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From this information we have to find the volume

Outer radius (R) = 12 cm

Inner radius (r)= 10 cm

Volume of hollow sphere =(4/3)Π (R³ - r³)

=(4/3)(22/7)(12³ - 10³)

=(88/21)(1728- 1000)

=(88/21)(728)

=(64064/21)

=3050.67cm³

Diameter of cone=14 cmso, Radius of cone= 7cm Height of cone= 8cm

∴ Volume of cone= 1/3*pi*r^2*h =1/3*pi*49*8 cm^3

In Sphere, External Radius R=5cm Let, Internal Radius = r

Volume of Sphere = External Volume- Internal Volume = 4/3*pi*R^3-4/3*pi*r^3 =4/3*pi[R^3-r^3] =4/3*pi[5^3-r^3]

But During Conversion Volume Remains Same

So, Volume of Sphere=Volume of Cone 4/3*pi[125-r^3]= 1/3*pi*49*8 4[125-r^3]=49*8 [125-r^3]=49*2 r^3=125-98 r^3=27 so, r =3 cm

Internal Radius= 3cm So, Internal Diameter=3*2= 6cm

From this information we have to find the volume

Outer radius (R) = 12 cm

Inner radius (r)= 10 cm

Volume of hollow sphere =(4/3)Π (R³ - r³)

=(4/3)(22/7)(12³ - 10³)

=(88/21)(1728- 1000)

=(88/21)(728)

=(64064/21)

=3050.67cm³

Total no of outcomes=6

No of possible outcome=1,2,3,6

So, No of outcomes = 4

Probability of not getting 4 or 5

= 4/6

= 2/3

66666

C.P. = 370 and profit = 20

Total number of discs can be prepared = Area of the sheet/Area of one circular discArea of the sheet = L*BArea of one circular disc = πr²Area of the sheet = 11*2 = 22 sq cmArea of one circular disc = 22/7*0.25*0.25⇒ (22)/(22/7*0.0625)⇒ 112 discsSo, total 112 discs can be prepared.Answer.

Area of the plate=(54×43)cm²=2322 cm²=0.2322 m²

Cost of the plate=Rs.75 per m²×0.2322 m²=Rs.17.415

X/a=sintheta + costheta

y/b=sin(theta)-cos(theta)

(x/a)²+(y/b)²=(sintheta +costheta)² + ( sintheta- costheta)²

= sin²theta + cos²theta +2sintheta*costheta +sin²theta + cos²theta = -2sintheta*costheta

= 2(sin²theta + cos²theta)

=2*1=2

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Hence, option A is correct

A=PI(r2-r1)^2 =22/7 (14-7)^2 =22/7×7^2 r=d/2 = 28/2=14cm r=d/2 = 14/2=7cm =22/7×49 =22×7 =154cm^2 Ans)The difference between the areas of two circles is 154cm^2.

Possible number of outcomes=90(i) Number of two digit numbers=81Probability=81/90=9/10(ii)Number of perfect squares=9Probability=9/90=1/10(iii) Number of numbers divisible by 5=18Probability=18/90=1/5

A charged Capacitor is a store of electrical potential energy.

To find the energy stored in a capacitor, let us consider a capacitor of capacitance C, with a potential difference V between the plates.

Potential of capacitor =q/C

Work done in giving additional charge dq to capacitor is

dW=q/C *dq

total work done in giving a charge Q to the capacitor is q.

Q=Q

W=1/C Q2/2

Energy stored in the capacitor

U=W=1/2 Q2/C

WE know that Q=CV

U=1/2 (CV)2/C =1/2 CV2

Now CV=Q

U=1/2 QV

Thus, U=1/2 Q2/C =1/2 CV2=1/2 QV

Where Q=Coloumb,V=Volt Energy U is in joule

one angle is 2 (pi)/9=2×180/9=40°let common ratio for other two angles be xthen4x+3x+40=1807×=140x=20other angles will be4×20=80° and 3×20=60°

good explanation😚

thnks bro

Here is an axiom of addition and multiplication.Let x and y be real numbers.Then x + y is also a real number and xy is also a real number

example of axioms in maths:

Two parallel lines never bisect each other

A line segment is obtained by joining two points

Circle has zero eccentricity

Probability cannot be greater than 1 or 100%

Real number + real number = real number

Let the initial expenditure on the commodity be Rs. 100.Now, the price decreases by 20%,Current Price = (100 - 20% of 100) = Rs. 80.Same time due to decrement in price 20% consumption has been increased. So,Current expenses on commodity = (80 + 20% of 80)= Rs. 96.Here, the initial expenditure was Rs. 100 which became 96 at the end, it means there is 4% decrement in the expenditure of the commodity.

LHS =cosA/(1+sinA) +(1+sinA)/cosA

={cos²A +(1+sinA)²}/cosA.(1+sinA)

={cos²A+1+sin²A+2sinA}/cosA.(1+sinA)

use sin²∅ +cos²∅ =1

=(1+1+2sinA)/cosA(1+sinA)

=2(1+sinA)/cosA(1+sinA)

=2/cosA

=2secA = RHS

banajksjklalalavllbhol

option B is the correct answer

As price increase and consumption are inversely proportional,

if one increases by 1/x then other should reduce by 1/(x+1)

hence 20% is 1/5, consumption should reduce by 1/6 = 16.66%

Distance covered in 90 min=12 kmDistance covered in 1 min=12/90 kmDistance covered in 180 min=(12/90)*180 km=24 km

Thanks

Tally marks, also called hashmarks, are a unary numeral system. They are a form of numeralusedfor counting. They are most useful in counting ortallyingongoing results, such as the score in a game or sport, as no intermediate results need to be erased or discarded.

Used to find frequency distribution

angle AD is equal to angle bc due to parallel linesangle AC is equals to angle BD because adjacent pair

In ∆ ADC and ∆BCD , draw a perpendicular from A and D , so height will be equal.. because AB||CD so, diagonals AC = BC ,

now again in ∆ADC and ∆BCDDC is common , angle C = D, so diagonals are equal .so, ∆ADC ≈ ∆BCD ... ( SSA) there fore AD = BC