98971 + Interview Questions in Primary School in Math

1.	A student multiplied 7236 by 65 instead of multiplying by 56. By how much was hisanswer greater than the correct answer? (Hint: Do you need to do both themultiplications)
Answer» onq-ydbe-deh jo.in me gi.rl

Discussion

2.	Find the area of the give figerurea
Answer» Answer: 98 cm² Step-by-step EXPLANATION: Area of parallelogram = Base x Height Therefore, for this figure area will be GIVEN by, Area = B x H = 14CM x 7CM = 98cm²

2.

Find the area of the give figerurea

Answer»

Answer:

98 cm²

Step-by-step EXPLANATION:

Area of parallelogram = Base x Height

Therefore, for this figure area will be GIVEN by,

Area = B x H

= 14CM x 7CM

= 98cm²

Discussion

3.	No.1 the following:-1. Find the diameter of a circle, if it's:- a) 12.5cmb) 15.2CM2) Find the area of the rectangular of a classroom whose length and breadth are 8m and 6m respectively.3) The area of a square is 576 sq. m. Find its perimeter.4) Find the cost of fencing a square field of side 8.4cm. at the rate of ₹2 per meter.5) The perimeter of a rectangle is 76cm. If its breadth is 16cm find its length. What would be the perimeter if length is doubled?
Answer» Answer: your MOTHER was the only reason you a GIRL Step-by-step explanation: US officials say they are INVESTIGATING

3.

No.1 the following:-1. Find the diameter of a circle, if it's:- a) 12.5cmb) 15.2CM2) Find the area of the rectangular of a classroom whose length and breadth are 8m and 6m respectively.3) The area of a square is 576 sq. m. Find its perimeter.4) Find the cost of fencing a square field of side 8.4cm. at the rate of ₹2 per meter.5) The perimeter of a rectangle is 76cm. If its breadth is 16cm find its length. What would be the perimeter if length is doubled?

Answer»

Answer:

your MOTHER was the only reason you a GIRL

Step-by-step explanation:

US officials say they are INVESTIGATING

Discussion

4.	Can someone help with the forth sum i do not know how to do it
Answer» ANSWER: HOPE it HELPS you MARK the BRAINLIEST

4.

Can someone help with the forth sum i do not know how to do it

Answer»

ANSWER:

HOPE it HELPS you MARK the BRAINLIEST

Discussion

5.	Express the number appearing in the following statement in standard form Average radius of the sun is 695000 km
Answer» ANSWER: $69510$ ³. Step-by-step explanation:* Standard form = $\frac{695000}{1000}$ = 695. How many zeroes removed? 3. Now, $695 * 10$ ³. The 3 zeroes are there in the POWER of the numerical value! HOPE it HELPS :)) #TogetherWeGoFar

5.

Express the number appearing in the following statement in standard form Average radius of the sun is 695000 km

Answer»

ANSWER:

$695*10$ ³.

Step-by-step explanation:

Standard form = $\frac{695000}{1000}$ = 695.

How many zeroes removed?

3.

Now, $695 * 10$ ³.

The 3 zeroes are there in the POWER of the numerical value!

HOPE it HELPS :))

#TogetherWeGoFar

Discussion

6.	(a) -14 + 16 - (-12) – 25
Answer» *REQUIRED* *ANSWER* :- -11 *HOPE* *IT IS HELPFUL TO* *YOU* !!!! To be *CONTINUED*......

6.

(a) -14 + 16 - (-12) – 25

Answer»

REQUIRED ANSWER :- -11

HOPE IT IS HELPFUL TO YOU !!!!

To be CONTINUED......

Discussion

7.	Please correct answer de Thanks
Answer» ANSWER: ISKA wajan 1250 GRAM HOGA

7.

Please correct answer de Thanks

Answer»

ANSWER:

ISKA wajan 1250 GRAM HOGA

Discussion

8.	A apple cost $ 20 then 2 apple cost
Answer» ANSWER: $40 Step-by-step EXPLANATION: $\huge{\underline{\mathfrak{❥Sachuuu}}}$

8.

A apple cost $ 20 then 2 apple cost

Answer»

ANSWER:

$40

Step-by-step EXPLANATION:

$\huge{\underline{\mathfrak{❥Sachuuu}}}$

Discussion

9.	a field is rectangular in shape and its length is 1 1/2 times breadth if its area is 2.4576hectares. what is its perimeter
Answer» Step-by-step EXPLANATION: [1234567890/1234567890] × 2 = 2 did it

9.

a field is rectangular in shape and its length is 1 1/2 times breadth if its area is 2.4576hectares. what is its perimeter

Answer»

Step-by-step EXPLANATION:

[1234567890/1234567890] × 2 = 2

did it

Discussion

10.	(iii) (p2 + 2q) (p2 – 3q)
Answer» Answer: make me brainleast Step-by-step EXPLANATION: p2(p2-3q) p $^2$ 4 - PQ6

10.

(iii) (p2 + 2q) (p2 – 3q)

Answer»

Answer:

make me brainleast

Step-by-step EXPLANATION:

p2(p2-3q)

p $^2$ 4 - PQ6

Discussion

11.	I am bored at seeing same wall guyswhat is plasma matter
Answer» Step-by-step explanation: Plasma is superheated matter – so HOT that the electrons are ripped away from the atoms forming an ionized gas. ... Just as a liquid will BOIL, CHANGING into a gas when energy is added, heating a gas will form a plasma – a soup of positively charged particles (IONS) and negatively charged particles (electrons). hope it helps you

11.

I am bored at seeing same wall guyswhat is plasma matter

Answer»

Step-by-step explanation:

Plasma is superheated matter – so HOT that the electrons are ripped away from the atoms forming an ionized gas. ... Just as a liquid will BOIL, CHANGING into a gas when energy is added, heating a gas will form a plasma – a soup of positively charged particles (IONS) and negatively charged particles (electrons). hope it helps you

Discussion

12.	( x + y +z) (x + y - z) simplify
Answer» ANSWER: x²+xy-xz+xy+y²-yz+xz+yz-z² x²+2xy+y²-z² is the CORRECT answer.

12.

( x + y +z) (x + y - z) simplify

Answer»

ANSWER:

x²+xy-xz+xy+y²-yz+xz+yz-z²

x²+2xy+y²-z²

is the CORRECT answer.

Discussion

13.	3. Find the value of x if 13/6 =-65/x
Answer» ANSWER: yst8s8tsitstistisitstistisitdodit hoxoydyodyodoydyyodyodoydyodyodydyo

13.

3. Find the value of x if 13/6 =-65/x

Answer»

ANSWER:

yst8s8tsitstistisitstistisitdodit

hoxoydyodyodoydyyodyodoydyodyodydyo

Discussion

14.	The radius of a circle of a Demeter 24 is
Answer» ANSWER = 48 DIAMETER

Discussion

15.	Isha travelled by a bus towards east of Delhi by 58 km and then towards the west of Delhi by 82 km.How far was she from Delhi finally?
Answer» Step-by-step explanation: SINCE UNIT of WEST is greater than east. so 82-58= 24 km west

15.

Isha travelled by a bus towards east of Delhi by 58 km and then towards the west of Delhi by 82 km.How far was she from Delhi finally?

Answer»

Step-by-step explanation:

SINCE UNIT of WEST is greater than east.

so 82-58= 24 km west

Discussion

16.	Samantha has 30 coins, consisng of 25 paise and 10 paise, which total Rs. 5.70. How many of each does she have?
Answer» Answer: There are 18 , 25-paise coins and 12 , 10-paise coins Step-by-step explanation: let the no. of 25paise coins = X and no. of 10 paise coins = y given, x + y = 30 -------------- (1) => y = 30-x ----------(2) also given, 25X + 10y = 570 (paise) => 25x + 10(30-x) = 570 => 25x + 300 - 10x = 570 => 15x = 570-300 => 15x = 270 => x = 270/15 => x = 18 so, (2) => y = 30-18 => y = 12 verification, 25(18) + 10(12) = 450 + 120 = 570 paise = Rs. 5.70 hence verified

16.

Samantha has 30 coins, consisng of 25 paise and 10 paise, which total Rs. 5.70. How many of each does she have?

Answer»

Answer:

There are 18 , 25-paise coins and

12 , 10-paise coins

Step-by-step explanation:

let the no. of 25paise coins = X

and no. of 10 paise coins = y

given, x + y = 30 -------------- (1)

=> y = 30-x ----------(2)

also given, 25X + 10y = 570 (paise)

=> 25x + 10(30-x) = 570

=> 25x + 300 - 10x = 570

=> 15x = 570-300

=> 15x = 270

=> x = 270/15

=> x = 18

so, (2) => y = 30-18

=> y = 12

verification,

25(18) + 10(12)

= 450 + 120

= 570 paise

= Rs. 5.70

hence verified

Discussion

17.	The numbers 1,4,9,16representsnumbers.[ ]A) TriangularB) RectangularC) SquareD) All
Answer» ANSWER:All is CORRECT answer. Step-by-step EXPLANATION:d)all

Discussion

18.	Factorise 10ab+4a+5b+2
Answer» ANSWER: (5b+2)(2A+1) Step-by-step explanation: 10ab +4a+5b+2 ={10a+4a} + {5b+2} =2a(5b+2)+1(5b+2) TAKING (5b+2) as COMMON (5b+2)(2a+1)

18.

Factorise 10ab+4a+5b+2

Answer»

ANSWER:

(5b+2)(2A+1)

Step-by-step explanation:

10ab +4a+5b+2

={10a+4a} + {5b+2}

=2a(5b+2)+1(5b+2)

TAKING (5b+2) as COMMON

(5b+2)(2a+1)

Discussion

19.	Find the two number whose sum is 3 and product is 1
Answer» Answer: 3= 2+1 and 0+3 1= 1×1 Step-by-step EXPLANATION: HOPE it is HELPFUL for you

19.

Find the two number whose sum is 3 and product is 1

Answer»

Answer:

3= 2+1 and 0+3

1= 1×1

Step-by-step EXPLANATION:

HOPE it is HELPFUL for you

Discussion

20.	In Srinagar, the temperature was 2°C in the afternoon on a particular day. What was the temperatureduring the night if it further dropped by 5°C?
Answer» Step-by-step EXPLANATION: TEMPERATURE at afternoon = 2°C = temperature at night if it drops by 5°C = 2+(-5) = -3 Therefore, temperature at night is -3°C Hope it HELPFUL !!

20.

In Srinagar, the temperature was 2°C in the afternoon on a particular day. What was the temperatureduring the night if it further dropped by 5°C?

Answer»

Step-by-step EXPLANATION:

TEMPERATURE at afternoon = 2°C

= temperature at night if it drops by 5°C

= 2+(-5)

= -3

Therefore, temperature at night is -3°C

Hope it HELPFUL !!

Discussion

21.	Ularly, centi shows 100 times smaller, i.e. 1 metre = 100 centimetres.7 TheseA bus started its journey and reached different places with a speed of60 km/hour. The journey is shown below.(i) Find the total distance covered by the bus from A to D.(ii) Find the total distance covered by the bus from D to G.(iii) Find the total distance covered by the bus, if it startsfrom A and returns back to A.(iv) Can you find the difference of distances from C to D and D to E?
Answer» ANSWER: okok Step-by-step EXPLANATION: PLEASE FOLLOW AND MARK ME AS BRAINLIEST!! I WILL TOO FOLLOW AND GIVE THANKS! "THANK you FRIEND".

21.

Ularly, centi shows 100 times smaller, i.e. 1 metre = 100 centimetres.7 TheseA bus started its journey and reached different places with a speed of60 km/hour. The journey is shown below.(i) Find the total distance covered by the bus from A to D.(ii) Find the total distance covered by the bus from D to G.(iii) Find the total distance covered by the bus, if it startsfrom A and returns back to A.(iv) Can you find the difference of distances from C to D and D to E?

Answer»

ANSWER:

okok

Step-by-step EXPLANATION:

PLEASE FOLLOW AND MARK ME AS BRAINLIEST!!

I WILL TOO FOLLOW AND GIVE THANKS!

"THANK you FRIEND".

Discussion

22.	Show that x? - x has 3 factors
Answer» ANSWER: x2-X =0 Step-by-step EXPLANATION: x(x-1)=0 one is x and SECOND is (x-1)

22.

Show that x? - x has 3 factors

Answer»

ANSWER:

x2-X =0

Step-by-step EXPLANATION:

x(x-1)=0

one is x and SECOND is (x-1)

Discussion

23.	ᴡʜᴀᴛ ɪs ᴛʜᴇ sᴛᴀɴᴅᴀʀᴅ ғᴏʀᴍ ᴏғ ᴛʜᴇ ᴘᴏʟʏɴᴏᴍɪᴀʟᴛʜᴏsᴇ ᴡʜᴏ ᴋɴᴏᴡs ᴀɴsᴡᴇʀ ᴛʜᴇʏ ᴡɪʟʟ ᴏɴʟʏ ᴀɴsᴡᴇʀ ᴅᴏɴ'ᴛ sᴘᴀᴍ ᴀɴᴅ ᴡʀᴏɴɢ ᴀɴsᴡᴇʀ ᴡɪʟʟ ʙᴇ ʀᴇᴘᴏʀᴛᴇᴅ ᴀɴᴅ ᴘʟᴇᴀsᴇ ɢɪᴠᴇ sᴛᴇᴘ ʙʏ sᴛᴇᴘ ᴇxᴘʟᴀɴᴀᴛɪᴏɴ...
Answer» Answer: The price of a smartphone is 5000 more than the cost of two feature phones & the cost of 4 feature phones and two smartphone is 88,000 . Exigency To FIND : The cost of a smartphone and a feature phone. ⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀ ❍ Let's Consider the cost price of smart phone and feature phone be Rs. x & Rs. y , respectively . ⠀⠀⠀⠀⠀⠀CASE I : The price of a smartphone is Rs. 5000 more than the cost of two feature phones . \BEGIN{gathered}\qquad :\implies \sf x = 2y + 5000 \:\:\\\end{gathered} :⟹x=2y+5000 \begin{gathered}\qquad :\implies \bf x = 2y + 5000 \:\:\:\qquad\qquad \bigg\lgroup \sf{ Eq^n \: 1 }\bigg\rgroup\\\end{gathered} :⟹x=2y+5000 ⎩ ⎪ ⎪ ⎪ ⎧ Eq n 1 ⎭ ⎪ ⎪ ⎪ ⎫ ⠀⠀⠀⠀⠀⠀CASE II : The cost of 4 feature phones and two smartphones is Rs. 88,000 . \begin{gathered}\qquad :\implies \sf 4y + 2x = 88000 \:\:\\\end{gathered} :⟹4y+2x=88000 \begin{gathered}\qquad :\implies \bf 4y + 2x = 88000 \:\:\:\qquad\qquad \bigg\lgroup \sf{ Eq^n \: 2}\bigg\rgroup\\\end{gathered} :⟹4y+2x=88000 ⎩ ⎪ ⎪ ⎪ ⎧ Eq n 2 ⎭ ⎪ ⎪ ⎪ ⎫ ⠀⠀⠀⠀⠀⠀Now , Finding the cost of Smart phone & Feature phone : \begin{gathered}\qquad \:\maltese\:\bf{ From \:Equation \:2 \:\::}\\\end{gathered} ✠FromEquation2: \begin{gathered}\qquad \dag\:\:\bigg\lgroup \sf{Equation \:2\:: 4y + 2x = 88000 }\bigg\rgroup \\\\\end{gathered} † ⎩ ⎪ ⎪ ⎪ ⎧ Equation2:4y+2x=88000 ⎭ ⎪ ⎪ ⎪ ⎫ \begin{gathered}\qquad :\implies \sf 4y + 2x = 88000 \:\:\\\end{gathered} :⟹4y+2x=88000 ⠀⠀⠀⠀⠀⠀\begin{gathered}\UNDERLINE {\boldsymbol{\star\:Now \: By \: Substituting \: the \: Eq^n\:1 \: : \::}}\\\end{gathered} ⋆NowBySubstitutingtheEq n 1:: \begin{gathered}\qquad \dag\:\:\bigg\lgroup \sf{Equation \:1\:: x = 2y + 5000 }\bigg\rgroup \\\\\end{gathered} † ⎩ ⎪ ⎪ ⎪ ⎧ Equation1:x=2y+5000 ⎭ ⎪ ⎪ ⎪ ⎫ \begin{gathered}\qquad :\implies \sf 4y + 2x = 88000 \:\:\\\end{gathered} :⟹4y+2x=88000 \begin{gathered}\qquad :\implies \sf 4y +2 (2y + 5000) = 88000 \:\:\\\end{gathered} :⟹4y+2(2y+5000)=88000 \begin{gathered}\qquad :\implies \sf 4y +4y + 10000 = 88000 \:\:\\\end{gathered} :⟹4y+4y+10000=88000 \begin{gathered}\qquad :\implies \sf 4y +4y = 88000 - 10000 \:\:\\\end{gathered} :⟹4y+4y=88000−10000 \begin{gathered}\qquad :\implies \sf 8Y = 88000 - 10000 \:\:\\\end{gathered} :⟹8y=88000−10000 \begin{gathered}\qquad :\implies \sf 8y = 78000 \:\:\\\end{gathered} :⟹8y=78000 \begin{gathered}\qquad :\implies \sf y = \dfrac{ 78000}{8} \:\:\\\end{gathered} :⟹y= 8 78000 \begin{gathered}\qquad :\implies \sf y = \cancel {\dfrac{ 78000}{8}} \:\:\\\end{gathered} :⟹y= 8 78000 \begin{gathered}\qquad :\implies \bf y = 9750 \:\:\\\end{gathered} :⟹y=9750 \begin{gathered}\qquad :\implies \frak{\underline{\purple{\:y = Rs.\: 9750 }} }\:\:\bigstar \\\end{gathered} :⟹ y=Rs.9750 ★ ⠀⠀⠀⠀⠀⠀\begin{gathered}\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: \: Value\:of\: y \ [ \ 9750 \ ] \:in \:Eq^n \:1 \::}}\\\end{gathered} ⋆NowBySubstitutingtheValueofy [ 9750 ]inEq n 1: \begin{gathered}\qquad \dag\:\:\bigg\lgroup \sf{Equation \:1\:: x = 2y + 5000 }\bigg\rgroup \\\\\end{gathered} † ⎩ ⎪ ⎪ ⎪ ⎧ Equation1:x=2y+5000 ⎭ ⎪ ⎪ ⎪ ⎫ \begin{gathered}\qquad :\implies \sf x = 2y + 5000 \:\:\\\end{gathered} :⟹x=2y+5000 \begin{gathered}\qquad :\implies \sf x = 2(9750) + 5000 \:\:\\\end{gathered} :⟹x=2(9750)+5000 \begin{gathered}\qquad :\implies \sf x = 19500 + 5000 \:\:\\\end{gathered} :⟹x=19500+5000 \begin{gathered}\qquad :\implies \bf x = 24500 \:\:\\\end{gathered} :⟹x=24500 \begin{gathered}\qquad :\implies \frak{\underline{\purple{\:x \:= Rs.\: 24500 }} }\:\:\bigstar \\\end{gathered} :⟹ x=Rs.24500 ★ Therefore, The cost of smartphone is : x = Rs. 24, 500 The cost of feature phone: y = Rs. 9,750 Therefore, ⠀⠀⠀⠀⠀\begin{gathered}\qquad \therefore {\underline{ \sf \:Cost \:of\:Smartphone \:and \:feature \:phone \:are\:\bf Rs. \ 24,500 \:\& \: Rs.\: 9,750\:\:\sf , \ respectively . }}\\\end{gathered} ∴ CostofSmartphoneandfeaturephoneareRs. 24,500&Rs.9,750, respectively. ⠀

23.

ᴡʜᴀᴛ ɪs ᴛʜᴇ sᴛᴀɴᴅᴀʀᴅ ғᴏʀᴍ ᴏғ ᴛʜᴇ ᴘᴏʟʏɴᴏᴍɪᴀʟᴛʜᴏsᴇ ᴡʜᴏ ᴋɴᴏᴡs ᴀɴsᴡᴇʀ ᴛʜᴇʏ ᴡɪʟʟ ᴏɴʟʏ ᴀɴsᴡᴇʀ ᴅᴏɴ'ᴛ sᴘᴀᴍ ᴀɴᴅ ᴡʀᴏɴɢ ᴀɴsᴡᴇʀ ᴡɪʟʟ ʙᴇ ʀᴇᴘᴏʀᴛᴇᴅ ᴀɴᴅ ᴘʟᴇᴀsᴇ ɢɪᴠᴇ sᴛᴇᴘ ʙʏ sᴛᴇᴘ ᴇxᴘʟᴀɴᴀᴛɪᴏɴ...

Answer»

Answer:

The price of a smartphone is 5000 more than the cost of two feature phones &

the cost of 4 feature phones and two smartphone is 88,000 .

Exigency To FIND : The cost of a smartphone and a feature phone.

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

❍ Let's Consider the cost price of smart phone and feature phone be Rs. x & Rs. y , respectively .

⠀⠀⠀⠀⠀⠀CASE I : The price of a smartphone is Rs. 5000 more than the cost of two feature phones .

\BEGIN{gathered}\qquad :\implies \sf x = 2y + 5000 \:\:\\\end{gathered}

:⟹x=2y+5000

\begin{gathered}\qquad :\implies \bf x = 2y + 5000 \:\:\:\qquad\qquad \bigg\lgroup \sf{ Eq^n \: 1 }\bigg\rgroup\\\end{gathered}

:⟹x=2y+5000

⎩

⎪

⎧

Eq

n

1

⎭

⎪

⎫

⠀⠀⠀⠀⠀⠀CASE II : The cost of 4 feature phones and two smartphones is Rs. 88,000 .

\begin{gathered}\qquad :\implies \sf 4y + 2x = 88000 \:\:\\\end{gathered}

:⟹4y+2x=88000

\begin{gathered}\qquad :\implies \bf 4y + 2x = 88000 \:\:\:\qquad\qquad \bigg\lgroup \sf{ Eq^n \: 2}\bigg\rgroup\\\end{gathered}

:⟹4y+2x=88000

⎩

⎪

⎧

Eq

n

2

⎭

⎪

⎫

⠀⠀⠀⠀⠀⠀Now , Finding the cost of Smart phone & Feature phone :

\begin{gathered}\qquad \:\maltese\:\bf{ From \:Equation \:2 \:\::}\\\end{gathered}

✠FromEquation2:

\begin{gathered}\qquad \dag\:\:\bigg\lgroup \sf{Equation \:2\:: 4y + 2x = 88000 }\bigg\rgroup \\\\\end{gathered}

†

⎩

⎪

⎧

Equation2:4y+2x=88000

⎭

⎪

⎫

\begin{gathered}\qquad :\implies \sf 4y + 2x = 88000 \:\:\\\end{gathered}

:⟹4y+2x=88000

⠀⠀⠀⠀⠀⠀\begin{gathered}\UNDERLINE {\boldsymbol{\star\:Now \: By \: Substituting \: the \: Eq^n\:1 \: : \::}}\\\end{gathered}

⋆NowBySubstitutingtheEq

n

1::

\begin{gathered}\qquad \dag\:\:\bigg\lgroup \sf{Equation \:1\:: x = 2y + 5000 }\bigg\rgroup \\\\\end{gathered}

†

⎩

⎪

⎧

Equation1:x=2y+5000

⎭

⎪

⎫

\begin{gathered}\qquad :\implies \sf 4y + 2x = 88000 \:\:\\\end{gathered}

:⟹4y+2x=88000

\begin{gathered}\qquad :\implies \sf 4y +2 (2y + 5000) = 88000 \:\:\\\end{gathered}

:⟹4y+2(2y+5000)=88000

\begin{gathered}\qquad :\implies \sf 4y +4y + 10000 = 88000 \:\:\\\end{gathered}

:⟹4y+4y+10000=88000

\begin{gathered}\qquad :\implies \sf 4y +4y = 88000 - 10000 \:\:\\\end{gathered}

:⟹4y+4y=88000−10000

\begin{gathered}\qquad :\implies \sf 8Y = 88000 - 10000 \:\:\\\end{gathered}

:⟹8y=88000−10000

\begin{gathered}\qquad :\implies \sf 8y = 78000 \:\:\\\end{gathered}

:⟹8y=78000

\begin{gathered}\qquad :\implies \sf y = \dfrac{ 78000}{8} \:\:\\\end{gathered}

:⟹y=

8

78000

\begin{gathered}\qquad :\implies \sf y = \cancel {\dfrac{ 78000}{8}} \:\:\\\end{gathered}

:⟹y=

8

78000

\begin{gathered}\qquad :\implies \bf y = 9750 \:\:\\\end{gathered}

:⟹y=9750

\begin{gathered}\qquad :\implies \frak{\underline{\purple{\:y = Rs.\: 9750 }} }\:\:\bigstar \\\end{gathered}

:⟹

y=Rs.9750

★

⠀⠀⠀⠀⠀⠀\begin{gathered}\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: \: Value\:of\: y \ [ \ 9750 \ ] \:in \:Eq^n \:1 \::}}\\\end{gathered}

⋆NowBySubstitutingtheValueofy [ 9750 ]inEq

n

1:

\begin{gathered}\qquad \dag\:\:\bigg\lgroup \sf{Equation \:1\:: x = 2y + 5000 }\bigg\rgroup \\\\\end{gathered}

†

⎩

⎪

⎧

Equation1:x=2y+5000

⎭

⎪

⎫

\begin{gathered}\qquad :\implies \sf x = 2y + 5000 \:\:\\\end{gathered}

:⟹x=2y+5000

\begin{gathered}\qquad :\implies \sf x = 2(9750) + 5000 \:\:\\\end{gathered}

:⟹x=2(9750)+5000

\begin{gathered}\qquad :\implies \sf x = 19500 + 5000 \:\:\\\end{gathered}

:⟹x=19500+5000

\begin{gathered}\qquad :\implies \bf x = 24500 \:\:\\\end{gathered}

:⟹x=24500

\begin{gathered}\qquad :\implies \frak{\underline{\purple{\:x \:= Rs.\: 24500 }} }\:\:\bigstar \\\end{gathered}

:⟹

x=Rs.24500

★

Therefore,

The cost of smartphone is : x = Rs. 24, 500

The cost of feature phone: y = Rs. 9,750

Therefore,

⠀⠀⠀⠀⠀\begin{gathered}\qquad \therefore {\underline{ \sf \:Cost \:of\:Smartphone \:and \:feature \:phone \:are\:\bf Rs. \ 24,500 \:\& \: Rs.\: 9,750\:\:\sf , \ respectively . }}\\\end{gathered}

∴

CostofSmartphoneandfeaturephoneareRs. 24,500&Rs.9,750, respectively.

⠀

Discussion

24.	5/7 by -3/4PLEASE SOLVE MY QUESTION. IT'S URGENT. I WILL MARK YOU AS BRAINLILIST.
Answer» ANSWER: here is UR Step-by-step EXPLANATION: $= \frac{5}{7} \div \frac{ - 3}{4}$ $= \frac{5}{7} \times \frac{4}{ - 3}$ $= \frac{ - 20}{21} \: \: \: \: done$ HOPE u will. understand

24.

5/7 by -3/4PLEASE SOLVE MY QUESTION. IT'S URGENT. I WILL MARK YOU AS BRAINLILIST.

Answer»

ANSWER:

here is UR

Step-by-step EXPLANATION:

$= \frac{5}{7} \div \frac{ - 3}{4}$

$= \frac{5}{7} \times \frac{4}{ - 3}$

$= \frac{ - 20}{21} \: \: \: \: done$

HOPE u will. understand

Discussion

25.	I have 262. How many 20 rupees notes can i get in exchange ? How many rupees will be left ?
Answer» Answer: Number of ₹20 notes : 13 Rupees left : ₹2 Step-by-step explanation: TOTAL amount :262 Number of ₹20 NOTE to be RECEIVED out OD ₹262 = 13 (13× 20 = 260) Balance = 262 - 260 = ₹2

25.

I have 262. How many 20 rupees notes can i get in exchange ? How many rupees will be left ?

Answer»

Answer:

Number of ₹20 notes : 13

Rupees left : ₹2

Step-by-step explanation:

TOTAL amount :262

Number of ₹20 NOTE to be RECEIVED

out OD ₹262 = 13 (13× 20 = 260)

Balance = 262 - 260 = ₹2

Discussion

26.	One-fifth of a mumber is 5. find the number
Answer» ANSWER: X=25 Step-by-step explanation: 1/5X =5 X =5x5 X =25 mark as BRAINLIEST

26.

One-fifth of a mumber is 5. find the number

Answer»

ANSWER:

X=25

Step-by-step explanation:

1/5X =5

X =5x5

X =25

mark as BRAINLIEST

Discussion

27.	869,768,584,230 write in expanded form in international system
Answer» Answer: 800,000,000,000+60,000,000,000+9,000,000,000+700,000,000+60,000,000+8,000,000+500,000+80,000+4,000+200+30+0

27.

869,768,584,230 write in expanded form in international system

Answer»

Answer:

800,000,000,000+60,000,000,000+9,000,000,000+700,000,000+60,000,000+8,000,000+500,000+80,000+4,000+200+30+0

Discussion

28.	336 - -28this is 336 mines 28 but 28 has mines
Answer» Answer: 364 Step-by-step EXPLANATION: LOL NURSERY QUESTION

28.

336 - -28this is 336 mines 28 but 28 has mines

Answer»

Answer:

364

Step-by-step EXPLANATION:

LOL NURSERY QUESTION

Discussion

29.	The outer angle of a triangle are inthe ratio 2:4:5 The smallest side is 15cm less than largest Side Calculatethe length of all there sides
Answer» Answer: 15 ,30 ,37.5 Step-by-step EXPLANATION:

29.

The outer angle of a triangle are inthe ratio 2:4:5 The smallest side is 15cm less than largest Side Calculatethe length of all there sides

Answer»

Answer:

15 ,30 ,37.5

Step-by-step EXPLANATION:

Discussion

30.	3/2(2x-1)+5 = 4x+92 solve
Answer» x=3 PLEASE MAKE BRAIN LIST

30.

3/2(2x-1)+5 = 4x+92 solve

Answer»

x=3

PLEASE MAKE BRAIN LIST

Discussion

31.	What is the product of 10101 and 17(A) 17017017 (B) 1717017(C) 171717 (D) 170017
Answer» ANSWER: a is RIGHT answer Step-by-step explanation: please MAKE me brain list

31.

What is the product of 10101 and 17(A) 17017017 (B) 1717017(C) 171717 (D) 170017

Answer»

ANSWER:

a is RIGHT answer

Step-by-step explanation:

please MAKE me brain list

Discussion

32.	determine the perimeter of the rectangle in terms of x. The length is 3x + 4 and the width is 2x - 3
Answer» ANSWER: PERIMETER = 10x + 2 Step-by-step explanation: Length = 3x + 4 Width ( breadth ) = 2x - 3 Perimeter = 2(l+b) = 2 [(3x + 4) + (2x - 3) = 2 (3x + 4 + 2x - 3) = 2 (5x +1) = 10x + 2 hope it helps...

32.

determine the perimeter of the rectangle in terms of x. The length is 3x + 4 and the width is 2x - 3

Answer»

ANSWER:

PERIMETER = 10x + 2

Step-by-step explanation:

Length = 3x + 4

Width ( breadth ) = 2x - 3

Perimeter = 2(l+b)

= 2 [(3x + 4) + (2x - 3)

= 2 (3x + 4 + 2x - 3)

= 2 (5x +1)

= 10x + 2

hope it helps...

Discussion

33.	Pl answer this question pls
Answer» this is gonna be a PIECE of CAKE

33.

Pl answer this question pls

Answer»

this is gonna be a PIECE of CAKE

Discussion

34.	Integers who's answers is -12
Answer» ANSWER: -6 + (-6) Step-by-step EXPLANATION: i HOPE this answer HELPFUL for all

34.

Integers who's answers is -12

Answer»

ANSWER:

-6 + (-6)

Step-by-step EXPLANATION:

i HOPE this answer HELPFUL for all

Discussion

35.	The mean age of nine members of a club is 30 years.When another person joins the club, the mean age increases to 32 years.How old is the new person?
Answer» Answer: 2 YEARS OLD okkkkkkkkkk

35.

The mean age of nine members of a club is 30 years.When another person joins the club, the mean age increases to 32 years.How old is the new person?

Answer»

Answer:

2 YEARS OLD okkkkkkkkkk

Discussion

36.	Ascending and descinding order 9.09,9.9,9.009
Answer» Step-by-step EXPLANATION: ASCENDING ORDER - 9.009, 9.09, 9.9 descending order - 9.9, 9.09, 9.009

36.

Ascending and descinding order 9.09,9.9,9.009

Answer»

Step-by-step EXPLANATION:

ASCENDING ORDER - 9.009, 9.09, 9.9

descending order - 9.9, 9.09, 9.009

Discussion

37.	A OBC is a rectangle whose three vertices are A(0, 3), O (0, 0) and B (5, 0). The length ofits diagonal is
Answer» ACCORDING to the question, We will use DISTANCE formula $\sqrt{ {x }^{2} + {y}^{2} }$ AO= Squareroot of 0^2 + 3^2 => AO = Squareroot of 0 +9 => AO = Squareroot of 9 AO = 3 units Now, BO = Squareroot of 5^2 +0^2 => BO= squareroot of 10+0 => BO = Squareroot of 10 => BO = 5 units Thereby, ${diagonal}^{2} = {length}^{2} + {breath}^{2}$ SO, AB^2 = AO^2 + BO^2 => AB^2 = (3 units)^2 + (5 units)^2 => AB^2 = 9 sq. units + 25 sq. units => AB^2 = 34 sq. units => AB = Squareroot of 34 units Hence, Length of diagonal of a rectangle is square root of 34 units

37.

A OBC is a rectangle whose three vertices are A(0, 3), O (0, 0) and B (5, 0). The length ofits diagonal is

Answer»

ACCORDING to the question,

We will use DISTANCE formula

$\sqrt{ {x }^{2} + {y}^{2} }$

AO= Squareroot of 0^2 + 3^2

=> AO = Squareroot of 0 +9

=> AO = Squareroot of 9

AO = 3 units

Now,

BO = Squareroot of 5^2 +0^2

=> BO= squareroot of 10+0

=> BO = Squareroot of 10

=> BO = 5 units

Thereby,

${diagonal}^{2} = {length}^{2} + {breath}^{2}$

SO,

AB^2 = AO^2 + BO^2

=> AB^2 = (3 units)^2 + (5 units)^2

=> AB^2 = 9 sq. units + 25 sq. units

=> AB^2 = 34 sq. units

=> AB = Squareroot of 34 units

Hence,

Length of diagonal of a rectangle is square root of 34 units

Discussion

38.	The solution of the equation 5x + 5 = 15,is x = 2 true or false
Answer» ANSWER: TRUE hope it's help you MARK me as brainlist

38.

The solution of the equation 5x + 5 = 15,is x = 2 true or false

Answer»

ANSWER:

TRUE

hope it's help you

MARK me as brainlist

Discussion

39.	Solve the following equation 3×-2=7 / 2×+4=6
Answer» ANSWER: The answer is 3/1 or in SIMPLE terms you can say 3 Step-by-step EXPLANATION: I am 100% SURE

39.

Solve the following equation 3×-2=7 / 2×+4=6

Answer»

ANSWER:

The answer is 3/1 or in SIMPLE terms you can say 3

Step-by-step EXPLANATION:

I am 100% SURE

Discussion

40.	Kripa aapki dhanywaad aapka
Answer» HM Ok JI ☺️ Be HAPPY and TAKE CARE Bye ☺️

40.

Kripa aapki dhanywaad aapka

Answer»

HM Ok JI ☺️

Be HAPPY and TAKE CARE

Bye ☺️

Discussion

41.	Write the median of the data 15, 40, 40, 25, 16, 28, 32, 36, 42, 16, 19, 28,
Answer» Answer: MEDIAN = 30 Step-by-step explanation: Median : The median is the middle most value of the given data. The given data is 15,40,25,16,28,32,36,42.16.19. There are 10 numbers in given data. Therefore, the middle VALUES of the given data are 18 and 32 And if there 2 middle values in the given data then we should, do the sum of the two middle values / 2 Therefore, if we take the middle values as a and b then the FORMULA will be, Median = ( a + b ) ÷ 2 Then here the median will be = 28 + 32 ÷ 2 = 60 ÷ 2 = 30 Therefore, the median of the given data 30

41.

Write the median of the data 15, 40, 40, 25, 16, 28, 32, 36, 42, 16, 19, 28,

Answer»

Answer:

MEDIAN = 30

Step-by-step explanation:

Median : The median is the middle most value of the given data.

The given data is 15,40,25,16,28,32,36,42.16.19.

There are 10 numbers in given data.

Therefore, the middle VALUES of the given data are 18 and 32

And if there 2 middle values in the given data then we should,

do the sum of the two middle values / 2

Therefore, if we take the middle values as a and b then the FORMULA will be,

Median = ( a + b ) ÷ 2

Then here the median will be

= 28 + 32 ÷ 2

= 60 ÷ 2

= 30

Therefore, the median of the given data 30

Discussion

42.	Root 294 - 5 root 3/2 +root 252- 3 root 1/6 simplify
Answer» Answer: 57 is the Step-by-step EXPLANATION: SQUARE ROOT very HARD

42.

Root 294 - 5 root 3/2 +root 252- 3 root 1/6 simplify

Answer»

Answer:

57 is the

Step-by-step EXPLANATION:

SQUARE ROOT very HARD

Discussion

43.	Clasure property is not true for division of rational numbers
Answer» Answer: The closure PROPERTY states that for any two RATIONAL NUMBERS a and b, a ÷ b is also a rational NUMBER. ... But we know that any rational number a, a ÷ 0 is not defined. So rational numbers are not closed under division

43.

Clasure property is not true for division of rational numbers

Answer»

Answer:

The closure PROPERTY states that for any two RATIONAL NUMBERS a and b, a ÷ b is also a rational NUMBER. ... But we know that any rational number a, a ÷ 0 is not defined. So rational numbers are not closed under division

Discussion

44.	_______ ÷ 10 = 0.05pls tell fast
Answer» Answer: 0.5/10=0.05 Step-by-step EXPLANATION:

44.

_______ ÷ 10 = 0.05pls tell fast

Answer»

Answer:

0.5/10=0.05

Step-by-step EXPLANATION:

Discussion

45.	I have 262. How many rupees notes can i get in exchange ? How many rupees will be left ?
Answer» ANSWER: vo AAP PR hai aap KO kitene ka chuuta chayea^o^

45.

I have 262. How many rupees notes can i get in exchange ? How many rupees will be left ?

Answer»

ANSWER:

vo AAP PR hai aap KO kitene ka chuuta chayea^o^

Discussion

46.	nope isiliye to kabhi kahin pae bhi mood kab chnge hojaaye aur plss dukhi honae waali koi baat hai hi ni
Answer» Ok ji mut BANO kuch bhi but I follow NI KARUNGI bye

46.

nope isiliye to kabhi kahin pae bhi mood kab chnge hojaaye aur plss dukhi honae waali koi baat hai hi ni

Answer»

Ok ji mut BANO kuch bhi but I follow NI KARUNGI

bye

Discussion

47.	869,768,584230 write in expanded form in international system
Answer» Answer: (i) eight HUNDRED sixty nine million seven hundred sixty eight thousand five hundred EIGHTY FOUR (II) two hundred thirty

47.

869,768,584230 write in expanded form in international system

Answer»

Answer:

(i) eight HUNDRED sixty nine million seven hundred sixty eight thousand five hundred EIGHTY FOUR

(II) two hundred thirty

Discussion

48.	Which language is best french/sanskrit?
Answer» Answer: SANSKRIT is best Step-by-step explanation: *please MARK me BRAINLIES answer*

48.

Which language is best french/sanskrit?

Answer»

Answer:

SANSKRIT is best

Step-by-step explanation:

please MARK me BRAINLIES answer

Discussion

49.	If A-4x+y²-6xy:B-3y² + 12x² + 8xyC-6x² + 8y² +6xyFind 2A + 2B+C.
Answer» Answer: If A = 4x^2 + y^2 - 6XY; B = 3y^2 + 12x^2 + 8XY; C = 6x^2 + 8y^2 + 6xy FIND A - 3B

49.

If A-4x+y²-6xy:B-3y² + 12x² + 8xyC-6x² + 8y² +6xyFind 2A + 2B+C.

Answer»

Answer:

If A = 4x^2 + y^2 - 6XY; B = 3y^2 + 12x^2 + 8XY; C = 6x^2 + 8y^2 + 6xy FIND A - 3B

Discussion

50.	Give me proper answerwrong answer -: report
Answer» ANSWER: -2 2 -80 80 Step-by-step explanation: Ohms LAW and Power ◆To FIND the Voltage, ( V ) [ V = I x R ] V (VOLTS) = I (amps) x R (Ω) ◆To find the Current, ( I ) [ I = V ÷ R ] I (amps) = V(volts) ÷ R (Ω) To find the Resistance, ( R ) [ R = V ÷ I ] R (Ω) = V (volts) ÷ I (amps) To find the Power (P) [ P = V x I ] P (watts) = V (volts) x I (amps) THANK you❤

50.

Give me proper answerwrong answer -: report

Answer»

ANSWER:

-2
2
-80
80

Step-by-step explanation:

Ohms LAW and Power

◆To FIND the Voltage, ( V ) [ V = I x R ] V (VOLTS) = I (amps) x R (Ω)

◆To find the Current, ( I ) [ I = V ÷ R ] I (amps) = V(volts) ÷ R (Ω)

To find the Resistance, ( R ) [ R = V ÷ I ] R (Ω) = V (volts) ÷ I (amps)

To find the Power (P) [ P = V x I ] P (watts) = V (volts) x I (amps)

THANK you❤

Discussion

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Hope it HELPFUL !!

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Pl answer this question pls

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The mean age of nine members of a club is 30 years.When another person joins the club, the mean age increases to 32 years.How old is the new person?

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Hence,

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Solve the following equation 3×-2=7 / 2×+4=6​

Kripa aapki dhanywaad aapka​

Write the median of the data 15, 40, 40, 25, 16, 28, 32, 36, 42, 16, 19, 28,​

Answer:

Step-by-step explanation:

Root 294 - 5 root 3/2 +root 252- 3 root 1/6 simplify​

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_______ ÷ 10 = 0.05pls tell fast

I have 262. How many rupees notes can i get in exchange ? How many rupees will be left ?​

nope isiliye to kabhi kahin pae bhi mood kab chnge hojaaye aur plss dukhi honae waali koi baat hai hi ni​

869,768,584230 write in expanded form in international system​

Which language is best french/sanskrit?​

please MARK me BRAINLIES answer

If A-4x+y²-6xy:B-3y² + 12x² + 8xyC-6x² + 8y² +6xyFind 2A + 2B+C.​

Give me proper answerwrong answer -: report​

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Find the area of the give figerurea

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(a) -14 + 16 - (-12) – 25

Please correct answer de Thanks

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Factorise 10ab+4a+5b+2

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One-fifth of a mumber is 5. find the number

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Ascending and descinding order 9.09,9.9,9.009

A OBC is a rectangle whose three vertices are A(0, 3), O (0, 0) and B (5, 0). The length ofits diagonal is

The solution of the equation 5x + 5 = 15,is x = 2 true or false

Solve the following equation 3×-2=7 / 2×+4=6

Kripa aapki dhanywaad aapka

Write the median of the data 15, 40, 40, 25, 16, 28, 32, 36, 42, 16, 19, 28,

Root 294 - 5 root 3/2 +root 252- 3 root 1/6 simplify

Clasure property is not true for division of rational numbers

I have 262. How many rupees notes can i get in exchange ? How many rupees will be left ?

nope isiliye to kabhi kahin pae bhi mood kab chnge hojaaye aur plss dukhi honae waali koi baat hai hi ni

869,768,584230 write in expanded form in international system

Which language is best french/sanskrit?

If A-4x+y²-6xy:B-3y² + 12x² + 8xyC-6x² + 8y² +6xyFind 2A + 2B+C.

Give me proper answerwrong answer -: report