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Let the width be x.then length be x+4A/Q-l+b=36x+(x+4)=362x+4=362x=36-42x=32x=16.Hence, The length of garden will be 20 m and width willbe 16 m.

perimeter =2 (l+b)half peri. 36m= (l+b)let breadth=xlength= 4xperimeter= 2×36= 72mperimeter = 2 (l+b)72= 2 (4+x+x)36= 4+2x36-4=2x32= 2x32/2=x16=xbreadth=16length= x+4=16+4=20

perimeter = 2( l+b); half peri=36m=( l+b); breadth=x; length=4x; perimeter=2×36=72 m; 36=4+2x; 36-4=2x; 32=2x; x=32/2=16 = breadth; length=x+4=16+4=20

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Total height = 66mSubmerged part = 5/6×66 = 55 mIceberg height seen above the water = 66-55 = 11 m

Above water will be (1-5/6)=1/6th partHence 1/6th of 66 will be 1/6*66=11m

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As DE || BC

Use Basic Proportionality Theorem

DE/BD = AE /EC

2.4/BD = 3.2/4.8

BD = (2.4 × 4.8)/3.2

BD = 3.6 cm

(a) Total area of the region = 100 × 144 = 14400 cm2

Area of one tile = 12 × 5 = 60 cm2

Number of tiles required =14400/60=240

Therefore, 240 tiles are required.

(b) Total area of the region = 70 × 36 = 2520 cm2

Area of one tile = 60 cm2

Number of tiles required =2520/60=42

Therefore, 42 tiles are required.

a

Ans :- Narendra Modi

Since2014

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take r^2 =tthen we can get simple quadratic eq. t^2 +t +1=0t={-1+(1-4)^0.5}/2,{-1-(1-4)^0.5)}/2t=-1/2 +sqrt(3) i /2,-1/2-sqrt(3) i /2r=t^0.5r={-1/2+sqrt(3) i /2}^0.5, {-1/2-sqrt(3) i/2}^0.5

ans is this

r^4 +r^2 +1add and subtract r^3 , r^2 and rwe get, r^4 +(r^3+r^2 -r^3 -r^2 +r -r )+r^2 +1now arranging them=(r^4 +r^3 +r^2)-(r^3 +r^2 +r)+(r^2 +r+1)=r^2(r^2+r+1)-r (r^2 +r+1)+1 (r^2 +r+1)=(r^2-r+1)(r^2 +r+1)

is there any trick to factorise the polynomial ?

some times tricks are not applied to all questions so we have try hit and trial method.

ummm i dont know theeeee anwser sorry but solve it pls some one

ummm I don't know there're answer sorry but solve it places some one

b+ 135 =180 (linear pair of angles)=>b =180-135 => b=45 degrees

a+40 =135 {the exterior angle is equal to the sum of opposite interior angles of a triangle}

=>a =135-40=>a =95 degrees

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Assuming Average diet per person = constant

Per Person Per Day Consumption = 200 kg/ (40 pax * 30 day) = 1/6 kg

Therefore, Days = 500 Kg / (1/6kg * 30 pax) = 100 days

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5x + 3y = 16x = (16 - 3y)/5

For y = 2x = (16 - 3*2)/5 = 10/5 = 2

For y = - 3x = (16 + 3*3)/5 = 25/5 = 5

For y = 3x = (16 - 3*3)/5 = 7/5

For y = 4x = (16 - 3*4)/5 = 3/5

Therefore, four solutions are(2,2), (5,-3), (7/5, 3), (3/5,4)

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