AnsQ 2) Deduce the expression for energy stored in a parallel plate ca

1.	AnsQ 2) Deduce the expression for energy stored in a parallel plate capacitorAns
Answer» A charged Capacitor is a store of electrical potential energy. To find the energy stored in a capacitor, let us consider a capacitor of capacitance C, with a potential difference V between the plates. Potential of capacitor =q/C Work done in giving additional charge dq to capacitor is dW=q/C *dq total work done in giving a charge Q to the capacitor is q. Q=Q W=1/C Q2/2 Energy stored in the capacitor U=W=1/2 Q2/C WE know that Q=CV U=1/2 (CV)2/C =1/2 CV2 Now CV=Q U=1/2 QV Thus, U=1/2 Q2/C =1/2 CV2=1/2 QV Where Q=Coloumb,V=Volt Energy U is in joule

AnsQ 2) Deduce the expression for energy stored in a parallel plate capacitorAns

Answer»

A charged Capacitor is a store of electrical potential energy.

To find the energy stored in a capacitor, let us consider a capacitor of capacitance C, with a potential difference V between the plates.

Potential of capacitor =q/C

Work done in giving additional charge dq to capacitor is

dW=q/C *dq

total work done in giving a charge Q to the capacitor is q.

Q=Q

W=1/C Q2/2

Energy stored in the capacitor

U=W=1/2 Q2/C

WE know that Q=CV

U=1/2 (CV)2/C =1/2 CV2

Now CV=Q

U=1/2 QV

Thus, U=1/2 Q2/C =1/2 CV2=1/2 QV

Where Q=Coloumb,V=Volt Energy U is in joule