This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Sunita is twice as old as Ashima. If six veais subtracted from Ashima's age and fourvears added to Sunita's age, then Sunitawill be four times that of Ashima's age. Findthe sum of their ages two years ago. |
|
Answer» Let present age of Ashima = xThen, present age of Sunita = 2x As per given condition(x + 4) = 4(2x - 6)x + 4 = 8x - 248x - x = 24 + 47x = 28x = 28/7 = 4 Therefore,Age of Sunita = 4 yearsAge of Ashima = 2*4 = 8 years Two years agoAge of Sunita = 4 - 2 = 2 yearsAge of Ashima = 8 - 2 = 6 years Sum of their ages two years ago = 2 + 6 = 8 |
|
| 2. |
threeis133years.Whatistheageofeach one of them ?INCERINCER(i) The ages of Rahul and Haroon are inthe ratio 5:7. Four vears later the sum of their ages will be 56 years. What are their presifteen |
|
Answer» let ravi present age be xthere according to question we get eqx+15=4xsolving it15 = 3x x= 5 |
|
| 3. |
Q.1, y = a is a straight line parallel to |
|
Answer» y = a is a straight line parallel to x -axis |
|
| 4. |
25. Equation of a straight-line parallel to y - axis isa. y kd. |
|
Answer» The equation of x-axis is y = 0, since, x-axis is a parallel to itself at a distance 0 from it. Let P (x,y) be any point on the x-axis. ... Therefore, the equation of x-axis is y = 0. If a straight line is parallel at a distance b, then its equation is y = k |
|
| 5. |
Equation of the straight line parallel to x -axis and passing through ( 0,-2) is-a) x-2-o |
| Answer» | |
| 6. |
16.)In a parallelogram ABCD, a straight line parallelto the side AB intersects AD, AC and BC. Theseline segments are produced at E, F and Grespectively. Prove that AAEG AAFD |
|
Answer» 1 2 3 |
|
| 7. |
Find the equation of a straight line parallel to 2x+3y+ 11=0 and which issuch that the sum of its intercepts on the axes is 15. |
|
Answer» Let the eqn. of a straight line parallel is. 2x+3y=c…………..(1) Intercepted form of eqn.(1) is:- x/(c/2)+ y/(c/3) = 1 Intercepts on x-axis is. (c/2). and on y-axis is (c/3) units ,accordingly:- c/2+c/3=15 or. 5c/6=15 or. c= 15×6/5=18 On putting c=18 in eqn.(1) the required eqn. is:- 2x+3y=18. Answer |
|
| 8. |
Find the equation of the straight line which passes through (2,-3(i) parallel to x-axis(ii)parallel to y-axis. |
| Answer» | |
| 9. |
If logXty __(log x + log y), theoglog x + logy), then show3 23that+7.ŃŃ |
|
Answer» log [ ( x + y )/3] = 1/2 ( logx + logy) 2× log[ ( x + y )/3 ] = log x + log y log [ ( x + y ) / 3 ]^2 = log xy { since i ) n log a = log a^n ii ) log a + log b = log ab } Remove log both sides, [ ( x + y ) / 3 ]^2 = xy ( x + y )^2 / 3^2 = xy x^2 + y^2 + 2xy = 9xy x^2 + y^2 = 9xy - 2xy x^2 + y^2 = 7xy Divide each term with xy x^2 / xy + y^2 / xy = 7xy / xy x / y + y / x = 7 |
|
| 10. |
Find the equation to the straight line parallel to 3x -4y+6 0 and passingthrough the middle point of the join of points (2, 3) and (4, -)J |
| Answer» | |
| 11. |
2500/41845/32448/63264/42872/84193/71794/22778/34770/96872/8 |
| Answer» | |
| 12. |
"लक - -’ Sin (A+B)=SinA + Sin B (True / False)o Lia T |
|
Answer» The statement is false. sin (A+B)=sinAcosB+cosAsinB |
|
| 13. |
13. Puu w sum UT14. Find the sum of the odd numbers between 0 and 50.11 fios a penalty for delay of completion |
|
Answer» 1+3+5+7+9+11+13+15+17+19+21+23+25+27+29+31+33+35+37+39+41+43+45+47+49=625 n(n+1)/2 n=25 because 25 odd numbers between 0 and 50 25(26)/2 325 |
|
| 14. |
\begin { equation } x^{2}-2 x-y^{2}+2 y \end { equation } |
| Answer» | |
| 15. |
\begin { equation } (2 x-1)^{2}-(x-1)^{2} \end { equation } |
|
Answer» 3x2_2x2 |
|
| 16. |
\begin { equation } m^{2}+\frac{1}{m^{2}}+2-2 m-\frac{2}{m} \end { equation } |
| Answer» | |
| 17. |
lia(x-22)lim x |
|
Answer» Put x=π(x-22/7)=(22/7-22/7)=0 |
|
| 18. |
\begin { equation } x^{2}-7 x+2 \end { equation } |
| Answer» | |
| 19. |
ăog |
| Answer» | |
| 20. |
१प्रश्न 9.] * * ** | dr का मान हैप्रश्न3. ।।* + ३५.dar का मान है।।= |
| Answer» | |
| 21. |
WWII4. aosqueare ogFind thelengthcenaucena ogcos.Pactan |
|
Answer» the Answer is 16cm square 16 cm² is the area of square whose sides are of 4cm |
|
| 22. |
3og |
| Answer» | |
| 23. |
rind Hine remainder ushens divided by 5+21χ3+ 3x2+3..)DateРосе |
|
Answer» Apply remainder theorem=>5+2x =0=> 2x = - 5=> x = - 5/2Replace x by – 5/2 we get=>x3+3x2+ 3x + 1=>(-5/2)3+ 3(-5/2)2+ 3(-5/2) + 1=> -125/8 + 75/4 – 15/2 + 1Add the fraction taking LCM of denominator=>(-125 + 150 - 60 + 8 )/125=> -27/8Remainder is -27/8 Like my answer if you find it useful! |
|
| 24. |
② 퀴-80、00.og 10./.aua 3 |
|
Answer» P=20000R=10%n=3So A=P(1+R/100)^3=20000(1+10/100)^3 =20000*(1.1)^3=20000*1.331=26620so interest is 26620-20000=6620 |
|
| 25. |
рди SinQ = o0<& O+i ccae- oG =130 |
|
Answer» cosA+sinA=√2cosAsquaring both the sides =>(cosA+sinA)²=2cos²A=>cos²A+sin²A+2sinAcosA=2cos²A=>cos²A-2cos²A+2sinAcosA= -sin²A=> -cos²A+2sinAcosA= -sin²A=> cos²A-2sinAcosA=sin²Aadding sin²A on both the sides => cos²A+sin²A-2sinAcosA=2sin²A=> (cosA-sinA)²=2sin²A=> cosA-sinA=√2sinA thank you |
|
| 26. |
Prove that og,3(log,Sxlog,3) |
| Answer» | |
| 27. |
Wharrinberiaftsogeciangcliainis its breadth? |
|
Answer» Let breadth of Reactangle = bLength of Reactangle l = 16 m Perimeter of Square with side 13 cm = 4*13 = 54 m Perimeter of Reactangle = Perimeter of Square2(l + b) = 542(16 + b) = 54b = 27 - 16b = 11 Therefore breadth of Reactangle = 11 m |
|
| 28. |
/Find the value ofa in the figure.106118° |
| Answer» | |
| 29. |
were recorded asDuring the medical check-ap of 35 students of a class, their weighesfollows2.Weight (in kLess than 38Les than 40Less than 42Less than 44Less than 46Less than 48Less than 50Less than 52Nanber of student14283235Draw a less than type ogive for the given data Hence obtain the median weigt trosthe graph and verify the result by using the formula. |
| Answer» | |
| 30. |
Ramesh sells shirts. He allows 5% discount on the market line and still gains 10% gain.Find the market price of the saree which cost 950 |
| Answer» | |
| 31. |
Arjun is twice as old as Shriya. If five years ago his age was three times Shnithen Arjun's present age is(a) 10 years(b) 15 years(c) 20 years() 25 years |
| Answer» | |
| 32. |
i years4. The population ofa town was 150000 three years ago. It increases by 2%, 5% and 8% in the last threeyears. What is the present population of the town?5. The population of |
| Answer» | |
| 33. |
A dealer allows a discount of Rs 10% and still gains by 10%. What should be the marked price if the cost price is 900 |
|
Answer» Let the marked price be x.Given cost price = 900.Given that gain = 10%.SP = 900 + 10% of 900 = 900 + 10/100 * 900 = 900 + 90 = 990.Given that Discount = 10%.SP = markedprice - 10% of 100SP = x - 10/100 * 100990 = x - 0.10x990 = 0.9xx = 1100.The marked price = 1100. |
|
| 34. |
-135और225 का hof |
|
Answer» 135=5×3×3×3225=5×5×3×3Hcf =3×3=9The answer is correctPlz like my answer and accept best answer 9 is the best answer the answer is hcf 9. 45 is the correct answer of the given question 9 is the best answer |
|
| 35. |
Ajeweller allows a discount of 16% to his customers and still gains 20%. Find the markeprice of a ring which costs the jeweller ? 1190. |
| Answer» | |
| 36. |
A shopkeeper allows a discount of 20% to his customers and still gains 25%. Find theMarked price of an article which costs 600 to the shopkeeper. |
|
Answer» P = P % * CP / 100 P = 25 * 600 / 100 P = Rs . 150 SP = CP + P SP = 600 + 150 SP = Rs . 750 D % = 20 % MP = ( 100 * SP ) / ( 100 - D % ) MP = ( 100 * 750 ) / ( 100 - 20 ) MP = 100 * 750 / 80 MP = Rs . 937.5 thnx |
|
| 37. |
Jhanvi sells sarees. She allows 5% discount on the marked price and still gains 10%. Find the marked priceof a saree which costs her5.950. |
| Answer» | |
| 38. |
Find , thP (- 1, 2) and Q (5,4).e projection of the point (1, 0) on the line joining the points |
| Answer» | |
| 39. |
The angle of elevation of the top of a tower from two points P andQ at distances of a and b respectively, from the base and in thesame straight line with it are complementary. Prove that the heightof tower is vab |
|
Answer» thankuuuu soo much mam😭😭😭❤❤❤ |
|
| 40. |
Eind the LCM and Hof.----the-fallo! ing": integerby applying the Paine Gacosisation methodand 21LS |
|
Answer» 12 = 2×2×3 15 = 3×5 21 = 3×7 HCF = 3 LCM = 2×2×3×5×7 = 60×7 = 420 |
|
| 41. |
Lol dt taka 67 mm to |
|
Answer» if 134 men can make a wall in 3 weeksthen 1 man can make it in 3×134 weeks so, 67 men will take 3×134/67 weeks = 6weeks and no. of days in 6weeks = 6×7 = 42 days |
|
| 42. |
which is sold by him for 880A dealer allows a discount of 10% and still gains by 10%, what should bemarked price if the cost price is t900? |
| Answer» | |
| 43. |
ans20%Findthemarkedprice of the refrigerator.10. Ajeweller allows a discount of 16% to his customers and still gains 20%. Find the markedprice of a ring which costs the jeweller R 1190. |
| Answer» | |
| 44. |
Find ofa day (in sec.) |
| Answer» | |
| 45. |
Atoyteyandif heheesellerstillgains10 toyallows 25% e ou MP of the oumakes a plupt of 26%Rs 360 at the sell offind the MP of the they# |
|
Answer» Profit = 20% = 360 Rs So, Cost Price = 360 / 20 * 100 = 1800 Rs And Sales Price = 1800 + 360 = 2160 Rs Discount = 25% of marked price So Sales Price = (100 - 25) % = 75% of marked price => 2160 = 75% of marked price => marked price = 2160 / 75 * 100 =2880 rs |
|
| 46. |
remaimder of 16, 10, , Itaptu8 The school bell rings every 40 minutes and the clock tower of the citycentre rings every 60 minutes. At 8 a.m. on a day both the bells soundedtogether. At what time will both of them make their sounds next? |
|
Answer» If you find this solution helpful, Please like it. |
|
| 47. |
The school bell rings every 40 minutes and the clock tower of the citcentre rings every 60 minutes. At 8 a.m. on a day both the bells sountogether: At what time will both of them make their sounds next? |
| Answer» | |
| 48. |
(238) The sum of ages of two friend is 20 years. Four years ago the product of the numbers showing their ages was 48. |
| Answer» | |
| 49. |
0.13, Four years ago, Raj was 10 years old. How old is he todayAns : |
|
Answer» Raj would be 14 years old today |
|
| 50. |
Sudesh is toice as old as Seemat sine years is subtracted fromSeemald age and four yearsare added to Sudaphs age, sadeshswill be four times lomas age.How old were they three yearsago' |
|
Answer» let present age of seema = x yrssudesh= 2x yrs4( x-6) = 2x + 44x- 24 = 2x +44x-2x=4+242x=28x=14present age of seema=14 yrspresent age of sudesh= 28 yrs3 yrs ago age of seema = 11 yrs3 yrs ago age of sudesh =25 yrs seema was 11 yrs old and sudesh was 25 yrs old 3 yrs ago |
|