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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
the length breadth and height of the room are 5m 4mand 3m respectively. find the area of the four wall of the room |
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Answer» Given that,length = 5 mbreadth = 4 mheight = 3 marea of 4 walls = 2h (L+ b) = 2 * 3 (4 +5 ) = 6*9 = 54 sq m Like my answer if you find it useful! |
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| 2. |
and+toposite+to, Q9. Four-fifth of a number is greatel Wall tQ.10. The greater of two odd numbers is 12 more than the smaller and the sum of the two numbers is10. Find the numbers. |
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Answer» Answer: 11 and -1 Explanation:Let the two number be x and yx-y=12.....(1)x+y=10....(2)(1)+(2);2x=22;x=11 then y=-1 please like my answer if you find it useful |
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| 3. |
A tile is 15 cm long and 10 cm wide. The four walls of the kitchen need to be tiled.If the length and breadth of each wall is 440 cm and 750 cm, how many tiles willrequired to tile the entire kitchen?be |
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Answer» Area of 4 walls=4*(440*750)cm²=4*330000 cm²=1320000 cm² Area of one tile=length×breadth=15×10 cm²=150 cm² No. of tiles required=1320000/150=8800 tiles this answer is correct |
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| 4. |
langSam af |
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Answer» In mathematics, the Pythagorean theorem, also known as Pythagoras' theorem, is a fundamental relation in Euclidean geometry among the three sides of a right triangle. It states that the square of the hypotenuse is equal to the sum of the squares of the other two sides. |
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| 5. |
Prove that a line drawn through the mid- point of one side of a triangle parallel to a.aother -Side bisects the third side. |
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Answer» ka be |
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| 6. |
(v) Prove that the line drawn through the mid-point of one side of a triangle paralle to another side bisects thethird side. |
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Answer» you can sure on your answer |
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| 7. |
The perimeter of a triangle is 50cm. one side of a triangle is 4cm longer than the smaller side andthe third side is 6cm less than twice the smaller side. Find the area of the triangle. |
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| 8. |
third side lie?The lengths of two sides of a triangle are 8.3 cm and 5.9 cm. Betweenwhich two numbers will the length of third side lie?4.5. PS is a median of APQR. Prove that PQ+ QR+ PR >2PS. |
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| 9. |
You will see that cUllbelow:Theorem 8.10: The line drawn through the mid-point of one side of a trianparallel to another side bisects the third side.gle |
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Answer» photo bhejo diagram car digram ka |
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| 10. |
6. Find the equation of the line whoseperpendicular distance from the origin is 4 andthe angle which the normal makes with positive[MSE 2009]directions of x-axis is 15. |
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| 11. |
5. एञ 26"(i) ot 640 |
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Answer» It will be 1as tan (90-26}= cot64° = cot 64/cot 64= 1 please like the solution 👍 ✔️ |
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| 12. |
640Fig. 25 |
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Answer» angle CAD + angle CDA + 64° = 180° 2 angle CDA = 180° - 64° = 116° angle CDA= 116°/2 = 58° So, angle ADB = 180° - 58° = 122° angle ADB + x + x = 180° 2x = 180° - 122° x = 58°/2 x = 29° |
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| 13. |
29.5%of 640 +16.5%of 188=2 |
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Answer» 29.5 % of 640 + 16.5 % of 780 = 29.5/100 * 640 + 16.5/100 * 780 = 188.8 + 128.7 = 317.5 29.5/100×640=188.816.5/100×780=128.7188.8+128.7=317.5 |
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| 14. |
FE GOALS. DONE.B BAJAJ Allianz â |
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Answer» 2x2 = 4( multiplication) 4 is the correct answer multiply 2 into 2 |
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| 15. |
Whats 9+10 |
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Answer» 9 + 10 = 19 |
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| 16. |
if x,y,z are in AP and AM of x and y is a and that of y and z is b then whatsAM of and b |
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| 17. |
Find the value of:of 04+of 640 ?85 |
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| 18. |
Find x, y and z in each of the(i)Dton>640 |
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Answer» y=116 degreex=z=64 degree |
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| 19. |
Draw the neat free hand sketch of Squirrel Cage Induction motor. |
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| 20. |
The angles of quadrilateral are in the ratio 3:5:9:13. Find all the angles of theguadrilateral |
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| 21. |
The angles of quadrilateral are in the ratio 3: 5:9:13. Find thesmallest angle of the quadrilateral. |
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| 22. |
3. In an AP(i) given a-5, d-3, a,-50, find n and S.(ü) given a -7,4, "35, find d and s,(ii) given a2 37, d-3, find a and S,2(iv) given a, 15, S 125, find d and a(v) given d 5, S, 75, find a and a(vi) given a 2, d -8, S, -90, find n and a,of13*10°9(vii) given a 8, a, 62, S, 210, find n and d.(vii) given a, -4,d -2, S,-14, find n and a.(ix) given a 3, n 8, S 192, find d.(3) given/ 28, S 144, and there are total 9 terms. Find a |
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| 23. |
The angles of quadrilateral are in the ratio 3 5 9 13 Find all the angles of thequadrilateral. |
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| 24. |
4.Draw the neat free hand sketch of Squirrel Cage Induction motor. |
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Answer» Draw this. |
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| 25. |
3. In an APgiven a-5,d-3,a, - 50, find n and S(Gi) given a 7,a, 35, find dand Sii) given a 37, d- 3, find a and S2(iv) given a, 15, S 125, find d and a()given d-5, S, 75, find a and a,vi) given a-2, d-8, s 90, find n and a(vi) given a -8,a,- 62, S(vili) given a 4, d-2, S210, find n and d14, find n and a(ix) given a 3, m 8,S 192, find d0) given/-28, S-144, and there are total 9 terms. Find a |
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| 26. |
23. Hasan buys two kinds of cloth materials forschool uniforms shirt material that costs him50 per metre and trouser material that costshim 90 per metre. For every 3 metres of theshirt material, he buys 2 metres of the trousermaterial. He sells the materials at 12% and10% profit respectively. His total sale is36600. How much trouser material did hebuy? |
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| 27. |
Q. 7. Hasan buys two kinds of clothmaterials for school uniforms, shirt materialthat costs him 50 per metre and trousermaterial that costs him R 90 per metre. Forevery 2 meters of the trouser material he buys3 metres of the shirt material. He sells thematerials at 12% and 10% profit respectively.His total sale is 36,600. How much trouser !material did he buy? |
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| 28. |
In a factory a certain type of material costs sh 76.75 per metre. Asha ordered15 rolls of the material. Each roll was 40 m 20 cm long. How much did Ashapay for the material? |
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Answer» total length of the material = 15×(40 m 20 cm) = 600m 300cm = 603mtotal cost=sh (603× 76.75) = sh 46280.25 how much does40m15cm exceed12m23cm? |
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| 29. |
10. The angles of a quadrilateral are in the ratio 3 59: 13. Find thegreatest angle of the quadrilateral. |
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Answer» thank you 😊 your phone number please😭 let angle=X1angle=3x2angle=5x3angle=9x4angle=13xtotal angle=30x=360X=360/30=1213*12=156 |
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| 30. |
10 The angles of a quadrilateral are in the ratio 3 :5:9 13. Find thegreatest angle of the quadrilateral |
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| 31. |
Three angles are 3:4:5 and the difference between least and the greatest angle is 45 find the four angles of quadrilateral |
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Answer» The ratio of the three angles of quadrilateral=3:4:5=3:4:5 Let the angles be3x,4x3x,4xand5x5x The greatest angle among these is5x5xand the least is3x3x According to the given condition , 5x−3x=455x−3x=45 2x=452x=45 x=452x=452 x=22.5x=22.5 Hence the three angles are 3×22.5=67.5∘3×22.5=67.5∘ 4×22.5=90∘4×22.5=90∘ 5×22.5=112.5∘ Answer :67.5,90,112.5 |
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| 32. |
ook at the Fig. 9.6. We have a rectangle and a parallelogram with same perimeter l4 cm4 omPB3cm(ir)Fig. 9.6 |
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| 33. |
Very-Short and Short-Answer Questions1. The first three terms of an AP are respectively (3y-1), (3y+5(5y +1), find the value of yCBSE 2 |
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| 34. |
& Ramesh had 20 pencils, Sheelu had 50 pencils and Jamaal had 80 pencils. After 4months, Ramesh used up 10 pencils, Sheelu used up 25 pencils and Jamaal used up!40 pencils. What fraction did each use up? Check if each has used up an equal fractionof her/his pencils? |
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Answer» hi uajahaiqijqvsvsuajabsbsbvdus The fraction in which they use up is 1/2.Yes,each has used up an equal fraction of his pencils 1/2 is your correct answer 1/2 is correct answer. |
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| 35. |
8. Ramesh had 20 pencils, Sheelu had 50 pencils and Jamaal had 80 pencils. Af4 months, Ramesh used up 10 pencils, Sheelu used up 25 pencils and Jamused up 40 pencils. What fraction did each use up? Check if each has used uprual fraction of her/his pencils? |
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| 36. |
60Ramesh had 20 pencils, Sheelu had 50 pencils and Jamaal had 80 pencils. After4 months, Ramesh used up 10 pencils, Sheelu used up 25 pencils and Jamaalused up 40 pencils. What fraction did each use up? Check if each has used up anequal fraction of her/his pencils? |
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| 37. |
sh had 20 pencils, Sheelu had 50 pencils and Jamaal had 80 penecils. After Aonths, Ramesh used up 10 pencils, Sheelu used up 25 pencils and Jamaal used up40 pencils. What fraction did each use up? Check ifeach has used up an equal fractionS2288.of her/his pencils? |
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Answer» Fraction used by Ramesh =10/20 Fraction used by Sheelu =25/50 Fraction used by Jamaal =40/80 Yes, all of them used equal fraction of pencils i.e., |
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| 38. |
1./Af nth term of an AP. is (2n+1), what is its 13th terms? |
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Answer» Given nth term is 2n +1 So, 13 th term will be 2 × 13 + 1 26 + 1 27 |
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| 39. |
then in badions6) The angles of a triangle are in ap thefind themgreatest angle af 3 times. The denseD degrees i) hadians. |
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| 40. |
)AB is a chord of length cm of a cincle of radius 5 cm. The tangents to thele af A and B interseet at P Find the length of APl fi1 omFig. (2)ORl noint to a circle are equal. |
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| 41. |
ClCL6726 |
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| 42. |
5. At what rate per cent per6. A sum of money becomesimipof itself in 6 years at a certain rate of simple interest. Find3the rate of interestn each of the following: |
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| 43. |
162519. Simple interest on a certain sumisof the sum. Findthe rate per cent and the time if both are numericallyequal. |
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Answer» let s be sumthen I =16/25 sr=t. (given)I=prt/10016/25 s =s×r×r/10016/25=r²/100r²=16×100/25r=40/5r=8%t=8yrs |
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| 44. |
wlo00 motuht to2Ife 640 amounts to 768 in 2 years 6cent per annum?months, what will* 1700 amount to in 3 years at the same rate pw |
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| 45. |
years?2.At what rate per cent per annum will3600 amount to4734 in 3 |
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Answer» thanks |
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| 46. |
5 A shim of money amounts to R 1150 in 3 years and to? 1250 in 5 years at a certain rate per cent p.a. simpleinterest. The rate per cent p.a. will be |
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Answer» Let the rate of interest be r% and the principal be Rs.P We know, Interest = (Principal*Rate*Time)/100 According to the problem, in 3 years, 1150-P = (P * 3 * r) / 100;i.e., (1150-P)/3 = (P*r)/100 ....... this be equation (i) According to the problem, in 5 years, 1250-P = (P * 5 * r) / 100;i.e., (1250-P)/5 = (P*r)/100 ....... this be equation (ii) Comparing equations (i) and (ii), we get:(1150-P)/3 = (1250-P)/5i.e., 5*(1150-P)=3*(1250-P);i.e., 5750 - 5P = 3750 - 3Pi.e., 2P = 2000i.e., P = Rs. 1000 Putting this value of P in equation (i), we get the value of ri.e., (1150-P)/3 = (P*r)/100i.e., 150/3 = (1000*r)/100i.e., 50 = (10*r)i.e., r = 5 % Ans: Rate = 5% |
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| 47. |
. Simple interest on a certain sum is 16/25 of the sum.The rate per cent, if the rate per cent and time (in yr)are equal, is(a) 6%(c) 10%m) 8%(d) 12% |
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| 48. |
rt what rate per cent per annumwoud? 5,000 become8,000 in 32 years? |
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Answer» r=?simpal interest= p*r*t/1003000= 5000*r*3.5/1003000= 50*3.5*rr= 17.1 percentage |
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| 49. |
. At what rate per cent per annum will a sum treble itself in 16 years |
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| 50. |
12. If 250 amounts to 285 in 2 years, find the rate per cent per annum. |
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