Explore topic-wise InterviewSolutions in Current Affairs.

Height = h= 55-10= 45Distance= s= 180 mtime taken = tso, h=1/2 gt²or t=√2h/g√2 x 45/9.8=√90/9.8=√9 = 3S= velocity x t180= velocity x 3velocity =180/3 = 60 m/s

Lightning conductors are fixed at the top of the buildings to protect the buildings from lightningLightningLightning is caused due to the heavy electric discharge from the clouds to the earth. If lightning is not controlled, it can cause heavy damage to life and property. Hence, protective measures are of utmost importance during lightning strikes.Lightning RodsTall buildings are provided with lightning rods. A lightning rod is a metal rod that is erected at the top of a building. It is connected to a thick metallic plate, made of a good conducting material like copper and buried under the earth, through a thick copper wire. If lightning is likely to strike the building, it is attracted by the lightning rod, and the electrical discharge is transferred through the wire to the ground. Thus, it keepsthe building safe

it consists of a long metal rod fixed with a side wall of th building .when lightning conductor quickly absorb the charges ,the long metal gives them an easy path to flow down to earth and the coppe plate helps in a quick distribution of charge

sort answer ha

sort answer ha

Tall structures are generally the strongest and have lots of steel and strong foundations. Its the old, flimsily-built buildings, particularly in narrow streets, that are much more dangerous.therefore we should stay away from tall Bridges and building.

Those substances which readily allow the passage of electricity through them are called conductors.

This question is based on concept of horizontal projectile .use trajectory equation of Horizontal projectile.

e.g Y = gx²/2u²

where Y is the displacement of object in y-component wrt to frame , x is the displacement of object in x -component wrt frame . g is acceleration due to gravity and u is intial velocity.

here ,Y = 200 m x = 540 -50 = 490 m

now,

200 = 10 (490)²/2u²

40 = (490)²/u²

u² = (490)²/40

u = 490/2√10=77.47 m/s

Vertical distance between the two buildings = 540 – 50 = 490m

Horizontal distance = 200 m

Suppose ball speed is u and time taken to reach the point is t so

Ball has no initial velocity and takes time t for 490 meter so

S = ut + ½ at^2

490 = 0 + ½ (9.8)(t^2)

T = 10 sec

Horizontal component remain same so we use x = ut

200 = u ( 10 )

U = 10

Ball will be thrown at a speed of 10 m / s

5 kg is the right answer.

5Kg. .

Weight (W) = 49 N

acceleration due to gravity (g) = 9.8 m/s^2

Mass (m) = ?

We know,

W = m * g

or, m = W / g

or, m = 49 / 9.8

Therefore, mass (m) = 5 kg

5kg right answer this question

We know that, weight= Mass × acceleration due to gravity.let weight = w let mass = m let acceleration due to gravity = g

w= m×g so m = w÷g w= 49g= 9.8 m/s^2

m= 49÷9.8 m= 5kg hence, mass is 5 kg

the force required is 100 N

pls explain

the force required wil be the sum of the force due to weight of block down the incline and the frictional force due to static friction on the surface. hence the force along the incline due to wieght of block is 100 cos (60) = 50 N. also the friction force = 10 sin(60)*1/root(3) = 50 N

Lactometer is used to measure purity of milk

a=v-u/t50=100-0/tt=100/50t=2s

tq

If the weather gets bad sodothe roads. Caraccidents happenveryoftenin the rain because water creates slick and dangerous surfaces for cars, trucks, and motorcycles andoftencauses automobilestospin out of control or skid while braking.Toavoid a caraccident, drive extra careful when it rains.

thank you

Velocity of B is = 10 ,

so, velocity of string connecting to A , u is given by

10 = (u+0)/2

=>u = 20 m/s

now this Velocity will always be constant along the stringso, velocity of A along the string is u'cos(37) = 20=>>u = 20/(cos37) = 20*5/4 = 25m/s

option B

option d is correct

wow😂😂

option b is correct 👍🏻👍🏻👍🏻👍🏻👍🏻👍🏻

Beyond Curie temperature, ferromagnetic substances behaves like a paramagnetic substances.

A hydraulic press is a device which is used for lifting a heavy or large load by the application of a comparatively much smaller force than is required to lift the load mechanically or manually. Hydraulic press used in industries are generally converted or built to crush or to press any “process" or the “product". For example, this may include steel plates, aluminum rolls, metallic ores, etc.

The system is a very simple example which demonstrates the operation of a basic hydraulic system. It has two simple cylinders connected to each other, containing an adequate quantity of hydraulic fluid in it. One of the cylinders is larger in size when compared to the other. Both the cylinders have pistons in them, but in strict “hydraulic" terminology, the larger piston is called as a “ram" and small one a “plunger". A small force “P" applied on the plunger, in the downward direction, presses the hydraulic fluid below it. This pressure is transmitted equally in all directions and raises the “ram". The heavier load placed on the “ram" is thus lifted up.

thelaw of conservation of energy statesthat the totalenergyof an isolated system remains constant, it is said to be conserved over time. Thislawmeans thatenergycan neither be created nor destroyed; rather, it can only be transformed or transferred from one form to another.

And:- Inertiais the measure of resistance to the Inertial force( i.e in translation) and simply called asmass.Moment of inertiais the measure of resistance of the object against rotation w.r.t an axis, which is also called as “SecondmomentofMass/Area” it varies from axis to axis of the same body.

Assuming the pendulum executes simple harmonic motion, a = -w^2 x.Since the pendulum is released from rest, only gravitational force acts on it to cause it to swing.The pendulum accelerates in the negative direction if its displacement is positive (depends on sign convention; just be consistent). a= -g sin B = -g B (small angle approximation; B in radians)x = LB (length of arc; B in radians)-g B = -w^2 LBg/L = (2π/T)^2T^2 = (2π)^2 (L/g)T = 2π√(L/g) [only consider the positive root since T cannot be negative]

Alpha particle has 2 protons

So, charge on alpha particle = 2×charge of proton = 2×1.6×10^-19 C

= 3.2×10^-19 C

thnx

= 3.2×10^-19C as a alpha particle has two proton

The first device is ammeter. The second device is galvanometer. The best device to measure change in direction of current would be Galvanometer. The least count of ammeter is 2 micro ampere.

Please hit the like button if this helped you

Least Count of a measuring instrument is the smallest change in the measured quantity that can be resolved on the instrument's scale.[1] The least count is related to the precision of an instrument; an instrument that can measure smaller changes in a value relative to another instrument, has a smaller "least count" value and so is more precise. Any measurement made by the instrument can be considered repeatable to no less than the resolution of the least count. The least count of an instrument is inversely proportional to the precision of the instrument.

PLEASE HIT THE LIKE BUTTON

tnq

The least angle a protector can measure is called least count of a protractor. It is 1 degree in normal protractors.

Convex lens are used to correct presbyopia as the object you see is out of focus convex lens converges the light rays and brings in focus.

So, the person is suffering from presbyopia.

Focal length=1/(power of lens) =1/+0.5=+2 metres

(c) At equilibrium, electric force on drop balances weight of drop.

qE = mg ? q = mg /E

q = 9.9 x 10^-15x 10 / 3 x 10^4= 3.3 x 10^-18©

Iflightstrikes an interface so that there is a 90oangle between the reflected and refracted rays, the reflectedlightwill be linearly polarized. The direction of polarization (the way the electric field vectors point)isparallelto the plane of the interface.

Magnifying poweris defined as the ratio between the dimensions of the image and the object. The process ofmagnificationcan occur in lenses, telescopes, microscopes and even in slide projectors.

Themagnifying power= (focal length of objective) / (focal length of eyepiece); both focal lengths must be in the same length units.

formula for the power of lense is power p. 1/f. p=1/50=0.02