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8. Divide 56 in four parts in A.P. such that the ratio of the product of their extremes to theICBSE 2016product of their means is 5:6. |
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Answer» 4 no =a-3d,a-d,a+d,a+3dsum , 4a=56a=14.(a-3d)(a+3d)/(a-d)(a+d)=5:66(a²-9d²)=5(a²-d²)a²=54d² - 5d²14² =49d²d²=14² /7²d=±14/7=±2for d=2,a-3d=14-6=8a-d=14-2=12a+d=14+2=16a+3d=14+6=20Numbers are 8,12,16,20. |
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