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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Practice Set 14.2the construction work of a flyover bridge therewere 320 workersThe number of workers were increased by 25% every year.number of workers after 2 years.the |
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Answer» 25 %of 320 is 80 workers so after two years :2 × 80 = 160(160 is no of workers increased)no of workers after 2 years are: 320 + 160=480 |
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| 2. |
e construction work of a flyover bridge there were 320 workers1. On thinitially. The number of workers were increased by 25% every year. Findthe number of workers after 2 years. |
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Answer» A = P[1+(r/100)]^n= 320*[1+(25/100)]^2= 320*(5/4)²= 500 workers. Please hit the like button |
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| 3. |
10 m long instead of S(U9. A brooch is made with silver wire in the form of acircle with diameter 35 mm. The wire is also used inmaking 5 diameters which divide the circle into 10ual sectors as shown in Fig. 12.12. Find:(0) the total length of the silver wire required.(ii) the area of each sector of the brooch. |
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| 4. |
8. A horse is tied to a peg at one corner of a squareshaped grass field of side 15 m by means of a 5 mlong rope (see Fig. 5.11). Find(i) the area of that part of the field in which thehorse can graze.(ii) the increase in the grazing area if the rope were10 m long instead of 5 m. (Use T 3.14)9. A brooch is made with silver wire in the form ofacircle with diameter 35 mm. The wire is also used inmaking 5 diameters which divide the circle into 10equal sectors as shown in Fig. 5.12. Find:(i) the total length of the silver wire required.(ii) the area of each sector of the brooch. |
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| 5. |
un51 01 11UL LUI CUIU. 110corresponding segment of the circle.(Use n=3.14 and 13 = 1.73)A horse is tied to a peg at one corner of a squshaped grass field of side 15 m by means of a 5long rope (see Fig. 12.11). Find(i) the area of that part of the field in which thorse can graze.(ii) the increase in the grazing area if the rope we10 m long instead of 5 m. (Use a=3.14)A brooch is made with silver wire in the form ofcircle with diameter 35 mm. The wire is also used imaking 5 diameters which divide the circle into 10equal sectors as shown in Fig. 12.12. Find :(i) the total length of the silver wire required.(ii) the area of each sector of the brooch. |
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| 6. |
e diameter of a copper sphere is 18 cm. It is melted and drawnlong wire of uniform cross section. If the length of the wire is 10 |
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| 7. |
29. A wire is broken into two places. If the wire is 3 m long and one peace is 1 m long , find the length ofother peace |
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Answer» Length of a wire =33/4one piece is =11/2and the other piece is= 33/4-11/2= 11/4m long |
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| 8. |
Std. VII: Mathematics Workbook2Carry out the following ad.5*13642iii.10 |
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| 9. |
5 Find the values of following |
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Answer» (5)(0) - (3)(-7) = 0 - (-21) = 21 |
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| 10. |
Find the values of each of the following: |
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| 11. |
L Find the decimal values of the following:2 |
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Answer» i.) = 0.5i.)= 0.25 0.51/4=0.25 |
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| 12. |
OLULI 20Es.ICBSE Sept.2012)33. a, b are the roots of the quadratic polynomial p(x) = x2 - (k-6)x + (2k + 1). Find the value ofk, if a + B = aß.[CBSE Sept. 2010, 2012] |
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Answer» Given:α , β are roots of x²-(k-6)x+2k+1 Also α + β=α βHere a=1;b=-(k-6);c=2k+1 sum of roots=α + β=-b/a=-(-(k-6))=k-6 product of roots =αβ=c/a=2k+1 now k-6=2k+12k-k=-6-1k=-7 Thus k=-7 |
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| 13. |
Revision(Questions based on the topics of std IX)Solve.) Write the following set in the list form.P = {x|x is an even natural number. 1 < x < 10} |
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Answer» P = { 2,4,6,8} ( set of even numbers} |
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| 14. |
There are 12 balls 2 red, 4 gold, 3 silver and 3 white. What is the probability of drawinga) a silver ball?(b) a ball which is not red? |
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Answer» a : 1/4 no of silver balls=3b: 5/6 no of balls which are not red = 10 probability is the no of the specific Colour ball/total number of ballshence a) probability=3/12=1/4b) probability=4+3+3/12=10/12=5/6 |
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| 15. |
97. दिये गये वृत्त में, ए का मान बराबर है? -850(A) 35°(B) 45°C) 5501 |
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| 16. |
(5)A purse contains 2 silver coins and 4 copper coins and another contains 4silver coins and 3 copper coins. If a coin is selected at random from one ofthe two purses, what is the probability that it is a silver coin? The coinselected is a silver coin, what is the probability that it was taken out fromthe first purse.(Ans. 19/42.7/19)(14 |
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Answer» A purse contains 2 silver coins and 4 copper coins. Thus, total number of coins = 2 + 4 = 6 coins Another purse contains 4 silver coins and 3 copper coins. Thus, total number of coins in the second purse = 4 + 3 = 7 coins Now, Total number of coins in the two purses = 6 + 7 = 13 coins Also, Number of silver coins = 4 + 2 = 6 coins Let E be the event of getting a silver coin. Thus,P(E) = n(E)/Total number of outcomes = 6/13 use "Bayes theorem" to the answer. |
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| 17. |
Find the mass of a solid cone of silver metal havingbase diameter 14 cm and vertical height 51 cmThe density of silver is 10 g/cm^3 |
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| 18. |
-26x+138-35 are 23, find other zeroes.olynomial athe polynomial616-25x+10 is divided by another polynomial -2k+a, find kand athe remainder comes out to be2.5 Summary |
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Answer» Fromx^2−2x+k=0,x^2=2x−k After replacingx^2into2x−kin polynomial and equating remainder intox+a, (x2)^2−6x(2x−k)+16(2x−k)−25x+10=x+a (2x−k)^2−12x^2+6kx+32x−16k−25x+10=x+a (2x−k)^2−12x^2+6kx+7x−16k+10=x+a 4x^2−4xk+k^2−12x^2+(6k+7)x−16k+10=x+a −8x^2−4xk+k^2+(6k+7)x−16k+10=x+a −8(2x−k)−4xk+k^2+(6k+7)x−16k+10=x+a −16x+8k+(2k+7)x+k^2−16k+10=x+a (2k−9)x+k^2−8k+10=x+a After equating coefficients, 2k−9=1anda=k^2−8k+10 Hencek=5anda=−5 |
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| 19. |
A Band C are interior angles of a triangle ABC, then sib(b+c/2)=cosa/2 |
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| 20. |
2. Verity that a tboeachohe following values ofa,band c. |
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| 21. |
Alends?2500 to Band a certain surn to CattheA altogether receives 1120 as interest trom Band C. the sum lent to(a) マ700same time at 7% annual simple interest. If after 4 yearC is(b) 1200o(d) e 2000(c) R 15009% p.a. for next fi |
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| 22. |
2. Find three rational numbers between:lançand (band(c) 3 and 4 |
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| 23. |
)7×10,000 + 2 × 1.000 + 8 × 100 + 3 × 10 + 8x1 |
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Answer» 7 × 10000 + 2 × 1000 + 8 × 100 + 3 × 10 + 8 × 1 = 70000 + 2000 + 800 + 30 + 8 = 72838 If you find it helpful then please like. |
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| 24. |
Divide? 7000 amongA. Band C such that A gets 50% of what B gets and B gets 50% of whatC gets.n. |
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| 25. |
convert each of the following into a decimal. (i) 47/10 (ii) 156/100 ( iii) 2516/100 ( iv) 25/8 |
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Answer» (i). 47/10 = 4.7(ii). 156/100 = 1.56(iii). 2516/100 = 25.16(iv). 25/8 = 3.125 ii) is the correct answer |
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2. A dealer comes from Mathura to Delhi to buy an article which costs 12% less in Delhi than in Mathura.His expenses are 240 and he makes a profit of R 300 on selling the article in Mathura. What did thearticle cost in Mathura? What is his profit percent?untwholesals price to the shopkeeper |
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| 27. |
Frvd Hhe WMl 1S L1S ELQ (बी 2 |
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| 28. |
36comes just before37 comes betweenandcomes just after 3597 comes betweenandcomes just before 67comes just after 83 |
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Answer» 3735 and 363696 and 986684 |
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Match each of the set on the left in the roster form with the same set on thedescribed in set-builder form:(a)(b)(â{ 1, 2, 36)(x:x is a prime number and a divisor of 6)(x:x is an odd natural number less than 10(m) (M.A,T,HEI.C,S (c) (x: x is natural number and divisor of 6] (x: x is natural number and divisor of 6)() (x xis a letter of the word MATHEMATI(iv) (1,3,5,7,9)3 The Empty Set |
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Answer» thank you |
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| 30. |
By selling a chair for Rs 30 a dealer makes a profit 25%. Find what price did the dealer pay for it |
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Answer» 1.25(CP)=30CP=30/1.25cp=24 SP is given 30 and profit is 25% so we can find CP by 75*30/100 sorry 1.25(CP) = 30 |
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| 31. |
79 |
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Answer» answer of this is question is 79 as. 79×79=6241🎂 79×79 is the answer for this question |
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| 32. |
Examine whether the following statements are true or false:(i) {a' b } ¢ { b, c, a }(ii) { a, e|cl-r : x isas vowel in the English alphabet)(ii) ( 1, 2, 31c(1,3,5(iv) {a|c {a, b, c }(v) tale ta, b, c2.r:r is an even natural number less than 6)(x:x is a natural numwhich divides 361 |
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| 33. |
Examine whether the following statements are true or falseIablclhcali False la.elc(a:xisa vowel in the English alphabet)T(iii) {1, 2, 3 }C/1.3.5) F(vi)f r :is an even natural number less than 6} c { x :x is a natural number |
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| 34. |
Match each of the set on the left in the roster form with the same set on the rightdescribed in set-builder form:0 [1,2,3,6)1) [2(a)(b){ M.AT.H.ELCS) (c)(1,3,5,7,9) (d)(x:x is a prime number and a divisor of 6)(x:xis an odd natural number less than 10){x : x is natural number and divisor of 6}(x :x is a letter of the word MATHEMATICS].(iii)(iv) |
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| 35. |
. The length of a rectangle is 2 less thantwice its breadth. If the perimeter of therectangle is less than 20, what could bethe maximum breadth of the rectangle?Consider the breadth of the rectangle tobe a natural number). |
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Answer» The maximum breadth could be 5 units |
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| 36. |
36MATHEMATICS2.Define a relation R on the set N of natural numbers by R-(x,y) : y "z+r is a natural number less than 4: x, yN). Depict this relationship using rogeform. Write down the domain and the rangeA(1, 2, 3, 5) and B (4, 6, 9). Define a relation R from A to B |
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| 37. |
Cards having numbers 2,4.6,8......100. One card is drawn at randonmfind the probability that number on card is:-(1) number divisible by 2 and 3(2) number is an even number(3) an even prime number |
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Answer» Total number of cards = 50. i) Cards divisible by 2 and 3 = 17. probability of number divisible by 2 and 3 = 17/50. ii) Number of even numbered cards = 50. probability of even numbered card = 1. iii) number of even prime numbers = 1. probability of even prime numbered card = 1/50. SMASH THE LIKE BUTTON! |
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| 38. |
The ratio Farhan's income to his saving is 4:1. Find the percentage of money |
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| 39. |
87878 — 7878 — 6666 — 777 — 33 =? |
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Answer» 87878-7878-6666-777-33=72524 |
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D3Observe the number line and answer the questions.A B E-32-2 -1 0 1(1) Which number is indicated by point B?(2) Which point indicates the number 1.?(3) State whether the statement, the point D denotes the numberis true or false |
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Answer» (1) -3+0.4(2) C(3) TRUE 1. -3+0.42. C3. true |
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| 41. |
7777+777 |
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Answer» the and is 8554 =7777 +777 7777+777 =8554therefore , the answer is 8554 |
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| 42. |
8AND STATISTICS-ELEMENTS OF BUSINESS MATHEMATICScar is boughtfră4,70,000 and sold for 4,46,500. Find his loss percentage in the |
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Answer» CP = 470000 SP = 446500 LOSS PERCENTAGE = (470000-446500)/470000 * 100 = 23500/470000 * 100 = 5% |
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| 43. |
thchild puts one five-rupee coin of her saving in the piggy bank onfirst day. She increases her saving by onc five-rupec coin dailyDigEy bank can hold 190 coins of five rupees in all, find the numberdays she can continue to put the five-rupce coins into it and find the tmoney she saved.Write your views on the habit of saving. |
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Answer» The child puts in her piggy bank on first day = Rs. 5 coin On second day she puts = 5 + 5 = Rs. 10 On third day she puts = 5 + 5 + 5 = Rs. 15 Her piggy bank can hold 190 5 rupee coin in all. So, this is the case of an Arithmetic Progression. 5, 10, 15, ......................190 a = 5, d = 5 and n = 190 S = n/2[2a + (n - 1)d] ⇒ 190/2[2*5 + (190 - 1)5 ⇒ 95[10 + 189*5] ⇒ 95[10 + 945] ⇒ 95*955 = Rs. 90725 Her total saving is Rs. 90725 |
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| 44. |
Mike has been saving his allovance, and then he got $25 for his birthday. Hethen went to the toy store and spent half his money, and now has $34 left.How much allowance money had he saved?$ |
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| 45. |
1. एक पिता और पुत्र की वर्तमान आयु का योगफल70 वर्ष है। 10 वर्ष बाद पुत्र की आयु अपने पिताकी आयु की ठीक आधी होगी। अब उनकी आयुकितनी है? (SSC 10+2 Level 2010) |
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Answer» Let age of father = xThen age of son = 70 - x After 10 yearsAge of son = (70 - x + 10)= (80 - x)Age of father = x + 10 As per given condition(80 - x) = (x + 10)/2160 - 2x = x + 103x = 150x = 150/3 = 50 Therefore,Age of son = 20 yearsAge of father = 50 years 50 years age of son 20 years |
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| 46. |
THEMATICS VOLI*EXERCISE -Fin 4530º =b2)- 3) 34)-D- |
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Answer» option (2) is the correct answer. |
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| 47. |
4.8ELEMENTS OF BUSINESS MATHEMATICSExample 8 How many three digit odd numbers can be formed from the digits1, 2, 3, 4, 5, 6 when(i) repetition of digits is not allowed(ii) repetition ofdigits is allowed |
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Answer» (i) if repetition is not allowedso at first position 6 possibility, at 2nd position remaining 5 possibility,at 3 rd place remaining 4 possibilityso total numbers=6×5×4=120(b) if repetition is allowedso at first position 6 possibility, at 2nd position again 6 possibility,at 3 rd place again 6 possibilityso total numbers=6×6×6=216 |
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| 48. |
(a) No war in the world(b) People are living with the feeling of brotherfraternity(c) Whole world is rich(d) People are silent and not making a noiseaiutch 9x2 +12xy + 4y2 Post 359 ht Quich g(a) a² + b2 + 2ab(b) a? – 2ab.2 12ca2 12. |
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| 49. |
2V2662ind the original price of a washing machclusive of 8% GST.actorise : y2y - 15thematics |
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| 50. |
BURIM BORIS JOHNTHEMATICSEXERCISE 6.1In A POR, D is the mid-point of QR.PM isPD iso Mbs QM = MR?Draw rough sketches for the following:a) In AABC, BEis a median.b) In APOR PA |
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Answer» visawash is your local |
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