This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1951. |
E X ER CIS E S1. A plece of wire of resistance R is cut into five equal parts. These parts are thenconnected in parallel. If the equivalent resistance of this combination ts R. then theratio R/R'is-(a) 1/25(c) 5(d) 25 |
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| 1952. |
A piece of wire of resistance R is cut into five equal parts. These parts areconnected in parallel. If the equivalent resistance of this combination is R. theratio R/R'is(a) 1/25Which of the following terms does not renresent electrical nower in a circuitb) 1/5(c) 5(d) 25 |
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| 1953. |
25lorgran transfercharacteristics |
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| 1954. |
Marks.- 79Can a body have zero velocity and a finite acceleration? Justify your answer. |
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Answer» Yes. When a ball is thrown vetrically upwards, then at the topmost point it has zero velocity but acceleration is non-zero and is equal to g = 9.8 m/s. |
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| 1955. |
Galilean Transformationcandsatransfer |
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| 1956. |
2KSgraw transfercharacterissiglov |
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| 1957. |
What would you suggest to a student if while performing anexperiment he finds that the pointer/needle of the ammeter andvoltmeter do not coincide with the zero marks on the scales whencircuit is open? No extra ammeter/voltmeter is available in thelaboratory |
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Answer» This is called the zero error of the scale of ammeter or voltmeter. If there is a zero error, then this error is subtracted from the value that it depicts when the circuit is closed, otherwise the accurate current or P.D. will not be recorded |
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| 1958. |
A block of mass 2kg slipped up a slant planerequires 300J of work. If height of slant is10m the work done against friction is -(A) 100JQ.2(B) 200J(D) zero(C) 300 |
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Answer» Work must be done againstfriction as well as gravity.The work done against gravity is change in potential energymgh=2×10×10=200JThe remaining work done againstfriction is 100J. thanku |
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| 1959. |
A heating coil is labelled 100 W. 220 V. The coil iscut in half and the two pieces are joined in parallelto the same source. The energy now liberateper second is(a) 25J(c) 200J16.11995(b) 50J(0 200 l 403 |
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| 1960. |
When a battery of unknown potential V, with zerointernal resistance is connected to a resistance R, 4A.current flows through it. Ifa 1in series with R, current drops to 3A. Find themagnitudes of R and V.0 Ω resistance is connected |
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| 1961. |
A body of mass 5 kg rests on a rough horizontalsurface of coefficient of friction 0.2. The body ispulled through a distance of 10 m by a horizontalforce of 25 N. The kinetic energy acquired by itis (take g = 1 0 ms-2)(a) 200J (b) 150J (c) 100J (d) 50J |
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Answer» Answer:b)150JExplanationLike if you find it useful |
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| 1962. |
2. The Arguments of P, Q, R and s students with respect to electric circuit asfollows. The correct argument isStudentArgumentAmmeter is connected in series and voltmeter in parallelQ Ammeter is connected in parallel and Voltmeter connected in seriesR Ammeter and Voltmeter are connected in seriesAmmeter and Voltmeter are connected in parallelA) P Student onlyC) R Student only(B) Q Student only(D) S Student Only |
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Answer» the correct statement is d |
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| 1963. |
34a) Derive an expression for the equivalent resistance of three resistorsR , and R. connected in seriesR |
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| 1964. |
Q. 4. A wire of 12 Ί resistance is stretcheddouble its length. Find out the new resistance of thwire. |
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Answer» As we know that ;Resistance = Resistivity*length/areaHere we note that the resistance is directly proportional to length and inversely proportional to area of cross section ....Now a/c to question,;Length of wire is double then area is reduced to half...NowNew resistance = resistivity*2length/area/2New resistance =(resistivity*length/area)*4New resistance = 4resistance Hit like if you find it useful |
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| 1965. |
A wire of resistance 16 ohms is elongated double its length. Find the new resistance. |
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Answer» As we know that ;Resistance = Resistivity*length/areaHere we note that the resistance is directly proportional to length and inversely proportional to area of cross section ....Now a/c to question,;Length of wire is double then area is reduced to half...NowNew resistance = resistivity*2length/area/2New resistance =(resistivity*length/area)*4New resistance = 4resistance |
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| 1966. |
A 4 ohm resistance wire is double on it. Calculate the new resistance of wire. |
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| 1967. |
(22.) A 4temperature.resistance wire is doubled on it. Calculate the new resistance of the wire. |
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Answer» The given resistance of wire 4 ohms If resistance is doubled then new resistance will be 8ohms |
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| 1968. |
Sample Problem 3. A 62 resistance wire is doubled up by folding. Calculate the new resistance of the |
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Answer» answer will be 12 as it is doubled answer was 12 because 6+6=12 |
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| 1969. |
To increase currant sensitivity of moving cell galvanometer by 50%, itsresistance is increased so that new resistance becomes twice its initialresistance. By what factor does its voltage sensitivity changes |
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Answer» Resistance formulae : R = V/I Where : R = the resistance V = voltage I = current If the I is increased by 50% then the new I = 1.5I The new resistance becomes : 2R 2R = 1.5I /V V = 1.5I/2R V = 0.75(I/R) The V changes by 0.25 The percentage change = 25% |
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| 1970. |
2/4Sample Problem 3, A 6 S2 resistance wire is doubled up by folding, Calculate the new resistance ofang wire. |
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| 1971. |
9.The resistance of a wire is 100. Its length is increased by 10% by stretching. The newresistance will now be nearly |
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| 1972. |
what is spectrum |
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| 1973. |
Find v vector r, v vector. r and v vector into r vector |
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Answer» Is there any additional Information provided? |
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| 1974. |
Two wires of equal length, one of aluminium and the othér of copper16havexpe the same resistance. Which of the two wires is lighter? Hencelain why aluminium wires are preferred for overhead power cables.= 2.63 x10-8 Ω m, focu-1.72 x 10-8 Ω m, Relative density ofAl 2.7, of Cu 8.9.)the follon nơ observations on a |
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| 1975. |
(3) deflect the rays towards N-pole(4) deflect the rays perpendicular to the plane of paper, upwardsTwelve wires of equal resistance x/y are connected to form a cube. The effective resistancetwo diagonal ends will be25.12x3x(3)V5 X2) 5 y6 y |
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Answer» ans kon ho ga |
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| 1976. |
The lead wires should have(a) Larger diameter and low resistance(b) Smaller diameter and high resistance(c) Smaller diameter and low resistance(d) Larger diameter and high resistance |
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Answer» The wire should be of small diameter and low resistance |
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| 1977. |
44. Twelve wires, each having equal resistance r, are joinedto form a cube as shown in figure (32-E20). Find theequivalent resistance between the diagonally oppositepoints a and f.9 |
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| 1978. |
R 62 ohm are connected so as to form a skeleton cube. Anelectric current enters this cube from one corner and leaves out the diagonally opposite corner. Calculatethe total resistance of this assembly.0.33. Twelve equal wires, each of resistanceAns. 52Sol.: |
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Answer» Kirchhoff's current law, which states that the sum of the currents entering and exiting a node is zero, is essential in the analysis.The first step is to recognize that at a node where equal resistances exist, current entering the node will be distributed equally between the number of output branches - in this case three. ---- Currentiwill be split into 3 branch currents. Since the resistance is same (i.e. r ohm), Current in each branch will bei/3. Thisi/3current will in turn split into 2 branch currents each of valuei/6. ------ The next step is to sum the voltage from input node "a" to output node "b." Any path you take travels along three edges, The current between 2 diagonally opposite side will be composed oftwo i/3 currents and one i/6 current. So that total voltage drop will be same along any path, let the volage drop be V (i/3)r + (i/3)r + (i/6)r = V V = (5i/6)r ------------- Finally, apply Ohms law, which says that the resistance is equal to the voltage divided by the current. Let the equivalent resistance be R R = V / i R = (5i/6)r/i R = 5r/6 ohm => R = 5(6)/6 = 5ohm |
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| 1979. |
One disadvantage of using alcohol as a fuel? Please hurry it's urgent 'morrow is my exam |
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Answer» Requires large piece of land Distillation process is not good for environment Spike in food prices Water attraction Difficult to vaporize I can't get you properly please explain properly |
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| 1980. |
Problem 2.12. Assume that the de-Broglie wave associ-ated with an electron can form a standing wave between theatoms arranged in a one dimensional array with nodes ateach of the atomic sites. It is found that one such standingwave is formed, if the distance d between the atoms of thearray is 2 A. A similar standing wave is again formed, if thedistance d is increased to 2.5 A, but not for any intermediatevalue of d. Find the energy of the electrons in eV and theleast value of d for which the standing wave of the typedescribed above can form.LIT 1997 |
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Answer» Thankyou Sobha Jha... |
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| 1981. |
Why do we need to manage our resources ? |
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Answer» We need to manage our natural resources because natural sources are limited.We need to conserve it forward future otherwise it will be finished. For example-Tree is a natural resource. We get Oxygen, food, medicine etc.Now a days, pollution is increasing. ... That's why we have to manage/save our natural resources. |
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| 1982. |
What is the minimun wavelength of X- rays obtained from Mo target with electrons accelerated by 35KeV potential difference. |
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Answer» f = [1.6 x 10^-19 x 3.5 x 10^4]/ 6.63 x 10^-34 = 8.4x10^18 Hz Therefore the wavelength l (= c/f) is 3 * 10^8/8.4x10^18 Hz = 0.357 x 10-10 m = 0.036 nm (compared with some 600 nm for yellow light). |
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| 1983. |
Q21.An electron microscope uses electrons accelerated by a voltage of V. Determine the de-Brogliewavelength associated with the electrons. Faking other factors, such as numerical aperture etc. to besame, how does the resolving power of an electron microscope compare with that of an opticalmicroscope which uses yellow light? |
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Answer» Thanks microwave> radiowave> x-ray>gammara The kinetic energy of the electron is given as:E=eV= 1.6 × 10−19× 50 × 103= 8 × 10−15J |
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| 1984. |
formula to find accelerated motion? |
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Answer» Acceleration Formula.Acceleration Formula.Accelerationis a measure of how quickly the velocity of an object changes. So, theaccelerationis the change in the velocity, divided by the time.Accelerationhas a magnitude (a value) and a direction |
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| 1985. |
5. A student obtains resistances of 3, 4, 12 and 16 ohnmusing two metallic resistors either separately or joinedtogether. What is the value of resistance of each ofAns 4 and 12 ohm]these wires? |
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Answer» Let us consider the two resistances as 4Ωand 12Ω.Case 1:If we use the only resistor of resistance 4 Ω in the circuitthe net resistance is 4 ΩCase 2:If we use the only resistor of resistance 12 Ω in the circuitthe net resistance is 12 ΩCase 3:If we combine the resistors of resistances 4 Ω, 12 Ω in series,the net resistance of the combination is expressed as the following:4 Ω + 12 Ω = 16 Ω no it is not correct answer |
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| 1986. |
. Two infinitely long parallel wires carry currents of 100 A and 200 A respectively and they repeleach other with a force of 0,.4 N/m. What is the distance between the two wires (in centimetre)Considering Ho 4Tx 10 T-m/A)? |
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Answer» thanks |
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| 1987. |
How does sound travel from one place to another? |
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| 1988. |
d. An electric iron of 1100 W isoperated for 2 hrs daily. What willbe the electrical consumptionexpenses for that in the month ofApril? (The electric companycharges Rs 5 per unit of energy(Ans : Rs 330) |
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Answer» Energy = 1100W = 1.1Kw Energy=power*time=1.1(kw)*2(hr)=2.2kwh Energy used in a day=2.2 unit Energy used in 30 days= 2.2×30unit = 66unit Total cost=66×5=330 rs |
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| 1989. |
CALCULATION OF TENSION17. Amass M is suspended by a rope from a rigid support at A as shown in figure. Another rope is tiedatthe end B, and it is pulled horizontally with a force F. If the rope AB makes an angle 6 with the vertiin equilibrium, then the tension in the string AB is(1) F sin 6(2) F/sin θ(3) F cos θ(4) F/cos e |
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| 1990. |
4. A steel wire and a copper wire of equal length and equalcross-sectional area are joined end to end and thecombination is subjected to a tension. Find the ratio of(a) the stresses developed in the two wires and (b) thestrains developed. Y of steel = 2 × 10 11 N m-t Y of copper-1.3 x 10 11 N m2 |
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| 1991. |
(3) Gases(4) P5 The ratio of radii of two wires of same material is2: 1. If these wires are stretched by equal force,the ratio of stresses produced in them is13.(4) 4 1hon nhreaking 14 |
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Answer» Stress = Force / Area of cross section. Area of cross section depends on square of radius, so the ratio of areas is 4:1 Stress is inversely proportional to area so the ratio of stresses will be 1:4 |
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| 1992. |
A light rod of length 2m is suspended from the ceiling horizontally by means of two vertical wires ofequal length tied to its end. One of the wires is made of steel and is of cross-section 0.1 cm2. The otherwire is of brass of cross-section 0.2 cm2 A weight is suspended from a certain point of the rod such thatequal stresses are produced in both the wires. The rod remains horizontal in this case also. Find out theposition of the load from the steel wire(A) 4/3 m18.(B) 2/3 m(C) 1 m(D) 3/2 m |
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| 1993. |
ERTIES OF SOLIDSd of length 1.05 m having negligible mass is supported at its ends by two wi(wire A) and aluminium (wire B) of equal lengths as show9.15. The cross-sectional areas of wires A and B are 1.0 mm2 and 2.0ctively. At what point along the rod should a mass m be suspended in orce (a) equal stresses and (b) equal strains in both steel and aluminium wi1 |
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| 1994. |
Example 12.16 A light rod of length 2m is suspended frceting horizontally by means of two vertical wires of equal lengthtiedto its ends. One of the wires is made of steel and is ofcross-section 103 m2 and the othe2x10-3m2. Find out the position along the rod at which aweight may be hang to produceis of brass of cross-section(i) equal stresses in both wires,(ii) equal strains on both wires.Young's modulus for steel is 2x10lNm2 and for brass is10Nm-2 |
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| 1995. |
Two thin lences of power +6D and-2D are in contact. What is the focal of the combination |
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Answer» Power of combination= 6 D+(-2 D ) = 6 D -2 D = 4 D power = 1/focal length(m) 4 = 1/ff = 1/4 f = 0.25 metres f of combination = 0.25 * 100 = 25 cm |
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| 1996. |
Two thin prism of crown glass have refractingangles of 10 & 20. The dispersive power ofhese prisms are in the ratio2) 2:14) 4 13) 1:2 |
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Answer» Dispersive power ∝ refractive angle Ratio of dispersive power= 10:20=1:2 |
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| 1997. |
Wheh the object is at distances x1 and x2 from the thin lens, theh the object is at distances x and 2 from the thin lens, the two images formed areof same size but the one is real and the other is virtual, respectively. The focal length cofthe lens is |
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Answer» Let us say it is a convex lens of focal length f. It can form both real and virtual images. 1/v1 - 1/x= 1/f, here v & f are positive and u is negative.1/v1 + 1/x1 = 1/f --- (1)=> x1/v1 + 1 = x1/f -- (2) The virtual image is formed in front of the lens. So v and u1 are negative.- 1/v2 + 1/x2 = 1/f --- (3)- x2/v2 + 1 = x2/f --(4) Magnification = v1/x1 = v2/x2 ---(5) Add (2) and (4) and use (5) to get: 2 = x1/f + x2/f => f = (x1 + x2)/2 |
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| 1998. |
what is Stoke theorom |
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Answer» thanks |
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| 1999. |
When an ideal simple perdulum oscillates between the extreme points P and Q, thereis continuous (i) of potential energy and kinetic energy, The potential energy dependson the choice of (ii) force acting on the bob of the pendulum is maximum at (ii)y andminimum at (iv).(a) Dissipation(b) Dissipation mass(c) Exchange) ExngeVelocity(iv)extremesextremesmid pointmid pointreference levelmid pointmid pointextremesextremesreference level |
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Answer» energy remains constant.. so , only exchange of energy takes place.. also Potential energy depends upon reference level and no. mass and velocity and since force is maximum at extreme level so, acceleration is also maximum at extreme level and minimum at midpoint. so option C |
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| 2000. |
236Jeevandeep SpeQ.2. Solve the following questions. (Any five)i. Study the following reaction and answer the questions asked.NC)//) electrical energy2H,O(D)(Acidic Water)a. What is the above reaction called? |
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Answer» When acidified water is electrolysed, hydrogen and oxygen is formed. Here a single substance water breaks up into two simpler substances, hydrogen and oxygen. So, this is a decomposition reaction. |
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