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Using differential, find the approximate value /0.6upto 3 places of decimal. |
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Answer» Let y=√0.6⇒y=√xx=0.64Δx=−0.04Δy=√(x+Δx)-√x=√(0.64+(−0.04))−√0.64=√0.6−0.8√0.6=Δy+0.8√0.6=Δy+0.8------(1)Step 2:dy is the approximate value of Δydy=dy/dx×Δxdy/dx=1/2√x[Differentiating with respect to x]dy=1/2√x.(−0.04)=−0.04/2√(0.64)=−0.04/(2×0.8)=−0.025Step 3:Substitute the value of dy in equation (1)√0.60=0.8−0.025=0.775 hit like if you find it useful |
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