two arscs.tem

1.	two arscs.tem
Answer» Area enclosed by two arcs = area of semicircle BQA - area of semicircle BPA given, radius of semicircle BQA, r = 14cmarea of semicircle BQA = 1/2 × πr² = 1/2 × 22/7 × (14)² = 1/2 × 22/7 × 14 × 14 = 11 × 2 × 14 = 308 m² radius of semicircle BPA , r' = 7cm area of semicircle BPA = 1/2 πr'² = 1/2 × 22/7 × (7)² = 1/2 × 22/7 × 7 × 7= 11 × 7 = 77 m² now, area enclosed by two arcs = 308m² - 77m²= 231 m² this answer is wrong

Answer»

Area enclosed by two arcs = area of semicircle BQA - area of semicircle BPA

given, radius of semicircle BQA, r = 14cmarea of semicircle BQA = 1/2 × πr² = 1/2 × 22/7 × (14)² = 1/2 × 22/7 × 14 × 14 = 11 × 2 × 14 = 308 m²

radius of semicircle BPA , r' = 7cm area of semicircle BPA = 1/2 πr'² = 1/2 × 22/7 × (7)² = 1/2 × 22/7 × 7 × 7= 11 × 7 = 77 m²

now, area enclosed by two arcs = 308m² - 77m²= 231 m²

this answer is wrong

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