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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
* Billo has kept his chickens in a box. He counted 28 legs. Howmany chickens are there? |
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| 2. |
ind the curved surface area and total surface area of a right circular cylinder whose heights 15cm and the radius of the base is 7cm. |
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| 3. |
27. Find the (i) curved surface area (ii) total surfacearea (iii) volume of a right circular cylinderwhose height is 15cm & the radius of the base is 7cm. |
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| 4. |
2 12 ok 15 2 €9 (1)! - - =ok Qih‘ (!)L= < hg’u, 2 = <1211 el 15 (ool spivie] हि धर] दि पुर |
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Answer» i) 83 aur 74 , anko ka yog 11 hai. ii) 63 se badi sankhya 64, 65..... hai |
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| 5. |
n the iUnIL*)2.2 Factor1) |
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| 6. |
hat ill be the cnit dayit oP the Sok-the fol lo Îź ing hurtbeng ? |
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Answer» The number 81 contains its unit’s place digit 1. So, square of 1 is 1. Hence, unit’s digit of square of 81 is 1. solution Karka dekana ha |
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| 7. |
find the curved surface area and total surface area of a right circular cylinder whose height is 15 cm and the radius of the base is a 7 cm |
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| 8. |
The sum of the first five multiples of 6 is |
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| 9. |
27. Find the (i) curved surface area (ii) total surface area (ii) volume of a right circularcylinderwhose height is 15cm & the radius of the base is 7cm.&its heigbt is 10cm Rind the area |
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| 10. |
\overline { A } = 2 \hat { i } + 3 \hat { j } - 2 \hat { k } , \vec { B } = \hat { i } + 3 \hat { j } + \hat { k } \text { and } \vec { A } = \hat { i } + \hat { j } - 2 \hat { k } |
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Answer» A-2B=(2-2)i+(3-2)j+(-2-2)k=0i+j-4kC(A-2B)=1(1)-2(-4)=1+8=9 |
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| 11. |
14. Give five examples of numbers, each one of which is divisible by 3 but not divisible by 9.15. Give five examples of numbers, each one of which is divisible by 4 but not divisible by 8. |
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Answer» 14)6,12,15,21,2415)12,20,28,36,44 14) 6,12,15,21,2415) 12,20,28,36,44 (1.) 6,12,15,21,24(2.) 12,20,28,36,44 (14)= 6,12,15,21,24(15)= 12,20,28,36,44 is correct answer of the following (1) 6,12,15,21,24(2) 12,20,28,36,44Is the right answer. divisible by 3 - 6,12,15,21,24divisible by 4-12,20,28,36,44 14=6,12,15,21,2415=12,20_28,36,44 14) 6,12,15,21,2415) 12,20,28,36,44 |
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| 12. |
EXERCISE 2A. Define: (i) factor (i) multiple. Give five examples of each. |
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| 13. |
Give five examples of data that you can collect from your day-to-da ife. |
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Answer» thanks so much for your help |
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| 14. |
EXERCISE 14.1Give five examplesClassify the data inexamples of data that you can collect from your day-to-day life.v the data in Q.1 above as primary or secondary data. |
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Answer» me gujarati midiam me padtha ●number of person in the house●number of taps in the school●telephone bill of last 4 years●rise or fall in the temperature of Different cities from television●number of different subject teacher in the school |
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| 15. |
1. Classify the following numbers as positive numbers and negative numbers. |
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Answer» Numbers less than 0 are negative numbersand rest are positive |
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| 16. |
Give five examples where the number of things counted would be more6-digit number.1. |
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| 17. |
8. Find three different irrational numbers between the rational numbers9. Classify the following numbers as rational oriand |
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| 18. |
(iii) 59628(vi) 367314EXERCISE 2B1. Test the divisibility of the following numbers by 2:(i) 2650(ii) 69435(iv) 789403(v) 3579862. Test the divisibility of the following numbers by 3:(i) 733(ii) 10038(iv) 524781(v) 79124Toat the dininihilitur of the following numbers by 4:(iii) 20701(vi) 872645A |
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| 19. |
1 is not a prime number.5.51.11.13.17.161 factor1. Test the divisibility of the following numbers by 2:EXERCISE 2B(1) 2650(11) 69435(iv) 789403(v) 3579862. Test the divisibility of the following numbers by 3:(1) 733(ii) 10038(iv) 524781(v) 79124Test the divisibility of the following numbers by 4.(v1) 367314(1) 20701(vi) 872845 |
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| 20. |
Find the arithmetic mean of the following n numbers:1,3,5, ... (2n-1)() Find the G.M. of the following numbers : 1, , , , , |
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| 21. |
EXERCISE 3.1(e) 144(d) 641. Write all the factors of the following numbers:(c) 51(b) 36feet five multiples of following numbers:(d) 15(a) 20 |
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Answer» A)20=2*2*5B)36=3*3*2*2C)51=17*3D)64=2*2*2*2*2*2E)144=2*2*3*2*2*3 20= 2*2*536=3*3*2*251=17*364=2*2*2*2*2*2144=2*2*3*2*2*3 a=2into2into5b=3into3into2into2c=17into3 a=2,5,10b=2,8,18,9,36 |
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| 22. |
each of the following numbers as the sum of two prime numbers : 18 24 20 |
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| 23. |
Test the divisibility of the following numbers by 2:(1) 2650(ii) 69435(iv) 789403(v) 357986Test the divisibility of the following numbers by 3:() 59628(vi) 367314 |
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| 24. |
of the relating tope2. A drum full of rice weighs 40 kg. If the empty drum weh 13the drumin 19h in alltad te weht sicethanh |
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| 25. |
9. The mean (average) weight of three students is 40 kg. One of the students Ranga weighs46 kg. The other two students, Rahim and Reshma have the same weight. Find Rahimweight. |
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Answer» avg wt Of ranga+ rahim+reshma= 40total wt= 40×3= 120wt of ranga= 46wt of resham+ rahim = 120-46= 74resham=rahim= x(let)2x= 74x= 74/2=37 kgwt of resham= wt of rahim= 37 kg (46+X+X)÷3 = 4046+2X = 1202X = 74X = 37so Rahim weight is 37 kg Answer Given: Mean of three students = 40 kg The three students are Ranga, Rahim and Reshma, where Ranga’s weight = 46 kg Let Rahim’s weight = x And Reshma’s weight = y [∵Rahim’s weight = Reshma’s weight, according to the question] Mean is given by Mean = 40] ⇒120 = 46 + 2x ⇒2x = 120 – 46 = 74 ⇒x = 74/2 ⇒x = 37 Thus, Rahim’s weight = 37 kg 40 = 46 + x + x/3=46 + 2x/3; 120 = 46 + 2x; 2x = 74; x = 74/2=37 don't know this itself |
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| 26. |
A sweet box contains 28 sweets. Mr. Sharma bought 116 boxes and distributed the sweets among 112employees of his company equally. How many sweets did each employee get?nr ir ne |
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Answer» each person will get 29 sweets 116×28÷112=29 hence each one will get 29 sweets 116×28÷112=29 hence each one will get 29 sweets |
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| 27. |
Amcal wa a blotond or K 96000of cohat-cain % 8hould be Rhell theresmeion)のihole |
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| 28. |
2 tan x6. Ir (x) = 2 tang , the value of r(1) will bene value owill be1+ tan |
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| 29. |
per annum ts equal to the simple imterest on the setu25. Dividet 3600 Into two parts sueJi that if one parl be lent it 9% per 8tititim ent f ge-0)10% per annum, the totar annual income is? |
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| 30. |
A watch dealer pays 10% custom duty on a watch which costs 500 abroad. For how shomark it, if he desires to nake a profit of 20% after giving a discount of 25% to the buyer ? |
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Answer» Custom duty is 10% Therefore, actual price is 500+500*(10/100)= 550 let marked price = x Discount 25% SP = x-(x*25/100) =3x/4 Now sp= (100+20)% of cp = 120%*550 = 660 so 3x/4= 660 x= 880 So he should mark it at 880 |
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| 31. |
8. E is a point on the side AD produced of aparallelogram ABCD and BE intersects CDat F. Show that ΔΑΒΕ ~ Δ CFB. |
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| 32. |
8. E is a point on the side AD produced of aparallelogram ABCD and BE intersects CDat F. Show that Δ ABE ~ Δ CFB |
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| 33. |
8. E is a point on the side AD produced of aparallelogram ABCD and BE intersects CDat F: Show that Δ ABE ~ Δ CFBd p |
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| 34. |
MaDR ){"âv ༤ |
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| 35. |
| Age (in yo) | 15 18| 2655 Rl et ¢ \v |2 |
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| 36. |
- Findthe â˘termotace - ]L& ?. v ; |
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| 37. |
. o v ey) ,,9(&Âť,â (! i) | |
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Answer» In the nervous system, asynapseis a structure that permits a neuron (or nerve cell) to pass an electrical or chemical signal to another cell (neural or otherwise). ... A mircoscopic gap between pair of adjacent neurons over which nerve impulses pass when going from one neuron to the next is calledsynapse. thanks please like the solution 👍 ✔️ |
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| 38. |
X-1=xz+¢c v |
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| 39. |
lá The dimensions of a rectangular box are inthe ratio of 2:3:4 and the difference8and 9.50 perbetween the cost of covering it with sheet of paper at the rates ofm2 is 1248. Find the dimensions of the box. |
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| 40. |
%6L () (A1)༤vâ1stl |
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Answer» option d is correct because the cube root of that number is equal to -5/9 |
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| 41. |
v 896+ 489)% - (896- 489)°(896 % 489) |
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| 42. |
Two trains A and B of length 400 m eachare moving on two paralilel tracks with auniform speed of 72 km/h in the samedirection, with A ahead of B. The driverof B decides to overtake A andaccelerates by 1 m/s2. If after 50 s, theguard of B just brushes past the driver ofA, what was the original distancebetween them? |
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| 43. |
E is a point on the side AD produced of aparallelogram ABCD and BE intersects CDatF.Show that ΔΑΒΕ ~ Δ CFB8. |
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| 44. |
21. The mean weight of 4 boys is 56 kg and that of 6 girls in 46 kg. Find the combinedmean weight of 10 students. |
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Answer» Mean weight of 4 boys = 56 kg Weight of 4 boys = 56 (4) = 224 Mean weight of 6 girls = 46 kg Weight of 6 girls = 46 (6) = 276 Total weight = 224 + 276 = 500 Average weight = 500/10 = 50 kg |
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| 45. |
- E is a point on the side AD produced of aparallelogram ABCD and BE intersects CDat F. Show that AABE-ACFB. |
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| 46. |
The average weight of 100 students is 46 kg. Theaverage weight of girls is 40 kg. If the number of girlsis 40, the average weight of boys in kilograms is |
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Answer» the average weight of 100 students is 46 kg the average weighg of 100 students is46 the average age of boys = 60×46= 2760kg 2760 is the right answer the average weight of boys=2760 kg the average age of boys= 2760 kg the average of boys= 2760 kg the average age of boys =60×46=2760kg |
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| 47. |
ative trequency distribution,e the medical check-up of 35 students of a class, their weights were recorded asWeight (in kg)Less than 38Less than 40Less than 42Less than 44Less than 46Less than 48Less than 50Less than 52Number of students14283235 |
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| 48. |
IOION PROGRAMMEDuring the medical check up of 35 students of a clas, heir weights were recorded as follows (RWeight (in Kg) | < 38 | 10 | < 42 | < 44 | < 46 | < 48 | < 50 52V)No. of students 35 9 14 28 3235Draw a less than type ogive for the given dath. Hence obtain the median weight from the graph andverify the result by using the formula. |
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| 49. |
..x (+10) = 3×-2 + 3 × 10 & also name the propertyVerify that5 7 four vears ago trorm |
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Answer» this is distributive property.a×(b+c)= (a×b)+(a×c)so similarly opening the brackets in the left hand side.(5/3)(-2/5)+(5/3)(-9/10)which is equal to RHS. this is distributive property of addition over multiplication |
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| 50. |
Find the nuhbent Sudesh is twice as old as Seema. If six years is subtracted from Seema's age and fourears are added to Sudesh's age, Sudesh will be four times Seema's age. How old werethey three years ago?Tii Ton vears hence, the ratio of their |
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Answer» Let present age of Seema is xand present age of Sudesh is 2x 4(x-6)=2x+44x-24=2x+44x-2x=4+24=282x=28x=28/2=14 Present age of Seema is 14and present age of Sudesh is 28 3 years ago, Seema is 14-3=11and Sudesh is 28-3=25 |
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