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x-y= 9 is the correct answer

x-y=3 is the correct answer

X= 150as 150= 5*5*2*3

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2*17=34=z34*2=68=y68*2=136=x

32 = 2*2*2*2*248=2*2*2*2*340 =2*2*2*5GCF =highest common factor in 32,48,40

=2*2*2 =8

Use afactor treeto express 60 as a product of prime factors. So the prime factorization of 60 is 2 × 2 × 3 × 5, which can be written as 22× 3 × 5. The actual prime factors of 60 are 2, 3, and 5.

rationalizing factor of √8=√8

Rationalising factor of √8 is √8 i.e. 2√2

rationalizing factor of root8 is 8

2^1/6hence rationalising factor will be 2^6=64=3√4

Write steps

here is a solution for a similar ques.

then ,AR=PERT=ENAT=PN

AR =PE RT=ENAT =PN This is answer

thenAR=PERT=ENAT=PN

madarchod

Given: The sum of the zeroes of the polynomialis equal to their product.

To find: The value ofk.

Letbe the two zeros of the polynomial.

We know that ifαandβare the zeros of a quadratic polynomialf (x), then

Sum of the zeros =

Therefore, using the given polynomial, we get



Also, we know that ifαandβare the zeros of a quadratic polynomialf (x), then

Product of the zeros =

Therefore, using the given polynomial, we get



Now, we know that the sum of the zeroes is equal to their product.

Therefore, we get



Therefore, the value ofk=.

Given f(t) = kt2+ 2t +3k

α,β are the roots of the quadratic polynomial then

α+β =-b/a= -2/k andαβ =c/a= 3k/k

According to the conditionα+β =αβie -2/k=3k/k

k=-2/3

wat iz da ans....

the correct ans. is option (b). rs.800

THREE MANAGEMENT PRACTICES ARE AS FOLLOWS

(a) Providing shelter, rich feed and clean drinking water.(b) Maintaining optimum temperature and good hygienic conditions in poultry farms.(c) Providing health care and timely vaccination to farm animals.

Que is not clear bcz of figure isnt clear

Ans- a) No P=18 b)Yes M=9

root2 + 3/root2=2+3/root2=5/root2

Area enclosed by two arcs = area of semicircle BQA - area of semicircle BPA

given, radius of semicircle BQA, r = 14cmarea of semicircle BQA = 1/2 × πr² = 1/2 × 22/7 × (14)² = 1/2 × 22/7 × 14 × 14 = 11 × 2 × 14 = 308 m²

radius of semicircle BPA , r' = 7cm area of semicircle BPA = 1/2 πr'² = 1/2 × 22/7 × (7)² = 1/2 × 22/7 × 7 × 7= 11 × 7 = 77 m²

now, area enclosed by two arcs = 308m² - 77m²= 231 m²

this answer is wrong

l.b.h 7.5.5 multiple b

The number which is neither prime nor composite is 1.

A = { x | 3x - 1 = 2 } 3x - 1 = 2 3x = 1 + 2 = 3 x = 1 A = { 1 } B = { 1 } Because 1 a natural number neither prime nor composite. A = B

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permanent magnets are used in moving coil instruments also know known as PMMC instruments which means permanent magnet moving coil instruments

Cost 5 m fabric is Rs 210Cost of 1 m fabric is Rs 210/5 = Rs 42Cost of 2 m fabric is Rs 42 × 2 = Rs 84

Special Angles.Special Angles- 30o, 45o, 60o. The values of the six trigonometric ratios cannot be calculated exactly for mostangles. Nor can the exact value of ananglegenerally be found given the value of one of the ratios

option b can be represented in the number line as route 25 is equal to 5 which we can determine in the number line

The correct answer is option (c) both(a) &(b)

option b can be represented in the number line

answer C both can be

answer b can represent on number line

c is the answer of the following

option b is the correct answer of the given question

b can be represented on number line because 5^2=25

b is the right answer

option b root 25 is correct

root 25(b) is the right answer.

A balanced die is rolled once.Sample space,S={1,2,3,4,5,6}i)Let E be the event when number received is neither prime nor composite.E={1}∴P(E)=1/6ii)Let F be an event of even number on face.F={2,4,6}∴P(F)=3/6=1/2

Length of the Bridge = 264 m.Time taken to pass the bridge = 20 sec.

Time taken to passe the post = 8 sec.Length of the train = X m (Let.)To pass the bridge train need to coverTrain's length + Bridge legnth(X +264).Speed = Distance covered / time takenNow,X/8 = (264 + X)/2020X = 264 *8 + 8X

20X - X = 264 *8

12X = 264 *8X = (264 *8)/12X = 176 m.Speed of the train = 176/8 = 22 m/sec = (22*18)/5 = 79.2 Kmph.

Trains speed is 70 km /hr

Length of the Bridge = 264 m.Time taken to pass the bridge = 20 sec.

Time taken to passe the post = 8 sec.Length of the train = X m (Let.)To pass the bridge train need to coverTrain's length + Bridge legnth(X +264).Speed = Distance covered / time takenNow,X/8 = (264 + X)/2020X = 264 *8 + 8X

20X - X = 264 *8

12X = 264 *8X = (264 *8)/12X = 176 m.Speed of the train = 176/8 = 22 m/sec = (22*18)/5 = 79.2 Kmph.