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5.Fig.5.19Line / is the bisector of an angle A and B is anypoint on 7. BP and BQ are perpendiculars from Bto the arms of Z A (see Fig. 5.20). Show that:(1) AAPB=AAQB(ii) BP = BQ or B is equidistant from the armsof ZA.Fig. 5.20 |
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Answer» In triangle APB & AQBThen,AB=AB (common)AQ=AP(side)QAB=PAB(angle)Then,We can say that,Triangle APB is congruent toAQB |
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