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let ( x1 , y1 ) = A( 2 , 0 ) ,

( x2 , y2 ) = B ( 0 , 2/9 ) ;

mid point of joining of A and B = ( x1+ x2 /2 , y1 + y2 /2 ) = ( 0 + 2 /2 , 0 + 2/9 / 2 ) = ( 1 , 1/9 )

p/3 = 1/9

[∵ If ( a , b ) = ( c , d ) then a = c and b = d ]

p = 1/3 --- ( 1 )

according to the problem given ,

put ( -1 , 3p ) in the equation 5x + 3y + 2 =0

5 ( -1 ) + 3× ( 3p ) + 2 = 0

-5 + 3× 3 ( 1/3 ) + 2 =0 [ from ( 1 ) ]

-5 + 3 + 2 =0

0 = 0 [ true ]

Therefore ,

5x + 3y + 2 =0 line passes through thepoint ( -1 , 3p ) .

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( 1, 2 ) is the right answer

(1,2) is the correct answer of the given question

(1,2) is the answer .......

(1,2)is the correct answer for the given question

This statement is True

Mid point= (x1+x2/2;y1+2/2)

X1= -4; x2= 2

Y1= 8; y2= 6

》[(-4+(-2))/2,(8+6)/2]

=[-3,(7)]........

Solution : part 1GivenΔ ABP is an equilateral triangle.Then, AP = BP (Same side of the triangle)and AD = BC (Same side of square)and,∠ DAP =∠ DAB -∠ PAB = 90° - 60° = 30°Similarly,∠ BPC =∠ ABC -∠ ABP = 90° - 60° = 30°∴∠ DAP =∠ BPC∴Δ APD is congruent toΔ BPC ( SAS proved)2nd partInΔ APDAP = AD II as AP = AB (equilateral triangle)We know that∠ DAP = 30°∴∠ APD = (180° - 30°)/2 (Δ APD is an isosceles triangle and∠ APD is on of the base angles.)= 150°/2 = 75°=∠ APD = 75°Similarly,∠ BPC = 75°Therefore,∠ DPC = 360° - (75°+75°+60°)=∠ DPC = 150°Now inΔ PDCPD = PC asΔ APD is congruent toΔ BPC∴Δ PDC is an isosceles triangleAnd∠ PDC =∠ PCD = (180° - 150°)/2or∠ PDC =∠ PCD = 15°∠ DPC = 150°;∠ PDC = 15° and∠ PCD = 15° Answer.

In triangle APB & AQBThen,AB=AB (common)AQ=AP(side)QAB=PAB(angle)Then,We can say that,Triangle APB is congruent toAQB

3x-y=3........19x-3y=9..(divided by 3)3x-y=3......2

3x=3-yX=3-y/3

sub X in 13x-y=33(3-y/3)-y=33-y-y=3-2y=3-3

y=0

sub y in 2

3x-y=33x-0=33x=3

X=1

(3x-y =3)3= 9x - 3y = 9; 9x+3y = 9:; 9x + 3y =9/6y =18; y = 18/6=3, ; 3x -3=3; 3x= 6:; x= 6/3=2

Draw a median CD to AB from C.

Now, by Pythagoras theorem in ABC, AB=2*BC.Thus, BD= half of AB = BC.

But, the point of bisection of the hypotenuse is equidistant from all sides.

Thus, CD=BD=AD.

That implifies, CD=BD=BC.

Thus, CDB is an equilateral triangle.

Therefore, angle DBC = angle ABC = 60 degrees.

If y = 73°Then2y-16= 130And 130+x= 180°X= 50°Please like the solutionAnd when x= 14°70+2y-16= 1802y= 126Y= 63°Please like the solution 👍 ✔️

s = 6/5 × 15/26 ×283.75s = 3 × 3/13 × 283.75s = 196.4423

s= 196.4423 is the correct answer of the given question is

1. ii

-x+y=6

if x=0 0+y=6 y=6if x=1 -1+y=6 y=7

Please post complete question

x + 2x = 9

We know same variable can be equated

So,

3x = 9

x = 3

thank you so much

The answer of 5+8 = 13

The answer is 9in to 5=45

34 is the best answer

The answer is 34 because1+4=52+5=7 then add before answer 7+5=123+6=9 9+12 =21

1×4 = 4 +1 =42×5 =10 +2 =123×6 =18 +3 = 215×8 = 40+5 = 45 ✔

there are two ways1)1+4=5 2+5=7+5=12 3+6=9+12=21 5+8=13+21=342) 1*4=4+1=5 2*5=10+2=12 3*6=18+3=21 5*8=40+5=45the answer may be 34 or45

34 os the correct answer exactly

34 is the right answer

Answer:The steps of construction are as follows.(i)Draw a line AB. Take a point P on it. Take a point C outside this line. Join C to P.(ii)Taking P as centre and with a convenient radius, draw an arc intersecting line AB atpoint D and PC at point E.(iii) Taking C as centre and with the same radius as before, draw an arc FG intersectingPC at H.(iv) Adjust the compasses up to the length of DE. Without changing the opening ofcompasses and taking H as the centre, draw an arc to intersect the previously drawn arcFG at point I.

Sum of all angles of a quadrilateral=360°2x+10+3x+15+4x-30+2x-20=36011x-25=36011x=385x=35Smallest exterior angle will of biggest angleAngles will be2x+10=2*35+10=80°3x+15=3*35+15=120°4x-30=4*35-30=110°2x-20=2*35-20=50°Hence biggest angle is 120°Hence ,exterior angle will be 180-120=60°option a

answer kya h

answer no 1 .50 %

what is your question

The profit share has to be proportional to the income u both earned.

15000: 25000

= 3:5

So the share of profit for

3x + 5x = 16800

x = 16800 / 8 = 2100

So, your share = 3x =$ 6300& her share = 5x =$ 10500

15000:250003:5(3x16800)/8=6300(5x16800)/8=10500

2100 is the correct answer of the given question

Let the number be xThen,3/5 * (60/100) * x = 363/5 * 3/5 * x = 369/25 * x = 36x = 36*25/9x = 4*25x = 100

Therefore, Number is 100

(a) is correct option

angle r is 52 alternate angle52+40+x=18092+x=180x=180-92x=88

8) a) =<QPT=52°=<TSR=40°given PQ||SRtherefore, we know that exterior angle is equal to the sum of two interior angle=QPT=STR+RST=52°=40°+xor, x=52°-40°=x=92°

(a) . X = 88 , (b). X = 130

sum of straight line 180

angles are 45 ,90,70

answer is 28•33° degree hoga

the straight line forming is forming an angle of 180 so the all the angle forming are supplementary x degree +70 degree + (2x-25) degree equal to 180that is x+70+2x-25 equal to 1803x+45 equal to 180 3x equal to 180-45 3x equal to 135 x equal to 45

28.33333333 is ryt answer

poq=45°and qos=65° hai

z+40+z+20+z+30=180angles in linear pairso,3z+90=1803z=180-90so,3z=90so,z=90/3=30so,z+40=30+40=70z+20=30+20=50z+30=30+30=60

thnkew