(5)A purse contains 2 silver coins and 4 copper coins and another cont

1.	(5)A purse contains 2 silver coins and 4 copper coins and another contains 4silver coins and 3 copper coins. If a coin is selected at random from one ofthe two purses, what is the probability that it is a silver coin? The coinselected is a silver coin, what is the probability that it was taken out fromthe first purse.(Ans. 19/42.7/19)(14
Answer» A purse contains 2 silver coins and 4 copper coins. Thus, total number of coins = 2 + 4 = 6 coins Another purse contains 4 silver coins and 3 copper coins. Thus, total number of coins in the second purse = 4 + 3 = 7 coins Now, Total number of coins in the two purses = 6 + 7 = 13 coins Also, Number of silver coins = 4 + 2 = 6 coins Let E be the event of getting a silver coin. Thus,P(E) = n(E)/Total number of outcomes = 6/13 use "Bayes theorem" to the answer.

(5)A purse contains 2 silver coins and 4 copper coins and another contains 4silver coins and 3 copper coins. If a coin is selected at random from one ofthe two purses, what is the probability that it is a silver coin? The coinselected is a silver coin, what is the probability that it was taken out fromthe first purse.(Ans. 19/42.7/19)(14

Answer»

A purse contains 2 silver coins and 4 copper coins.

Thus, total number of coins = 2 + 4 = 6 coins

Another purse contains 4 silver coins and 3 copper coins.

Thus, total number of coins in the second purse = 4 + 3 = 7 coins

Now,

Total number of coins in the two purses = 6 + 7 = 13 coins

Also, Number of silver coins = 4 + 2 = 6 coins

Let E be the event of getting a silver coin.

Thus,P(E) = n(E)/Total number of outcomes

= 6/13

use "Bayes theorem" to the answer.