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Answer»

Since curved surface area of cyliner is 2π(y^2-7y+12)

Then 2π*y-3*h=2π(y²-7y+12) then cancel 2π on both sides and then h(y-3)=y²-7y+12 then y²-3y-4y+12 which will give (y-3)and (y-4)

then h(y-3)=(y-4)(y-3) then cancel (y-3) and hence the answer will be h=y-4



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