Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
2x(4x-3y) |
|
Answer» 2x(4x -3y)= 2x × 4x - 2x × 3y= 8x² - 6xy |
|
| 2. |
09n the given figuse DE IIACc and DfIIAE.Poove that BE--BE.FEEC3 |
| Answer» | |
| 3. |
72 ^ { \circ } \operatorname { cos } 108 ^ { \circ } \operatorname { cos } 144 ^ { \circ } = \frac { 1 } { 16 } |
| Answer» | |
| 4. |
find out the value of M and N in 73M divided 8=9N |
| Answer» | |
| 5. |
Find out the value of M and N in 73 M 8-9N |
|
Answer» thanks but shot ho gya thoda long |
|
| 6. |
\operatorname { rix } \left[ \begin{array} { c c c } { 1 } & { 3 } & { - 2 } \\ { - 3 } & { 0 } & { - 1 } \\ { 2 } & { 1 } & { 0 } \end{array} \right] |
|
Answer» mode of matrix=1(1)-3(2)-2(-3)=1-6+6=1adj matrix=1 -2 -3 -2 4 5 -3 7 9inverse of matrix=adj matrix/mode of matrix =1 -2 -3 -2 4 5 -3 7 9 please answer rest of the questions |
|
| 7. |
A = \left[ \begin{array} { c c } { - 5 } & { - 3 } \\ { 2 } & { 0 } \end{array} \right] \text { and } I = \left[ \begin{array} { c c } { 1 } & { 0 } \\ { 0 } & { 1 } \end{array} \right] \text { prove that } A ^ { 3 } = 19 A + 30 I |
| Answer» | |
| 8. |
(b) The sum of n terms of two A.P.'s are in the ratio 5n + 4: 9n +the ratio of the 11th terms |
|
Answer» We have two APs. AP1: The sum of the first 11 terms = 5n+4 or 5*11+4 = 59. The sum of the first 10 terms = 5n+4 or 5*10+4 = 54 The 11th term is 59–54 = 5. AP2: The sum of the first 11 terms = 9n+6 or 9*11+6 = 105 The sum of the first 10 terms = 9n+6 or 9*10+6 = 96 The 11th term is 105–96 = 9 SO the ratio of the 11th term of AP1 and AP2 = 5:9 |
|
| 9. |
१०32°/5 4. ०१19प्रबन्ध सम्पादक : आलोक कुप्रकाशक : आलोक कुमार, समुद्रक : आलोक कुमार, साधनKHd9N/sadhanhindimonthlygmail.comfacebook.com/sadhanf |
|
Answer» the answer is........15 |
|
| 10. |
54. The sum of n terms of two A.P's, are inthe ratio (5n 4): (9n 6). Find theratio of their eighteenth term |
| Answer» | |
| 11. |
108*(a*b^2) - 144*a^2*b %2B 64*a^3 - 27*b^3 |
|
Answer» correct answer is (4a--3b)³ |
|
| 12. |
64*y^3 %2B 144*(x*y^2) %2B 27*x^3 %2B 108*(x^2*y) |
| Answer» | |
| 13. |
3. Measure of each interior angle of a regular polygon can never b105 (3) 108 (4) 144 |
| Answer» | |
| 14. |
4860Find the HCF of the following by prime factorisation method:a. 144 and 180 b. 120 and 204 c. 72 and 108 |
| Answer» | |
| 15. |
A suitcase with measures 80cm Ă 48cm x 24cm is to be covered with a tarpaulin cloth. The length of thtarpaulin of width 96cm is required to cover 100 such suitcase isa) 136 cmb) 108 cmc) 124 cmd) 144 cm |
|
Answer» The suitcasel = 80 cmb = 48 cm h = 24 cmtherefore,Total Surface Area = 2(lb + bh + lh)= 2 [(80*48) + (48*24) + (80 * 24)]= 2 (3840 + 1152 + 1920)= 2 * 6912= 13824 cm^2 Length of cloth required = (area of suitcase/ breadth) * 100= (13824/ 96) * 100= 144 * 100= 14400 cm= 14400 /100 m= 144 |
|
| 16. |
What would be subtracted from x-2x + 4x + 1 to get 1?(a) x² – 2x² + 4x(6) x 2x2 + 4x + 1(x-2x2 + 4x - 1 (d) x + 2x2 + 4x + 1 |
|
Answer» option (a) is the correct answer for this following question a option is correct of answer option a is correct answer option a is a correct answer |
|
| 17. |
7/4x+3y+4/4x--3y=5/4, 8/4x-3y-14/4x+3y=3/2, x=?, y=? |
| Answer» | |
| 18. |
Use the identity (x+a) (x+b)+(a+ b)r+ ab to findthe following products(m) (4x + 5) (4x + 1)(v) (4x +5) (4x-I)(vi) (2a + 9) (2a+ 5)(im) (4x -5) (4x - 1)(2x + 5y) (2x +3y)(xyz-4) (pz-2)(v)(vii)VII |
| Answer» | |
| 19. |
,2Use the identity (x + a) (x + b) =x2 + (a + b) x + ab to find the following products.(iii)(v)(4x 5) (4x-1)(2x + 5y) (2x +3y)(i) (4x 5) (4x + 1)(iv) (4x + 5) (4x-1)(vi) (2a2 +9) (2a25)(vi) (xyz-4) (axyz- 2) |
| Answer» | |
| 20. |
4x+4x=? |
|
Answer» 4x+4x=8x |
|
| 21. |
it 4x-4x-1-24 then find 4x-1 |
| Answer» | |
| 22. |
3. The missing digit in the following number is:(a) O (b) 8 7 0 0 04291. 4 2 3(c) 1 (d) 7 0 +26 42.8 3 5 4 |
|
Answer» 8 is the answer of the following option b is the following question answer. correct answer is 8 . option b is the correct answer option (b)8 is the correct answer the answer could be option b correct answer is 8 . (b) 8. so cute question.... 8 is right ans than missing digit no in box option (b) 8 is the right answer. option b is correct answer option (b)8 is the missing digit |
|
| 23. |
3.69 X : 2x + 4 = x-3(A) 7 (B)-70 (0) 0 (A)(C)-10 (0)(D) 10 (B) |
|
Answer» Answer:B)-7Explanation:2x+4=x-32x-x=-3-4x=-7 2x+4=x-3take X on left side and 4 on right side X=-7 |
|
| 24. |
(5^0+6^0+7^0+8^0)1/2 |
|
Answer» (1+1+1+1)1/2=4 1/2=2 |
|
| 25. |
(2) 40(4) 353) 28If the coefficients of 2nd, 3rd and 4th terms in theexpansion of (1 + x)2n are in A.P, then(1) 2n2 - 9n 7 0(2) 2n2 + 5n + 7 0(3) n2 - 9n + 7 0(4) n2+ 9n-7 0 |
|
Answer» Hence proved |
|
| 26. |
1)5x2 + 16x + 7 = 0 2) 5x2-16x + 7 = 0The eequation x2 + ax-b = 0 is1) x2-bx + a = 03) 2ax" + (a,-8b)x-4ab = 05,n whose roots are the A.M and twice the H.M.between the roots of the4) 2ax2-86x-4ab = 0andisre |
|
Answer» Let A and B are the roots of given equation .A + B = -(a)/1 = -a AB = -c/1 = -bnow , AM = ( A + B)/2 = (-a)/2 and HM = 2AB/(A + B)= 2(-b)/(-a) = 2b/a now, a/c to question , AM and 2HM are the roots of unknown equation .so, x² -(AM +2HM)x +2(AM).(HM) =0x²-(-a -2b)x +2(-a)(-b) =0x² +(a +2b)x +2ab =0 |
|
| 27. |
ख) --अक्ष पर एक बिन्दु, जो बिन्दुओं A ( 2, -5)और B (-2, 9) से समदूरस्थ है, का निर्देशांकहोगाi) (-7, 0)iii) (0, -7)ii) (0, 7)iv) (7,0) |
|
Answer» option 1 is the correct answer option 1 is correct answer. 1 is the correct answer 1 is the right answer |
|
| 28. |
(-1 %2B 6^0)*(6^0 %2B 7^0) |
|
Answer» 0 is the correct answer of the given question 0 is right answer of this question. please like my answer correct answer is 0 0 is the correct answer following 0 is the answer of this sum 0 is the answer . because if the power of any number is 0 then the number become one formula = a^0= 1(6^0 + 7^0)×(6^0-7^0)=(1+1)×(1-1)=2×0=0 is the answer 0 is the bestest answer (1+1)*(1+1)=4this is a correct answer |
|
| 29. |
Rakhi's mother is four times as old as Rakhi. After 5 YEARS ,her mother will be three times as she will be then . Find their present ages |
| Answer» | |
| 30. |
IF 4x - 4x-1= 24, then find the value of x. |
|
Answer» 5/2 is the correct answer |
|
| 31. |
24.cos 4x1-8sin2 x cos2 x |
|
Answer» cos4x as cos2(2x) =1-2sin²(2x) =1-2(2sinx . cosx)² { sin2x = 2sinx. cosx} =1-2(4sin²x.cos²x) =1-8sin²x.cos²x LHS=RHS |
|
| 32. |
निम्नलिखित बहुपदों में से प्रत्येक बहुपद के लिए P(2), P(1) और P(0) का मान ज्ञात ।कीजिए।(com(i) p(x) ='-r+1 (i) p(v) = (+1)(-1)(i) p(x) =(iv) p(t) =2+1+1=3 |
| Answer» | |
| 33. |
Removing brackets, 5x-15-42 + 7xcollecting terms12x -573x-324-24subtracting 3x from each side, we get 9x 57Adding 57 to each side, we have 9x54Dividing by 9, we get x = 6(ii)Solve 5x-(4x-7) (3x-5) = 6-3 (4x-9) (x-1)Solution:If the t |
|
Answer» 5x-(4x-7)(3x-5) = 6-3(4x-9)(x-1) => 5x-[12x²-20x-21x+35] = 6- 3[4x²-13x+9]=> 5x-12x²+41x-35 = 6-12x²+39x-27=> 46x-35 = 39x-21=> 7x = 14=> x = 14/7 = 2 |
|
| 34. |
ghey thre6 yoars agors. The ages of Leena and Hoena are in the ratio 7 : 5. Ten years hence, the ratio of theirages will bo 9:7. Find their present ages. |
| Answer» | |
| 35. |
(b)Using the duality theory solve the following:Maximize Z = 3x2 + 4x,Subject to the constraintsX; - x, 51x + 2g 24x - 3x2 53d. dg 20 |
| Answer» | |
| 36. |
ZIf 4* - 4x-1= 24, then find the value of x. |
|
Answer» Like if you find it useful |
|
| 37. |
3. Show that (p-1) is a factor of both the polynomials p-1 and p-1 |
|
Answer» Thanks |
|
| 38. |
2. Find p(0), p(1) and p(2) for each of the following polynomials:0 p() = y2-y +1 (i) p(t) = 2 +t+2-(ii) p(x) = x(iv) p(x)=(x - 1)(x + 1) |
|
Answer» p(0)= -1 is correct answering |
|
| 39. |
If p(x) = x3-x2 + x + 1, then find the value of P(1) + p(-1)7.2 |
|
Answer» Given p(x) = x³-x²+x+1 so, p(1) = (1)³-(1)²+1+1 = 2. and p(-1) = -1-1+1+1 = 0 therefore , p(1)+p(-1) = 2+0 = 2. and {p(1)+p(-1)}/2 = 2/2 = 1. |
|
| 40. |
if p(x)=x3-x2+x+1 then find the value of p(1)+p(-1) |
| Answer» | |
| 41. |
(1/2)^(-5*p)/(1/2)^(3*p)=(1/2)^24 |
|
Answer» As base are same using laws of indiceshence(1/2)^-5p-3p(1/2)^-8phencecomparing the powers-8p=24p=-3 |
|
| 42. |
EXERCISE 7.6Solve(c)) + 7(d)ラ+(f)5+3(g)a-32 3416 75-5(n) |
| Answer» | |
| 43. |
Ans:Section CFor questions 34 to 41, each answer carries I point.Write your answer in the space provided.Show your work.34. The product of two numbers is 5888.The smaller number is 16a. What is the greater number?b. What is the difference between the two numbers? |
| Answer» | |
| 44. |
this way also!steps in your mind.directly in the boxes.= 33 + 2755 + 25= 34 +6367 + 25= 53 +6472 + 5 |
| Answer» | |
| 45. |
MATH ACTE60Exercise 58Fill in the blanks.1. Re 0.60 = ......... paise. |
|
Answer» the answer of this question is 60 paise |
|
| 46. |
nerns f the height.Meena. Beena and Leena are climbing thesteps to the hill top. Meena is at step s. Beenais 8 steps ahead and Leena 7 steps behind.Where are Beena and Meena? The total ngmberof steps to the hill top is 10 less than 4timeswhat Meena has reached. Express the totalnumber of steps usings |
|
Answer» please like my answer if you find it useful |
|
| 47. |
k > 5 \frac { 3 } { 4 } \div 3 \frac { 5 } { 6 } |
| Answer» | |
| 48. |
Find two rational numbers between 1/4 and 1/2. |
|
Answer» rational numbers between 1/4 and 1/2=1/3,2/5 |
|
| 49. |
Find two rational numbers between 1 and 2.1 |
|
Answer» Two rational numbers✓ 1+2/2= 3/2and 1.5+2/2= 3.5/2= 1.75 |
|
| 50. |
Find two rational numbers between 1 and 2. |
|
Answer» Two rational numbers✓ 1+2/2= 3/2and 1.5+2/2= 3.5/2= 1.75 first take 1/1and then2/1*by 3/3to both and get answer by writing between answer The two rational number between 1 and 2 are 1.2 and 1.5 Two rational numbers 1+2/2=3/2and 1.5+2/2=3.5/2= 1.75 1. 3. 3_ × _. =. _ 2. 3. 6 2 3. 6_. × _ =. _ 2. 3 6 Anser: 4. 5 _. ;. _ 6. 6 👍 👍 👍 👍 👍 👍 👍 |
|