Sunita is twice as old as Ashima. If six veais subtracted from Ashima'

1.	Sunita is twice as old as Ashima. If six veais subtracted from Ashima's age and fourvears added to Sunita's age, then Sunitawill be four times that of Ashima's age. Findthe sum of their ages two years ago.
Answer» Let present age of Ashima = xThen, present age of Sunita = 2x As per given condition(x + 4) = 4(2x - 6)x + 4 = 8x - 248x - x = 24 + 47x = 28x = 28/7 = 4 Therefore,Age of Sunita = 4 yearsAge of Ashima = 2*4 = 8 years Two years agoAge of Sunita = 4 - 2 = 2 yearsAge of Ashima = 8 - 2 = 6 years Sum of their ages two years ago = 2 + 6 = 8

Sunita is twice as old as Ashima. If six veais subtracted from Ashima's age and fourvears added to Sunita's age, then Sunitawill be four times that of Ashima's age. Findthe sum of their ages two years ago.

Answer»

Let present age of Ashima = xThen, present age of Sunita = 2x

As per given condition(x + 4) = 4(2x - 6)x + 4 = 8x - 248x - x = 24 + 47x = 28x = 28/7 = 4

Therefore,Age of Sunita = 4 yearsAge of Ashima = 2*4 = 8 years

Two years agoAge of Sunita = 4 - 2 = 2 yearsAge of Ashima = 8 - 2 = 6 years

Sum of their ages two years ago = 2 + 6 = 8