This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
I purchased a hair-dryer forwas added5400 including 8% VAT Find the price before VAT |
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| 2. |
= 3000I purchased a hair-dryer for 5.400 including 8% VAT. Find the price before VATadded |
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Answer» 500 is the correct answer of the given question f 8 percent of 5400 = 8×5400/100 =432 VAT price i=432 price of hair-dryer before VAT was added = 5400-432 =4968 is the correct answer |
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| 3. |
10. I bought a hair-dryer for Rs 5,400 including 8% VAT. Find the pricebefore VAT was added. |
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| 4. |
l purchased a hair dryer for? 5.400 including 8% VAT. Find the price before VATwas added |
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| 5. |
Q.10.rpurchasedahair-dryerforRa5.400 including 8% VAT. Find the pricebefore VAT was added. |
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Answer» This 2 both answer continue |
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| 6. |
lu the marked price.I purchased a hair-dryer for? 5,400 including 8% VAT. Find the price belowas added |
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| 7. |
write the the smallest whole number also write the the smallest natural number |
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Answer» whole number=3*4natural number=4*2 please like my answer and accept best 0. 0000000000000001 and 1 is natural number whole number=3×4natural number=4×2 सबसे छोटी संख्या 0 है और प्राकृत संख्या भी 1 है smallest whole number = 0smallest natural number = 1 |
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| 8. |
1. Fill in the blanks.(i) The smallest natural number is ......GT |
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| 9. |
find the smallest natural number by which 1200 should be multiplied so that the square root of the product is a rational number |
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Answer» Solution:-√1200⇒√100×12⇒√100×√12⇒10×√4×3⇒10×2√3⇒ 20√3So, 3 is the smallest natural number that needs to be multiplied with 1200, so as to make the product a rational number. |
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| 10. |
The smallest value of k, for which both the roots of the equation x2distinct and have values atleast 4, is8kx 16(k+ISIT-JEE 2009, Paper-2, (4,-1) 80 |
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| 11. |
What is mant by atom |
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Answer» Ans :- Atom. Atoms are the main building blocks of matter. All the materials are made up of very small particles called atoms. Atom consists of three sub atomic particles they are electron, proton and neutron. Protons and neutrons are stick together to form a nucleus in the center of atom. |
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| 12. |
UTION TO TURUNUNU GEU HUIC!11. One day, during their vacation at a beach resort, Shella found twice as many sea shells asAnita and Anita found 5 shells more than sandy. Together sandy and Shella found 16 sea |
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| 13. |
46)Onset of pregnancy |
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Answer» Pregnancysymptoms at 4 weeks. Normally you get your period about 4 weeks from thestartof your last period, but the clearest sign at this point is a missed period. Many women still feel fine at 4 weeks, but others may notice sore breasts, fatigue, frequent urination, and nausea. |
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| 14. |
If the angle of elevation of Sun increases from 0° to 90° then the length ofshadow of a tower decreases. Is this true ? Justify your answer. |
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Answer» Let the height of tower is h unitsand length of shadow is d unitsinitially, angle of elevation is 0°tan0° = h/d = 0that means length of shadow is∞(infinity) = maximumfinally,tan90° = h/d =∞that means length of shadow is 0 =minimum∴as the angle of elevation increases from 0° to 90°, the length of shadow decreases from maximum to minimum. |
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| 15. |
8 The shadow of a vertical tower on a level ground increases by 10 m when the altitude45 to 30. Find thr heigt aof the sun changes from 45° to 300. Find the height of the tower, correct to two decimal(2006)places. |
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| 16. |
ĺ 6. A sphere of diameter 18 cm is dropped into a cylindrical vessel of diameter 36 cm partlyfilled with water. If the sphere is completely submerged, then find the water level rises(in cm) |
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Answer» Volume of sphere= 4/3 x π x 9³ =972 π Volume of water in vessel= π x 18² x h = 324 π h New volume in vessel = Vol. of sphere + Vol. of water π x 18² x H = 972 π + 324 π h 324 H = 972 + 324 h (here in RHS and LHS π is common ) 324 H - 324 h = 972 H - h = 972/324 = 3 cm level of water rises by 3cm |
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| 17. |
Spherical Marbles of diameter 1.4 cm are dropped into a cylindrical beaker of diameter7 cm, which contains some water. Find the number of marbles that should be dropped into the beaker, so that water level rises by 5.6 crm |
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| 18. |
0. Marbles of diameter 1.4 cm are dropped into a cylindrical beaker ofdiameter 7 cm, containing some water. Find the number of marbles thatshould be dropped into the beaker so that the water level rises by 5.6 cm. |
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| 19. |
— G ) जी L1 ’V |
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Answer» The answer of this question is 1024. |
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| 20. |
30. Marbles of diameter 1.4 cm are dropped into a cylindrical beaker ofdiameter 7 cm, containing some water. Find the number of marbles thatshould be dropped into the beaker so that the water level rises by 5.6 cm. |
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Answer» thank yoi |
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| 21. |
l1-cos A ;Sin zâ |
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Answer» LIKE THE SOLUTION |
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| 22. |
EXERCISE9.2l1 |
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| 23. |
A's income is 60% more than that of B. By what per cent is B's income less thanA's?· |
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| 24. |
6. Spherical Marbles of diameter 1.4 cm are dropped into a cylindrical beaker of diameter7 cm, which contains some water. Find the number of marbles that should be dropped into the beaker, so that water level rises by 5.6 cm. |
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Answer» Thank you |
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| 25. |
When the angle of elevation of the sunincreases from 30 to 60, the shadow of atower decreases by 50 m. Find the height ofthe tower. |
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| 26. |
14. As income is 20% less than that of B. By what per cent is B's income more than A's? |
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| 27. |
A plant's height increases 1/8" of its height in everyyear. If the present height of tree is 64 c.m. then whatwill be the plant's height after two years from now? |
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Answer» 65.cm is the best answer please like Present height of tree = 64 cm Let height of tree after two years = H Then,H = 64* (1 + 1/8)^2 = 64* (9/8)^2 = 64*81/64 = 81 Therefore,Height of tree after 2 years = 81 cm 81 is the best answer Bolo Ha Ki nahi bahi 80 cm ho jayegi bhai 81 is the right answer 81 is the correct answer |
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| 28. |
A height is more than B height by 20% what per cent B height less than A height |
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Answer» B height=HA height=H+(20/100)H=H+H/5=6H/5 B is less by 6H/5-H=H/5%=(H/5)/H*100=20% |
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| 29. |
29. A teacher on attempting to arrange the students for mass drill in theform of a solid square found that 24 students were left. When he increthe size of the square by one student, he found that he was short of 25students. Find the number of students.CBSE 2004 |
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| 30. |
a/(-a %2B x) %2B b/(-b %2B x)=(2*c)/(-c %2B x) |
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Answer» A / (x - a) + b / (x - b) = 2c / (x - c)=> [a(x - b) + b (x - a)] / (x - a) (x - b) = 2c / (x - c)=> [(a + b) x - 2ab] (x - c) = 2c [x^2 - (a + b)x + ab]=> (a + b) x^2 - [2ab + c(a + b)]x + 2abc = 2cx^2 - 2c(a + b)x + 2abc=> (a + b - 2c) x^2 = (2ab + ac + bc - 2ca - 2bc) x=> (a + b - 2c) x^2 = (2ab - ca - bc) x=> x = 0or x = (2ab - ca - bc) / (a + b - 2c) |
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| 31. |
(B %2B X)/(A - B)=(-B %2B X)/(A %2B B) |
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Answer» (x + B)/(A-B) = (x - B)/(A + B) (x + B)(A+B) = (x - B)(A - B) xA + xB + AB + B^2 = xA - xB - AB + B^2 xB + xB = - AB - AB 2xB = - 2AB x = - AB/B = - A |
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| 32. |
DPITCODYual.A general wishing to arrange his 120419 men in the form of a solid square, found that he had 10 extra men. Findthe number of men in the front row. |
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Answer» total number of men = 120419. number of extra men = 10 So, number of men arranged in square = 120419 - 10 = 120409 number of men in front row = √120409 = 347 (ANS) here total no of man =120419exitra man =10 so man in squar be =120419 -10 =120409 henxe squar root of 120409 = 337 347 is the correct answer |
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| 33. |
A teacher on attemipting to arrange thestudenta for mess drill in the form af a27.solid square find that 24 students were left. When he increased the size of thesquare by one student, he found that he was short of 25 students. Find thenumber of students. |
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| 34. |
27. A teacher on attempting to arrange the students for mess drnlintheformofasolid square find that 24 students were ieft. When he increased the ssquare by one student, he found that he was short ofnumber of students.size of the25 students. Find the |
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| 35. |
8. A teacher on attempting to arrange the students for mass drill in the form of a soldsquare found that 24 students were left. When he increased the size of the squareby one student, he found that he was short of 25 students. It is required to find thenumber of students. |
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Answer» Given:A teacher attempts to arrange his students in the form of a solid square.ii24 students were left.iiiiWhen he increased the size of the square by 1, he was short of 25 students. We need to find the number of students. Let the number of rows of students bexx.Since the number of columns of students is alsoxx, the number of students in each row is thusxx. Conditioniigives us:The total number of students =x2+24x^2 + 24. Conditioniiiigives us:(x+1)2−25=x2+24(x + 1)^2 - 25 = x^2 + 24∴x2+2x+1−25=x2+24\therefore x^2 + 2x + 1 - 25 = x^2 + 24 (using(a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2)∴x2+2x−24=x2+24\therefore x^2 + 2x - 24 = x^2 + 24∴2x−48=0\therefore 2x - 48 = 0∴x=24\therefore x = 24 Conditioniigives us:The total number of students =242+24=60024^2 + 24 = 600. Therefore, there were a total of 600 students. |
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| 36. |
A General wishing to draw up his 64,019 men in the form of a square found thathe had 10 men extra. Find the number of men in the front row. |
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Answer» Total number of men=64019After arranging them in the form of a square 10men were left outSo number of men in the square=64019-10=64009In a square all the sides are equalSo....the number of columns will be equal to the number of rowsSo....the number of men in a row will be equal to the total number of columnsColumns will be equal to the √69009=253No of men in front row will be 253 |
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| 37. |
Mie neath row of the lecture hall?General wishing to draw up his 64,019 mhe had 10 men extra. Find the number of mew up his 64,019 men in the form of a square found that |
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Answer» 235 Let number of men in each row be xAs all men are arranged in the form of square Then,x*x = 64019 - 10 = 64009x = 253 Therefore, Number of of men in front row = 253 |
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| 38. |
53 cm) and Sujeet (height 5Scm) are standing in a ground. If distance between the ir toesare standing in a ground. If distance between their toesis 12 cm, what is the distance between their heads? |
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| 39. |
(a %2B x)*(b %2B x)=a*(b*text) %2B x^2 %2B x*(a %2B b) |
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| 40. |
sin(-x)/sin(pi %2B x) %2B cos(x)/sin(pi/2 %2B x) - tan(pi/2 %2B x)/cot(x) |
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Answer» Hi Subhranil, Here is the answer to your question. |
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| 41. |
sqrt(a*x)/(sqrt(a) %2B sqrt(x) %2B sqrt(a %2B x)) %2B sqrt(a*x)/(sqrt(a) %2B sqrt(x) - sqrt(a %2B x)) |
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| 42. |
Why dowe need food? |
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| 43. |
ind the ratio of the following:)800g to 1.ókg则ǐsa altering malus..…Conversion ratios ALWA12 inches fooMalhlib.com 12 inches 12 ind)200cmto 1.2 m400ml to 2/ |
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Answer» 1) 800 g = 0.8 kg800g : 1.6 kg = 0.8:1.6 = 1:2 2) 200cm = 0.2m200cm : 1.2m = 0.2m : 1.2m= 1:6 3) 400ml = 0.4L400ml : 2L = 0.4:2= 1:5 PLEASE HIT THE LIKE BUTTON |
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| 44. |
longdiv*(2*x - 7*x^2 %2B 3*x^4 %2B 5*x^3 %2B 2) %2B x^2 %2B 3*x |
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| 45. |
ind dx |
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| 46. |
versal n cuts two lines I and m. 1s line I m?two li85°1120。60°BD and AE I BF. Find the values ofre, AC II BD andire |
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Answer» 1. These are not parallel lines because the corresponding opposite angles are not equal, which is a necessary condition for two lines to be parallel.2. These two lines are parallel because the corresponding complementary angles are equal, which is a necessary condition for two lines to be parallel. Please hit the like button if this helped you |
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| 47. |
ind05 |
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Answer» 7/3.5 = 2 is the answer but how send a pic 7)3.5(0.5 3.5=0 but answer is 2 2 is correct answer by mistakely it was sent oh thanks |
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| 48. |
ind ute |
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| 49. |
Answers the following questions.: 1. Why should we eat food? |
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Answer» Thefoods we eatprovide us with a range of nutrients: vitamins, minerals, water, fat, carbohydrates, fibre, and protein. |
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| 50. |
Bhavana rides her cycle around therectangular park everyday. The length of thepark is 20 m and breadth is half the length.How many metres she rides daily, if she takes5 rounds daily |
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Answer» Perimeter of park=2(length+breadth)=2(20+10)=2(30)=60m 1 round=60m5 rounds=60*5=300m |
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