This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
12. Rice weighingPOunds was divided equally and placed in 4containers, how manv bundes of rice were in each? |
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Answer» 1 pound = 16 ounces3.75 pounds = 44 ounces. This is divided into 4 containersRice in each container = 44/4= 11 ounces. Please hit the like button if this helped you |
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| 2. |
12. Rice weighing 3/, pounds was divided equally and placed in 4containers. How many ounces of rice were in each? |
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Answer» Total weight = 15/4 poundnow divided in 4 partsso each part would be = 0.9375 poundor 15 ounchesplease like the solution 👍 ✔️ and do check previous answers and like them as well |
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| 3. |
Find the value of 15 upto 3 decimal places. |
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Answer» the correct answer is 2.5 solution = 2 |
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| 4. |
Find the value of v5 upto 3 decimal places. |
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| 5. |
Find the value of sqrt5 upto 3 decimal places.. |
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| 6. |
20. In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1: 2: 3. If there isRs. 30 in all, how many 5 p coins are there? |
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Answer» suppose coins are k,2k,3know total 30rs=3000 paisaso 25(k)+10(2k)+5(3k)=300060k=3000so k=50so 5 paisa coins are=3k=150 |
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| 7. |
-What is a polygon? Give some real-lifeexamples where polygons can be seen. |
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Answer» In elementary geometry, a polygon is a plane figure that is described by a finite number of straight line segments connected to form a closed polygonal chain or polygonal circuit. The solid plane region, the bounding circuit, or the two together, may be called a polygon The tiles need to tessellate to cover an area without leaving any gaps. ... The best ratio in tessellatingpolygonsis in a hexagon. As soon as the cost of doing something one way as compared to another, it becomes areal lifeissue. We are surrounded bypolygonsall the time A flat shape at least three and usually five or more, angles and straight ideasEG- |
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| 8. |
Find the value of 13 upto three places of decimal. |
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Answer» hence upto 3 places1.732 |
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| 9. |
Using differential, find the approximate value /0.6upto 3 places of decimal. |
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Answer» Let y=√0.6⇒y=√xx=0.64Δx=−0.04Δy=√(x+Δx)-√x=√(0.64+(−0.04))−√0.64=√0.6−0.8√0.6=Δy+0.8√0.6=Δy+0.8------(1)Step 2:dy is the approximate value of Δydy=dy/dx×Δxdy/dx=1/2√x[Differentiating with respect to x]dy=1/2√x.(−0.04)=−0.04/2√(0.64)=−0.04/(2×0.8)=−0.025Step 3:Substitute the value of dy in equation (1)√0.60=0.8−0.025=0.775 hit like if you find it useful |
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| 10. |
Udit can complete his work in 10 days. What amount of work will be completedin eight days? |
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Answer» He can complete 100 percentage work in 10 daysmeansin one day he can do10 percentageso in 8 he will do 80 percentage of the work |
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| 11. |
wy -+ UTT ( |
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Answer» 21m²------- 7m 3m yeh nahi hai only answer noo full sum |
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| 12. |
3 -9 13++—+— +—20 10 1513-20 |
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| 13. |
(A) 20(C) 24(B) 32(D) 22 |
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Answer» वह संख्या 22होगीक्योंकि22/5=20+2 |
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| 14. |
17. If sec+ tan 8 = x, then tane -(A)0Dags |
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Answer» sec+tan=xsquaring both sides we get(sec+tan)²=x²sec²+tan²+2sectan=x²1+tan²+tan²+2(x-tan)tan=x²1+2tan²+2xtan-2tan²=x²1+2xtan=x²2xtan=x²-1tan=(x²-1)/2xso correct option is C as by squaring both side..(secA+ tanA)™=x™tanA =x*x-1/2x |
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| 15. |
If 60% of A-3 of B, then A:B is4(a) 9:20(b) 20:9(c) 4:5(d) 5:4 |
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| 16. |
20(5+8+5-9-9+6) |
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Answer» 20(18-18+6)20× 6 120is the correct answer of the given question 20 ( 5+8+5+6-9-9)20 ( 24 -9-9)20( 24-18)20( 6)20x6120 120 is the correct answer 20(5+8+5-9-9+6)=20*6=120 is the right answer 20(5+8+5-9-9+6)20*6=120 120 is the correct answer |
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| 17. |
A man spends 75% of his income. His income increased by 20% and he increased his expenditureby 15%. His savings will then be increased by |
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Answer» Let us assume his income is Rs . 100.Now A/Q his expenditure is 75 % i.e. Rs . 75 So his savings = S1 = 100-75 = RS . 25 Later his income increases by 20% → 100 + 100 x 20/100 = Rs. 120and his expenditure increases by 15% → 75 + 75 x 15 /100 = 345/4 = Rs. 86.25 So his savings = S2 = 120 - 86.25 = Rs . 33.75Increment in savings = S2-S1 = 33.75 - 25 = Rs. 8.75 percentage increase = 8.75 / 25 x 100 = 35 % |
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| 18. |
solf a man spends 8e4 of his income, what percentagedoes fesave?ă |
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| 19. |
A man spends 80% of his income. His income is increased by 20% andhe increases his expenditure by 15%. Find the percentage increase in hissavings.17,25000 Due to an increase of5% |
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Answer» Let income = 100exp = 75savings = 25 New income = 100 + 20%(100) = 120New Exp. = 75 + 15%(75) = 86. 25New Sav. = 120 - 86.25 = 33.75% increase in savings = (16.25/50)x100 = 32. 5% 20 persent |
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| 20. |
3. If a man spends 60% of his income, what % does he save? |
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Answer» let the man earn rs 100 so if he spends 60% hence 60/100*100=60 rupeesremaining amount is 100-60=40 rupeeshence he is left with 40 rupeesnow 40 is 40% of 100 rupeeshence he saves 40% of the earnings. |
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| 21. |
A man spends 12% of his income on house rent, 32% on the education of his children16% on food items. Ifhe save Rs 2400 per month, what his monthly income in rupees |
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| 22. |
15. A man spends 1/4 th of his incomeon food, 2/3rd of it on house rent andthe remaining income which is Rs630 on other commodities. Findhis house rent. |
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| 23. |
A man spends on an average Rs.269.47 for the first 7 months and Rs. 281.05 for the next 5 months.Find his monthly salary if he saves Rs.308.46 during the whole year? |
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Answer» Man spend for first 7 months = 269.47 Man spend for next 5 months = 281.05 Man saves during whole year = 308.46 Total income = 269.47 + 281.05 + 308.46 = = 858.98 Monthly salary = 858.98/12= Rs 71.58 |
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| 24. |
What is the purpose of mathematics?How is maths useful in real life? |
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Answer» students see that mathematics can help them better understand and describe the world around them. There is real-life application of almost every form of mathematics. It does not mean that every student will use every piece of mathematics that they learn, but it does mean we can show them how we can use that bit of mathematics to understand and explain something around us. |
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| 25. |
iii) Mr.Shekhar spends 60% of his incom. Frorn the balance he donats Rs.300 torphanage. He is then left with Rs.3200. What is his income? |
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Answer» Let Mr Shekhar's income be Rs xhis expenditure =6x/10donation =Rs300balance =Rs 3200x=6x /10 +300 +320010x =6x +350004x=35000x=Rs 8750Mr Shekhar income is Rs 8750 |
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| 26. |
The sides of a certain triangle are given below. Find, which of them is right-triangle(016 cm, 20 cm and 12 cm(ii) 6 m, 9 m and 13 m |
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Answer» i)12^2+16^2=144+256=400=20^2so it is right angled triangleii)6^2+9^2=36+81=117!=13^26^2+13^2=36+169=205!=9^29^2+13^2=81+169=250!=6^2so it is not right angled triangle |
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| 27. |
same work in 20 days, how many hours shouUdit can complete his workin eight days?days, how many hours should he work in duy(a) Hotis work in 10 days. What amount of work will be completed(b) W |
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| 28. |
10. Find the rate of change in the table below.Show all work.20 22 245.518y 4.5 |
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| 29. |
Practice Set 6.2The followingber ofnumber of hours they work.ing table shows classification of number of workers and the numhoursllowthey work in a software company. Find the median of theDaily No. of hoursNumber of workers15010-1250012-1430014-16508-10The freau |
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| 30. |
3. The capacity of a water tank is 1425litres. Find the capacity of 72 suchwater tanks |
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Answer» capacity of one water tank= 1425 litrecapacity of 72 water tank = 1425×72 = 99750 litre |
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| 31. |
womers heigne2. The Capacity ofthat what is theglass.a glass is 240 tetorescapacity of to suchE |
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Answer» If the capacity of a glass is 240 teses.The capacity of 10 such glasses=240×10= 2400 2400 is the answer...... 1 glass=240 litres10 glasses=10 x 240=2400 litres I mean teses not litres if the capacity of a glass is 240 teses The capacity of 10 such glasses=240×10=2400 |
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| 32. |
I. Ajuice seller was serving his customers using glasses. The inner diameter ofglass was 5 cm, but the bottom of the glass has a hemispherical raisereduced the capacity of the glass. If the height of the glass was 10 emapparent capacity of the glass was and what the actual capacity was. (Use312 |
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| 33. |
13. If 89 buckets of equal capacity can be filled with 586.5 litres of water, what is the capacity ofeach bucket? |
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| 34. |
13. If 69 buckets of equal capacity can be filled with 586.5 litres of water, what is the capacity ofeach bucket? |
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Answer» capacity of 69 buckets= 586.5 litrescapacity of 1 bucket= 586.5/69 = 8.5 litres Answer = 8.5 litres |
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| 35. |
State the name of a regular polygon of(1) 3 sides (ii 4 sides (ii 6 sides |
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| 36. |
denominatmotor boat goes downstream and covers a distance in 4 hours while it coversthe same distance upstream in 5 hours. If the speed of the stream is 3 km/hr, findthe speed of the motor boat in still water. |
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Answer» Let speed of boat in still water be v. Speed of stream = 3 km/hr As distance cover upstream and down stream is same Then,For upstreamDistance = (v - 3)*5 For downstreamDistance = (v + 3)*4 (v - 3)*5 = (v + 3)*45v - 15 = 4v = 125v - 4v = 15 + 12v = 27 Therefore,Speed of boat in still water = 27 km/hr |
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| 37. |
10. A motor boat goes downstream and covers a distance in 4 hours while it coverthe same distance upstream in 5 hours. If the speed of the stream is 3 km/hr, findthe speed of the motor boat in still water.2 DA |
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Answer» Let the speed of the motorboat be X.speed of motorboat in downstream=x+3speed of motorboat in downstream=x-3since,distance=time x speedtherefore,distance travelled by speed of X+3=4(X+3)distance travelled by speed of x+-3=5(x-3)since distance travelled was same, so4(X+3)=5(x-3)4x+12=5x-154x-5x=-15-12-x=-27X=27 therefore, the speed of motorboat is 27 km/hr |
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| 38. |
ă480 is divided equally among x children. If the number of children was 20 more,then each would have got ? 12 less. Find the value of x.1. |
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Answer» thank you |
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| 39. |
Q 26. A motor boat covers a certain distance downstream in a river in 5 hours. It coversthe same distance upstream in 6 hours. The speed of water is 2km/hr. Find the speed ofthe boat in still water. |
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Answer» Let, the speed of boat in still water be x kmph Therefore, speed of boat in downstream is (x+5) kmph And, speed of boat in upstream is (x-5) kmph Now, in downstream the boat covers distance in 1/2 hr (30m) =(x+5)/2 km And, in upstream the boat covers distance in 3/4 hr (45m) = (x-5).3/4km As both the distances are same,(x+5)/2= (x-5).3/4 i.e., 2.(x+5)/2.2 = (x-5).3/4 i.e., 10+2x = 3x-15 i.e., 2x-3x = -15–10 i.e.,-x=-25 i.e., x=25 Hence, the speed of boat in still water is 25 kmph |
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| 40. |
120 kites were divided equally among a certainnumber of children in a school. If four childrenwere less, each would have got i kite moreFind the number of children. |
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Answer» let number of children= xeach get = 120/x4 children less number of children= x-4each get = 120/x-4A/S120/x-4-120/x=1120(x- x+4/x(x-4)=1120×4/x^2-4x=1x^2-4x=480x^2-4x-480=0x^2-24x+20x-480=0x(x-24)+20(x-24)=0(x-24)(x+20)=0either x-24=0 x= 24or x+20=0 x= -20(no of children never be negetive)so number of children= 24 chidren=x; each =120/x; NO. is chikdren=x-4each get=x-4 , 120/x-4-120/x=1; 120(x, x+4-/x( x-4)=1; 120x4/x^2-4x=1;; x^2-4x=-480, x^2-24x+20x-480=0. x(x-24)+20( x-24)=0;(x-24)(x+20); x=24; x=20 |
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| 41. |
is90cmThe diameter of a wheel of a busHow many revolutions will it make totravel 110 km? |
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| 42. |
n a class is 52. Ifthe number ofgrls is 10 moreTotal number of the boys and girls ithan that of boys, find the number ofboys? |
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Answer» Total = 52let the number of boys be Xthen the number of girls = X + 10X+(X+10) = 522x+10= 522x = 52-102x= 42X= 42/ 2X = 21 so number of boys = 21 |
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| 43. |
11. Mr. Vinod has x2 - 4x + 3 children. On the occasionof Holi Mr. Vinod brought some sweets. Thenumber of sweets is represented by x + 2x - 13x- 12x + 21. Mr. Vinod wants to distribute sweetsamong all his children equally. But the number ofsweets is not exactly divisible by the number ofchildren. So, Mr. Vinod decides to distribute theextra sweets among the slum children.(i) Find the number of sweets which wasdistributed among the slum children.(ii) What values have been shown by Mr. Vinod?[Value Based Question] (4) |
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| 44. |
13. Mr. Cupta has 85 pens. He wants to distribute them equally among 5 childrenHow many pens is each child get? |
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Answer» Each child gets 17 pens 85/5 = 17 |
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| 45. |
Calculate the edge of the cube, if its volume is 1331 cm^3 |
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| 46. |
- कितने समय में ३ 1000, 10% प्रतिवर्षचक्रवृद्धि दर पर * 1331 हो जाएगा? |
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| 47. |
Posmaa133112136 |
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Answer» thanks bhai |
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| 48. |
(11/10)^n=1331/1000 |
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Answer» as 11^3=1331and 10^3=1000hence(1331/1000)=(11/10)^3n=3 |
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| 49. |
Reduce the following tolowest form121/1331 |
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Answer» 121/1331 = 11/121 = 1/11 |
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| 50. |
Find the cube root of the following numbers:13314096(tb) |
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Answer» First find prime factors of1331 and 4096 1331 = 11*11*114096 = 2*2*2*2*2*2*2*2*2*2*2*2 Therefore,1331/4096 = (11)^3 /(2)^12 cube root of 1331/4096= [(11)^3 /(2)^12]^1/3= 11/(2)^4= 11/16 |
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