Are these three lines parallel to each other?Justify your answer.
Answer» ong>Answer: Here the length of AB = 5cm DA is perpendicular to AB. EB is perpendicular to AB. Two lines perpendicular to same line are parallel to each other. Also So If the sum of CO interior angles = 180°, the lines are parallel. HENCE AD \|\| BE Now we construct the perpendicular bisector of AB which INTERSECTS AB at C Again So We know If the sum of co interior angles = 180°, the lines are parallel. Hence AD \|\| CF Now BE \|\|AD \|\| CF Hence all the three lines are parallel to each other. Step-by-step explanation:

37.

Draw a line segment AB of length 5 cm. At A and B, construct lines perpendicular to AB.Also, draw the perpendicular bisector of AB.Are these three lines parallel to each other?Justify your answer.

Answer»

ong>Answer:

Here the length of AB = 5cm

DA is perpendicular to AB.

EB is perpendicular to AB.

Two lines perpendicular to same line are parallel to each other.

Also

So

If the sum of CO interior angles = 180°, the lines are parallel.

HENCE AD || BE

Now we construct the perpendicular bisector of AB which INTERSECTS AB at C

Again

So

We know If the sum of co interior angles = 180°, the lines are parallel.

Hence AD || CF

Now BE ||AD || CF

Hence all the three lines are parallel to each other.

Step-by-step explanation:

Discussion

38.	89+___ =169 +70 Please tell me the answer
Answer» ong>Answer: 150 Step-by-step explanation: PLEASE mark me as brainliest and follow me and THANK all my answers hope it HELPS

38.

89+___ =169 +70 Please tell me the answer

Answer»

ong>Answer:

150

Step-by-step explanation:

PLEASE mark me as brainliest and follow me and THANK all my answers

hope it HELPS

Discussion

39.	C={x l x is an even prime number ) what will be the symbolic statement in words
Answer» ANSWER will B c=2 because 2 is only the PRIME NUMBER which is even also

Discussion

40.	An article is sold for RS:555 at a loss of 7 1/2% The cost price of the article is
Answer» RONG>ANSWER: ÷°÷×°°={°°°°°={°^°•==^°{°^=÷¶¶¶¶=°{°^×=°™=™™π}°{{÷×®× Step-by-step EXPLANATION: jozhdjdpxnckcokckc

40.

An article is sold for RS:555 at a loss of 7 1/2% The cost price of the article is

Answer» RONG>ANSWER:

÷°÷×°°={°°°°°={°^°•==^°{°^=÷¶¶¶¶=°{°^×=°™=™™π}°{{÷×®×

Step-by-step EXPLANATION:

jozhdjdpxnckcokckc

Discussion

41.	Awire is looped in the form of a circle of radius 63cm.it is re bent into a square form Determine the length of the square.
Answer» ong>Answer: radius=63cm PI=22/7 circumference=2 pi R = 222/763 =396cm therefore square and circle are MADE from same wire. hence circumference of circle=perimeter of the square=396cm Step-by-step explanation:

41.

Awire is looped in the form of a circle of radius 63cm.it is re bent into a square form Determine the length of the square.

Answer»

ong>Answer:

radius=63cm

PI=22/7

circumference=2 pi R

= 2*22/7*63

=396cm

therefore square and circle are MADE from same wire.

hence circumference of circle=perimeter of the square=396cm

Step-by-step explanation:

Discussion

42.	The fuction f(x)=\|x\|+\|x-1\| is
Answer» align="absmiddle" alt="\huge\blue{\MATHBB{ANSWER:-}}" CLASS="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?F=%5Chuge%5Cblue%7B%5Cmathbb%7BANSWER%3A-%7D%7D" title="\huge\blue{\mathbb{ANSWER:-}}"> The function, f(x)=\|x\|+\|x-1\| is continuous but not differentiable at x=0. ${\huge{\underline{\small{\mathbb{\blue{HOPE\:HELP\:U\:BUDDY :)}}}}}}$ ${\huge{\underline{\small{\mathbb{\pink{~cαndчflσѕѕ♡ :)}}}}}}$

42.

The fuction f(x)=|x|+|x-1| is

Answer»

align="absmiddle" alt="\huge\blue{\MATHBB{ANSWER:-}}" CLASS="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?F=%5Chuge%5Cblue%7B%5Cmathbb%7BANSWER%3A-%7D%7D" title="\huge\blue{\mathbb{ANSWER:-}}">

The function,

f(x)=|x|+|x-1|

is continuous but not differentiable at x=0.

${\huge{\underline{\small{\mathbb{\blue{HOPE\:HELP\:U\:BUDDY :)}}}}}}$

${\huge{\underline{\small{\mathbb{\pink{~cαndчflσѕѕ♡ :)}}}}}}$

Discussion

43.	(5+6x^2-11x) divided by (2x-3) long division factorisation please answer fast to be followed
Answer» t be DETERMINED at all

Discussion

44.	The perimeter of an equilateral triangle is 24 cm, then its area is
Answer» ONG>Answer: 27.71 cm² Step-by-step explanation: Perimeter = 24cm Side of TRIANGLE = 24÷3 CM = 8CM Area of equilateral triangle = √3/4 × 8² = 27.71 cm²

44.

The perimeter of an equilateral triangle is 24 cm, then its area is

Answer» ONG>Answer:

27.71 cm²

Step-by-step explanation:

Perimeter = 24cm

Side of TRIANGLE = 24÷3 CM = 8CM

Area of equilateral triangle = √3/4 × 8² = 27.71 cm²

Discussion

45.	Point P is the midpoint of seg CD. If CP = 2.5, find l (CD)
Answer» ong>ANSWER:P> POINT P is the midpoint of seg CD and l(CP) = 2.5 …[Given] ∴ l(CD) = 2.5 X 2 ∴ l(CD) = 5

45.

Point P is the midpoint of seg CD. If CP = 2.5, find l (CD)

Answer»

ong>ANSWER:P>

POINT P is the midpoint of seg CD and l(CP) = 2.5 …[Given]

∴ l(CD) = 2.5 X 2

∴ l(CD) = 5

Discussion

46.	I am one more than the greatest 5-digit number: 1
Answer» TEST 5 DIGIT no.= 99999 Samllest 5 digit No.= 10000 hope it HELPS ❣️

46.

I am one more than the greatest 5-digit number: 1

Answer» TEST 5 DIGIT no.= 99999

Samllest 5 digit No.= 10000

hope it HELPS ❣️

Discussion

47.	If a=2+√3, then a+1/a=?
Answer» align="ABSMIDDLE" alt="\huge\blue{\tt{Question:-}}" CLASS="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%5Chuge%5Cblue%7B%5Ctt%7BQuestion%3A-%7D%7D" TITLE="\huge\blue{\tt{Question:-}}"> $If \: a = (2 + \sqrt{3} ) , \: then \: a + \frac{1}{a} = ?$ $\huge\blue{\tt{Solution:-}}$ $a + \frac{1}{a} = (2 + \sqrt{3} ) + \frac{1}{(2 + \sqrt{3} )}$ $solving \: \frac{1}{a}$ Using rationalisation, $\frac{1}{(2 + \sqrt{3} )} \times \frac{(2 - \sqrt{3} )}{(2 - \sqrt{3} )}$ $Since, (a+b)(a-b) = {a}^{2} - {b}^{2}$ Therefore, $= > \frac{(2 - \sqrt{3}) }{ {(2)}^{2} - {( \sqrt{3} )}^{2} }$ $= > \frac{(2 - \sqrt{3}) }{<klux>4</klux> - 3}$ $= > \frac{(2 - \sqrt{3}) }{1} = (2 - \sqrt{3} )$ $Now, a + \frac{1}{a} = (2 + \sqrt{3} ) + (2 - \sqrt{3} )$ => 2 + 2 => 4. Hence, 4 is the required answer.

47.

If a=2+√3, then a+1/a=?

Answer»

align="ABSMIDDLE" alt="\huge\blue{\tt{Question:-}}" CLASS="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%5Chuge%5Cblue%7B%5Ctt%7BQuestion%3A-%7D%7D" TITLE="\huge\blue{\tt{Question:-}}">

$If \: a = (2 + \sqrt{3} ) , \: then \: a + \frac{1}{a} = ?$

$\huge\blue{\tt{Solution:-}}$

$a + \frac{1}{a} = (2 + \sqrt{3} ) + \frac{1}{(2 + \sqrt{3} )}$

$solving \: \frac{1}{a}$

Using rationalisation,

$\frac{1}{(2 + \sqrt{3} )} \times \frac{(2 - \sqrt{3} )}{(2 - \sqrt{3} )}$

$Since, (a+b)(a-b) = {a}^{2} - {b}^{2}$

Therefore,

$= > \frac{(2 - \sqrt{3}) }{ {(2)}^{2} - {( \sqrt{3} )}^{2} }$

$= > \frac{(2 - \sqrt{3}) }{<klux>4</klux> - 3}$

$= > \frac{(2 - \sqrt{3}) }{1} = (2 - \sqrt{3} )$

$Now, a + \frac{1}{a} = (2 + \sqrt{3} ) + (2 - \sqrt{3} )$

=> 2 + 2

=> 4.

Hence, 4 is the required answer.

Discussion

48.	Solve the following simultaneouscy equations2x+y=35 4x-3y=11
Answer» ONG>Step-by-step explanation: 2x+y=35 - - - - EQ 1 4x-3y=11- - - - - - eq2 Multiply eq 1 by 3 6x+3y=105 - - - - eq3 Now, adding eq 2 and 3 6x+3y=105 + 4x-3y=11 ___________ 10x =116 x= 116 __ 10 Therfore x=11.6 Substituting x=11.6 in eq 1 2(11.6)+y =35 23.2+y =35 y=35-23.2 Therfore, y =11.8

48.

Solve the following simultaneouscy equations2x+y=35 4x-3y=11

Answer» ONG>Step-by-step explanation:

2x+y=35 - - - - EQ 1

4x-3y=11- - - - - - eq2

Multiply eq 1 by 3

6x+3y=105 - - - - eq3

Now, adding eq 2 and 3

6x+3y=105

+ 4x-3y=11

___________

10x =116

x= 116

__

10

Therfore x=11.6

Substituting x=11.6 in eq 1

2(11.6)+y =35

23.2+y =35

y=35-23.2

Therfore, y =11.8

Discussion

49.	Factorise: a3 + 8a?a 3 in step.
Answer» ong>ANSWER: a3+2^3 Step-by-step explanation: a3+ 8IS EQUAL to a3+2^3 [8=2^3]

49.

Factorise: a3 + 8a?a 3 in step.

Answer»

ong>ANSWER:

a3+2^3

Step-by-step explanation:

a3+ 8IS EQUAL to a3+2^3 [8=2^3]

Discussion

50.	Probability means...............
Answer» ONG>Answer: the CHANCE that something will HAPPEN

50.

Probability means...............

Answer» ONG>Answer:

the CHANCE that something will HAPPEN

Discussion

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