A OBC is a rectangle whose three vertices are A(0, 3), O (0, 0) and B

1.	A OBC is a rectangle whose three vertices are A(0, 3), O (0, 0) and B (5, 0). The length ofits diagonal is
Answer» ACCORDING to the question, We will use DISTANCE formula $\sqrt{ {x }^{2} + {y}^{2} }$ AO= Squareroot of 0^2 + 3^2 => AO = Squareroot of 0 +9 => AO = Squareroot of 9 AO = 3 units Now, BO = Squareroot of 5^2 +0^2 => BO= squareroot of 10+0 => BO = Squareroot of 10 => BO = 5 units Thereby, ${diagonal}^{2} = {length}^{2} + {breath}^{2}$ SO, AB^2 = AO^2 + BO^2 => AB^2 = (3 units)^2 + (5 units)^2 => AB^2 = 9 sq. units + 25 sq. units => AB^2 = 34 sq. units => AB = Squareroot of 34 units Hence, Length of diagonal of a rectangle is square root of 34 units

A OBC is a rectangle whose three vertices are A(0, 3), O (0, 0) and B (5, 0). The length ofits diagonal is

Answer»

ACCORDING to the question,

We will use DISTANCE formula

$\sqrt{ {x }^{2} + {y}^{2} }$

AO= Squareroot of 0^2 + 3^2

=> AO = Squareroot of 0 +9

=> AO = Squareroot of 9

AO = 3 units

Now,

BO = Squareroot of 5^2 +0^2

=> BO= squareroot of 10+0

=> BO = Squareroot of 10

=> BO = 5 units

Thereby,

${diagonal}^{2} = {length}^{2} + {breath}^{2}$

SO,

AB^2 = AO^2 + BO^2

=> AB^2 = (3 units)^2 + (5 units)^2

=> AB^2 = 9 sq. units + 25 sq. units

=> AB^2 = 34 sq. units

=> AB = Squareroot of 34 units

Length of diagonal of a rectangle is square root of 34 units