Explore topic-wise InterviewSolutions in Current Affairs.

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1.

11./fn Δ ABCand Δ DEF. ABEDE, AB 11 DE, BCEFand BC II EF. Vertices A, B and C are joined tovertices D, E and F respectively (see Fig. 8.22)Show that0) quadrilateral ABED is a parallelogram(ii) quadrilateral BEFC is a parallelogram(ii) AD II CF and AD CFFig. 8952(iv) quadrilateral ACFD is a parallelogranm(v) AC DF(vi) Δ ABC= Δ DEF.igog

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2.

Fig 8.211. In Δ ABC and Δ DEF. ABDE' ABIDE, BCEFand BC II EF. Vertices A, B and C are joined tovertices D, E and F respectively (see Fig. 8.22).Show that0 quadrilateral ABED is a parallelogram(ii) quadrilateral BEFC is a parallelogram(iii) AD II CF and AD CF(iv) quadrilateral ACFD is a parallelogram(v) AC DFFig. 8.22

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3.

11. 1n Δ ABC and Δ DEF, ABDE, AB 11 DE, BCEFand BC II EF. Vertices A, B and C are joined tovertices D, E and F respectively (see Fig. 8.22).Show that130 quadrilateral ABED is a parallelogram(ii) quadrilateral BEFC is a parallelogram pao(ii) AD IICF and AD CFFig. 8.22(iv) quadrilateral ACFD is a parallelograma a t(v) AC DF(vi) Δ ABC= Δ DEF.

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thanks

4.

11. In Δ ABC and Δ DEE AB-DE, AB 11 DE, BC-EFand BC II EF. Vertices A, B and C are joined tovertices D, E and F respectively (see Fig. 8.22).Show thatquadrilateral ABED is a parallelogram(ii) quadrilateral BEFC is a parallelogram(iii) AD 11 CF and AD CF(iv) quadrilateral ACFD is a parallelogram(v) AC-DF(vi) Δ ABC Δ DEF.Fig. 8.22

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5.

In Δ ABC and Δ DEF, AB DE, AB 11 DE.BC EF and BC II EF. Vertices A, B and Care joined to vertices D, E and Frespectively (see Fig. 7.22). Show that(i) quadrilateral ABED is a parallelogram(ii) quadrilateral BEFC is a parallelogram(iii) AD 11 CF and AD CF(iv) quadrilateral ACFD is a parallelogram(v) AC DF(vi) Δ ABC Δ DEF.Fig.

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6.

Each floor of a high rise building is fittedwith 20 doors. There are 12 floors in eachbuilding. There are 25 such buildings in acomplex. The total number of doors fittedin the complex is _____A. 2400B. 3000C.6000D. 5000

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7.

Each floor of a high rise building is fittedwith 20 doors. There are 12 floors in eachbuilding. There are 25 such buildings in acomplex. The total number of doors fittedin the complex is _____A. 2400C. 6000B. 3000D. 5000

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8.

पे हज - %iy o *2/ oo ey ”’I ‘/) eo- 4] ~

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hit like if you find it useful

9.

7. निम्न रैखिक समीकरणों के युग्मों, को हल कीजिए: px+qy=p-gq (i)qQ-py=p+yq

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10.

Practice Set 15.6Radii of the circles are given below, find their areas.(1) 28 cm(2) 10.5 cm (3) 17.5 cm

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area of circle=πr^2=22/7×28×28=22×4×28=88×28=2464rest of the same use the formula

formula=d/228/2=1410.5/2=5.2517.5/2=8.7517.5/2=10.5/2

"Area of circle''

R1=28cmArea =πr2 =22/7×28×28 =2464cm2

R2=10.5cmArea =22/7×10.5×10.5 =

use the area of radius formula then u get the answer....and....do examples....u can get the correct steps and solution also understand

r=28cmA=πr^2 =22/7×28×28 =2464cm^2r=10.5A=22/7×10.5×10.5 =346.5cm^2

1.area=2464cm^22 area=346•5cm^23 area 962•5 cm^2

use formula area of circle= πr^2π=22/7

first wala ka answer 2464

area of circleR1=πr2 =22/7*28*28 =2464cm*2464cm

R2 =10.5cmarea =22/7*10.5*10.5 =346.5cm*346.5cm

R3=17.5cm

area=22/7*17.5*17.5 =962.5cm*962.5cm

1)2464 sq cm2)346.5 sq cm3)962.5 sq cm

2464 , 346.5 , and. ,962.5 is the answer

(1)2,464sqcm(2)346.5sqcm(3)962.5sqcm are the correct answers

1 246sq cm 2 346.5 sq cm 3 962.5 sq cm

ans. 2464 square centimetres

11.

7. The period of sine wave is.02 seconds. Its frequency is(a) 20 Hz(b) 30 Hz(c) 40 1Iz(d) 50 Hz

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12.

Radii of the circles are given below, find their areas.(1) 28 cm (23 10.5 cm (3) 17.5 cm

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13.

निम्नलिखित को सत्यापित कोजिएहै. a0B e

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14.

Practice Set 15.6Radii of the circles are given below, find their areas.(1) 28 cm(2) 10.5 cm(3) 17.5 cm

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15.

e - a0 जज—————————-—'—b——_fke_v_k__&w_f b, = ( (O

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16.

12. In the adjoining figure, O is the centre of a circle, XY is adiameter and XZ is a chord. Prove that XY > XZ[Hint. Join OZ. Then, OX + OZ > XZ → XY > XZ.]110

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Pata nahi mujhe salo kameeno mujse kyu puch rahe ho

17.

EIf x: y-38 and yz-4:9 find xz

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18.

सनक की के; का ना Ao7 2, RGO x +y= 5 % और रद ¥ y_z न2को हल रहर

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thank you

19.

way the property:-xxlyxz) = (xxy) xz by taking 2:31974 xxY) xz dytw

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x*(y*z)=7/3*(12/5*4/9)=7/3*(4/5*4/3)=7*16/3*15=112/15and(x*y)*z=(7/3*12/5)*4/9=112/15hence verified

20.

Inthegivenfigure POLAB, If xz 1:3:5, then find the degree measure of x, y and z

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21.

Hence, xz +yz-zxy.Find the sum of each of the followi1. 8+4/2+4+2/2+... oo

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22.

3. The numbers X, Y, Z are such that XY 96050 & XZis greater than Z by one. Find out the number Z?95625&Y

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23.

8. In the figure, YQ L XZ and ZP L XY, alsoy'Q ZP. Find three pairs of correspondingparts which make AYQZ AZPY by RHScongruence rule.154

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24.

In a survey it was found that 21 people liked prodúct A, 26 liked product B and29 liked product C. If 14 people liked products A and B, 12 people liked productsC and A, 14 people liked products B and C and 8 liked all the three products.Find how many liked product C only

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Let A, B and C denote the set of people who like products A, B and C respectively.Then it is given that 21 people like product A, i.e. n(A) = 21.Similarly, we have n(B) = 26 and n(C) = 29.Now, 14 people like both A and B, so this means n(A \cap B) = 14.Similarly, n(C \cap A) = 12, n(B \cap C) = 14 and n(A \cap B \cap C) = 8.The number of people who liked just product C is given by =n(C) – n(C \cap A) – n(B \cap C) + n(A \cap B \cap C)( you can also create venn diagram for the same, the formula will be clearer in that case)= 29-12-14+8= 11.Hence,11 people liked only product C.

thnk uhh

25.

V What do you mean by LPP?) Solve the following by graphical methoMaximize z = 2x1 +5x2subject to the constraints5x1 +6x2 2303x1 + 2x2 521x1 + x2 512Xz, xz 20

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LPPstands for Linear Programming Problems. It is a method to achieve the best outcome (such as maximum profit or lowest cost) in a mathematical model whose requirements are represented by linear relationships. Linear programming is a special case of mathematical programming.

what is lpp

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LPPstands for Linear Programming Problems. According to Wikipedia. It is a method to achieve the best outcome (such as maximum profit or lowest cost) in a mathematical model whose requirements are represented by linear relationships. Linear programming is a special case of mathematical programming.

LPPstands for Linear Programming Problems. According to Wikipedia. It is a method to achieve the best outcome (such as maximum profit or lowest cost) in a mathematical model whose requirements are represented by linear relationships. Linear programming is a special case of mathematical programming.

26.

newspaper.In a survey it was found that 21 people liked product A, 26 liked product B and29 liked product C. If 14 people liked products A and B, 12 people liked productsC and A, 14 people liked products B and C and 8 liked all the three products.Find how many liked product C only.16.et Bthen

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27.

In a survey it was found that 21 people liked product A, 26 liked product B and29 liked product C. If 14 people liked products A and B, 12 people liked productsC and A, 14 people liked products B-and C and 8 liked all the three products.Find how many liked product C only.) 7

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11liked C only

28.

urvey it vas found that 21 people liked product A, 26 liked product B and29 liked product C. If 14 people liked products A and B, 12 people liked productsC and A, 14 people liked products B and C and 8 liked all the three productsFind how many liked product Conly.Suunmaryntor deals rith some basic definitions and operations involving sets. The

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29.

In a survey it is found that 21 people likes product A,26Likes product B and 29 people likes product C if 14 peA and B, 12 people likes C&A, 14 people likes B anall three products.find That How Many People likes8ople likes

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30.

If (a +b+c)>0 and a0 b c, then the equationa(x -b)(x -c)+ b(x- c)(x- a)+c(x - a)(x - b) 0 has(A) real and distinct roots(C) product of roots is negative(B) roots are imaginary(D) product of roots is positive

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The roots are real

a(x−b)(x−c)+b(x−c)(x−a)+c(x−a)(x−b)=0a(x−b)(x−c)+b(x−c)(x−a)+c(x−a)(x−b)=0

⟹a[x2−(b+c)x+bc]+b[x2−(c+a)x+ca]+c[x2−(a+b)x+ab]=0⟹a[x2−(b+c)x+bc]+b[x2−(c+a)x+ca]+c[x2−(a+b)x+ab]=0

⟹(a+b+c)x2−2(ab+bc+ca)x+3abc=0⟹(a+b+c)x2−2(ab+bc+ca)x+3abc=0

D=4(ab+bc+ca)2−4(a+b+c)(3abc)D=4(ab+bc+ca)2−4(a+b+c)(3abc)

=4(a2b2+b2c2+c2a2+2a2bc+2ab2c+2abc2−3a2bc−3ab2c−3abc2)=4(a2b2+b2c2+c2a2+2a2bc+2ab2c+2abc2−3a2bc−3ab2c−3abc2)

=4(a2b2+b2c2+c2a2−a2bc−ab2c−abc2)=4(a2b2+b2c2+c2a2−a2bc−ab2c−abc2)

=2(2a2b2+2b2c2+2c2a2−2a2bc−2ab2c−2abc2)=2(2a2b2+2b2c2+2c2a2−2a2bc−2ab2c−2abc2)

=2[(ab−bc)2+(bc−ca)2+(ca−ab)2]=2[(ab−bc)2+(bc−ca)2+(ca−ab)2]

⟹D≥0∀a,b,c∈R⟹D≥0∀a,b,c∈R

Ifx=a=b=cx=a=b=c, we haveD=0D=0

31.

o7(3); =% 59ÂĽ~ 4) :

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(3y²+5y-4)-(8y-y²-4)=3y²+5y-4-8y+y²+4=4y²-3y=y(4y-3)

32.

Shruti bought 2.95 m dress material for her mother and 4.65 m for her sister. How much drmaterial did she buy?5.

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total dress material2.95m+4.65m=7.60m

33.

s oKk o7 Yok o

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Explanation : 135 = 3×3×3×5 225 = 3×3×5×5 HCF = 3×3×5 = 45

Solution : 45

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34.

Lalita wants to buy a border material for her saree. The shopkeeperthat a roll of 25 metres of the border material would cost her 700. Lalitjust 9 metres of border. How much does she have to pay the shop

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Cost of 25 metres = Rs. 700Cost of 1 metre = 700/25 = Rs. 28Cost of 9 metres = 28*9 = Rs. 252

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35.

When simplified(2/3 is

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= (-1/27)-2/3= [(-1/3)3]-2/3= (-1/3)-2= 1 / (-1/3)2= 1/ (1/9)= 9

36.

xx3xx can be simplified as

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Answer is 1/5 power of x

37.

2. What is the simplified form of

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√7/8 is the correct answer of the given question

38.

vTitC(a) CH,-CCHCH

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2-methyl-propene

39.

WHAT IS THE SIMPLIFIED VALUE OF[cValtv7) = (VT-va] ?

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[ ( 41+7 ) ÷ ( 41-7 ) ] = 0

1 is the answer of this question because similar value division answer is 1

(√41-√7)² is answer by using identity (a-b)²=(a-b)(a+b)

the answer is 34 by using the formula of (a+b) (a-b) = a^2 - b^2...

the answer of the question is 0

when divide these terms then answer will be obtained 1

ravan ke pitaji ka naam kya hai

1 is the answer because dividing these no. we get 1

1 i̸͟͞s̸͟͞ t̸͟͞h̸͟͞e̸͟͞ a̸͟͞n̸͟͞s̸͟͞w̸͟͞e̸͟͞r̸͟͞

firstly we know, divide is the inverse of multiplication, then we can write

(√41 + √7)-----------------(√41 - √7 )

then (√41 + √7) (√41 + √7 ) ----------------- x -----------------(√41 - √7 ) (√41 + √7 )

upper make the formula of (A +B) 2and downward (A2 - B2)

41 + 7 + 2√41√7-------------------------- 41 - 7

48 + 2√287---------------- 34

24 +√287--------------- answer 17

1 is the answer of this question

root 41+ root 7 ------------ root 41 -root 7

root 41 + root 7 × root 41 +root 7__________________________

root 41- root 7 × root 41 +root 7

(root 41 +root 7) power 2 ____________________ 34

it will be 0 because + intu -=

24/7)+(2*(287)"1/2))/17

(24 + √287)/17 ans hoga Rationalisation kr ke solve kr sakte hai

17/17√287 is correct answer

1 is the simplified answer

40.

(13)L. Write the simplified form of:(13)

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41.

81x^4/y^-8has simplified value equal to

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42.

el' what is the simplified value of (81)-÷ (81)1?

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43.

(b) Write (22)3 x 36 in simplified exponential form.

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Your correct answer is (2*2)³* =643*3*3*3*3*3*=72964*729=46,656

46,656 is the correct answer of the given question

44.

A stone is dropped into a quiet lake and waves move in circles at the speed of swhen the radius of the circular wave is 8cm, how fast is the enclosed area is increasing

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this is a solution for a similar ques, only the numerical values are different.

45.

A stone is dropped into a quiet lake and waves move in circles at the speed of 5cm / sec. Atwhen the radius of the circular wave is 8em, how fast is the enclosed area is i

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Step 1:Given :drdt=5cm/s and radius=8cmArea of the circle is πr2Differentiating w.r.t t on both sides we get,dAdt=2πrdrdtStep 2:Substituting for r and drdt we get,dAdt=2×π×8×5=80πcm2/sHence the enclosed area is increasing at the rate of 80πcm2/s

46.

of 4 cm/sec. AtA stone is dropped into a quiet lake and waves move in circles at a speedthe instant when the radius of the circular wave is 10 cm, how fast is the enclosed areaincreasing?24.

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plz send me again

47.

CHWrite the IUPAC name of H3C-CH-CH CH2Cl

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2-chloro-3-methyl butane

48.

. Select from the following a groupof electrical appliances in which(1) Electric bell, electric iron,(2) Electric generator, electric(3) Electric motor, electricmagnets are used.electric buibmotor, electric beillgenerator, electric furnace4) Electric generator, electric bell,electric heater

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Magnets are used in electric generator,electric motor and electric bell.(option 2)

49.

3. In the adjoining figure, ABCD is a trapeziumin which ABIDC. If <A = 55° and <B = 700find ZC and LD.55°700

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50.

en figure.lines PO and RS intersect at pointO. If △-53°, find all ober anges2

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angle 3 = angle 1 = 53° ( vertically opposite angle)

So,

angle 1 + angle 4 = 180°

angle 4 = 180° - 53° = 127°

angle 2 = 127°

( vertically opposite angle)