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To increase currant sensitivity of moving cell galvanometer by 50%, itsresistance is increased so that new resistance becomes twice its initialresistance. By what factor does its voltage sensitivity changes |
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Answer» Resistance formulae : R = V/I Where : R = the resistance V = voltage I = current If the I is increased by 50% then the new I = 1.5I The new resistance becomes : 2R 2R = 1.5I /V V = 1.5I/2R V = 0.75(I/R) The V changes by 0.25 The percentage change = 25% |
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