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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
4.Divideas directed:(a) (m2 - 14m -32)(m+2) |
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Answer» [m^2 - 14m - 32] ÷ [m+2] First factorise (m^2 - 14m - 32)= m^2 - 16m + 2m - 32= m(m - 16) +2(m - 16)= (m+2)(m-16) Thus,(m+2)(m-16)/(m+2)= (m-16) |
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| 2. |
(7/2)*(6*(2/3)) %2B (3/2)*(6*(2/3)) %2B (5/2)*(6*(2/3)) |
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Answer» 20/3*3/2+5/2*20/2+7/2*20/3=10+25+70/3=35+70/3=105+70/3=175/3 |
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| 3. |
ही)... / 2-2).(ज़िन 2) +6 (X——6 0 la X # "2, 6 |
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| 4. |
I.In figure : AD+4 cm, BD-3 cm, CB12 cm, then cot θ |
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| 5. |
.\begin{array} { l } { \text { Evaluate: } } \\ { \text { (1) } 2 ^ { 5 } \times 2 ^ { 8 } + 2 ^ { 6 } } \\ { \text { (3) } ( - 2 ) ^ { 6 } \div ( - 2 ) ^ { 12 } \times ( - 2 ) ^ { 3 } } \\ { \text { (5) } 5 \times 2 ^ { 6 } + 2 ^ { 4 } } \end{array} |
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Answer» This is the answer |
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| 6. |
12. To warn ships for underwater rocks, a lighthousespreads a red coloured light over a sector of angle80° to a distance of 16.5 km. Find the area of the seaover which the ships are warned. (Use t 3.14) |
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| 7. |
12. To warn ships for underwater rocks, a lighthousespreads a red coloured light over a sector of angle80° to a distance of 16.5 km. Find the area of the seaover which the ships are warned. (Use π = 3.14) |
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| 8. |
1/3rd part of the bamboo is coloured green and 1/5th is coloured in red and remaining 14m is coloured in yellow. find the length of the bamboo? |
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Answer» Let total length=xx/3 + x/5 + 14=x8x/15 + 14=x14=7x/15x=30 Total length=30m thanks |
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| 9. |
Find the area of a carpet that fully covers arectangular room whose length รกnd breadthare 1600 cm and' 10 m respectively. Whatwould it cost to get the carpet dry cleaned atthe rate of 5 per square metre? |
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Answer» Area of the rectangular carpet = l*b = 16m*10m = 160 m² Cost = 160 m² * 5rps/m² = 800 rupees Hit like if you find it useful! thanks |
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| 10. |
Find the area of the four walls of the room whose length, breadth and height are 8 m, 6 m and 5 mrespectively. Ignoring the door, windows and other openings, find the cost of whitewashing the wallsat the rate of 7 per sq. m |
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Answer» Area of four walls= 2 (length*height + breadth*height) Length = 8 m, Breadth = 6 m, Height = 5 m Then,Area of four walls = 2(8*5 + 6*5)= 2(40 + 30)= 2*70 = 140 m^2 Cost of painting = 140*7= Rs 980 |
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| 11. |
Find the height of a room whose length is 10 cm, breadth is 25 cm and total surfacearea is 2635 cm2c.Find the metal sheet required to make a closed cylindrical tank of heigdiameter 90 cmht 14 cm an |
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Answer» thank you Thank You |
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| 12. |
36. The length and breadth of a rectangular room is 4mand 3 m respectivety. IH aisclass room is to be tiled with square tiles whose side is 40 en, bow masy dles will berequired ?(1) 503) 75(2) 100(4) 400 |
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Answer» Assuming floor tiles for a room size of 4x3 m =12 m²area. Tile side = 40 cm = 0.4 m =0.16 m²area. 12 / 0.16 =75 tiles. |
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| 13. |
3. If each side of a regular heptagon of side 5 cm is increased by 1 cm, then increase in perimeter is |
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Answer» Number of sides in a heptagon = 7 Perimeter of a regular heptagon= 7(length of each side) Hence, increase in perimeter= 7(increase in length of each side)=7×1cm=7cm |
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| 14. |
an(b) The perimeter of a triangle is 14 cm. The second side is 5 cm less than the first sideside is 3 cm more than the second side. The first side of the triangle is unknown. |
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| 15. |
1. 80 beads remained with Swati after making 3 strings using 4and g of the28beads she had. Find the number of beads used by Swati to make the threestrings(1) 320 (2) 540 (3) 560 (4) 640 |
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Answer» Parts of beads remaining = 1-(1/4+1/2+1/8)= 1/812.5 percentage = 80 beads25 percentage= 16050 percentage = 320total beads = 560 |
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| 16. |
(b) The perimeter of a triangle is 14 cm. The second side is 5 cm less than the first side and the thirdside is 3 cm more than the second side. The first side of the triangle is unknown. |
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Answer» let the second side be Xhence the first side is X+5third side will be X+3hence perimeter is sum of all sidesX+X+5+X+3=143X+8=143x=6X=2hence the first side is X+5=2+5=7cm |
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| 17. |
uiugolal Is 3u cm.SshĂźma divided it in two different ways (Fig 11.21)J the area of this hexagon using both ways.Hende3: There is a hexagon MNOPQR of side 5 cm (Fig 11.20). Aman and11 cm5 cmRidhima' methodAman's method:Fig 11.20Fig 11.21 |
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Answer» There are two ways of finding the area. 1) Dividing the hexagon into 6 equilateral triangles and getting the area of one triangle multiplied by 6. 2) Dividing the hexagon into two trapezium and getting the area of individual trapezium. First we need the height of the equilateral triangle. By pythagorean theorem we have : 5^2 - 2.5^2 = 18.75 Square root of 18.75 = 4.330 1) Area of one equilateral triangle : 4.330 × 0.5 × 5 = 10.825 For the six : 6 × 10.825 = 64.95 square centimeters. 2) The area of the trapezium is : The two parallel sides of the trapezium are 10cm and 5 cm. The height is 4.30cm Area : (10 + 5) /2 × 4.30 = 32.25 We have two trapezium. 2 × 32.28 = 64.5 square centimeter. |
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| 18. |
1. Find the area of a:(i) regular pentagon ABCDE of side 5 cm and AD BD 4 cm. |
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| 19. |
andFind the length of the wooden strip required to frame a photogy aphbreadth 25 cm. If the wooden strip costs 50 paise per centimeof lengh 35 cnthe cost of tramingthe photograph.centipnetre, find the cost of framing |
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Answer» loans hydro electric on a bsgx |
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| 20. |
Archana bought some kilograms of wheat She requires 12 ka per month and she got enoughwheat milled for 3 months. After that, she had 14 kg left. How much wheat had Archana boughtaltogether?Ans. |
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Answer» archana bought =( 3 × 12 + 14)kg of wheat = 36+14 kg =50kg |
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| 21. |
what is the length of the wooden strip required to frame a photograph of length and breadth 32 cm and 21 CM respectively |
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| 22. |
. In Question 2 above, if I part of a red pigment requires 75 mL of base, )red pigment should we mix with 1800 mL of base? |
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| 23. |
B 2 ) o4 (ii) 17 |
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| 24. |
| और.Find: o4 /)\/‘3;-5" |
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Answer» (a). 64½ =(8²)½So,8 is the answer. (b) (2ⁿ) ¹/ⁿ=2 is the answer (c). 125⅓= (5³)⅓So 5 is the answer |
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| 25. |
s S ———¢ o4 15 60 X7 3,5 |
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| 26. |
लिए ८20८ पलिए “न o4 te98 -p ; पा क |
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Answer» Secθ+tanθ=p ----------------------(1)∵, sec²θ-tan²θ=1or, (secθ+tanθ)(secθ-tanθ)=1or, secθ-tanθ=1/p ----------------(2)Adding (1) and (2) we get,2secθ=p+1/por, secθ=(p²+1)/2p∴, cosθ=1/secθ=2p/(p²+1)∴, sinθ=√(1-cos²θ)=√[1-{2p/(p²+1)}²]=√[1-4p²/(p²+1)²]=√[{(p²+1)²-4p²}/(p²+1)²]=√[(p⁴+2p²+1-4p²)/(p²+1)²]=√(p⁴-2p²+1)/(p²+1)=√(p²-1)²/(p²+1)=(p²-1)/(p²+1)∴, cosecθ=1/sinθ=1/[(p²-1)/(p²+1)]=(p²+1)/(p²-1) |
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| 27. |
20. ८०8 [5० त् के बराबर मान होगा- o4~ |
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| 28. |
Outمار 8Sec Atan Acosec ANot definedNot definedای داده انده - ادتدردهانهامآ- ا- ا-)5- |Not definedNot defined |
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Answer» this is trigonometry table but where us question what do you want from me Trigonometry Table is good It Is A Trigoñometry Tàble and ask you a question it's a trigonometry table what's the question in this table...??? do you have any doubt..? this is the table of trigonometry tangent ratios it's a trigonometry table what is the question? this is the table of Trigoñometry ratios |
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| 29. |
. “कक के की WY |
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| 30. |
WY .. e 24y के ‘J&’ = |
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| 31. |
Wy(рек) 23 > (0.7) x 53 | |
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Answer» Please hit the like button if this helped you |
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| 32. |
Choose the odd numeral pair/group in the given question:(a) 2 -83 - 27(c) 4-32(d) 5- 125 |
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Answer» odd no.s are which are not divisible by 2 so (b) and (d) is the right option As in the option (a) cube of 2 is 8 (b) cube of 3 is 27 (d) cube of 5 is 125but in (c) cube of 4 is not 32 Therefore c is the answer |
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| 33. |
Wy '14, tan! J3 —sec”! (-2) का मान बराबर |
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Answer» tan-1(3½) - sec-1(-2)= 60 - 120= -60 degrees. Please hit the like button sec-1(-2)=? |
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| 34. |
Wy 'nf flflfi e एकgb wflj'fl- oo |
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Answer» Let the other zero be q. 2x^2-3x+p=0 Sum of zeroes = -b/a3+q = 3/2q = 3/2 - 3q = 3-6/2q = -3/2 Product of zeroes = c/a3+(-3/2) = p/26-3/2 = p/23/2 = p/2p=3 |
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| 35. |
1) Each prime number has exactlyfactors.wy- |
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Answer» Two Each prime number has exactly two factors. two. 2 numbers is the right answer two. emo telyadu............ Two factors is the answer |
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| 36. |
2. निम्नलिखित को 1 ली के प्रतिशत में बदलिए-(क) 5419 मिली (ख) 90 मिली(ग) 37 मिली(घ) 54 मिली। |
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Answer» 1 litre=1000mlA)5.412 litreB) 0.029 litre C) 0.037 litre D) 0.054 litre |
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| 37. |
a ofthe4wallsofa room is 168 m2. The breadth and heightof the room are 10 m and4 m respectively. Find the length of the room.18. The areá of the 4 walls of a room is 77 m2. The length and breadth of the room are f15 m3.5 m respectively. Find the height of the room. |
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| 38. |
18. The area of the 4 walls of a room is 77 m2. The length and breadth of the room are 7.5and 3.5 m respectively. Find the height of the room |
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| 39. |
18. The area of the 4 walls of a room is 77 m2. The length and breadth of the room are7.5 nare 7.5 mand 3.5 m respectively. Find the height of the room |
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| 40. |
18. The area of the 4 walls of a room is 77 m2. The length and breadth of the room are?.5 mand 3.5 m respectively. Find the height of the room |
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| 41. |
e area of the 4 wallhe area of the 4 walls of a room is 77 m2. The length and breadth of the roommnd 3 5 m respectively. Find the height of the room |
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| 42. |
30. What will come in a place of questionmark?निम्नलिखित में प्रश्नवाचक के स्थान पर क्याआएगा?233(A) 306(C) 141(B) 278(D) 300 |
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Answer» ans is the question B 278 ans is the question B 278 |
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| 43. |
and 4 m respectively. Find the length of the room.18. The area of the 4 walls of a room is 77 m2. The length and breadth of the room are 7.5 mand 3.5 m respectively. Find the height of the room. |
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| 44. |
Now you write these analso say them aloud.27=31 30+54790 +963 =36 -s 80 + 2 |
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| 45. |
15291710en below is a grouped frequency distributionss interval 100-150 150-200 200-250 250-300 300-350 3uencya cumulative frequency distribution table 'of less than type' for it.8152917 |
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Answer» no you told wrong answer Question you have submitted is incomplete. Please post a complete question. |
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| 46. |
17. Find the loss per cent, if CP= 300,SP=250.INV |
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Answer» I don't no............. See- Given: CP=300 and SP=250=CP-SP= 300-250 =50 percent loss, = loss÷cp*100 = 50÷300*100=50÷3= 16.6666667This is your answer...if my answer helps you so please like cp=300, sp=250 then loss percentage is 16 =CP-SP=300-250=50loss %=50.formal of loss%=loss×100/CP=50×100/300=16.6 16.6 present loss is right answer |
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| 47. |
Vani is 6th from the front end of the line of girls and Swati is 9ith from the back end of the line. Ifthere are 7 girls between Vani and Swati, then how many maximum girls are there in the line?(A) 20ox (B) 21(D) 23e (C) 22 |
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| 48. |
Swati is 3 years younger than her brother Ravi. Ifthe sum of their ages is 33 years, write an equationto find their ages. |
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| 49. |
be reguiredtopatk8888bal3u. If the thickness of a pile of 16 cardboards is 44 mm, how many cardboards will be there in apile which is 71.5 cm thick? |
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| 50. |
In a stack there are 5 books each of thickness 20mm and 5 paper sheets ethickness 0.016 mm. What is the total thickness of the stack. |
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