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Length of the reservoir = 120 mBreadth of the reservoir = 75 mThe height of the water level in 18 hours = 2.4 mVolume of the water collected in the reservoir 120× 75× 2.4= 21600 m³Let the speed of the flowing water = x m/hrthe water flowing in the pipe eventually forms a cuboid of width 20 cm or 0.2 m and height of 20 cm or 0.2 m.The length of the cuboid so formed in the pipe in 18 hours = 18x mTherefore, the volume of the water flows out of the pipe in 18 hours = 0.2× 0.2× 18x= 0.72x m³Therefore,Volume of the water collected in the reservoir = volume of the water flows out of the pipe in 18 hours.21600 = 0.72xx = 21600/0.72x = 30000 m/hrOr, speed of the water = 30 km/hr

Total samosa =180no of friends=6 Thus each friend will get=180/6=30

Total samosha =180number of his friends =30each friends get samosha=180/6=30 samosha

total samosas÷no of friends180÷6=30each friend will get 30 samosas

2x/3 + 5x/8 + x/4 = 7400

16x+21x/24 = 7400

x = 7400*24/37

x = 4800

As share : 2*4800/3 = 2*1600 = 3800

Bs share : 5*4800/8 = 5*600 = 3000

Cs share : 4800/4 = 1200

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210.93 litres ...............

Hi there ❣️

We have to find H.C.F becoz we have to find maximum capacity of a milk.

\begin{lgathered}40 = 2 \times 2 \times 2 \times 5 \\ \\ 75 = 3 \times 5 \times 5 \\ \\ common \: factor \: is \: 5 \: so \: answer \: is \: 5\end{lgathered}40=2×2×2×575=3×5×5commonfactoris5soansweris5​

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Ratio of petrol in tank : Capicity of tank25 L : 100 L = 1 : 4So, ratio is 1 : 4

40 liters of mixture contains 4 liters of water (10%). So, it has 36 liters of milk.

if 36 liters <-> 80%,100% <-> (36/80)x100 = 45 liters

So, the total water in the mixture should be 9 liters. Since there is already 4 liters in the mixture, 5 liters need to be added.

rate of profit = (7350-7000)/7000 * 100 = 350×100/7000 = 5%

Wheat = 2058.25Maize = 1154.50Total amount = 3212.75

Total=60Female=35Male=60-35=25a. ratio of number of males to number of females=25/35=5:7b. number of females to total persons= 35/60=7:12

Total population of the city = 28756304Number of males in the city = 16987059∴ Number of females in the city = 28756304 ‒ 16987059 = 11769245

3/5 are male so 2/5 are female.now 30% males are married so 30% females are also.marriedso unmarried women=70% of 2/5=(70*2)/(5*100)=(7)/(25)=7/25 of total population

If 75 percentage = 360then 1 percentage = 360/75= 4.8then 25 percentage = 4.8*25= 120total number of workers= 120+360= 480

38 .55 is right answer

38.55 is the correct answer

I dont no hytf huff yrdfu yytf sru

Amount of money he required = 17.65 x 4 = 70.6Money he had = 31.45Amount of money he take from his father = 70.6 - 31.45 =39.1539.15 Answer

number of relation are 3×2 = 6 as A has three element ans B has two element

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nhi aya

(iii) diameter is the answer

diameter is the correct answer of the given question

2. Chord3. diameter4.125. length of arc

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4 no =a-3d,a-d,a+d,a+3dsum , 4a=56a=14.(a-3d)(a+3d)/(a-d)(a+d)=5:66(a²-9d²)=5(a²-d²)a²=54d² - 5d²14² =49d²d²=14² /7²d=±14/7=±2for d=2,a-3d=14-6=8a-d=14-2=12a+d=14+2=16a+3d=14+6=20Numbers are 8,12,16,20.

Distance left to travel = (3x²+4x-25) - (5x+4)= (3x²+4x-25-5x-4)= (3x²-x-29)

can't understanding

total distance is 3x^2+4x-25Ram has covered distance is 5x + 4So remaining distance is total- already covered distance=3x^2+4x-25-5x-4=3x^2-x-29

thank you so much

1 Rs, 50 Paise and 25 Paise are in 5 : 6 : 7 Suppose 1 Rs are 5k coins, 50 Paise 6k coins and 25 Paise 7k coins Total 117 Rs and 1 Rs = 100 Paisa so 5k + 50*6k/100 + 25*7k/100 = 117 5k + 3k + 7k/4 = 117 (32k+7k) = 117×4 39k = 117×4 k = 3×4 = 12 1 Rs 60 coins 50 Paise 72 coins 25 Paise 84 coins

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1 Rs, 50 Paise and 25 Paise are in 5 : 6 : 7 Suppose 1 Rs are 5k coins, 50 Paise 6k coins and 25 Paise 7k coins Total 117 Rs and 1 Rs = 100 Paisa so 5k + 50*6k/100 + 25*7k/100 = 117 5k + 3k + 7k/4 = 117 (32k+7k) = 117×4 39k = 117×4 k = 3×4 = 12 1 Rs 60 coins 50 Paise 72 coins 25 Paise 84 coins

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1 Rs, 50 Paise and 25 Paise are in 5 : 6 : 7 Suppose 1 Rs are 5k coins, 50 Paise 6k coins and 25 Paise 7k coins Total 117 Rs and 1 Rs = 100 Paisa so 5k + 50*6k/100 + 25*7k/100 = 117 5k + 3k + 7k/4 = 117 (32k+7k) = 117×4 39k = 117×4 k = 3×4 = 12 1 Rs 60 coins 50 Paise 72 coins 25 Paise 84 coins

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B is the ans become it includes both irrational and national

10 horses consume 18 bushel in 36 daysthen, 1 horse consumes 18 bushels in (36×10) days then,1 horse consumes 1 bushel in [(36 × 10) /18] days

then 30 horses consume 1 bushel in [(36 × 10)/(18 × 30)] days then 30 horses consume 18 bushel in[(36 × 10× 24)/(18 × 30)]day =16 days

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I am in class 8 . Let me TRY. I have solved but not confirmed can u please tell me the answer

8

13

540 kha s aya h