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We can write it 52.5= 525/10= 52.5Please like the solution 👍 ✔️

distance cover by foot = total distance - distance by scooter - distance by bicycle = 47 - 29 - 8 = 10 km

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A kaya question hai Apna break up hooa hai kaya

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147 is the correct answer of the given question.

525* 28/100= 147thanks

525 .28/100=147 is the right answer.

hope this will help you like my answer and MARK IT AS BEST ANSWER.

28/100 *525=147 is the right answer

525/100 = 5.255.25 x 28 = 147

525का28% 525×28/100=147

147 aayega mere hisaab se

147 is the right answer

55/105= 11/21 is the correct answer of the given question

55/105 = 11/21 I do here reduse

Your correct answer is 11/21

Your correct answer is 11/21

11/21 is the correct answer

the correct answer is 11/21

11/21 is the right answer

11/21 is the correct answer of thish question I think

3/(5-√3)+2/(5+√3)

=3(5+√3)+2(5-√3)/5²-(√3)²

=8+3√3+10-2√3/25-3

=18+√3/22

let ratio be x/ythen y-x=40and x/y=2/7x=2y/7y-2y/7 =405y/7=40y=40×7/5y=56x=y-40x=56-40x=16so the ratio is 16/56

The heart has four chambers: two atria and two ventricles. The right atrium receives oxygen-poor blood from the body and pumps it to the right ventricle. The right ventricle pumps the oxygen-poor blood to the lungs. The left atrium receives oxygen-rich blood from the lungs and pumps it to the left ventricle.

Advantages of SHGs:

SHGsarethe building blocks of organisation ofthe rural poor. Not only do they help women become financially self-reliant, theregular meetings ofthegroup providea platform to discuss and act on a variety of social issues such as health, nutrition, domestic violence, etc

In general, we say that the density of water is1000 kg/m^3(or1 g/cm^3). But you're right that it does vary a little bit with temperature. It is exactly1000 kg/m^3at 4 degrees Celsius. At 20 degrees Celsius it is998.23 kg/m^3 ( or 0.99823 g/cm^3

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Please give me answers in detail and step by step please

give me answers please

2² -(√3)²4-3=1

correct answer for this question

2²-(√3)²4-31is the best answer

4-31hence 1 is the right answer.

answer is 1 correct answer

1 is the correct answer of this question

Range or width= upper- lower thanksplease like the solution 👍 ✔️

thanks yar

eliminating the log to the R.H.S

=> 2^(x+2) -4^x ≤ (1/3)^-2 => 4.2^x -(2^x)² ≤ 9=> (2^x)² -4.2^x +9 ≥0

let 2^x = t

=> t²-4t+9 ≥ 0 ∆ = 4²-36 = -ve...so this equation is always +ve..

so x ==> R

Since curved surface area of cyliner is 2π(y^2-7y+12)

Then 2π*y-3*h=2π(y²-7y+12) then cancel 2π on both sides and then h(y-3)=y²-7y+12 then y²-3y-4y+12 which will give (y-3)and (y-4)

then h(y-3)=(y-4)(y-3) then cancel (y-3) and hence the answer will be h=y-4

nCr = nC(n-r)

=> r = 8 and n-r =2 => n = r+2= 8+2 = 10

so, nC2 = 10C2 = 45

pls solve my difficulty...

My Answer Is 1/2 Is Right Answer

answer Shi hai to bolna

The right answer is 1/2.

1/2 is the right answer

We knowthatarea = base x height

Area/ base = height = 108/12= 9cm

108 =b*h108 = 12*hH=108/12 H=9So the height is 9

pls post full answer

Let the number of Boys = Xnumber of Girls = 3X/5

X + 3X/5 = 508X/5 = 50X = 250/8 = 125/4

number of Boys = 125/4number of Girls = 125/4 X 3/5 = 75/4

ratio of Boys to girls = (125/4)/(75/4) = 5:3 (ANS)

5:3 is the ratio of boys to the girls

(3/5) of a class are girls. (2/5) of the class are boys. So, number of boys = (2/5)*45= 2*9 = 18

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total 5 part of class 3 part of girl & 2part of boys , girls are 45,. 45/5=9,& 2*9=18 boyes

use formulax^m/x^n=x^(m-n)for each term then simplyby taking L.c.m

x² - 4x + 3

quotient of X² = 1so 3×1 = 3.

factors of 3 = 1 and 3sum of factors after addition or subtraction should be equal to the quotient of the middle term i.e. 43×1 = 43+1= 4

x²- 4x +3x² -3x - X + 3. X (X - 3 ) - 1 ( X - 3 )( X - 1 ) ( X - 3 )X - 1 = 0 X - 3 = 0

X = 0+1. X = 0+3

X = 1.... X = 3......

x^2-4x+3=x^2-3x-x+3=x(x-3)-1(x-3); (x+3)(x-1); x=-3 & 1

Circumference = 2 × pi × r2 × (22/7) × r = 132 r = (132 × 7)/(2 × 22) = 21 cmVolume of cylinder = (1/3) pi r²h = (1/3) × (22/7) × 21 × 21 × 25 = 11550 cm³

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a^3-b^3=(a-b)(a^2+ab+b^2)hencex^3-8=(x-2)(x^2+2x+4)hencelim x-2/(x-2)(x^2+2x+4)lim 1/x^2+2x+41/4+4+4=1/12

4y-2x=-12...... (1)2y-x=2......(2)dividing eq.1 by 22y-x=-6since discriminant of coeff.=2×(-1)-2×(-1)=0so the given set of eq.s has no sol.

let total number of students be xso we have Equation3x/4 + 50 = x50 = x -3x/450 = x/4x = 200so total Numbers of students are 200

Let X be the number4x + 5x =9x9x = 135x = 135/9x = 15So, no.s are 4x= 4×15 = 605x = 5×15 = 75

Let the common ratio be x4x + 5x = 1359x = 135x = 135÷9x =15

4x = 15×4 =605x = 15×5 =75

Let the two numbers be '4x' and '5x'Now 4x+5x=135 9x=135 x=15Again 4x 4×15=60 5x 5×15=75

Let the two numbers be a and b,

AM = a+b/2 and GM = √(ab)

So ….(a+b/2)/√(ab) = m/n,

Applying componendo and dividendo i.e if p/q = l/m then p+q/p-q = l+m/l-m,

=> (a+b+2√(ab))/(a+b-2√(ab)) = m+n/m-n

=> (√(a)+√(b))^2/(√(a)-√(b))^2 = m+n/m-n

=> √(a)+√(b)/√(a)-√(b) = √(m+n)/√(m-n)

Applying componendo and dividendo,

=> 2√(a)/2√(b) = √(m+n)+√(m-n)/√(m+n)-√(m-n)

Squaring both sides,

a/b = (m+n+m-n+2√(m^2-n^2))/(m+n+m-n-2√(m^2-n^2))

=> a/b = m+√(m^2-n^2)/m-√(m^2-n^2)

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Given Cost price of article = Rs. 3450AndShopkeepermarks the price of the article 16% above the cost price.​So,1 ) Marked price of the article = 3450 + 16% of 3450 = 3450 +16×3450100=3450+16×34.50=3450+552=Rs.4002(Ans)AndSales tax on the article = 10%

2 ) Price paid by customer = 4002 + 10% of 4002 = 4002 +10×4002100= 4002 + 400.20 =Rs. 4402.20 ( Ans )

2 is the correct answer

[10/3 × 9/3]²

= [10]² = 100