Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

The direction of magnetic field depends on direction of

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A magnetic field is a vector field that describes the magnetic influence of electrical currents

2.

Electrostatic Potential

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The electrostatic potential at any point in an electric field is equal to the amount of work done.

An electric potential is the amount of work needed to move a unit of charge from a reference point to a specific point inside the field without producing an acceleration. Typically, the reference point is the Earth or a point at infinity, although any point can be used.

plz like my answer

3.

A car is moving along a straight road at a steady speed. It travels 150 m in 5 seconds :(a) What is its average speed ?(b) How far does it travel in 1 second ?(C) How far does it travel in 6 seconds ?!(d) How long does it take to travel 240 m ?

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30 m/s , 30×1 30, 30×6 180, 240÷30 8s

4.

1. People who travel into space

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Astronaut is the people who travel into space

people who travel to space is astronaut

5.

Which zone of a flame does a goldsmith use for melting, gold silver and why?

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6.

The total charge induced in a conducting loopwhen it is moved in a magnetic field depends on(a) the rate of change of magnetic flu(b) initial magnetic flux only(c) the total change in magnetic flux(d) final magnetic flux only

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7.

(Magnetic Flux)

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Inphysics, specificallyelectromagnetism, themagnetic flux(often denotedΦorΦB) through a surface is the surfaceintegralof the normal component of themagnetic fieldBpassing through that surface. TheSIunitof magnetic flux is theweber(Wb) and theCGSunit is themaxwell.

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8.

7.The unit of magnetic flux is:

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Unit of magnetic flux is weber.Please hit the like button if this helped you

9.

Q. 2·The angle of projection at which the horizontal range & maximum height of proile are equalA) 45C) θ tan-1 (4)B) θtan-1 (025)D) 60

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10.

(ßi) A 10 mm long pin is placed vertically in frontof a concave mirror. A 5 mm long image of thepin is formed at 30 cm in front of the mirror,find the focal length of this mirror[Ans.き-10 cm]

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We know that

m= h'/h= -v/u

5/10=-30/u

u=-300/5

u=-60cm

1/f=1/v+1/u

1/f = 1/-30 + 1/-60

1/f = -2-1/60

1/f=-3/60

1/f=-1/20

f=-20cm

Therefore the focal length of the concave mirror is 20 cm front of the mirror

11.

2.Electrostatic Potential Difference

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12.

What is electrostatic force

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Electrostatic force is the force that exists between electrically charged particles or objects at rest. Examples of electrostatic forces: When we run a piece of paper with the oil in our head with the help of a comb produces electrostatic force.

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it is force between charged body to an uncharged body

Elecroastic is a type of force where like pole repels each other and unlike pole attract each other.

Electrostatic forces are attractive or repulsiveforcesbetween particles that are caused by their electric charges. This force is also called the Coulomb force or Coulomb interaction and is so named for French physicist Charles-Augustin de Coulomb, who described the force in 1795.

The branch of physic which deals electro means electric field and statics means rest is caller electrostatics force

Electrostatic force are attractive or repulsive forces between particle that are caused by their electric charges. This force is also called the Coulomb force or Coulomb interaction and is so named for French physicist Charles -Augustin de Coulomb, who described the force in 1795.

13.

The example of dot product is(A) angular momentum(B) moment of force(C) linear velocity in terms of angularvelocity(D) magnetic flux linked with the surface ,ofmagnetic induction

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option D is correct , as magnetic flux is ∅ = B•ds = |B||ds|cos∅ .

14.

A coil of resistance 400 is placed in a magnetic field.If the magnetic flux (Wb) linked with the coil varieswith time t (Second) as 6 = 50 +4. The corrent in thecoil at t=2 sis:

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15.

how much of force is resulted due to magnetic field when the magnetic field B is perpendicular to surface of a paper and current I is passing through the conducting wire

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A magnetic field is a picture that we use as a tool to describe how themagnetic forceis distributed in the space around and within something magnetic.

I want answer for this question

16.

A conducting circular loop is placed in a uniformmagnetic field of 0.04 T with its planeperpendicular to the magnetic field. The radiusof the loop starts shrinking at 2 mm/s. Thinduced emf in the loop when the radius is 2 cm11(a) ,48 πμν(b)(d)0.8 πμν3.2 π1iV1.6TI

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17.

State whether the given statement is true or falseA concave lens is a converging lens

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Concave lenses are thinner at the middle. Rays of light that pass through the lens are spread out (they diverge). A concave lens is a diverging lens. When parallel rays of light pass through a concave lens the refracted rays diverge so that they appear to come from one point called the principal focus.

Therefore, statement "A concave lens is a converging lens" is false.

18.

A loop of wire is placed in a magnetic field B-0021TThen the flux through the loop if its area vectorA-30i+16j+23k cm2is(a) 60 uWb(b) 32 u Wb(d) 138 μ Wb

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since B = 0.02i T that is i direction.

so only i direction of area vectors will have flux

so flux = B.A = 0.02T×30cm² = 60μWb option A.

19.

raw graph showing variation of stopping potential with frequency of incident radiation.

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20.

Which colour has maximum stopping potential?Red)B) VioletYe) Yellow D) Green

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Violet.

It will be maximum for photons having maximum energy. Violet color photon has minimum wavelength and maximum energy therefore stopping potential will be maximum for it.

21.

(x) For which of the following stopping potential requried is maximum?(a) Green(b) Yellow(c) Red(d) Violet

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It will be maximum for photons having maximum energy.

Violet color photon has minimum wavelength and maximum energy therefore stopping potential will be maximum for it.

22.

Ammetal sphere A of radius ry charged to a potentialis enveloped by a thin walled conductingherical shell B of radius ry. Then potential o. ofhere A after it is connected to the shell BTby a thin conducting wire will be :-+ATA

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When it is connected by wire, all charge from inside is conducted to the outer shell.And then potential inside the shell is a constant and equal to the potential at the surface i.e kQ/bkQ/a = V So, Q = Va/KSo, New Potential = k(Va/k)/b = Va/b

23.

Write the SI unit of magnetic polestrength.

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Magnetic Pole Strength is the measurement of the force that a pole of a magnet exerts when another pole (similar or dissimilar) of another magnet is brought near to it.

It has got SI unit of- A m (Ampere-Meter)

24.

Consider the diode forward drop equal to 0.7 V, find I?DD(A) 0 mA(B) 0.695 mA(C) 1.608 mA(D) 1 mAVVV2.3KO

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25.

Consider the diode forward drop equal to 0.7 V, find I?3VD D2NAM(A) 0 mA(B) 0.695 mA(C) 1.608 mA(D) 1 mAW2.3K

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26.

190THE CONCEPTUM66. दो चालकों को श्रेणीक्रम एवं समांतरक्रम में जोड़ने परसमतल्य प्रतिरोध क्रमश: 162 एवं 42 होते हैं। प्रत्येकचालक का प्रतिरोध निकालें।(a) 82, 82(b) 42, 82(c) 42, 42(d) 92, 90

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a point 8 ohm and 4 ohm

right answer is option (a)

27.

©Solue the following and enpress theresult to an appespre ate number of significantLo add 6.29 4.332, 17.4569O Seebstract 63.54 kg from 187.2 kg

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27.9. and

180. 8

28.

le is thrown with an initial velocity ofv.i+ v.j) ms-1. If the range of the projectle is2 A projectidouble the maximum height, then v,(1) 2) 2, (3) 3V (4) 4v,

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Range = Vx.T and T = 2Vy/g so, Range = 2Vx.Vy/g

and maximum height = H = Vy²/2g

now, R = 2H => 2Vx.Vy/g = 2*(Vy²/2g)=> Vx.Vy = 1/2*(Vy.Vy)=> Vy = 2Vx

option 2

29.

Consider the diode forward drop equal to 0.7 V, find I ?Di Dz3V NHH(A) 0 mA(B) 0.695 mA(C) 1.608 mA(D) 1 mA2.3KO

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30.

A ball of maskinetic energy of the balls after the collision is three fourths of the original. Find the coefficient ofrestitution.0.35s m moving at a speed v makes a head-on collision with an identical ball at rest. The

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31.

8. Find out the wavelength of the electronorbiting in the ground state of hydrogenatom.

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Radius of ground state of hydrogen atom = 0.53 A° = 0.53*10^-10 m

According to de Broglie relation 2pi*r = n*λ

For ground state n = 1Then,2*3.14*0.53*10^-10 = 1*λ

Therefore, λ = 3.32*10^-10 m= 3.35 A°

32.

31. What would happen to an orbiting planet if all of a sudden it comes to standstill?

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IftheEarthstopped spinning suddenly, the atmospherewouldstill be in motion with theEarth'soriginal 1100 mile per hourrotationspeed at the equator. All of the land masseswouldbe scoured clean of anything not attached to bedrock.

33.

03.A ring A which can slide on a smooth wire is connectedto one end of a string as shown in Fig. 7.133. Other endof the string is connected to a hanging mass B. Findthe speed with the ring when the string makes an anglewith the wire and mass B is going down with a velocity v.

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34.

3. A person completes half of its his journey with speed v, and rest half with speed v. The average speed ofthe person is2D, vDEv +D2

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35.

A person travels along a straight road for the first3 time with a speed v, and for next time witha speed v2. Then the mean speed v is given by6.2t31 1 2v 3v, 3v3v2V123

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Avg velocity =Vavg = S/tTotal distance = S = S1 + S2or V1 x t/3 + V2 x 2t/3

so,

Vavg =V1 x t/3 + V2 x 2t/3 /t

=V1 + 2V2/3

36.

If a sphere is rolling, find the ratio of the translational energy to total kinetic energy

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37.

tationalkineticenergy of a body is E. In the |9of external torque, if mass of the bodyis halved and radius of gyration doubled, then itsrotational kinetic energy will be(1) 0.5E (2) 0.25E (3) E (4) 2E

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Well, if mass is doubled, K. E is doubled

So now K.E1=2K.E

When velocity is halved, K.E becomes 1/4th of initial value

K.E 2 = K.E1 /4

=2*K.E/4

=K.E/2 =0.5E

so, kinetic energy is halved after the changes

38.

A body of mass 5 kg is thrown verticallywith a kinetic energy of 490 J. The heightwhich the kinetic energy of the body beconhalf of the original value is(1) 12.5 m (2) 10 m (3) 2.5 m (4) 5 n

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Let u be the velocity with which it was projectedK = 0.5mu²490 J = 0.5 × 5 kg × u²u² = 196 J/kg

Let v be the velocity at the point where it’s kinetic energy becomes half is490/2 = 0.5 mv²490 Joule = 5 kg × v²v² = 98 Joule/kg

Now, use equation of motion v² - u² = 2aSh = [(98 - 196) J/kg] / (2 × -9.8 m/s²) = 5 m

K.E will become half at height of 5 m

39.

C-8.sThe spacecraft of rmass M moves with velocity Vin free space at first, then it explodes breaking into twopieces. If after explosion a piece of mass m comes to rest, the other piece of space craft wil have avelocity:(A) MVI(M-m)(B) MV/(M + m)(C) mV/(M-m)(D) mV/(M + m)

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Here initial momentum is M*V,

and final momentum , whem mass m is at rest will be m*0 + (M-m)*v' ( v' is needed to be found out..)

so, conserving the momentum ,

MV = (M-m)v'

=> v' = MV/(M-m)

option A

40.

bodyA thrown with an initial speed of 96 ft/sec will reachthe ground after (g 32 ft/sec2)(a) 3 sec (b) 6 sec (c) 12 sec (d) 8 sec

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A = v÷ t T = v ÷ a T = 96 ÷ 32 T = 3 sec

सॉरी sorry bro i think you are right but ans is b

41.

T12 A reference frame attached to the earth18(1) Is an inertial frame by definition2) Cannot be an inertial frame because earth isrevolving round the sunare applicableing about its own axis.(3) Is an inertial frame because Newton's laws(4) Is an inertial frame because the earth is rotat-

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42.

&सरकार एडek e e L B2 काटा डॉनए रररत o g g Bia gp b2 S

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2F=m.a 2F=12×22F=24F=24÷2F=12 N. that's answer.

43.

7n. If the distance between two masses is incresedby a factor of 5, by what factor would the masof one of them have to be altered to maintainthe same gravitational force ? Would this be anincrease or decrease in the mass ?

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44.

State relation between line 8 phasevoltages, line 8 Phase current forstar connected between Systemdelta connected balanced System.

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45.

what will be distance and displacement during one cycle of a field of radius 21meter

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distance= circumference of circle= 2πr= 2(22/7)(21)m=22×6m=132mdisplacement=0

46.

Which year is declared as International yearof physics?

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International year of physics-2005

47.

Discuss the following biomass, good fuels,and tidal energy

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Biomass is waste material from plants or animals that is not used for food or feed; it can be waste from farming (like wheat stalks) or horticulture (yard waste), food processing (like corn cobs), animal farming (manure rich in nitrogen and phosphorus), or human waste from sewage plants.

2)Tidal power or tidal energy is a form of hydropower that converts the energy obtained from tides into useful forms of power, mainly electricity. Although not yet widely used, tidal energy has potential for future electricity generation. Tides are more predictable than the wind and the sun

3)All combustion process give out heat energy.Fuelsare burnt to provide us with energy. However, not every chemical substance that burns is agood fuel. For agood fuel, it must gives out a lot of heat energy to the surroundin

48.

19. What is tidal energy? Why is it not likely to be a potential source of energy?

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49.

A ray of light travelling in the direction + 13) is incidenton a plane mirror. After reflection, it travels along the direction(i-13j). The angle of incidence is (JEE (Advanced) 2013](a) 30°(c) 60°(b) 45°(d) 75°

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50.

Does cosωt + sínωt + cos4ωt represent periodic motion? If yes, then find the period (ω is any positive constant)

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Yes they represent period and periodic isLCM of (2π/w,2π/2w,2π/4w)=2π/2w=π/whence period is pi/w